Pearson Edexcel IGCSE · Further Pure Mathematics

Trigonometry: Practice Questions

5 multiple-choice questions marked as you go, and 5 written questions with worked solutions. All on Trigonometry.

10 questions24 marksFree, no account
Question 1
1 mark

Find the exact value of \(\sin 150^\circ + \cos 240^\circ\).

Question 2
1 mark

Solve the equation
\(4\sin^2\theta = 3\)
for \(0 \le \theta \le \pi\).
Give your answers in terms of \(\pi\).

Question 3
1 mark

Solve the equation \(2\cos^2 x + \sin x - 1 = 0\) for the interval \(0^\circ \le x < 360^\circ\).

Question 4
1 mark

Find all solutions to the equation
\(2\sin\theta - 1 = 0\)
for \(0^\circ \le \theta \le 360^\circ\).

Question 5
1 mark

Solve the equation
\(2\cos^2\theta - 3\cos\theta + 1 = 0\)
for \(0 \le \theta \le 2\pi\).
Give your answers in terms of \(\pi\).

Question 6
3 marks

Using the addition formula for \(\sin(A - B)\), find the exact value of \(\sin 15^\circ\).
Give your answer in the form \(\frac{\sqrt{6} - \sqrt{2}}{k}\), where \(k\) is an integer.

Write your answer out first, then check it against the worked solution.

Question 7
3 marks

A sector of a circle with radius \( r \) and center angle \( \theta \) radians has an area of \( 24\text{ cm}^2 \) and an arc length of \( 8\text{ cm} \). Find the value of \( r \) and the value of \( \theta \).

Write your answer out first, then check it against the worked solution.

Question 8
5 marks

Find the exact solutions of the equation \( 2\cos^2 \theta + 5\sin \theta = 4 \) for the interval \( 0 \le \theta \le 2\pi \).

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Question 9
3 marks

A sector of a circle of radius \(8\text{ cm}\) has an angle of \(1.25\) radians at the centre.
(a) Find the length of the arc of the sector.
(b) Find the area of the sector.

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Question 10
5 marks

(a) Use the identity \(\sin(A - B) = \sin A\cos B - \cos A\sin B\) with \(A = 45^\circ\) and \(B = 30^\circ\) to show that the exact value of \(\sin 15^\circ\) is \(\frac{\sqrt{6} - \sqrt{2}}{4}\).
(b) Solve the equation
\(4\sin\left(\theta - 15^\circ\right) = \sqrt{6} - \sqrt{2}\)
for \(0^\circ \le \theta \le 360^\circ\).

Write your answer out first, then check it against the worked solution.

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