AQA GCSE · Chemistry 8462
2 multiple-choice questions marked as you go, and 5 written questions with worked solutions. All on Using concentrations of solutions in mol/dm3 (chemistry only) (HT only).
In a titration, \(25.0\text{ cm}^3\) of \(0.100\text{ mol/dm}^3\) sodium hydroxide (\(\text{NaOH}\)) is neutralised by exactly \(20.0\text{ cm}^3\) of sulfuric acid (\(\text{H}_2\text{SO}_4\)).
The equation for the reaction is:
\(2\text{NaOH} + \text{H}_2\text{SO}_4 \rightarrow \text{Na}_2\text{SO}_4 + 2\text{H}_2\text{O}\)
Calculate the concentration of the sulfuric acid.
What mass of anhydrous sodium carbonate, \(\text{Na}_2\text{CO}_3\), is required to prepare \(500\text{ cm}^3\) of a solution with a concentration of \(0.2\text{ mol/dm}^3\)?
(Relative formula mass: \(\text{Na}_2\text{CO}_3 = 106\))
A solution of sodium chloride has a concentration of 0.200 mol/dm³. Calculate the mass of \(NaCl\) dissolved in 250 cm³ of this solution.
(Relative atomic masses: \(Na = 23\), \(Cl = 35.5\))
Write your answer out first, then check it against the worked solution.
In a titration, 20.0 cm³ of 0.500 mol/dm³ hydrochloric acid (\(HCl\)) neutralises 25.0 cm³ of sodium hydroxide (\(NaOH\)) solution. Calculate the concentration of the \(NaOH\) solution in g/dm³.
\(NaOH + HCl \rightarrow NaCl + H_{2}O\)
(Relative atomic masses: \(Na = 23, O = 16, H = 1\))
Write your answer out first, then check it against the worked solution.
A chemist prepares a solution by dissolving \(4.00\text{ g}\) of sodium hydroxide (\(NaOH\)) to make a final volume of \(500\text{ cm}^{3}\). Calculate the concentration of the solution in \(mol/dm^{3}\).
(Relative atomic masses: \(Na = 23\), \(O = 16\), \(H = 1\))
Write your answer out first, then check it against the worked solution.
A solution of sulfuric acid (\(H_2SO_4\)) has a concentration of \(0.250 \text{ mol/dm}^3\).
(a) Calculate the mass of sulfuric acid dissolved in \(200 \text{ cm}^3\) of this solution. (2 points)
(b) Convert the concentration of the solution from \(mol/dm^3\) to \(g/dm^3\). (2 points)
(Relative atomic masses: \(H = 1, S = 32, O = 16\))
Write your answer out first, then check it against the worked solution.
In a titration, \(25.0 \text{ cm}^3\) of \(0.150 \text{ mol/dm}^3\) sodium hydroxide solution (\(NaOH\)) was neutralised by \(30.0 \text{ cm}^3\) of hydrochloric acid (\(HCl\)).
The equation for the reaction is:
\(NaOH(aq) + HCl(aq) \rightarrow NaCl(aq) + H_2O(l)\)
(a) Calculate the number of moles of \(NaOH\) used in the titration. (1 point)
(b) Determine the concentration of the hydrochloric acid in both \(mol/dm^3\) and \(g/dm^3\). (4 points)
(Relative atomic masses: \(H = 1, Cl = 35.5\))
Write your answer out first, then check it against the worked solution.
* The content provided by thinka is generated by AI and may not always be accurate or up-to-date. Please use it as a supplementary resource and verify with official materials.
This page can show you how a good answer looks. It cannot tell you what your answer was missing. thinka marks your written work against the real mark scheme in about 15 seconds.
Want more questions like these? Get a fresh set on this topic, graded as you go.
Practice More