In terms of collision theory, why does an increase in the concentration of a reactant in the aqueous phase usually increase the rate of reaction?
Cambridge International A Level · Chemistry (9701)
Reaction kinetics (A Level only): Practice Questions
5 multiple-choice questions marked as you go, and 4 written questions with worked solutions. All on Reaction kinetics (A Level only).
In the industrial manufacture of ammonia by the Haber process, iron serves as a heterogeneous catalyst. Which of the following describes the correct sequence of steps for the mechanism on the catalyst surface?
The reaction between \(P\) and \(Q\) is represented by the equation: \(2P + Q \rightarrow R + S\).
A proposed mechanism for this reaction is:
Step 1: \(P + P \rightarrow P_2\) (slow)
Step 2: \(P_2 + Q \rightarrow R + S\) (fast)
What is the rate equation consistent with this mechanism?
Which statement best explains how a homogeneous catalyst functions in a chemical reaction?
The initial rate of a reaction between substances \(P\) and \(Q\) was measured in three separate experiments at constant temperature:
• Experiment 1: \([P] = 0.10 \text{ mol dm}^{-3}\), \([Q] = 0.10 \text{ mol dm}^{-3}\), Initial rate = \(2.0 \times 10^{-4} \text{ mol dm}^{-3} \text{ s}^{-1}\)
• Experiment 2: \([P] = 0.20 \text{ mol dm}^{-3}\), \([Q] = 0.10 \text{ mol dm}^{-3}\), Initial rate = \(8.0 \times 10^{-4} \text{ mol dm}^{-3} \text{ s}^{-1}\)
• Experiment 3: \([P] = 0.10 \text{ mol dm}^{-3}\), \([Q] = 0.30 \text{ mol dm}^{-3}\), Initial rate = \(6.0 \times 10^{-4} \text{ mol dm}^{-3} \text{ s}^{-1}\)
What is the overall order of the reaction?
Define the term activation energy, \(E_A\).
Write your answer out first, then check it against the worked solution.
Explain how the Boltzmann distribution curve changes when the temperature of a reaction mixture is increased and how this affects the rate of reaction.
Write your answer out first, then check it against the worked solution.
The decomposition of substance \(A\) follows first-order kinetics.
(a) State the relationship between the half-life of a first-order reaction and the initial concentration of the reactant.
(b) The rate constant for the decomposition of \(A\) is \(3.85 \times 10^{-4}\,s^{-1}\) at \(298\,K\). Calculate the half-life, \(t_{1/2}\), for this reaction.
(c) Explain, with reference to the Boltzmann distribution, why a small increase in temperature leads to a significant increase in the rate of reaction.
(d) State how a catalyst increases the rate of a reaction in terms of the activation energy, \(E_a\), and the reaction mechanism.<\/p>
Write your answer out first, then check it against the worked solution.
The reaction between hydrogen peroxide and iodide ions in acidic solution is a common reaction studied in kinetics:
\(H_2O_2(aq) + 2I^-(aq) + 2H^+(aq) \rightarrow I_2(aq) + 2H_2O(l)\)
The following initial rate data were obtained at a constant temperature:
| Experiment | \([H_2O_2]_0 / mol dm^{-3}\) | \([I^-]_0 / mol dm^{-3}\) | \([H^+]_0 / mol dm^{-3}\) | Initial Rate / \(mol dm^{-3} s^{-1}\) |
|---|---|---|---|---|
| 1 | 0.010 | 0.010 | 0.010 | \(1.15 \times 10^{-4}\) |
| 2 | 0.020 | 0.010 | 0.010 | \(2.30 \times 10^{-4}\) |
| 3 | 0.010 | 0.020 | 0.010 | \(2.30 \times 10^{-4}\) |
| 4 | 0.010 | 0.010 | 0.020 | \(1.15 \times 10^{-4}\) |
(a) Determine the order of reaction with respect to \(H_2O_2\), \(I^-\), and \(H^+\).
(b) Write the rate equation for this reaction.
(c) Calculate the rate constant, k, for this reaction, stating its units.
(d) Suggest a two-step mechanism for this reaction that is consistent with the derived rate equation. Clearly identify the rate-determining step.
Write your answer out first, then check it against the worked solution.
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