Pearson Edexcel GCSE (9-1) · Mathematics (1MA1)

Quadratic, cubic and reciprocal graphs: Practice Questions

5 multiple-choice questions marked as you go, and 5 written questions with worked solutions. All on Quadratic, cubic and reciprocal graphs.

10 questions30 marksFree, no account
Question 1
1 mark

Factorise the quadratic expression completely:
\(x^2 - 9x + 20\)

Question 2
1 mark

A sequence is defined by the quadratic formula for the \(n\)th term: \(u_n = an^2 + bn + c\).
The first four terms of the sequence are 5, 12, 23, and 38.
Find the expression for the \(n\)th term of this sequence.

Question 3
1 mark

The functions \(f\) and \(g\) are such that \(f(x) = 2x - 3\) and \(g(x) = x^2 + 1\).
Find the value of \(gf(4)\).

Question 4
1 mark

A sequence is defined by the term-to-term rule \(u_{n+1} = 3u_n - 4\).
Given that \(u_3 = 23\), calculate the value of \(u_1\).

Question 5
1 mark

Find the \(n\)-th term of the quadratic sequence:
\(5, 12, 23, 38, ...\)

Question 6
3 marks

A sequence is defined by the rule \(u_{n+1} = 2u_n - 3\). Given that \(u_1 = 5\), calculate the value of \(u_4\).

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Question 7
5 marks

Write \(3x^2 + 12x - 5\) in the form \(a(x+b)^2 + c\). Hence, write down the coordinates of the turning point of the graph of \(y = 3x^2 + 12x - 5\).

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Question 8
5 marks

Consider the function \(f(x) = x^2 + 5\) and its inverse \(f^{-1}(x)\).
Find the equation for the tangent to the curve \(y = f(x)\) at the point where the gradient of the curve is equal to the gradient of the line \(y = 6x - 1\).

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Question 9
5 marks

Solve the simultaneous equations:
\( y = 2x + 1 \)
\( x^2 + y^2 = 13 \)

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Question 10
7 marks

The first five terms of a quadratic sequence are: \(5, 12, 23, 38, 57\).

(a) Find an expression, in terms of \(n\), for the \(n\)th term of this sequence.
(b) The \(k\)th term of the sequence is \(530\). Find the value of \(k\).
(c) Prove that \(100\) cannot be a term in this sequence.

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