Senior Secondary (HKDSE) · Mathematics M2 (Algebra and Calculus)

More about trigonometric functions: Practice Questions

5 multiple-choice questions marked as you go, and 5 written questions with worked solutions. All on More about trigonometric functions.

10 questions27 marksFree, no account
Question 1
1 mark

Convert the angle \(315^\circ\) into radians, expressing the answer in terms of \(\pi\).

Question 2
1 mark

In \( \triangle ABC \), if \( \tan A = 2 \) and \( \tan B = 3 \), find the value of \( \tan C \).

Question 3
1 mark

Simplify the trigonometric expression:

$$E = \cos^2 x + \cos^2 \left(x + \frac{2\pi}{3}\right) + \cos^2 \left(x - \frac{2\pi}{3}\right)$$

Question 4
1 mark

Simplify the expression \( \sec^2 \theta - \frac{1}{\csc^2 \theta} - \tan^2 \theta \).

Question 5
1 mark

Simplify the expression \( \frac{1 - \cos 4\theta}{\sin^2 2\theta} \), assuming \( \sin 2\theta \ne 0 \).

Question 6
3 marks

Find the exact value of \( \cos \frac{5\pi}{12} + \cos \frac{\pi}{12} \).

Write your answer out first, then check it against the worked solution.

Question 7
5 marks

Let \(0 < x < \frac{\pi}{2}\).

(a) Find a pair of constants \(h\) and \(k\) such that
\(\frac{\sec x + \tan x}{\csc x + \cot x} + \frac{\sec x - \tan x}{\csc x - \cot x} \equiv h \sec x \csc x + k\).

(b) Solve the equation \(\frac{\sec x + \tan x}{\csc x + \cot x} + \frac{\sec x - \tan x}{\csc x - \cot x} = 2\).

Write your answer out first, then check it against the worked solution.

Question 8
6 marks

Solve the trigonometric equation \(sin(5\theta) + sin(3\theta) = cos(\theta) \) for \(0 \le \theta < \pi \).

Write your answer out first, then check it against the worked solution.

Question 9
3 marks

(a) Convert \( 150^\circ \) to radians, expressing the answer in terms of \( \pi \).
(b) A sector of a circle has radius 6 cm and a central angle of \( \frac{2\pi}{3} \) radians. Find the exact value of its arc length and area.

Write your answer out first, then check it against the worked solution.

Question 10
5 marks

(a) Prove the trigonometric identity:

$$ \frac{\cos 2x - \cos 4x}{\sin 4x + \sin 2x} = \tan x $$

(b) Hence, solve the equation \( \frac{\cos 2x - \cos 4x}{\sin 4x + \sin 2x} = 1 \) for \( 0 \le x < 2\pi \), ensuring the denominator is non-zero.

Write your answer out first, then check it against the worked solution.

* The content provided by thinka is generated by AI and may not always be accurate or up-to-date. Please use it as a supplementary resource and verify with official materials.

You've seen the model answer. Now get yours marked.

This page can show you how a good answer looks. It cannot tell you what your answer was missing. thinka marks your written work against the real mark scheme in about 15 seconds.

Want more questions like these? Get a fresh set on this topic, graded as you go.

Practice More