Cambridge OCR A Level · Further Mathematics A - H245

進階向量:练习题

5 道选择题即时批改,另有 5 道文字题附完整解题步骤,全部围绕「進階向量」。

10 道题目28 免费,无需注册
第 1 题
1

Determine the value of the constant \(k\) such that the line with direction vector \(\begin{pmatrix} 2 \\ -1 \\ 3 \end{pmatrix}\) is perpendicular to the line with direction vector \(\begin{pmatrix} k \\ 4 \\ 2 \end{pmatrix}\).

第 2 题
1

Find the shortest distance from the point \((1, -2, 3)\) to the plane with equation \(2x - 3y + 6z = 10\).

第 3 题
1

A tetrahedron has vertices at the points \(O(0, 0, 0)\), \(A(2, 0, 0)\), \(B(1, 3, 0)\), and \(C(1, 1, 4)\).
Calculate the volume of the tetrahedron.

第 4 题
1

Find the acute angle between the line \(\mathbf{r} = \begin{pmatrix} 1 \\ 2 \\ 3 \end{pmatrix} + \lambda \begin{pmatrix} 1 \\ 1 \\ 0 \end{pmatrix}\) and the plane \(x + z = 5\).

第 5 题
1

Find the shortest distance between the skew lines \(L_1\) and \(L_2\) with equations:
\(L_1: \mathbf{r} = \begin{pmatrix} 1 \\ 1 \\ 0 \end{pmatrix} + \lambda \begin{pmatrix} 1 \\ 0 \\ 1 \end{pmatrix}\)
\(L_2: \mathbf{r} = \begin{pmatrix} 2 \\ 0 \\ 1 \end{pmatrix} + \mu \begin{pmatrix} 0 \\ 1 \\ 1 \end{pmatrix}\)

第 6 题
2

Find the value of the constant \(k\) such that the vectors \(\mathbf{a} = 2\mathbf{i} - 3\mathbf{j} + \mathbf{k}\) and \(\mathbf{b} = k\mathbf{i} + 2\mathbf{j} + 4\mathbf{k}\) are perpendicular.

先自己写一遍答案,再对照解题步骤。

第 7 题
4

Find the coordinates of the point of intersection between the line with vector equation \(\mathbf{r} = \begin{pmatrix} 2 \\ -1 \\ 3 \end{pmatrix} + \lambda \begin{pmatrix} 1 \\ 2 \\ -1 \end{pmatrix}\) and the plane with cartesian equation \(2x - y + z = 12\).

先自己写一遍答案,再对照解题步骤。

第 8 题
5

A point \(P\) has position vector \(\mathbf{b} = \begin{pmatrix} 1 \\ 5 \\ -2 \end{pmatrix}\) and a plane is defined by the equation \(\mathbf{r} \cdot \begin{pmatrix} 3 \\ -4 \\ 12 \end{pmatrix} = 10\). Use the formula \(D = \frac{|\mathbf{b} \cdot \mathbf{n} - p|}{|\mathbf{n}|}\) to calculate the shortest distance from point \(P\) to the plane.

先自己写一遍答案,再对照解题步骤。

第 9 题
5

The line \(L\) has vector equation \(\mathbf{r} = \begin{pmatrix} 1 \\\\ -2 \\\\ 3 \end{pmatrix} + \lambda \begin{pmatrix} 2 \\\\ 1 \\\\ -1 \end{pmatrix}\) and the plane \(\Pi\) has cartesian equation \(x - 2y + 2z = 7\).
(a) Find the coordinates of the point \(P\) where the line \(L\) intersects the plane \(\Pi\).
(b) Calculate the acute angle between the line \(L\) and the plane \(\Pi\), giving your answer in degrees to one decimal place.

先自己写一遍答案,再对照解题步骤。

第 10 题
7

The lines \(L_1\) and \(L_2\) are defined by the following vector equations:
\(L_1: \mathbf{r} = \begin{pmatrix} 1 \\\\ 0 \\\\ 1 \end{pmatrix} + \lambda \begin{pmatrix} 1 \\\\ 2 \\\\ -1 \end{pmatrix}\)
\(L_2: \mathbf{r} = \begin{pmatrix} 2 \\\\ 1 \\\\ 0 \end{pmatrix} + \mu \begin{pmatrix} 0 \\\\ 1 \\\\ 1 \end{pmatrix}\)
(a) Show that the lines \(L_1\) and \(L_2\) are skew.
(b) Use the vector product to find a vector \(\mathbf{n}\) that is perpendicular to both \(L_1\) and \(L_2\).
(c) Hence, determine the shortest distance between the lines \(L_1\) and \(L_2\), giving your answer in exact form.

先自己写一遍答案,再对照解题步骤。

* thinka 提供的内容由 AI 生成,未必在任何情况下都完全准确或最新,请结合官方教材与教师指导使用。

你已看过标准答案。现在轮到你的答案被批改。

这一页能告诉你好答案是什么样子,却无法指出你的答案缺了什么。thinka 按真实评分标准批改你的文字答案,约 15 秒完成。

想多做几道同类题目?立即开始练习这个课题,边做边批改。

立即练习