A capacitor has a capacitance of \(4.7\text{ }μ\text{F}\) and is charged to a potential difference of \(12\text{ V}\). What is the magnitude of the charge stored on either plate of the capacitor?
GCE A-Level - Higher 2 (H2) · Physics (9478)
Capacitance:练习题
5 道选择题即时批改,另有 2 道文字题附完整解题步骤,全部围绕「Capacitance」。
A capacitor is charged to a potential difference \(V_0\) and stores energy \(E_0\). If the potential difference across the capacitor is increased such that the stored energy becomes \(4E_0\), by what factor does the charge stored on the capacitor increase?
A \(20\text{ }μ\text{F}\) capacitor is charged to a potential difference of \(50\text{ V}\) and then disconnected from the power supply. It is then connected in parallel with an uncharged \(30\text{ }μ\text{F}\) capacitor. What is the total energy dissipated as heat and radiation during the redistribution of charge?
A capacitor stores a charge of \(3.0 \times 10^{-4}\text{ C}\) when connected across a \(15\text{ V}\) power supply. What is the electrical energy stored in the capacitor?
Two capacitors of capacitance \(6.0\text{ }μ\text{F}\) and \(12.0\text{ }μ\text{F}\) are connected in series across a \(9.0\text{ V}\) d.c. supply. What is the potential difference across the \(6.0\text{ }μ\text{F}\) capacitor?
A parallel-plate capacitor is charged such that the potential difference across its plates is \(12.0\text{ V}\). The charge stored on each plate is \(4.80\times 10^{-5}\text{ C}\).
(a) Calculate the capacitance \(C\) of the capacitor.
(b) Determine the energy stored in the capacitor.
先自己写一遍答案,再对照解题步骤。
A capacitor \(C_1 = 6.0\,\mu\text{F}\) is charged to a potential difference of \(50.0\text{ V}\) and then isolated from the power supply. It is then connected in parallel with an uncharged capacitor \(C_2 = 4.0\,\mu\text{F}\).
(a) State the total charge conserved in the system.
(b) Calculate the common potential difference \(V_f\) across the parallel combination.
(c) Calculate the loss in total electrostatic energy stored in the capacitors after connection.
先自己写一遍答案,再对照解题步骤。
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