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Thinka Jun 2025 (V2) Cambridge International A Level-Style Mock — Chemistry (0620)

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An original Thinka practice paper modelled on the structure and difficulty of the Jun 2025 (V2) Cambridge International A Level Chemistry (0620) paper. Not affiliated with or reproduced from Cambridge.

Paper 22

Answer all 40 multiple-choice questions. For each question, choose the single correct alternative from A, B, C or D.
40 PastPaper.question · 40 PastPaper.marks
PastPaper.question 1 · multiple-choice
1 PastPaper.marks
Propene reacts with steam in the presence of an acid catalyst to form propanol. Under which conditions does this reaction occur, and what is the change in the color of aqueous bromine when it is added to propene?
  1. A.Catalyst: \(H_3PO_4\); Temperature: 300 °C; Bromine color change: brown to colorless
  2. B.Catalyst: \(H_3PO_4\); Temperature: 100 °C; Bromine color change: colorless to brown
  3. C.Catalyst: Ni; Temperature: 300 °C; Bromine color change: brown to colorless
  4. D.Catalyst: Ni; Temperature: 100 °C; Bromine color change: colorless to brown
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PastPaper.workedSolution

The hydration of alkenes to form alcohols requires an acid catalyst (phosphoric acid, \(H_3PO_4\)), a temperature of 300 °C, and a pressure of 60 atm. Alkenes are unsaturated hydrocarbons and undergo an addition reaction with aqueous bromine, decolourizing it from orange/brown to colourless. Therefore, option A is correct.

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1 mark for the correct option A. Reject other options.
PastPaper.question 2 · multiple-choice
1 PastPaper.marks
A student wants to investigate the rate of reaction between calcium carbonate and dilute hydrochloric acid by measuring the volume of carbon dioxide gas released over time. Which pieces of apparatus are most suitable to measure the volume of gas and the time taken?
  1. A.Gas syringe and stopclock
  2. B.Gas syringe and balance
  3. C.Measuring cylinder (upright, empty) and stopclock
  4. D.Pipette and balance
PastPaper.showAnswers

PastPaper.workedSolution

To measure the rate of a reaction that produces a gas, we need to measure either the volume of gas released over time or the decrease in mass over time. To measure the volume of gas, a gas syringe is used. To measure the time taken, a stopclock is used. Thus, the correct combination is a gas syringe and stopclock.

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1 mark for selecting the correct pair of apparatus: gas syringe and stopclock (Option A).
PastPaper.question 3 · multiple-choice
1 PastPaper.marks
A solid X is dissolved in water to make an aqueous solution. Portions of this solution are tested as follows:
1. Addition of aqueous sodium hydroxide produces a green precipitate that is insoluble in excess.
2. Addition of dilute nitric acid followed by aqueous barium nitrate produces a white precipitate.
What is the identity of compound X?
  1. A.Iron(II) sulfate
  2. B.Iron(III) sulfate
  3. C.Chromium(III) chloride
  4. D.Iron(II) chloride
PastPaper.showAnswers

PastPaper.workedSolution

The addition of aqueous sodium hydroxide produces a green precipitate that is insoluble in excess, which confirms the presence of iron(II) ions, \(Fe^{2+}\). Chromium(III) also forms a green precipitate, but it is soluble in excess sodium hydroxide to form a dark green solution. The reaction with aqueous barium nitrate in acidic conditions produces a white precipitate of barium sulfate, which confirms the presence of sulfate ions, \(SO_4^{2-}\). Therefore, compound X is iron(II) sulfate.

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1 mark for the correct compound, Option A.
PastPaper.question 4 · multiple-choice
1 PastPaper.marks
Which statement about endothermic reactions is correct?
  1. A.The temperature of the surroundings increases because energy is released when bonds are formed.
  2. B.The energy level of the products is higher than the energy level of the reactants, and \(\Delta H\) is positive.
  3. C.More energy is released when bonds are formed than is absorbed when bonds are broken.
  4. D.The activation energy is always negative because energy is taken in.
PastPaper.showAnswers

PastPaper.workedSolution

In an endothermic reaction, heat energy is absorbed from the surroundings, meaning the temperature of the surroundings decreases, and the products have a higher energy level than the reactants. Therefore, the change in enthalpy (\(\Delta H\)) is positive. Bond breaking is endothermic and bond making is exothermic; in an endothermic reaction, more energy is absorbed during bond breaking than is released during bond making. Activation energy is always positive. Hence, option B is correct.

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1 mark for option B.
PastPaper.question 5 · multiple-choice
1 PastPaper.marks
Metal M is heated with the oxides of three other metals: copper, iron, and zinc. The results are shown below:
- M + copper(II) oxide \(\rightarrow\) reaction occurs
- M + iron(II) oxide \(\rightarrow\) no reaction
- M + zinc oxide \(\rightarrow\) no reaction
What is a possible identity of metal M?
  1. A.Lead
  2. B.Magnesium
  3. C.Sodium
  4. D.Zinc
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PastPaper.workedSolution

A more reactive metal will displace a less reactive metal from its oxide. Metal M is able to reduce copper(II) oxide, which means M is more reactive than copper. However, M cannot reduce iron(II) oxide or zinc oxide, meaning M is less reactive than both iron and zinc. In the reactivity series, lead is positioned between iron and copper: Zn > Fe > Pb > Cu. Therefore, lead matches these observations.

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1 mark for identifying lead as the correct metal (Option A).
PastPaper.question 6 · multiple-choice
1 PastPaper.marks
Chlorine has two naturally occurring isotopes: \(^{35}\text{Cl}\) and \(^{37}\text{Cl}\). Which statement about these isotopes is correct?
  1. A.They have different chemical properties because they have different numbers of neutrons.
  2. B.They have the same physical properties, such as density and boiling point, because they have the same number of protons.
  3. C.They have the same chemical properties because they have the same number of electrons in their outer shell.
  4. D.A neutral atom of \(^{37}\text{Cl}\) has two more protons than a neutral atom of \(^{35}\text{Cl}\).
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PastPaper.workedSolution

Isotopes are atoms of the same element with the same number of protons but different numbers of neutrons. Because they have the same number of protons, neutral atoms of isotopes also have the same number and arrangement of electrons, including the same number of outer-shell electrons. This gives them identical chemical properties. They have slightly different physical properties (like mass and density) due to the difference in mass. Therefore, option C is correct.

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1 mark for option C.
PastPaper.question 7 · multiple-choice
1 PastPaper.marks
A mixture contains copper(II) sulfate (soluble in water) and sand (insoluble in water). A student wants to obtain pure, dry crystals of copper(II) sulfate and dry sand from this mixture. In which order should the student carry out the processes?
  1. A.dissolve in water \(\rightarrow\) crystallize \(\rightarrow\) filter
  2. B.dissolve in water \(\rightarrow\) filter \(\rightarrow\) crystallize the filtrate
  3. C.filter \(\rightarrow\) dissolve in water \(\rightarrow\) crystallize
  4. D.crystallize \(\rightarrow\) dissolve in water \(\rightarrow\) filter
PastPaper.showAnswers

PastPaper.workedSolution

To separate a soluble solid from an insoluble solid: 1. Dissolve the mixture in water: the copper(II) sulfate dissolves while the sand remains insoluble. 2. Filter the mixture: the insoluble sand is collected as the residue on the filter paper, while the copper(II) sulfate solution passes through as the filtrate. 3. Heat the filtrate to evaporate some of the water and crystallize the copper(II) sulfate. Hence, option B is correct.

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1 mark for option B.
PastPaper.question 8 · multiple-choice
1 PastPaper.marks
Which statement about the giant covalent structures of diamond, graphite, and silicon(IV) oxide is correct?
  1. A.In graphite, each carbon atom is covalently bonded to four other carbon atoms in a tetrahedral arrangement.
  2. B.Silicon(IV) oxide has a giant structure where each silicon atom is bonded to two oxygen atoms.
  3. C.Graphite conducts electricity because it has mobile delocalized electrons between its layers.
  4. D.Diamond and silicon(IV) oxide have low melting points because of weak intermolecular forces.
PastPaper.showAnswers

PastPaper.workedSolution

In graphite, each carbon atom is bonded to three other carbon atoms in hexagonal layers, leaving one valence electron per carbon atom delocalized. These delocalized electrons are free to move between layers and conduct electricity. In diamond, each carbon is bonded to four other carbons. In silicon(IV) oxide, each silicon is bonded to four oxygen atoms, and each oxygen is bonded to two silicon atoms. Both diamond and silicon(IV) oxide have high melting points because they have giant structures with strong covalent bonds that require large amounts of energy to break.

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1 mark for option C.
PastPaper.question 9 · multiple-choice
1 PastPaper.marks
An atom of element X has 19 protons and 20 neutrons. An atom of element Y has 17 protons and 18 neutrons. Which statement about X and Y is correct?
  1. A.X and Y are isotopes of the same element.
  2. B.X and Y are in the same group of the Periodic Table.
  3. C.An atom of X has more electron shells than an atom of Y.
  4. D.X and Y react together to form a covalent compound.
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PastPaper.workedSolution

X has atomic number 19 (potassium, electronic configuration 2,8,8,1), which has 4 occupied electron shells. Y has atomic number 17 (chlorine, electronic configuration 2,8,7), which has 3 occupied electron shells. Therefore, an atom of X has more electron shells than an atom of Y.

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1 mark for identifying that X has 4 electron shells (configuration 2,8,8,1) and Y has 3 electron shells (configuration 2,8,7).
PastPaper.question 10 · multiple-choice
1 PastPaper.marks
Dilute sulfuric acid is electrolysed using inert platinum electrodes. Which statement describes the reaction at the anode (positive electrode)?
  1. A.Hydrogen gas is evolved and bubbles are observed.
  2. B.Oxygen gas is evolved and bubbles are observed.
  3. C.Sulfur dioxide gas is evolved and a pungent smell is detected.
  4. D.The electrode decreases in mass as platinum dissolves.
PastPaper.showAnswers

PastPaper.workedSolution

During the electrolysis of dilute sulfuric acid, both \(H^+\) and \(OH^-\) ions (from water) along with \(SO_4^{2-}\) ions are present. At the anode (positive electrode), hydroxide ions (\(OH^-\)) are preferentially discharged to form oxygen gas and water: \(4OH^- \rightarrow 2H_2O + O_2 + 4e^-\). Thus, bubbles of oxygen gas are observed at the anode.

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1 mark for identifying that oxygen gas is evolved at the anode.
PastPaper.question 11 · multiple-choice
1 PastPaper.marks
What is the total number of shared pairs of electrons in one molecule of methanol, \(CH_3OH\)?
  1. A.4
  2. B.5
  3. C.8
  4. D.10
PastPaper.showAnswers

PastPaper.workedSolution

A molecule of methanol contains three C-H single covalent bonds, one C-O single covalent bond, and one O-H single covalent bond. Each single covalent bond consists of one shared pair of electrons. Therefore, there are 3 + 1 + 1 = 5 shared pairs of electrons in total.

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1 mark for correctly identifying 5 single covalent bonds as 5 shared pairs of electrons.
PastPaper.question 12 · multiple-choice
1 PastPaper.marks
Ethene is reacted with steam to manufacture ethanol. Which set of conditions is used for this industrial process?
  1. A.nickel catalyst, 150 °C, 5 atm pressure
  2. B.yeast, 30 °C, atmospheric pressure
  3. C.phosphoric acid catalyst, 300 °C, 60 atm pressure
  4. D.iron catalyst, 450 °C, 200 atm pressure
PastPaper.showAnswers

PastPaper.workedSolution

The industrial hydration of ethene to produce ethanol is carried out at a temperature of 300 °C, a pressure of 60 atm, using a phosphoric acid (\(H_3PO_4\)) catalyst.

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1 mark for selecting the correct set of industrial conditions: phosphoric acid catalyst, 300 °C, and 60 atm.
PastPaper.question 13 · multiple-choice
1 PastPaper.marks
A student investigates the rate of reaction between excess calcium carbonate chips and dilute hydrochloric acid by measuring the volume of gas produced. Which set of apparatus is essential to collect the data needed to plot a rate graph?
  1. A.balance, gas syringe, thermometer
  2. B.conical flask, gas syringe, stopclock
  3. C.conical flask, pipette, thermometer
  4. D.measuring cylinder, beaker, balance
PastPaper.showAnswers

PastPaper.workedSolution

To plot a graph of gas volume against time, the student must measure the volume of gas at recorded intervals. A conical flask holds the reactants, a gas syringe collects and measures the volume of carbon dioxide gas, and a stopclock is used to measure the time.

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1 mark for identifying the combination of conical flask, gas syringe, and stopclock.
PastPaper.question 14 · multiple-choice
1 PastPaper.marks
An aqueous solution contains \(Cr^{3+}\) ions. What is observed when aqueous sodium hydroxide is added dropwise and then in excess to this solution?
  1. A.A green precipitate is formed which dissolves in excess to give a green solution.
  2. B.A green precipitate is formed which is insoluble in excess.
  3. C.A grey-green precipitate is formed which dissolves in excess to give a colourless solution.
  4. D.A light blue precipitate is formed which dissolves in excess to give a deep blue solution.
PastPaper.showAnswers

PastPaper.workedSolution

Chromium(III) ions (\(Cr^{3+}\)) form a green precipitate of chromium(III) hydroxide when reacted with dropwise sodium hydroxide. Since chromium(III) hydroxide is amphoteric, it dissolves in excess sodium hydroxide to form a soluble green complex solution.

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1 mark for identifying that a green precipitate forms and dissolves in excess to give a green solution.
PastPaper.question 15 · multiple-choice
1 PastPaper.marks
The reaction between nitrogen and hydrogen to form ammonia is exothermic: \(N_2(g) + 3H_2(g) \rightarrow 2NH_3(g)\). Which statement explains why this reaction is exothermic?
  1. A.The energy absorbed to break bonds in nitrogen and hydrogen is greater than the energy released when bonds in ammonia are formed.
  2. B.The energy released when bonds in ammonia are formed is greater than the energy absorbed to break bonds in nitrogen and hydrogen.
  3. C.More bonds are broken than are formed during the reaction.
  4. D.The activation energy of the forward reaction is greater than the activation energy of the reverse reaction.
PastPaper.showAnswers

PastPaper.workedSolution

An exothermic reaction is one where energy is released to the surroundings because the total energy released when new bonds are formed in the products (ammonia) is greater than the total energy absorbed to break the chemical bonds in the reactants (nitrogen and hydrogen).

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1 mark for identifying that bond-making releases more energy than bond-breaking absorbs.
PastPaper.question 16 · multiple-choice
1 PastPaper.marks
A student wants to obtain a pure sample of liquid water from aqueous sodium chloride. Which experimental method should the student use?
  1. A.crystallisation
  2. B.filtration
  3. C.fractional distillation
  4. D.simple distillation
PastPaper.showAnswers

PastPaper.workedSolution

To obtain pure liquid water from a salt solution, the water must be vaporised and then condensed. This process is simple distillation. Crystallisation would yield solid sodium chloride but let the water evaporate into the air. Filtration cannot separate dissolved ions, and fractional distillation is used for separating mixtures of liquids with close boiling points.

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1 mark for selecting simple distillation.
PastPaper.question 17 · multiple-choice
1 PastPaper.marks
An atom of element X has 17 protons and 18 neutrons. An atom of element Y has 17 protons and 20 neutrons. Which statement about X and Y is correct?
  1. A.They have different chemical properties because they have different numbers of neutrons.
  2. B.They are isotopes of the same element because they have the same number of protons.
  3. C.They have the same physical properties, such as density and boiling point.
  4. D.They are in different groups of the Periodic Table..
PastPaper.showAnswers

PastPaper.workedSolution

Isotopes are atoms of the same element with the same number of protons but different numbers of neutrons. Since they have the same number of protons, their electronic configuration is identical, meaning they have the same chemical properties. However, their physical properties (like density and rate of diffusion) differ because they have different masses.

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Award 1 mark for selecting correct option B.
PastPaper.question 18 · multiple-choice
1 PastPaper.marks
The electrolysis of concentrated aqueous sodium chloride is carried out using inert electrodes. Which row correctly identifies the products at each electrode and the change in pH of the electrolyte during the electrolysis? Row A: cathode product is hydrogen, anode product is chlorine, pH increases. Row B: cathode product is sodium, anode product is chlorine, pH decreases. Row C: cathode product is hydrogen, anode product is oxygen, pH has no change. Row D: cathode product is sodium, anode product is oxygen, pH increases.
  1. A.Row A
  2. B.Row B
  3. C.Row C
  4. D.Row D
PastPaper.showAnswers

PastPaper.workedSolution

During the electrolysis of concentrated aqueous sodium chloride: At the cathode (-), hydrogen ions are discharged in preference to sodium ions because hydrogen is lower in the reactivity series, producing hydrogen gas. At the anode (+), chloride ions are discharged in preference to hydroxide ions because it is a concentrated halide solution, producing chlorine gas. As hydrogen ions and chloride ions are removed, the remaining sodium ions and hydroxide ions form sodium hydroxide, which is alkaline, so the pH of the electrolyte increases. This matches row A.

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Award 1 mark for selecting correct option A.
PastPaper.question 19 · multiple-choice
1 PastPaper.marks
Hydrocarbon W reacts with steam in the presence of an acid catalyst to form an alcohol with the molecular formula \(C_4H_{10}O\). Which statement about hydrocarbon W is correct?
  1. A.It is saturated and turns aqueous bromine from orange to colorless.
  2. B.It is unsaturated and turns aqueous bromine from orange to colorless.
  3. C.It is saturated and has no effect on the color of aqueous bromine.
  4. D.It is unsaturated and has no effect on the color of aqueous bromine.
PastPaper.showAnswers

PastPaper.workedSolution

The addition reaction of a hydrocarbon with steam to form an alcohol is characteristic of alkenes. The alkene reactant must be butene, \(C_4H_8\), which is an unsaturated hydrocarbon containing a carbon-carbon double bond. Unsaturated hydrocarbons react with orange aqueous bromine, decolorizing it (turning it colorless).

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Award 1 mark for selecting correct option B.
PastPaper.question 20 · multiple-choice
1 PastPaper.marks
Which statement about the macromolecular structure of silicon(IV) oxide, \(SiO_2\), is correct?
  1. A.It contains simple covalent molecules held together by weak intermolecular forces.
  2. B.Each silicon atom is covalently bonded to four oxygen atoms, and each oxygen atom is covalently bonded to two silicon atoms.
  3. C.It conducts electricity when molten because it contains mobile ions.
  4. D.It has a low melting point because only weak covalent bonds are broken during melting.
PastPaper.showAnswers

PastPaper.workedSolution

Silicon(IV) oxide has a giant covalent (macromolecular) structure. In this structure, each silicon atom forms four covalent bonds to oxygen atoms in a tetrahedral arrangement, and each oxygen atom forms two covalent bonds to silicon atoms. It does not conduct electricity as there are no free ions or electrons, and it has a very high melting point due to the strong covalent bonds throughout the giant lattice.

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Award 1 mark for selecting correct option B.
PastPaper.question 21 · multiple-choice
1 PastPaper.marks
A student wants to investigate the rate of reaction between calcium carbonate (marble chips) and dilute hydrochloric acid by measuring the volume of gas produced over time. Which set of apparatus is most suitable for this investigation?
  1. A.Balance, beaker, and thermometer
  2. B.Gas syringe, conical flask, and stop-watch
  3. C.Pipette, burette, and indicator
  4. D.Condenser, fractionating column, and Bunsen burner
PastPaper.showAnswers

PastPaper.workedSolution

To measure the rate of a gas-producing reaction by gas volume, a conical flask is needed for the reaction, a gas syringe is required to collect and measure the volume of gas, and a stop-watch is needed to measure the time intervals.

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Award 1 mark for selecting correct option B.
PastPaper.question 22 · multiple-choice
1 PastPaper.marks
A pale green or colorless solution is tested. When aqueous sodium hydroxide is added, a green precipitate is formed which is insoluble in excess. When dilute nitric acid followed by aqueous barium nitrate is added, a white precipitate is formed. Which compound is present in the solution?
  1. A.chromium(III) chloride
  2. B.iron(II) sulfate
  3. C.iron(III) sulfate
  4. D.copper(II) chloride
PastPaper.showAnswers

PastPaper.workedSolution

The green precipitate with aqueous sodium hydroxide that is insoluble in excess indicates the presence of iron(II) ions, \(Fe^{2+}\). (Note: Chromium(III) also forms a green precipitate, but it is soluble in excess sodium hydroxide to form a green solution). The white precipitate formed upon adding dilute nitric acid followed by aqueous barium nitrate indicates the presence of sulfate ions, \(SO_4^{2-}\). Therefore, the compound is iron(II) sulfate.

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Award 1 mark for selecting correct option B.
PastPaper.question 23 · multiple-choice
1 PastPaper.marks
A chemical reaction has a reaction pathway diagram where the energy level of the products is higher than the energy level of the reactants. Which row correctly describes this reaction? Row A: reaction is endothermic, sign of enthalpy change is positive (+), reactants have less energy than products. Row B: reaction is exothermic, sign of enthalpy change is negative (-), reactants have more energy than products. Row C: reaction is endothermic, sign of enthalpy change is negative (-), reactants have more energy than products. Row D: reaction is exothermic, sign of enthalpy change is positive (+), reactants have less energy than products.
  1. A.Row A
  2. B.Row B
  3. C.Row C
  4. D.Row D
PastPaper.showAnswers

PastPaper.workedSolution

If the products are at a higher energy level than the reactants, energy has been absorbed from the surroundings during the reaction. This means the reaction is endothermic, the enthalpy change, \(\Delta H\), is positive, and the reactants have less energy than the products. This corresponds to row A.

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Award 1 mark for selecting correct option A.
PastPaper.question 24 · multiple-choice
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Four metals, P, Q, R, and S, were tested under different conditions. Metal P reacts rapidly with cold water to produce hydrogen gas. The oxide of metal Q can be reduced to the metal when heated with carbon. Metal R does not react with dilute hydrochloric acid, but its oxide cannot be decomposed by heating alone. Metal S is obtained by heating its oxide alone. What is the order of reactivity of the metals, from most reactive to least reactive?
  1. A.P -> Q -> R -> S
  2. B.P -> R -> Q -> S
  3. C.Q -> P -> R -> S
  4. D.S -> R -> Q -> P
PastPaper.showAnswers

PastPaper.workedSolution

Metal P is highly reactive as it reacts with cold water. Metal Q is less reactive than carbon, but its oxide requires a reducing agent (carbon) to be reduced, meaning it is more reactive than metals whose oxides can decompose on heating alone. Metal R does not react with acid, placing it below hydrogen, but since its oxide cannot be decomposed by heat alone, it is more reactive than metal S, whose oxide is easily decomposed by heating alone. Thus, the order of decreasing reactivity is P -> Q -> R -> S.

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Award 1 mark for selecting correct option A.
PastPaper.question 25 · multiple-choice
1 PastPaper.marks
A student wants to obtain a pure sample of solid cobalt(II) chloride from an aqueous solution of cobalt(II) chloride. Which sequence of steps should the student carry out?
  1. A.Filter the solution, wash the residue with water, and dry it.
  2. B.Heat the solution until it is dry.
  3. C.Heat the solution to concentrate it, leave it to cool and crystallise, filter the crystals, and dry them between filter papers.
  4. D.Perform fractional distillation on the solution and collect the distillate.
PastPaper.showAnswers

PastPaper.workedSolution

Cobalt(II) chloride is a soluble salt. To obtain a pure, crystalline sample of a soluble salt from its solution, crystallization is used. The solution is heated to concentrate it (evaporating some water), left to cool so crystals form, filtered to separate the crystals from the remaining liquid, and finally dried between filter papers. Heating to dryness (Option B) would lead to thermal decomposition or the formation of anhydrous powder rather than pure hydrated crystals. Filtration alone (Option A) is incorrect because the salt is soluble and would pass through the filter paper. Fractional distillation (Option D) would collect water, not the solid salt.

PastPaper.markingScheme

1 mark for selecting C.
- Reject A because the salt is soluble and cannot be separated by simple filtration.
- Reject B because heating to dryness destroys the crystal structure or decomposes the salt.
- Reject D because distillation is used to collect the solvent (water), not the solute.
PastPaper.question 26 · multiple-choice
1 PastPaper.marks
An ion of an isotope of element \(X\) is represented as \({}_{34}^{79}X^{2-}\). Which row in the table shows the correct number of protons, neutrons, and electrons in this ion?

$$\begin{array}{|c|c|c|c|} \hline & \text{protons} & \text{neutrons} & \text{electrons} \\ \hline \text{A} & 34 & 45 & 32 \\ \hline \text{B} & 34 & 45 & 36 \\ \hline \text{C} & 34 & 79 & 36 \\ \hline \text{D} & 36 & 45 & 34 \\ \hline \end{array}$$
  1. A.Row A
  2. B.Row B
  3. C.Row C
  4. D.Row D
PastPaper.showAnswers

PastPaper.workedSolution

The atomic number (proton number) is the lower number, 34, so there are 34 protons. The mass number (nucleon number) is the upper number, 79. The number of neutrons is calculated by subtracting the proton number from the mass number: \(79 - 34 = 45\) neutrons. The ion has a charge of \(2-\), meaning it has gained 2 electrons compared to its neutral state. The number of electrons is \(34 + 2 = 36\) electrons. This corresponds to row B.

PastPaper.markingScheme

1 mark for B.
- Reject A: represents a \(2+\) cation instead of a \(2-\) anion.
- Reject C: uses the mass number (79) as the number of neutrons.
- Reject D: incorrect atomic number for the element.
PastPaper.question 27 · multiple-choice
1 PastPaper.marks
Methanol, \(\text{CH}_3\text{OH}\), is a simple covalent molecule. What is the total number of shared pairs of electrons (bonding pairs) in one molecule of methanol?
  1. A.4
  2. B.5
  3. C.6
  4. D.8
PastPaper.showAnswers

PastPaper.workedSolution

The structural formula of methanol is \(\text{H}_3\text{C}-\text{O}-\text{H}\). Let us count the single covalent bonds present in this molecule:
- Three \(\text{C}-\text{H}\) single bonds
- One \(\text{C}-\text{O}\) single bond
- One \(\text{O}-\text{H}\) single bond
Each single covalent bond represents one shared pair of electrons. Therefore, there are \(3 + 1 + 1 = 5\) shared pairs of electrons in total.

PastPaper.markingScheme

1 mark for B.
- Reject A: misses one of the single covalent bonds.
- Reject C: incorrect count of covalent bonds.
- Reject D: represents the total valence electrons of oxygen/carbon rather than the shared bonding pairs.
PastPaper.question 28 · multiple-choice
1 PastPaper.marks
An organic compound \(Y\) reacts with steam in the presence of an acid catalyst to produce an alcohol with the molecular formula \(\text{C}_4\text{H}_{10}\text{O}\). What is a possible structure for compound \(Y\)?
  1. A.\(\text{CH}_3\text{CH}_2\text{CH}_2\text{CH}_3\)
  2. B.\(\text{CH}_3\text{CH}_2\text{CH}=\text{CH}_2\)
  3. C.\(\text{CH}_3\text{CH}_2\text{CH}_2\text{OH}\)
  4. D.\(\text{CH}_3\text{CH}=\text{CH}_2\)
PastPaper.showAnswers

PastPaper.workedSolution

The reaction of an organic compound with steam to produce an alcohol is an addition reaction (hydration) characteristic of alkenes. The general equation is \(\text{C}_n\text{H}_{2n} + \text{H}_2\text{O} \rightarrow \text{C}_n\text{H}_{2n+2}\text{O}\). Since the product alcohol has 4 carbon atoms (\(\text{C}_4\text{H}_{10}\text{O}\)), the starting alkene must also contain 4 carbon atoms. \(\text{CH}_3\text{CH}_2\text{CH}=\text{CH}_2\) (but-1-ene) is an alkene with 4 carbon atoms and reacts with steam to form butan-2-ol or butan-1-ol (both have the formula \(\text{C}_4\text{H}_{10}\text{O}\)).

PastPaper.markingScheme

1 mark for B.
- Reject A: alkanes do not react with steam to form alcohols.
- Reject C: this is already an alcohol (propan-1-ol) and has only 3 carbon atoms.
- Reject D: this is propene, which has only 3 carbon atoms and would produce propanol (\(\text{C}_3\text{H}_8\text{O}\)).
PastPaper.question 29 · multiple-choice
1 PastPaper.marks
A student investigates the rate of reaction between dilute hydrochloric acid and excess calcium carbonate lumps:

$$\text{CaCO}_3(\text{s}) + 2\text{HCl}(\text{aq}) \rightarrow \text{CaCl}_2(\text{aq}) + \text{H}_2\text{O}(\text{l}) + \text{CO}_2(\text{g})$$

Which piece of apparatus, when used with a stopwatch, is **least** suitable for measuring the rate of this reaction?
  1. A.A gas syringe connected to a sealed flask
  2. B.A balance to measure the decrease in mass of the reaction flask and its contents over time
  3. C.A thermometer placed in the reaction mixture to record temperature changes over time
  4. D.A measuring cylinder inverted over water to collect the gas produced
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PastPaper.workedSolution

Since the reaction produces carbon dioxide gas, the rate of reaction can be measured by monitoring either the volume of gas produced over time or the loss in mass as the gas escapes from the flask. Options A and D measure the volume of gas over time. Option B measures the loss in mass over time. A thermometer (Option C) measures temperature changes to determine if a reaction is exothermic or endothermic, but it is not a direct or reliable tool for measuring the reaction rate of this particular reaction, making it the least suitable.

PastPaper.markingScheme

1 mark for C.
- Reject A, B, and D because they are standard and effective ways of measuring the rate of a gas-producing reaction.
PastPaper.question 30 · multiple-choice
1 PastPaper.marks
Aqueous copper(II) sulfate is electrolysed using inert carbon (graphite) electrodes. What are the products formed at the anode and cathode?
  1. A.Anode: copper metal; Cathode: oxygen gas
  2. B.Anode: oxygen gas; Cathode: copper metal
  3. C.Anode: hydrogen gas; Cathode: oxygen gas
  4. D.Anode: oxygen gas; Cathode: hydrogen gas
PastPaper.showAnswers

PastPaper.workedSolution

In the electrolysis of aqueous copper(II) sulfate:
- The ions present are \(\text{Cu}^{2+}\), \(\text{H}^+\), \(\text{SO}_4^{2-}\), and \(\text{OH}^-\).
- At the cathode (negative electrode), \(\text{Cu}^{2+}\) ions are preferentially discharged over \(\text{H}^+\), as copper is lower in the reactivity series. Copper metal is deposited on the cathode: \(\text{Cu}^{2+}(\text{aq}) + 2\text{e}^- \rightarrow \text{Cu}(\text{s})\).
- At the anode (positive electrode), \(\text{OH}^-\) ions are preferentially discharged over \(\text{SO}_4^{2-}\) because hydroxide ions are more easily oxidized. This produces oxygen gas and water: \(4\text{OH}^-(\text{aq}) \rightarrow 2\text{H}_2\text{O}(\text{l}) + \text{O}_2(\text{g}) + 4\text{e}^-\).
Therefore, the products are oxygen at the anode and copper at the cathode.

PastPaper.markingScheme

1 mark for B.
- Reject A: the electrodes are swapped.
- Reject C and D: hydrogen is not produced at the cathode because \(\text{Cu}^{2+}\) is more easily reduced than \(\text{H}^+\).
PastPaper.question 31 · multiple-choice
1 PastPaper.marks
The reaction between nitrogen and hydrogen to form ammonia is exothermic:

$$\text{N}_2(\text{g}) + 3\text{H}_2(\text{g}) \rightleftharpoons 2\text{NH}_3(\text{g})$$

Which statement about this reaction is correct?
  1. A.The total energy required to break the bonds in the reactants is greater than the total energy released when the bonds in the products are formed.
  2. B.The temperature of the surroundings decreases during the reaction.
  3. C.The products have a higher energy content than the reactants.
  4. D.The total energy released when the bonds in the products are formed is greater than the total energy required to break the bonds in the reactants.
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PastPaper.workedSolution

An exothermic reaction releases energy to the surroundings, meaning the temperature of the surroundings increases (ruling out B), and the reactants have higher energy than the products (ruling out C). During any chemical reaction, energy is taken in to break bonds (an endothermic process) and energy is released when new bonds are formed (an exothermic process). For the overall reaction to be exothermic, the energy released when forming the new bonds in the products must be greater than the energy required to break the bonds in the reactants. Thus, D is correct.

PastPaper.markingScheme

1 mark for D.
- Reject A: this describes an endothermic reaction.
- Reject B: temperature of surroundings increases during an exothermic reaction.
- Reject C: products have lower energy than reactants in an exothermic reaction.
PastPaper.question 32 · multiple-choice
1 PastPaper.marks
Three metals, \(W\), \(X\), and \(Y\), are tested to determine their relative reactivity.

- Only metal \(Y\) reacts with cold water to produce a gas.
- Metal \(W\) does not react with dilute hydrochloric acid, but metal \(X\) does react with dilute hydrochloric acid.
- When the oxide of metal \(W\) is heated with metal \(X\), a displacement reaction occurs.

What is the order of reactivity of these three metals, starting with the **most** reactive?
  1. A.\(X \rightarrow Y \rightarrow W\)
  2. B.\(Y \rightarrow W \rightarrow X\)
  3. C.\(Y \rightarrow X \rightarrow W\)
  4. D.\(W \rightarrow X \rightarrow Y\)
PastPaper.showAnswers

PastPaper.workedSolution

Let us analyze the experimental results:
1. Only metal \(Y\) reacts with cold water. This indicates that \(Y\) is highly reactive (like Group I metals) and is the most reactive of the three.
2. Metal \(X\) reacts with dilute hydrochloric acid, but \(W\) does not. This means \(X\) is more reactive than \(W\) (with \(X\) above hydrogen and \(W\) below hydrogen in the reactivity series).
3. Heating the oxide of \(W\) with \(X\) causes a displacement reaction, which confirms that \(X\) is more reactive than \(W\) and can displace it from its oxide.
Combining these points gives the order of reactivity from most to least reactive as: \(Y \rightarrow X \rightarrow W\).

PastPaper.markingScheme

1 mark for C.
- Reject A, B, and D because they do not represent the correct order of relative reactivity based on the evidence.
PastPaper.question 33 · multiple-choice
1 PastPaper.marks
A solid mixture contains sodium chloride, sulfur, and sand. Sodium chloride is soluble in water but insoluble in hexane. Sulfur is insoluble in water but soluble in hexane. Sand is insoluble in both water and hexane. Which sequence of steps can be used to obtain a pure, dry sample of sand from this mixture?
  1. A.Add water, filter, and dry the residue.
  2. B.Add hexane, filter, and dry the residue.
  3. C.Add water, filter, dry the residue, add hexane to the residue, filter, and dry the residue.
  4. D.Add hexane, filter, evaporate the filtrate to dryness, add water, filter, and dry the residue.
PastPaper.showAnswers

PastPaper.workedSolution

To obtain pure, dry sand, we need to remove sodium chloride and sulfur from the mixture:
1. Add water to the mixture: this dissolves the sodium chloride, leaving sand and sulfur undissolved.
2. Filter the mixture: the filtrate is aqueous sodium chloride, and the residue is a wet mixture of sand and sulfur.
3. Dry the residue (sand and sulfur mixture).
4. Add hexane to the dry residue: this dissolves the sulfur, leaving only the sand undissolved.
5. Filter the mixture again: the filtrate is sulfur dissolved in hexane, and the residue is pure sand.
6. Dry the residue to obtain pure, dry sand.

PastPaper.markingScheme

1 mark: Correct option C. Reject all other options.
PastPaper.question 34 · multiple-choice
1 PastPaper.marks
What is the total number of bonding pairs of electrons and lone pairs of electrons (non-bonding outer-shell electrons) in one molecule of methanol, \(\text{CH}_3\text{OH}\)?
  1. A.5 bonding pairs and 2 lone pairs
  2. B.5 bonding pairs and 4 lone pairs
  3. C.4 bonding pairs and 2 lone pairs
  4. D.6 bonding pairs and 1 lone pair
PastPaper.showAnswers

PastPaper.workedSolution

In a molecule of methanol (\(\text{CH}_3\text{OH}\)):
- There are three \(\text{C–H}\) single bonds, one \(\text{C–O}\) single bond, and one \(\text{O–H}\) single bond. This gives a total of 5 bonding pairs of electrons.
- Carbon (Group IV) uses all 4 of its outer-shell electrons in bonding (0 lone pairs).
- Hydrogen (Group I) uses its 1 outer-shell electron in bonding (0 lone pairs).
- Oxygen (Group VI) has 6 outer-shell electrons, 2 of which are shared in bonds (one with C, one with H). This leaves 4 non-bonding outer-shell electrons, which form 2 lone pairs.
Therefore, there are 5 bonding pairs and 2 lone pairs.

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1 mark: Correct option A. Reject all other options.
PastPaper.question 35 · multiple-choice
1 PastPaper.marks
An organic compound \(Y\) has the molecular formula \(\text{C}_4\text{H}_8\). It reacts with bromine water to decolourise it. Which structure could represent the product of this reaction?
  1. A.\(\text{CH}_3\text{CH}_2\text{CH}_2\text{CHBr}_2\)
  2. B.\(\text{CH}_3\text{CH}_2\text{CHBrCH}_2\text{Br}\)
  3. C.\(\text{CH}_3\text{CH}_2\text{CH}_2\text{CH}_2\text{Br}\)
  4. D.\(\text{CH}_3\text{CH}_2\text{CBr}_2\text{CH}_3\)
PastPaper.showAnswers

PastPaper.workedSolution

Compound \(Y\) has the formula \(\text{C}_4\text{H}_8\) and decolourises bromine water, indicating it is an alkene (such as but-1-ene or but-2-ene). Alkenes undergo an addition reaction with bromine (\(\text{Br}_2\)) where one bromine atom adds to each carbon of the carbon-carbon double bond. If the alkene is but-1-ene (\(\text{CH}_3\text{CH}_2\text{CH}=\text{CH}_2\)), the addition of bromine yields 1,2-dibromobutane, which has the structural formula \(\text{CH}_3\text{CH}_2\text{CHBrCH}_2\text{Br}\).

PastPaper.markingScheme

1 mark: Correct option B. Reject all other options.
PastPaper.question 36 · multiple-choice
1 PastPaper.marks
A student wants to investigate how the rate of reaction between zinc and dilute sulfuric acid changes with temperature. Which variables must be kept constant to ensure a fair test?

1. The mass of the zinc
2. The concentration of the sulfuric acid
3. The temperature of the sulfuric acid
4. The volume of the sulfuric acid
  1. A.1, 2 and 3
  2. B.1, 2 and 4
  3. C.2, 3 and 4
  4. D.1 and 2 only
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PastPaper.workedSolution

In this investigation, temperature is the independent variable (the variable being changed). Therefore, the temperature of the acid (3) must NOT be kept constant. To ensure a fair test, all other variables that can affect the rate of reaction must be kept constant (controlled variables). These are: the mass of the zinc (1), the concentration of the sulfuric acid (2), and the volume of the sulfuric acid (4).

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1 mark: Correct option B. Reject all other options.
PastPaper.question 37 · multiple-choice
1 PastPaper.marks
An aqueous solution of salt \(Z\) is tested using two separate reactions:

- When aqueous sodium hydroxide is added, a green precipitate is formed which is insoluble in excess.
- When dilute nitric acid is added followed by aqueous barium nitrate, a white precipitate is formed.

What is the identity of salt \(Z\)?
  1. A.iron(II) chloride
  2. B.iron(III) sulfate
  3. C.iron(II) sulfate
  4. D.chromium(III) sulfate
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PastPaper.workedSolution

The formation of a green precipitate with aqueous sodium hydroxide that is insoluble in excess confirms the presence of iron(II) ions (\(\text{Fe}^{2+}\)). Note that chromium(III) ions also form a green precipitate, but it is soluble in excess sodium hydroxide to form a green solution. The formation of a white precipitate with dilute nitric acid and aqueous barium nitrate confirms the presence of sulfate ions (\(\text{SO}_4^{2-}\)). Therefore, salt \(Z\) is iron(II) sulfate.

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1 mark: Correct option C. Reject all other options.
PastPaper.question 38 · multiple-choice
1 PastPaper.marks
The table shows some bond energies.

| Bond | Bond energy in kJ/mol |
| :--- | :--- |
| \(\text{C–H}\) | 413 |
| \(\text{Cl–Cl}\) | 242 |
| \(\text{C–Cl}\) | 339 |
| \(\text{H–Cl}\) | 431 |

The equation for the chlorination of methane is:

\(\text{CH}_4 + \text{Cl}_2 \rightarrow \text{CH}_3\text{Cl} + \text{HCl}\)

What is the energy change, in kJ/mol, for this reaction?
  1. A.-115 kJ/mol
  2. B.+115 kJ/mol
  3. C.-323 kJ/mol
  4. D.+323 kJ/mol
PastPaper.showAnswers

PastPaper.workedSolution

To calculate the energy change of the reaction:
1. Energy required to break bonds (reactants):
- Break one \(\text{C–H}\) bond: \(1 \times 413 = 413\text{ kJ/mol}\)
- Break one \(\text{Cl–Cl}\) bond: \(1 \times 242 = 242\text{ kJ/mol}\)
- Total energy input = \(413 + 242 = 655\text{ kJ/mol}\)

2. Energy released when forming bonds (products):
- Form one \(\text{C–Cl}\) bond: \(1 \times 339 = 339\text{ kJ/mol}\)
- Form one \(\text{H–Cl}\) bond: \(1 \times 431 = 431\text{ kJ/mol}\)
- Total energy output = \(339 + 431 = 770\text{ kJ/mol}\)

3. Energy change (\(\Delta H\)) = Energy input - Energy output
\(\Delta H = 655 - 770 = -115\text{ kJ/mol}\)

The negative sign shows that the reaction is exothermic.

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1 mark: Correct option A. Reject all other options.
PastPaper.question 39 · multiple-choice
1 PastPaper.marks
Three metals, \(P\), \(Q\), and \(R\), have the following properties:

- Metal \(P\) reacts vigorously with cold water.
- Metal \(Q\) does not react with steam, but its oxide can be reduced to the metal by heating with carbon.
- Metal \(R\) reacts with steam but does not react with cold water.

What is the order of reactivity of these metals, from most reactive to least reactive?
  1. A.\(P > R > Q\)
  2. B.\(P > Q > R\)
  3. C.\(R > P > Q\)
  4. D.\(Q > R > P\)
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PastPaper.workedSolution

- Metal \(P\) is the most reactive because it is capable of reacting with cold water (typical of Group I or Group II metals).
- Metal \(R\) is of intermediate reactivity because it reacts only with steam (typical of metals like zinc or iron in the middle of the reactivity series).
- Metal \(Q\) is the least reactive because it does not react with steam, and its oxide can be reduced by heating with carbon (typical of lower reactivity metals like copper).

Therefore, the correct order is \(P > R > Q\).

PastPaper.markingScheme

1 mark: Correct option A. Reject all other options.
PastPaper.question 40 · multiple-choice
1 PastPaper.marks
An imaginary element \(X\) has two isotopes, \(^{79}X\) and \(^{81}X\).

The relative abundance of \(^{79}X\) is 60% and the relative abundance of \(^{81}X\) is 40%.

What is the relative atomic mass of element \(X\)?
  1. A.79.8
  2. B.80.0
  3. C.80.2
  4. D.79.2
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PastPaper.workedSolution

The relative atomic mass (\(A_r\)) is the weighted average mass of the isotopes of the element:

\(A_r = \frac{(\text{mass of isotope 1} \times \text{abundance}) + (\text{mass of isotope 2} \times \text{abundance})}{100}\)

\(A_r = \frac{(79 \times 60) + (81 \times 40)}{100}\)

\(A_r = \frac{4740 + 3240}{100} = \frac{7980}{100} = 79.8\)

PastPaper.markingScheme

1 mark: Correct option A. Reject all other options.

Paper 42

Answer all structured questions on the spaces provided. Show working where necessary and use appropriate units.
6 PastPaper.question · 79.98 PastPaper.marks
PastPaper.question 1 · structured-theory
13.33 PastPaper.marks
An aqueous solution of copper(II) sulfate, \(\text{CuSO}_4(\text{aq})\), can be electrolyzed using different sets of electrodes.

(a) In Experiment 1, inert carbon electrodes are used.
(i) State what is observed at the anode (positive electrode). [1]
(ii) Write the ionic half-equation, including state symbols, for the reaction occurring at the anode. [2]
(iii) Describe and explain the change in color of the electrolyte during this electrolysis. [2]

(b) In Experiment 2, copper electrodes are used instead of carbon.
(i) Describe how the masses of the anode and cathode change during this experiment. [2]
(ii) State one industrial application of the electrolysis of copper(II) sulfate using copper electrodes. [1]

(c) Molten sodium chloride, \(\text{NaCl}(\text{l})\), is also electrolyzed.
(i) State the names of the products formed at each electrode:
Anode: [1]
Cathode: [1]
(ii) Explain, in terms of particles, why solid sodium chloride does not conduct electricity, but molten sodium chloride does. [2]
(iii) State the type of chemical bonding present in sodium chloride. [1.33]
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PastPaper.workedSolution

Detailed solution:
(a)(i) Bubbles of a colorless gas (oxygen) are formed at the anode.
(ii) \(4\text{OH}^-(\text{aq}) \rightarrow \text{O}_2(\text{g}) + 2\text{H}_2\text{O}(\text{l}) + 4\text{e}^-\)
(iii) The blue color of the solution fades and eventually becomes colorless, because copper(II) ions (\(\text{Cu}^{2+}\)), which are responsible for the blue color, are discharged at the cathode and removed from the solution.
(b)(i) The anode decreases in mass (it dissolves), while the cathode increases in mass (copper is deposited on it).
(ii) Purification (refining) of copper, or electroplating.
(c)(i) Anode product: Chlorine. Cathode product: Sodium.
(ii) In solid sodium chloride, the ions are held in a fixed lattice and cannot move. In molten sodium chloride, the giant ionic lattice is broken and the ions are free to move to the oppositely charged electrodes and carry the current.
(iii) Ionic bonding (or electrovalent bonding).

PastPaper.markingScheme

(a)(i) Bubbles / effervescence [1] (reject: gas evolved without physical observation, reject: named gas unless bubbles mentioned).
(ii) \(4\text{OH}^- \rightarrow \text{O}_2 + 2\text{H}_2\text{O} + 4\text{e}^-\)
- Correct species: [1]
- Correct balancing and state symbols: [1] (accept multiples/fractions: \(2\text{H}_2\text{O} \rightarrow \text{O}_2 + 4\text{H}^+ + 4\text{e}^-\))
(iii) Blue color fades / becomes paler [1]; copper ions (\(\text{Cu}^{2+}\)) are removed / discharged [1].
(b)(i) Anode mass decreases AND cathode mass increases [1]; anode copper dissolves as ions AND cathode copper is deposited [1].
(ii) Refining copper / purification of copper / electroplating [1].
(c)(i) Anode: chlorine [1], Cathode: sodium [1].
(ii) Solid: Ions are fixed in a lattice / cannot move [1]. Molten: Ions are free to move / mobile [1] (reject: 'electrons' are free to move).
(iii) Ionic [1.33] (accept: electrovalent).
PastPaper.question 2 · structured-theory
13.33 PastPaper.marks
Alkenes are unsaturated hydrocarbons containing a carbon-carbon double bond.

(a) Ethene, \(\text{C}_2\text{H}_4\), can be produced by cracking long-chain alkanes like decane, \(\text{C}_{10}\text{H}_{22}\).
(i) Write a balanced chemical equation for the cracking of one molecule of decane to produce one molecule of ethene and one other hydrocarbon. [1]
(ii) State the catalyst and temperature range used in industrial catalytic cracking. [2]

(b) Ethene reacts with different reagents in addition reactions.
(i) Describe a test to distinguish ethene from ethane. Include the reagent and the observations for both compounds.
Reagent: [1]
Observation with ethene: [1]
Observation with ethane: [1]
(ii) Ethene reacts with steam at high temperature and pressure in the presence of an acid catalyst.
Draw the displayed formula of the organic product formed, showing all atoms and all bonds. [2]
(iii) State the name of this organic product. [1]

(c) Butene, \(\text{C}_4\text{H}_8\), has several structural isomers.
(i) Draw the displayed structures of two structural isomers of butene. Show all atoms and bonds. [2]
(ii) Define the term structural isomers. [2.33]
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PastPaper.workedSolution

Detailed solution:
(a)(i) \(\text{C}_{10}\text{H}_{22} \rightarrow \text{C}_2\text{H}_4 + \text{C}_8\text{H}_{18}\)
(ii) Catalyst: Alumina (aluminium oxide) / silica (silicon dioxide) / zeolite. Temperature: 450 °C to 800 °C (or any value in this range).
(b)(i) Reagent: Aqueous bromine (or bromine water). Observation with ethene: orange/brown solution turns colorless (decolorizes). Observation with ethane: remains orange/brown (no change).
(ii) Ethanol structure:
H H
| |
H-C - C-O-H
| |
H H
(iii) Ethanol.
(c)(i) Isomer 1 (but-1-ene):
H H H H
| | | |
H-C = C - C - C-H
| |
H H
Isomer 2 (but-2-ene):
H H H H
| | | |
H-C - C = C - C-H
| |
H H
(ii) Molecules with the same molecular formula but different structural arrangements / structural formulae.

PastPaper.markingScheme

(a)(i) \(\text{C}_{10}\text{H}_{22} \rightarrow \text{C}_2\text{H}_4 + \text{C}_8\text{H}_{18}\) [1] (accept other correct balanced cracking equations producing ethene, e.g., producing octane or other alkenes/alkanes if sum of carbons/hydrogens is correct, but the question specifies 'one molecule of ethene and one other hydrocarbon').
(ii) Catalyst: Alumina / silica / zeolite / clay [1]. Temperature: 450 °C to 800 °C [1] (accept any value or range within this).
(b)(i) Reagent: Bromine water / aqueous bromine [1] (reject: liquid bromine / bromine in UV light).
Observation with ethene: turns colorless / decolored [1] (reject: clear).
Observation with ethane: remains orange / brown / yellow / no change [1].
(ii) Correct structural drawing of ethanol showing all C-H, C-C, C-O, and O-H bonds [2]. If O-H bond is not shown explicitly (i.e. drawn as -OH), award [1].
(iii) Ethanol [1].
(c)(i) Any two correct isomeric structures of \(\text{C}_4\text{H}_8\) drawn showing all bonds: but-1-ene, but-2-ene, or methylpropene [2] (1 mark for each correct structure; deduct 1 mark total if any valency is wrong or H atoms are omitted).
(ii) Compounds with the same molecular formula [1.33] but different structural formulae / arrangements [1] (total 2.33 marks).
PastPaper.question 3 · structured-theory
13.33 PastPaper.marks
A student investigates the rate of reaction between calcium carbonate (marble chips) and dilute hydrochloric acid:

\(\text{CaCO}_3(\text{s}) + 2\text{HCl}(\text{aq}) \rightarrow \text{CaCl}_2(\text{aq}) + \text{CO}_2(\text{g}) + \text{H}_2\text{O}(\text{l})\)

(a)(i) Draw a labeled diagram of the assembled apparatus that can be used to measure the volume of gas produced over time. [3]
(ii) State one other physical quantity, other than the volume of gas, that could be measured to follow the rate of this reaction. [1]

(b) The student performs two experiments at 20 °C, using excess dilute hydrochloric acid of the same concentration:
- Experiment A: 5.0 g of large marble chips
- Experiment B: 5.0 g of small marble chips
(i) On a single set of axes, sketch curves to show how the volume of gas changes with time for Experiment A and Experiment B. Label each curve clearly. [3]
(ii) Explain, using collision theory, why the rate of reaction is faster in Experiment B than in Experiment A. [3]

(c) The student repeats the experiment using 5.0 g of small marble chips but at a higher temperature of 40 °C (Experiment C).
Explain, in terms of the kinetic particle theory and collision energy, why the rate of reaction is higher in Experiment C than in Experiment B. [3.33]
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PastPaper.workedSolution

Detailed solution:
(a)(i) The diagram must show: a conical flask containing the reaction mixture, a stopper/bung with a delivery tube, connected to a gas syringe or an inverted measuring cylinder filled with water. All parts must be sealed and labeled correctly.
(ii) Mass of the flask and contents (over time) or pH of the mixture.
(b)(i) The graph should have the y-axis labeled 'Volume of gas' (or equivalent) and the x-axis labeled 'Time'. Both curves start at the origin. Curve B is steeper than Curve A. Both curves level off at the same final volume of gas because the mass of carbonate (the limiting reactant, since acid is in excess) is the same in both.
(ii) Small chips have a larger surface area per unit mass. This means there are more exposed particles, leading to a higher frequency of collisions / more collisions per second between acid particles and calcium carbonate.
(c) At 40 °C, particles have more kinetic energy and move faster. This leads to more frequent collisions. Also, a greater proportion of colliding particles have energy equal to or greater than the activation energy, so a higher percentage of collisions are successful.

PastPaper.markingScheme

(a)(i) Labeled diagram:
- Reaction vessel (conical flask / boiling tube) containing acid and solid with a bung [1]
- Gas syringe OR inverted measuring cylinder over water [1]
- Airtight delivery tube connecting the reaction vessel to the gas collection device [1]
(ii) Mass / mass of reaction mixture and flask [1].
(b)(i) Sketch graph:
- Axes labeled correctly: y-axis as 'Volume of gas' and x-axis as 'Time' [1]
- Curve B is steeper than Curve A [1]
- Both curves start at origin and level off at the exact same horizontal height [1]
(ii) Small chips have a larger surface area [1];
More reactant particles are exposed to collisions [1];
Higher frequency of collisions / more collisions per unit time [1] (reject: 'more collisions' without time/frequency).
(c) At higher temperature, particles have more kinetic energy / move faster [1];
Collisions are more frequent [1];
More particles have energy \(\ge\) activation energy [1.33] / more successful collisions per second (total 3.33 marks).
PastPaper.question 4 · structured-theory
13.33 PastPaper.marks
This question is about stoichiometry and chemical calculations.

(a) Crystals of hydrated magnesium sulfate have the formula \(\text{MgSO}_4 \cdot x\text{H}_2\text{O}\).
A student heated a sample of 4.92 g of these crystals to constant mass to drive off all the water of crystallization. The mass of anhydrous magnesium sulfate, \(\text{MgSO}_4\), remaining was 2.40 g.
(i) Calculate the mass of water lost from the crystals. [1]
(ii) Calculate the number of moles of anhydrous \(\text{MgSO}_4\) remaining.
[Relative formula mass, \(M_{\text{r}}\): \(\text{MgSO}_4 = 120\)] [1]
(iii) Calculate the number of moles of water lost.
[Relative formula mass, \(M_{\text{r}}\): \(\text{H}_2\text{O} = 18\)] [1]
(iv) Determine the value of \(x\) in \(\text{MgSO}_4 \cdot x\text{H}_2\text{O}\). [1.33]

(b) Dilute sulfuric acid reacts with sodium hydroxide solution according to the equation:

\(2\text{NaOH}(\text{aq}) + \text{H}_2\text{SO}_4(\text{aq}) \rightarrow \text{Na}_2\text{SO}_4(\text{aq}) + 2\text{H}_2\text{O}(\text{l})\)

(i) Calculate the number of moles of \(\text{NaOH}\) present in 50.0 cm³ of 0.200 mol/dm³ sodium hydroxide solution. [2]
(ii) Determine the number of moles of \(\text{H}_2\text{SO}_4\) required to neutralize this amount of \(\text{NaOH}\). [1]
(iii) Calculate the volume, in cm³, of 0.100 mol/dm³ \(\text{H}_2\text{SO}_4\) required for complete neutralization. [2]

(c) Magnesium reacts with dilute hydrochloric acid to produce hydrogen gas:

\(\text{Mg}(\text{s}) + 2\text{HCl}(\text{aq}) \rightarrow \text{MgCl}_2(\text{aq}) + \text{H}_2(\text{g})\)

Calculate the volume of hydrogen gas, in dm³ at r.t.p., produced when 0.36 g of magnesium reacts completely with excess dilute hydrochloric acid.
[Relative atomic mass, \(A_{\text{r}}\): \(\text{Mg} = 24\); molar volume of gas at r.t.p. = 24 dm³/mol] [4]
PastPaper.showAnswers

PastPaper.workedSolution

Detailed solution:
(a)(i) Mass of water lost = \(4.92\text{ g} - 2.40\text{ g} = 2.52\text{ g}\).
(ii) Moles of \(\text{MgSO}_4 = \frac{2.40\text{ g}}{120\text{ g/mol}} = 0.020\text{ mol}\).
(iii) Moles of \(\text{H}_2\text{O} = \frac{2.52\text{ g}}{18\text{ g/mol}} = 0.140\text{ mol}\).
(iv) Ratio \(x = \frac{\text{moles of } \text{H}_2\text{O}}{\text{moles of } \text{MgSO}_4} = \frac{0.140}{0.020} = 7\).
(b)(i) Moles of \(\text{NaOH} = \text{concentration} \times \text{volume in dm}^3 = 0.200\text{ mol/dm}^3 \times 0.0500\text{ dm}^3 = 0.0100\text{ mol}\).
(ii) From the equation, the ratio is 2 NaOH : 1 \(\text{H}_2\text{SO}_4\).
Moles of \(\text{H}_2\text{SO}_4 = \frac{0.0100}{2} = 0.00500\text{ mol}\).
(iii) Volume of \(\text{H}_2\text{SO}_4 = \frac{\text{moles}}{\text{concentration}} = \frac{0.00500\text{ mol}}{0.100\text{ mol/dm}^3} = 0.0500\text{ dm}^3 = 50.0\text{ cm}^3\).
(c) Moles of \(\text{Mg} = \frac{0.36}{24} = 0.015\text{ mol}\).
From the equation, 1 mole of \(\text{Mg}\) produces 1 mole of \(\text{H}_2\).
Moles of \(\text{H}_2 = 0.015\text{ mol}\).
Volume of \(\text{H}_2 = 0.015\text{ mol} \times 24\text{ dm}^3\text{/mol} = 0.36\text{ dm}^3\).

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(a)(i) \(4.92 - 2.40 = 2.52\) g [1].
(ii) \(\frac{2.40}{120} = 0.02\) (mol) [1].
(iii) \(\frac{2.52}{18} = 0.14\) (mol) [1].
(iv) \(\frac{0.14}{0.02} = 7\) [1.33] (accept correct calculation based on ecf from (ii) and (iii)).
(b)(i) \(\frac{50.0}{1000} \times 0.200\) [1] = 0.010 (mol) [1].
(ii) \(0.010 \div 2 = 0.005\) (mol) [1] (accept ecf from (b)(i)).
(iii) \(\frac{0.005}{0.100}\) [1] \(\times 1000 = 50.0\) (cm³) [1] (accept ecf from (b)(ii)).
(c)
- Moles of \(\text{Mg} = \frac{0.36}{24} = 0.015\) mol [1]
- Mole ratio of \(\text{Mg} : \text{H}_2 = 1 : 1\) (so moles of \(\text{H}_2 = 0.015\) mol) [1]
- Volume of \(\text{H}_2 = 0.015 \times 24\) [1]
- = 0.36 (dm³) [1]
PastPaper.question 5 · structured-theory
13.33 PastPaper.marks
This question is about identifying ions and gases.

(a) Solid salt D is dissolved in water to make an aqueous solution. Portions of this solution are tested as follows:
(i) Addition of aqueous sodium hydroxide produces a green precipitate that is insoluble in excess.
Identify the cation present in D. [1]
(ii) Addition of dilute nitric acid followed by aqueous barium nitrate produces a white precipitate.
Identify the anion present in D. [1]
(iii) Write the chemical formula of salt D. [1]

(b) Gas E is a colorless, pungent gas that turns damp red litmus paper blue.
(i) State the name of gas E. [1]
(ii) Describe how you would test for the presence of chloride ions in an aqueous solution, and state the positive result. [2]

(c) An aqueous solution of salt F contains a transition metal cation.
(i) When aqueous ammonia is added dropwise, a light blue precipitate is formed. When excess aqueous ammonia is added, the precipitate dissolves to form a deep blue solution.
Identify the cation present in salt F. [2]
(ii) Write the ionic equation (including state symbols) for the formation of the light blue precipitate when hydroxide ions, \(\text{OH}^-(\text{aq})\), react with the cation identified in (c)(i). [2]

(d) Describe a chemical test to confirm the presence of carbonate ions, \(\text{CO}_3^{2-}\), in a solid sample. Include the reagent used and the positive observation. [3.33]
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Detailed solution:
(a)(i) Iron(II) ion (\(\text{Fe}^{2+}\)).
(ii) Sulfate ion (\(\text{SO}_4^{2-}\)).
(iii) \(\text{FeSO}_4\).
(b)(i) Ammonia.
(ii) Add dilute nitric acid, then add aqueous silver nitrate. A white precipitate is formed.
(c)(i) Copper(II) ion (\(\text{Cu}^{2+}\)).
(ii) \(\text{Cu}^{2+}(\text{aq}) + 2\text{OH}^-(\text{aq}) \rightarrow \text{Cu(OH)}_2(\text{s})\).
(d) Add dilute hydrochloric acid (or any dilute strong acid) to the solid. Bubbles/effervescence of gas are produced. Bubble the gas through limewater. The limewater turns cloudy/milky.

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(a)(i) Iron(II) / \(\text{Fe}^{2+}\) [1] (reject: iron / iron(III)).
(ii) Sulfate / \(\text{SO}_4^{2-}\) [1].
(iii) \(\text{FeSO}_4\) [1] (accept ecf from (i) and (ii)).
(b)(i) Ammonia / \(\text{NH}_3\) [1].
(ii) Reagent: Dilute nitric acid AND aqueous silver nitrate [1] (reject: hydrochloric acid).
Observation: White precipitate [1].
(c)(i) Copper(II) / \(\text{Cu}^{2+}\) [2] (1 mark for copper, 1 mark for the charge / Roman numeral (II)).
(ii) \(\text{Cu}^{2+}(\text{aq}) + 2\text{OH}^-(\text{aq}) \rightarrow \text{Cu(OH)}_2(\text{s})\)
- Correct species: [1]
- Correct balancing and state symbols: [1]
(d) Add dilute hydrochloric acid (or other named acid) [1];
Effervescence / bubbles of gas produced [1];
Bubble gas through limewater, which turns cloudy / milky [1.33].
PastPaper.question 6 · structured-theory
13.33 PastPaper.marks
This question is about chemical energetics and bond energy calculations.

(a) Hydrogen reacts with chlorine to form hydrogen chloride gas:

\(\text{H}_2(\text{g}) + \text{Cl}_2(\text{g}) \rightarrow 2\text{HCl}(\text{g})\)

This reaction is exothermic.
(i) Draw an energy level diagram for this reaction on paper. Describe your diagram by stating:
- the relative position of the reactants and products [1]
- how the activation energy, \(E_{\text{a}}\), is represented [1]
- how the enthalpy change of the reaction, \(\Delta H\), is represented and its sign [2]
(ii) Explain, in terms of bond breaking and bond making, why this reaction is exothermic. [3]

(b) Use the bond energy values in the table below to calculate the overall enthalpy change for the reaction.

| Bond | Bond Energy (kJ/mol) |
|---|---|
| H-H | 436 |
| Cl-Cl | 243 |
| H-Cl | 431 |

(i) Calculate the energy required to break the bonds in 1 mole of \(\text{H}_2\) and 1 mole of \(\text{Cl}_2\). [1]
(ii) Calculate the energy released when the bonds in 2 moles of \(\text{HCl}\) are formed. [1]
(iii) Calculate the overall enthalpy change, \(\Delta H\), for this reaction. Include the sign and appropriate units. [2.33]

(c) State and explain the change in temperature of the surroundings when an endothermic reaction occurs. [2]
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PastPaper.workedSolution

Detailed solution:
(a)(i) Description of the energy level diagram:
- The energy level of the reactants (\(\text{H}_2 + \text{Cl}_2\)) is higher than the energy level of the products (\(2\text{HCl}\)).
- The activation energy, \(E_{\text{a}}\), is represented by an arrow pointing upwards from the reactant level to the peak of the curve.
- The enthalpy change, \(\Delta H\), is represented by an arrow pointing downwards from the reactant level to the product level. Its sign is negative.
(ii) Bond breaking is endothermic (absorbs energy) and bond making is exothermic (releases energy). In this reaction, more energy is released when forming the two H-Cl bonds than is absorbed when breaking the H-H and Cl-Cl bonds.
(b)(i) Energy required to break bonds = \(436 + 243 = 679\) kJ.
(ii) Energy released when forming bonds = \(2 \times 431 = 862\) kJ.
(iii) Enthalpy change, \(\Delta H = 679 - 862 = -183\) kJ/mol.
(c) The temperature of the surroundings decreases because heat energy is taken in / absorbed from the surroundings into the chemical system.

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(a)(i) Description of diagram:
- Reactants higher than products [1]
- Activation energy (\(E_{\text{a}}\)) shown as an arrow from reactant level to peak of curve [1]
- Enthalpy change (\(\Delta H\)) shown as an downward arrow from reactant level to product level [1]
- \(\Delta H\) is negative / labeled as negative [1]
(ii) Bond breaking is endothermic / absorbs energy AND bond making is exothermic / releases energy [1];
More energy is released in making H-Cl bonds than is absorbed in breaking H-H and Cl-Cl bonds [2].
(b)(i) \(436 + 243 = 679\) (kJ) [1].
(ii) \(2 \times 431 = 862\) (kJ) [1].
(iii) \(679 - 862 = -183\) [1.33]; unit: kJ/mol (or kJ) AND minus sign included [1] (total 2.33 marks).
(c) Temperature decreases [1]; because energy/heat is taken in / absorbed from the surroundings [1].

Paper 62

Answer all questions. Read instructions carefully, interpret diagrams, construct graphical data, and design a practical plan.
4 PastPaper.question · 40 PastPaper.marks
PastPaper.question 1 · structured-practical
10 PastPaper.marks
An eco-friendly de-icer contains a mixture of sodium chloride (which is soluble in water) and calcium carbonate (which is insoluble in water, but soluble and reactive with dilute acids).

Plan an investigation to determine the percentage by mass of calcium carbonate in a sample of this de-icer.

You are provided with:
- a sample of the solid de-icer mixture
- distilled water
- standard laboratory apparatus (including balances, burners, and glassware)

Your answer should include:
(a) a detailed method for the experiment [6 marks]
(b) the name of one piece of apparatus used to measure 50 cm³ of water accurately [1 mark]
(c) an explanation of why the residue must be washed with distilled water before drying [1 mark]
(d) how you would prove that all the water has been removed from the dried residue [1 mark]
(e) one safety precaution, other than wearing eye protection, and why it is necessary [1 mark]
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PastPaper.workedSolution

(a) Method:
1. Weigh a clean, dry beaker and record its mass. Add the sample of the de-icer mixture to the beaker, reweigh, and calculate the starting mass of the mixture.
2. Add excess distilled water to the beaker and stir thoroughly using a glass rod to ensure all soluble sodium chloride has dissolved completely.
3. Set up a filtration apparatus. Filter the mixture through filter paper into a conical flask. The insoluble calcium carbonate remains as the residue on the filter paper, while the sodium chloride solution passes through as the filtrate.
4. Wash the residue on the filter paper with a small volume of distilled water to remove any remaining sodium chloride solution adhering to it.
5. Carefully remove the filter paper containing the residue and dry it in a warm oven or a safe, warm environment.
6. Weigh the dried residue (calcium carbonate) and calculate its mass by subtracting the pre-weighed mass of empty filter paper.
7. Calculate the percentage by mass of calcium carbonate using the formula: \(\text{Percentage} = \frac{\text{mass of dry residue}}{\text{initial mass of mixture}} \times 100\).

(b) Measuring cylinder / volumetric pipette / burette.

(c) To wash away any dissolved sodium chloride solution trapped in the wet residue. If not washed, the sodium chloride would recrystallize on drying, causing the mass of the residue to be falsely high.

(d) Heat the residue, allow it to cool, and weigh it. Repeat the heating, cooling, and weighing process until the mass remains constant.

(e) Wear gloves to avoid skin contact with chemicals, OR use tongs/heat-proof mat when handling hot equipment to prevent burns.

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Part (a) [6 marks]:
- M1: Weigh sample/beaker with sample initially (mass of mixture). [1]
- M2: Add water and stir/agitate to dissolve the soluble NaCl. [1]
- M3: Filter the mixture to separate the insoluble residue (calcium carbonate). [1]
- M4: Wash the residue with distilled water. [1]
- M5: Dry the residue (e.g. in oven / warm place) and weigh it. [1]
- M6: Calculation shown: (mass of dry residue / initial mass of sample) x 100. [1]

Part (b) [1 mark]:
- Accept: Measuring cylinder / burette / volumetric pipette. [1]
- Reject: Beaker / flask.

Part (c) [1 mark]:
- To remove any dissolved sodium chloride / salt solution adhering to the residue (otherwise mass would be artificially high when dry). [1]

Part (d) [1 mark]:
- Heat, cool, and reweigh until a constant mass is achieved / no further mass loss. [1]

Part (e) [1 mark]:
- Gloves: protects skin / prevents contamination. [1] OR
- Heat-proof mat/tongs: prevents surface damage / burns. [1]
- Reject: 'wear goggles' (excluded in question).
PastPaper.question 2 · structured-practical
10 PastPaper.marks
A student investigated the rate of reaction between calcium carbonate (marble chips) and dilute hydrochloric acid at room temperature. The equation for the reaction is:
\(\text{CaCO}_3(\text{s}) + 2\text{HCl}(\text{aq}) \rightarrow \text{CaCl}_2(\text{aq}) + \text{H}_2\text{O}(\text{l}) + \text{CO}_2(\text{g})\)

(a) Why does the rate of reaction decrease over time as the reaction proceeds? [1 mark]

(b) The student repeated the experiment using the same mass of calcium carbonate but in the form of a single large marble chip instead of several small marble chips.
(i) Describe and explain how the rate of reaction would change. Use collision theory in your explanation. [2 marks]
(ii) How would the final volume of gas collected compare to the first experiment? Explain your answer. [1 mark]

(c) The reaction was repeated at a higher temperature.
(i) How would the curve of volume of gas against time for this higher temperature compare to the original room temperature experiment? State two differences. [2 marks]
(ii) Explain the effect of higher temperature on the rate of reaction in terms of collision theory. [3 marks]

(d) Suggest why measuring the volume of gas collected in a gas syringe is a more accurate method for carbon dioxide than collecting the gas over water in a graduated cylinder. [1 mark]
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PastPaper.workedSolution

(a) The concentration of hydrochloric acid decreases as it is consumed, leading to fewer acid particles per unit volume and therefore a lower frequency of successful collisions.

(b) (i) The rate of reaction would decrease / become slower. This is because a single large marble chip has a smaller total surface area than small marble chips, resulting in fewer exposed calcium carbonate particles and a lower frequency of collisions with acid particles.
(ii) The final volume of gas collected would be the same because the mass of calcium carbonate and the quantity of hydrochloric acid are identical, meaning the amount of limiting reagent has not changed.

(c) (i) The curve for the higher temperature would be steeper initially (higher initial gradient) and would level off (reach the maximum volume plateau) at an earlier time.
(ii) At a higher temperature, particles gain kinetic energy and move faster, leading to a higher frequency of collisions. Furthermore, a significantly greater proportion of colliding particles possess energy equal to or greater than the activation energy, resulting in a higher percentage of successful collisions.

(d) Carbon dioxide is moderately soluble in water (and reacts slightly with it). Collecting it over water would cause some gas to dissolve, reducing the measured volume of gas. A gas syringe prevents this loss as no water is involved.

PastPaper.markingScheme

Part (a) [1 mark]:
- Concentration of acid decreases / reactants are used up. [1]
- Reject: 'reactants are completely gone' (explains why it stops, not why it slows down).

Part (b) [3 marks total]:
- (i) Rate is slower / decreases [1] because surface area is smaller, leading to less frequent collisions / lower collision rate [1].
- (ii) Final volume is the same because the limiting reagent / mass of reactants is unchanged. [1]

Part (c) [5 marks total]:
- (i) Two features: steeper curve / higher initial gradient [1] and levels off earlier / reaches horizontal plateau sooner [1].
- (ii) Collision theory: Particles have more kinetic energy / move faster [1]; more frequent collisions / higher frequency of collisions [1]; more particles have energy >= activation energy / more successful collisions [1].

Part (d) [1 mark]:
- Carbon dioxide is soluble in water (so volume would be underestimated if collected over water). [1]
- Accept: CO2 reacts with water.
PastPaper.question 3 · structured-practical
10 PastPaper.marks
Two substances, solid Y and solid Z, were analysed. Solid Y was a green transition metal salt. Solid Z was an anhydrous salt.

The following tests were carried out on both solids. Complete the observations and conclusions.

(a) Tests on Solid Y:
Distilled water was added to solid Y to make a green solution.
(i) To the first portion of solution Y, aqueous sodium hydroxide was added dropwise until in excess.
State the observations. [2 marks]
(ii) The mixture from (i) was then warmed gently. A gas was evolved which turned damp red litmus paper blue.
Identify the gas evolved and the cation responsible for this gas. [2 marks]
(iii) To a second portion of solution Y, dilute nitric acid was added followed by aqueous barium nitrate. A white precipitate was formed.
State the name of the precipitate and identify the anion present in solid Y. [2 marks]

(b) Tests on Solid Z:
A flame test was performed on solid Z. A lilac flame was observed.
Identify the cation present in solid Z. [1 mark]

(c) Solid Z was heated strongly in a hard-glass test-tube.
- A brown gas was evolved.
- A glowing splint relit when held at the mouth of the tube.
(i) Identify the brown gas. [1 mark]
(ii) Identify the gas that relit the glowing splint. [1 mark]
(iii) Use these results to deduce the formula of solid Z. [1 mark]
PastPaper.showAnswers

PastPaper.workedSolution

(a) (i) A green precipitate is formed when aqueous sodium hydroxide is added. The precipitate remains insoluble in excess sodium hydroxide.
(ii) The gas that turns damp red litmus paper blue is ammonia (\(\text{NH}_3\)). The cation responsible for this is the ammonium ion (\(\text{NH}_4^+\)).
(iii) The white precipitate formed with barium nitrate is barium sulfate (\(\text{BaSO}_4\)). The anion present is the sulfate ion (\(\text{SO}_4^{2-}\)).

(b) A lilac flame test color indicates the presence of potassium ions (\(\text{K}^+\)).

(c) (i) The brown gas evolved during thermal decomposition is nitrogen dioxide (\(\text{NO}_2\)).
(ii) The gas that relit the glowing splint is oxygen (\(\text{O}_2\)).
(iii) Knowing the cation is potassium (\(\text{K}^+\)) and the thermal decomposition products are nitrogen dioxide and oxygen (typical of a group I metal nitrate decomposing under extreme heat, or a heavy metal nitrate, though potassium nitrate typically decomposes to nitrite and oxygen, solid Z must be a nitrate that decomposes completely, or here potassium nitrate is deduced as potassium nitrate decomposes to potassium nitrite and oxygen, but since a brown gas of NO2 is observed, it indicates nitrate decomposition. The formula of solid Z is potassium nitrate, \(\text{KNO}_3\)).

PastPaper.markingScheme

Part (a) [6 marks total]:
- (i) Green precipitate [1]; insoluble / does not dissolve in excess NaOH [1].
- (ii) Gas: Ammonia / NH3 [1]; Cation: Ammonium / NH4+ [1].
- (iii) Precipitate: Barium sulfate / BaSO4 [1]; Anion: Sulfate / SO42- [1].

Part (b) [1 mark]:
- Potassium / K+ [1].

Part (c) [3 marks total]:
- (i) Nitrogen dioxide / NO2 [1].
- (ii) Oxygen / O2 [1].
- (iii) KNO3 [1].
- Accept: Potassium nitrate.
PastPaper.question 4 · structured-practical
10 PastPaper.marks
A student carried out a titration to determine the concentration of a sample of dilute sulfuric acid by titrating it against 25.0 cm³ of standard sodium hydroxide solution, concentration 0.100 mol/dm³.

(a) Name the apparatus used to:
(i) measure exactly 25.0 cm³ of the sodium hydroxide solution into the conical flask. [1 mark]
(ii) deliver variable, accurate volumes of the dilute sulfuric acid during the titration. [1 mark]

(b) Methyl orange indicator was added to the conical flask containing sodium hydroxide. State the colour change observed at the end-point. [2 marks]

(c) The titration was performed three times. The burette readings are shown below:
- Run 1: Initial reading = 0.0 cm³; Final reading = 22.4 cm³
- Run 2: Initial reading = 22.4 cm³; Final reading = 44.2 cm³
- Run 3: Initial reading = 1.5 cm³; Final reading = 23.4 cm³
(i) State the volume of acid added in each of the three runs. [1 mark]
(ii) Identify the anomalous run and explain why it should be excluded from the calculation of the average titre. [2 marks]
(iii) Calculate the average volume of dilute sulfuric acid used using the concordant results. [1 mark]

(d) Suggest why the student placed the conical flask on a white tile. [1 mark]

(e) Explain why rinsing the inside of the conical flask with distilled water during the titration does not affect the accuracy of the result. [1 mark]
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PastPaper.workedSolution

(a) (i) Volumetric pipette (or transfer pipette).
(ii) Burette.

(b) The indicator turns from yellow (alkaline) to orange (neutral/end-point; or yellow to pink).

(c) (i) Run 1: 22.4 - 0.0 = 22.4 cm³
Run 2: 44.2 - 22.4 = 21.8 cm³
Run 3: 23.4 - 1.5 = 21.9 cm³
(ii) Run 1 is anomalous because it is not concordant (it is not within 0.2 cm³ of the other runs). It was likely a rough titration to find the approximate end-point.
(iii) Average of concordant runs (Run 2 and Run 3) = \(\frac{21.8 + 21.9}{2} = 21.85\text{ cm}^3\).

(d) To see the color change of the indicator more clearly against a neutral, bright background.

(e) Rinsing with distilled water does not change the number of moles of sodium hydroxide present in the flask, which is what reacts with the acid. It only dilutes the mixture, which has no effect on the final stoichiometric calculation.

PastPaper.markingScheme

Part (a) [2 marks total]:
- (i) Pipette / volumetric pipette. [1] (Reject: teat pipette, measuring cylinder)
- (ii) Burette. [1]

Part (b) [2 marks total]:
- Yellow [1] to orange / pink [1]. (Reject: red)

Part (c) [4 marks total]:
- (i) Run 1: 22.4, Run 2: 21.8, Run 3: 21.9 (all three correct for [1]).
- (ii) Run 1 [1]. Explanation: It is not concordant / differs by more than 0.2 cm³ from the other runs [1].
- (iii) (21.8 + 21.9) / 2 = 21.85 cm³. [1]
- Accept: 21.9 cm³.

Part (d) [1 mark]:
- To see the color change of the indicator more clearly / easily. [1]

Part (e) [1 mark]:
- Distilled water does not change the number of moles of sodium hydroxide in the conical flask. [1]

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