GCE O-Level · Mathematics (4052)

Vectors in two dimensions: Practice Questions

5 multiple-choice questions marked as you go, and 4 written questions with worked solutions. All on Vectors in two dimensions.

9 questions29 marksFree, no account
Question 1
1 mark

Given that \( \mathbf{p} = \begin{pmatrix} 3 \\ -2 \end{pmatrix} \) and \( \mathbf{q} = \begin{pmatrix} -1 \\ 4 \end{pmatrix} \), find the column vector \( 2\mathbf{p} - \mathbf{q} \).

Question 2
1 mark

Given the vector \(\mathbf{v} = \begin{pmatrix} -3 \\ 4 \end{pmatrix}\), find the magnitude of \(\mathbf{v}\), denoted by \(|\mathbf{v}|\).

Question 3
1 mark

In a parallelogram OABC, \( \vec{OA} = \mathbf{a} \) and \( \vec{OC} = \mathbf{c} \). Point P lies on the diagonal AC such that \( AP : PC = 1 : 2 \). Point Q is the midpoint of the side BC. Express the vector \( \vec{PQ} \) in terms of \( \mathbf{a} \) and \( \mathbf{c} \).

Question 4
1 mark

Given the vectors \( \mathbf{a} = \begin{pmatrix} 3 \\ 4 \end{pmatrix} \) and \( \mathbf{b} = \begin{pmatrix} -1 \\ 2 \end{pmatrix} \), find the magnitude of the vector \( \mathbf{a} + \mathbf{b} \).

Question 5
1 mark

In triangle \(OAB\), \(\vec{OA} = 6\mathbf{a}\) and \(\vec{OB} = 4\mathbf{b}\). The point \(X\) lies on \(OA\) such that \(OX : XA = 2 : 1\), and the point \(Y\) lies on \(AB\) such that \(\vec{AY} = \frac{1}{3}\vec{AB}\). The lines \(OY\) and \(XB\) intersect at the point \(G\). Given that \(\vec{OG} = h\vec{OY}\) and \(\vec{XG} = k\vec{XB}\), find the value of \(h\).

Question 6
4 marks

Given the vectors \(\mathbf{a} = \begin{pmatrix} 3 \\ -4 \end{pmatrix}\) and \(\mathbf{b} = \begin{pmatrix} -1 \\ 2 \end{pmatrix}\), find the magnitude of the vector \(2\mathbf{a} + \mathbf{b}\).

Write your answer out first, then check it against the worked solution.

Question 7
5 marks

In triangle \( OAB \), \( \vec{OA} = \mathbf{a} \) and \( \vec{OB} = \mathbf{b} \). The point \( X \) lies on the line \( OA \) produced such that \( OA:AX = 2:1 \), and point \( Y \) lies on \( AB \) such that \( AY = 2YB \). Express the vector \( \vec{XY} \) in terms of \( \mathbf{a} \) and \( \mathbf{b} \).

Write your answer out first, then check it against the worked solution.

Question 8
7 marks

In triangle \( OAB \), \( \vec{OA} = \mathbf{a} \) and \( \vec{OB} = \mathbf{b} \). The point \( P \) lies on \( OA \) such that \( OP = \frac{2}{3}OA \). The point \( Q \) is the midpoint of \( AB \). The line \( PQ \) is produced to \( R \) such that \( PQ = QR \).
(a) Express \( \vec{AB} \) and \( \vec{OQ} \) in terms of \( \mathbf{a} \) and \( \mathbf{b} \).
(b) Express \( \vec{PQ} \) and \( \vec{OR} \) in terms of \( \mathbf{a} \) and \( \mathbf{b} \).
(c) Show that \( O, B, \) and \( R \) are collinear and find the ratio \( OB:BR \).

Write your answer out first, then check it against the worked solution.

Question 9
8 marks

In triangle \( OAB \), \( \vec{OA} = \mathbf{a} \) and \( \vec{OB} = \mathbf{b} \). Point \( M \) lies on \( OA \) such that \( OA = 3OM \) and \( N \) is the midpoint of \( AB \). The lines \( OB \) and \( MN \) are produced to meet at point \( P \).
(a) Express \( \vec{AB} \) and \( \vec{MN} \) in terms of \( \mathbf{a} \) and \( \mathbf{b} \).
(b) Given that \( \vec{MP} = k\vec{MN} \), express \( \vec{OP} \) in terms of \( k, \mathbf{a} \) and \( \mathbf{b} \).
(c) Use the fact that \( P \) lies on the line \( OB \) to find the value of \( k \) and hence express \( \vec{OP} \) in terms of \( \mathbf{b} \) only.

Write your answer out first, then check it against the worked solution.

* The content provided by thinka is generated by AI and may not always be accurate or up-to-date. Please use it as a supplementary resource and verify with official materials.

You've seen the model answer. Now get yours marked.

This page can show you how a good answer looks. It cannot tell you what your answer was missing. thinka marks your written work against the real mark scheme in about 15 seconds.

Want more questions like these? Get a fresh set on this topic, marked as you go.

Practise More