OCR GCSE · thinka-original Practice Paper

2025 OCR GCSE Twenty First Century Science - Biology B - J257 Practice Paper with Answers

Thinka June 2025 — Foundation OCR GCSE (9-1)-Style Mock — Twenty First Century Science - Biology B - J257

180 marks210 mins2025
An original Thinka practice paper modelled on the structure and difficulty of the June 2025 — Foundation OCR GCSE (9-1) Twenty First Century Science - Biology B - J257 paper. Not affiliated with or reproduced from OCR.

Paper 1: Breadth in Biology

Answer all questions. 90 marks in 1 hour 45 minutes. Ten structured questions spanning the whole specification, with a high proportion of closed items, two calculation items and one graph plotting item.
66 Question · 99.5 marks
Question 1 · closed_selection
1.5 marks
A student measures the reaction time of five friends using a ruler-drop test. The times, in seconds, are: 0.21, 0.19, 0.24, 0.19, 0.22.

Tick (✓) one box in each row to show whether each statement about these results is true or false.

| Statement | True | False |
|---|---|---|
| The mode is 0.19 s | [ ] | [ ] |
| The median is 0.22 s | [ ] | [ ] |
| The range is 0.05 s | [ ] | [ ] |
Show answer & marking scheme

Worked solution

Mode = most common value = 0.19 s (appears twice), so true. Ordered values: 0.19, 0.19, 0.21, 0.22, 0.24, so the median is 0.21 s, not 0.22 s: false. Range = 0.24 - 0.19 = 0.05 s: true.

Marking scheme

All three rows correct = 1.5 marks (AO2.1). Two rows correct = 1 mark. One row correct = 0.5 marks. Correct answers: mode True; median False; range True.
Question 2 · closed_selection
1.5 marks
This question is about a pond food chain:

algae → water snail → stickleback → heron

Draw lines to connect each organism with the correct description.

Organism: (1) algae, (2) water snail, (3) heron
Description: (A) producer, (B) primary consumer, (C) top predator / tertiary consumer, (D) decomposer
Show answer & marking scheme

Worked solution

Algae make their own food by photosynthesis, so they are producers. The snail eats the producer, so it is a primary consumer. The heron is at the end of the chain and is eaten by nothing in it, so it is the top predator (the third consumer). Decomposer is a spare description.

Marking scheme

Algae–A, water snail–B, heron–C. All three correct = 1.5 marks; two correct = 1 mark; one correct = 0.5 marks (AO1.1). DO NOT ALLOW more than one line from an organism.
Question 3 · closed_selection
1.5 marks
Complete the sentences about how plants take in substances. Use words from the list. Each word may be used once, more than once, or not at all.

Word list: stomata, root hairs, xylem, phloem, osmosis, active transport, nitrate, glucose

Water enters a plant root by ______________ through the ______________ . Plants need ______________ ions from the soil to make proteins.
Show answer & marking scheme

Worked solution

Water moves into root cells from the soil by osmosis through the root hair cells, which have a large surface area. Nitrate ions are needed to make amino acids and so proteins.

Marking scheme

osmosis (0.5); root hairs (0.5); nitrate (0.5) (AO1.1). Total 1.5 marks. DO NOT ALLOW glucose for nitrate.
Question 4 · closed_selection
1.5 marks
A study found that people who eat more processed meat are more likely to develop bowel cancer.

Tick (✓) three boxes to show the statements that are correct.

[ ] A. The study shows a correlation between processed meat and bowel cancer.
[ ] B. The study proves that processed meat causes bowel cancer.
[ ] C. A larger sample of people would make the evidence more reliable.
[ ] D. Everyone who eats processed meat will develop bowel cancer.
[ ] E. Other risk factors, such as smoking, could also affect the results.
Show answer & marking scheme

Worked solution

A correlation shows a link, not proof of cause (B is wrong). A larger sample improves reliability (C). Other factors may affect the outcome (E). D is wrong because risk factors only raise the chance of disease.

Marking scheme

A, C, E ticked. 0.5 marks for each correct tick (AO2.1). If more than three boxes are ticked, subtract 0.5 for each extra tick, to a minimum of 0.
Question 5 · closed_selection
1.5 marks
Some strawberry plants produce runners that grow into new plants.

Tick (✓) one box in each row to show whether each statement describes sexual reproduction or asexual reproduction.

| Statement | Sexual | Asexual |
|---|---|---|
| Offspring are genetically identical to the parent | [ ] | [ ] |
| Gametes fuse at fertilisation | [ ] | [ ] |
| Produces the most genetic variation in a population | [ ] | [ ] |
Show answer & marking scheme

Worked solution

Asexual reproduction involves one parent and mitosis, giving clones. Fertilisation is the fusion of gametes in sexual reproduction, which mixes genes from two parents and so gives more variation.

Marking scheme

Row 1 Asexual; row 2 Sexual; row 3 Sexual. All correct = 1.5 marks; two correct = 1 mark; one correct = 0.5 marks (AO1.1).
Question 6 · closed_selection
1.5 marks
Tick (✓) three boxes to show the diseases that are communicable.

[ ] Cholera
[ ] Type 1 diabetes
[ ] Malaria
[ ] Lung cancer
[ ] Tuberculosis (TB)
[ ] Coronary heart disease
Show answer & marking scheme

Worked solution

Communicable diseases are caused by pathogens that can pass between people or from animals. Cholera (bacterium), malaria (protist) and TB (bacterium) are communicable. Diabetes, lung cancer and heart disease are non-communicable.

Marking scheme

Cholera, malaria, TB ticked: 0.5 marks each (AO1.1). Subtract 0.5 for each extra tick, minimum 0.
Question 7 · closed_selection
1.5 marks
Draw lines to connect each part of a cell with its function.

Cell part: (1) mitochondria, (2) ribosomes, (3) cell membrane
Function: (A) controls which substances enter and leave the cell, (B) site of protein synthesis, (C) site of aerobic respiration, (D) contains chromosomes
Show answer & marking scheme

Worked solution

Mitochondria release energy by aerobic respiration. Ribosomes join amino acids to make proteins. The cell membrane is partially permeable and controls what moves in and out. D describes the nucleus and is spare.

Marking scheme

1–C, 2–B, 3–A. All correct = 1.5 marks; two correct = 1 mark; one correct = 0.5 marks (AO1.1).
Question 8 · closed_selection
1.5 marks
A person touches a hot object and pulls their hand away without thinking. The steps in this reflex are listed below.

A. Motor neurone carries impulse
B. Receptor detects the heat
C. Muscle in the arm contracts
D. Relay neurone passes the impulse on
E. Sensory neurone carries impulse

Write the letters in the boxes to show the correct order. The first is done for you.

[ B ] → [ ] → [ ] → [ ] → [ ]
Show answer & marking scheme

Worked solution

The receptor detects the stimulus, the sensory neurone carries the impulse to the spinal cord, the relay neurone passes it to the motor neurone, which carries it to the effector (muscle), which contracts.

Marking scheme

B, E, D, A, C. All four remaining letters in correct positions = 1.5 marks; three correct positions = 1 mark; two correct positions = 0.5 marks (AO1.1).
Question 9 · Closed selection
1.5 marks
A student measured the height of bean seedlings grown with different amounts of fertiliser. For each statement about the results, tick (✓) one box in each row to show whether it is a correct use of the data.

Table 1.1
| Fertiliser (g per plant) | Mean height (cm) |
| 0 | 12 |
| 2 | 18 |
| 4 | 25 |
| 6 | 24 |

Row 1: Plants given 4 g of fertiliser grew taller on average than plants given none. [Supported by data / Not supported by data]
Row 2: Fertiliser causes bean seedlings to grow taller in every soil type. [Supported by data / Not supported by data]
Row 3: Adding 6 g of fertiliser gave a smaller mean height than adding 4 g. [Supported by data / Not supported by data]

Each correct row = 0.5 marks. [1.5]
Show answer & marking scheme

Worked solution

Row 1: 25 cm is greater than 12 cm, so supported. Row 2: only one soil type was tested, so the claim goes beyond the data. Row 3: 24 cm is less than 25 cm, so supported.

Marking scheme

Row 1 Supported (0.5, AO3.2a)
Row 2 Not supported (0.5, AO3.2a)
Row 3 Supported (0.5, AO3.2a)
Guidance: all three correct = 1.5 marks; award 0.5 per correct row. DO NOT ALLOW more than one tick in a row.
Question 10 · Closed selection
1.5 marks
A pond food chain is: pondweed → water snail → stickleback → heron.

Complete the sentences. Use words from the list. Each word may be used once, more than once, or not at all.

Word list: producer, primary consumer, secondary consumer, tertiary consumer, decomposer, energy, protein

The pondweed is the ........ because it makes its own food. The stickleback is the ........ in this chain. Biomass is passed along the chain, but some ........ is lost at each step as heat. [1.5]
Show answer & marking scheme

Worked solution

Pondweed photosynthesises so it is the producer. The snail eats the producer (primary consumer), so the stickleback eating the snail is the secondary consumer. Heat loss is loss of energy.

Marking scheme

producer (0.5, AO1.1)
secondary consumer (0.5, AO2.1)
energy (0.5, AO1.1)
Guidance: ALLOW 'second consumer'. DO NOT ALLOW 'primary consumer' or 'tertiary consumer' for the second blank.
Question 11 · Closed selection
1.5 marks
Draw lines to connect each plant structure with its function in a leaf or root.

Left column: (A) Root hair cell; (B) Stomata; (C) Xylem
Right column: (1) Allow carbon dioxide to diffuse into the leaf; (2) Carries water and minerals up the plant; (3) Has a large surface area to absorb water and mineral ions; (4) Stores starch

Write the number of the correct function for each structure. [1.5]
Show answer & marking scheme

Worked solution

Root hair cells have a large surface area for absorption. Stomata let CO2 diffuse in. Xylem transports water and minerals upward. Function 4 is a spare.

Marking scheme

A–3 (0.5, AO1.1)
B–1 (0.5, AO1.1)
C–2 (0.5, AO1.1)
Guidance: all three correct = 1.5; award 0.5 per correct link. Two links from one structure = no mark for that structure.
Question 12 · Closed selection
1.5 marks
This question is about risk factors for non-communicable diseases.

Tick (✓) the three boxes that show factors which increase the risk of cardiovascular disease.

☐ Regular vigorous exercise
☐ A diet high in saturated fat
☐ Smoking cigarettes
☐ High blood pressure
☐ Eating five portions of fruit and vegetables daily
☐ Being vaccinated against measles [1.5]
Show answer & marking scheme

Worked solution

Saturated fat raises cholesterol and causes fatty deposits in arteries; smoking damages artery walls; high blood pressure damages vessels and strains the heart. Exercise and fruit and vegetables lower the risk; measles vaccination is unrelated.

Marking scheme

Diet high in saturated fat (0.5, AO1.1)
Smoking cigarettes (0.5, AO1.1)
High blood pressure (0.5, AO1.1)
Guidance: each extra tick above three cancels one correct mark (minimum 0).
Question 13 · Closed selection
1.5 marks
Tick (✓) one box in each row to show whether each statement describes sexual reproduction or asexual reproduction.

Row 1: Offspring are genetically identical to the parent. [Sexual / Asexual]
Row 2: Two gametes fuse at fertilisation. [Sexual / Asexual]
Row 3: Produces offspring with greater variation, which helps a species survive when the environment changes. [Sexual / Asexual] [1.5]
Show answer & marking scheme

Worked solution

Asexual reproduction involves one parent and mitosis, giving clones. Sexual reproduction involves fusion of gametes and mixing of genes, giving variation.

Marking scheme

Row 1 Asexual (0.5, AO1.1)
Row 2 Sexual (0.5, AO1.1)
Row 3 Sexual (0.5, AO1.2)
Guidance: 0.5 per correct row.
Question 14 · Closed selection
1.5 marks
Complete the sentences about disease. Use words from the list. Each word may be used once, more than once, or not at all.

Word list: bacteria, virus, fungus, communicable, non-communicable, inherited, antibiotic, vaccine

Malaria is caused by a protist, so it is a ........ disease because it can be passed from one person to another. Cystic fibrosis is an ........ disorder, so it cannot be caught. Tuberculosis is caused by ........ and can be treated with an antibiotic. [1.5]
Show answer & marking scheme

Worked solution

Diseases that spread between people are communicable. Cystic fibrosis is passed on through genes, so is inherited. Tuberculosis is a bacterial disease, so antibiotics are effective.

Marking scheme

communicable (0.5, AO1.1)
inherited (0.5, AO1.1)
bacteria (0.5, AO1.1)
Guidance: ALLOW 'bacterium' / 'bacterial'. DO NOT ALLOW 'non-communicable' for the second blank as the sentence reads 'an ........ disorder'.
Question 15 · Closed selection
1.5 marks
Draw lines to connect each cell structure with its function.

Left column: (A) Mitochondrion; (B) Ribosome; (C) Nucleus
Right column: (1) Contains genetic material; (2) Site of protein synthesis; (3) Site of aerobic respiration; (4) Site of photosynthesis

Write the number of the correct function for each structure. [1.5]
Show answer & marking scheme

Worked solution

Mitochondria release energy by aerobic respiration, ribosomes make proteins, and the nucleus holds DNA. Photosynthesis happens in chloroplasts, so 4 is a spare.

Marking scheme

A–3 (0.5, AO1.1)
B–2 (0.5, AO1.1)
C–1 (0.5, AO1.1)
Guidance: 0.5 per correct link.
Question 16 · Closed selection
1.5 marks
A person touches a hot pan and pulls their hand away without thinking. The steps of this reflex are listed below.

A The relay neuron passes the impulse to a motor neuron.
B Receptors in the skin detect the heat.
C The muscle in the arm contracts.
D A sensory neuron carries the impulse to the spinal cord.

Write the letters in the boxes to show the correct order. The first step has been done for you.

B → [ ] → [ ] → [ ]

[1.5]
Show answer & marking scheme

Worked solution

Receptor detects the stimulus (B), the sensory neuron carries the impulse to the spinal cord (D), the relay neuron passes it to the motor neuron (A), and the muscle effector contracts (C).

Marking scheme

D second (0.5, AO1.2)
A third (0.5, AO1.2)
C last (0.5, AO1.2)
Guidance: ECF allowed for correct relative order of remaining letters; 0.5 per letter in the correct position.
Question 17 · Closed selection
1.5 marks
A survey of 12 towns recorded the number of hours of sunshine per week and the number of cases of a skin condition per 10 000 people. The scatter diagram showed that towns with more hours of sunshine had more cases of the skin condition.

Tick (✓) one box in each row to show whether each statement is supported by the survey.

| Statement | Supported | Not supported |
|---|---|---|
| There is a positive correlation between sunshine hours and cases. | ☐ | ☐ |
| More sunshine causes the skin condition. | ☐ | ☐ |
| Towns with fewer sunshine hours had more cases. | ☐ | ☐ |
Show answer & marking scheme

Worked solution

The scatter diagram shows more sunshine goes with more cases, which is a positive correlation. A correlation alone does not show cause, so row 2 is not supported. Row 3 is the opposite of the pattern.

Marking scheme

All three rows correct = 1.5 marks (AO3.1a). Two rows correct = 1 mark. One row correct = 0.5 mark. Row 1 Supported; row 2 Not supported; row 3 Not supported. DO NOT ALLOW two ticks in one row.
Question 18 · Closed selection
1.5 marks
Complete the sentences about the carbon cycle. Use words from the list. Each word may be used once, more than once, or not at all.

Word list: carbon dioxide, decomposers, glucose, nitrate, photosynthesis, respiration

Plants take in carbon dioxide from the air and use it for ______ (1) to make ______ (2).
When dead leaves are broken down, ______ (3) release carbon dioxide back into the air by ______ (4).

There are four gaps; each correct pair of gaps (gaps 1 and 2, gaps 3 and 4) earns 0.75 marks.
Show answer & marking scheme

Worked solution

Plants use carbon dioxide in photosynthesis to make glucose. Decomposers break down dead material and release carbon dioxide through respiration.

Marking scheme

All four correct = 1.5 marks (AO1.1). Three correct = 1 mark. Two correct = 0.5 mark. Fewer than two = 0. DO NOT ALLOW 'carbon dioxide' for gap 2 or 'respiration' for gap 1.
Question 19 · Closed selection
1.5 marks
Plants take up mineral ions from the soil through their roots.

Draw one line from each mineral ion to the substance that the plant uses it to make.

Mineral ion: Nitrate | Magnesium | Phosphate

Substance made: Chlorophyll | Amino acids (for proteins) | DNA and cell membranes (phospholipids)
Show answer & marking scheme

Worked solution

Nitrate supplies nitrogen for amino acids and proteins. Magnesium is needed for chlorophyll. Phosphate is used in DNA and membranes.

Marking scheme

Three correct lines = 1.5 marks (AO1.1). Two correct = 1 mark. One correct = 0.5 mark. DO NOT ALLOW more than one line from a mineral ion.
Question 20 · Closed selection
1.5 marks
Some people have a higher risk of developing cardiovascular disease than others.

Which two of the following are risk factors for cardiovascular disease? Tick (✓) two boxes.

☐ Eating a diet high in saturated fat
☐ Having a low resting heart rate because of regular exercise
☐ Smoking cigarettes
☐ Drinking plenty of water
☐ Having a low blood pressure
Show answer & marking scheme

Worked solution

Saturated fat raises blood cholesterol and smoking damages artery walls and raises blood pressure. The other options are not risk factors.

Marking scheme

Both correct boxes ticked = 1.5 marks (AO1.1). One correct box and no incorrect box = 0.75 marks. Ticking more than two boxes: deduct 0.75 for each incorrect tick beyond two (minimum 0).
Question 21 · Closed selection
1.5 marks
Offspring can be produced by sexual reproduction or by asexual reproduction.

Tick (✓) one box in each row to show which type of reproduction each statement describes.

| Statement | Sexual | Asexual |
|---|---|---|
| Offspring are genetically identical to the parent. | ☐ | ☐ |
| Gametes fuse at fertilisation. | ☐ | ☐ |
| Increases genetic variation in a population. | ☐ | ☐ |
Show answer & marking scheme

Worked solution

Asexual reproduction involves one parent and produces clones. Sexual reproduction involves fusion of gametes and mixes alleles, increasing variation.

Marking scheme

All three rows correct = 1.5 marks (AO1.1). Two rows correct = 1 mark. One row correct = 0.5 mark. DO NOT ALLOW two ticks in one row.
Question 22 · Closed selection
1.5 marks
Different types of pathogen cause different diseases.

Draw one line from each disease to the type of pathogen that causes it.

Disease: Malaria | Rose black spot | Measles

Type of pathogen: Virus | Fungus | Protist
Show answer & marking scheme

Worked solution

Malaria is caused by a protist carried by mosquitoes. Rose black spot is a fungal disease of plants. Measles is caused by a virus.

Marking scheme

Three correct lines = 1.5 marks (AO1.1). Two correct = 1 mark. One correct = 0.5 mark. DO NOT ALLOW more than one line from a disease.
Question 23 · Closed selection
1.5 marks
Cells contain different structures called organelles.

Draw one line from each organelle to its function.

Organelle: Mitochondrion | Ribosome | Chloroplast

Function: Site of protein synthesis | Absorbs light for photosynthesis | Releases energy during aerobic respiration
Show answer & marking scheme

Worked solution

Aerobic respiration happens in mitochondria, proteins are made at ribosomes, and chloroplasts contain chlorophyll that absorbs light.

Marking scheme

Three correct lines = 1.5 marks (AO1.1). Two correct = 1 mark. One correct = 0.5 mark. DO NOT ALLOW more than one line from an organelle.
Question 24 · Closed selection
1.5 marks
A person touches a hot object and pulls their hand away without thinking. This is a reflex action.

The steps in the reflex arc are listed below, labelled A to D.

A Relay neuron passes the impulse to a motor neuron
B Receptor detects the stimulus
C Muscle contracts
D Sensory neuron carries the impulse to the spinal cord

Write the letters in the boxes to show the correct order. The first step has been done for you.

[B] → [ ] → [ ] → [ ]
Show answer & marking scheme

Worked solution

The receptor detects the stimulus (B), the sensory neuron carries the impulse to the spinal cord (D), the relay neuron passes it to the motor neuron (A), and the effector muscle contracts (C).

Marking scheme

B, D, A, C in that order = 1.5 marks (AO1.1). Two of the three boxes in the correct position = 1 mark. One of the three boxes in the correct position = 0.5 mark.
Question 25 · Closed selection
1.5 marks
A student measured the heart rate of five volunteers after they drank different amounts of a caffeinated drink. The results are shown in the table.

| Drink volume (cm³) | 0 | 100 | 200 | 300 | 400 |
|---|---|---|---|---|---|
| Heart rate (beats per minute) | 64 | 68 | 73 | 77 | 82 |

Tick (✓) one box in each row to show whether each statement is a correct conclusion from the data.

Statement 1: Heart rate increases as drink volume increases.
Statement 2: Caffeine is the only factor that causes the change in heart rate.
Statement 3: There is a positive correlation between drink volume and heart rate.

For each statement, choose 'Correct conclusion' or 'Not a correct conclusion'.
Show answer & marking scheme

Worked solution

The heart rate rises steadily from 64 to 82 beats per minute as volume rises, so statements 1 and 3 are supported. The data show a correlation only; other factors were not controlled or tested, so statement 2 cannot be concluded.

Marking scheme

All three rows correct = 1.5 marks (AO3.2b)
Two rows correct = 1 mark
One row correct = 0.5 marks
Guidance: a correlation does not prove causation (AO3).
Question 26 · Closed selection
1.5 marks
This question is about a pond food chain.

waterweed → water snail → stickleback → heron

Complete the sentences. Use words from the list. Each word may be used once, more than once or not at all.

consumer decomposer herbivore producer secondary consumer tertiary consumer

The waterweed is the ________________ in this food chain. The stickleback is a ________________ . The heron is a ________________ .
Show answer & marking scheme

Worked solution

Waterweed makes food by photosynthesis so is the producer. The snail eats the producer (primary consumer), the stickleback eats the snail (secondary consumer), and the heron eats the stickleback (tertiary consumer).

Marking scheme

producer = 0.5 mark (AO1.1)
secondary consumer = 0.5 mark (AO2.1)
tertiary consumer = 0.5 mark (AO2.1)
Guidance: DO NOT ALLOW 'consumer' alone for the last two blanks as it is not specific enough.
Question 27 · Closed selection
1.5 marks
A gardener notices that a tomato plant has yellow leaves and very poor growth. The soil is short of one mineral ion.

Draw one line from each mineral ion to the way the plant uses it.

Mineral ions: Nitrate | Magnesium | Phosphate

Uses: A. Needed to make chlorophyll | B. Needed to make amino acids and proteins | C. Needed to make DNA and cell membranes
Show answer & marking scheme

Worked solution

Nitrate supplies nitrogen for amino acids and proteins. Magnesium is a component of chlorophyll. Phosphate is needed for DNA and membranes.

Marking scheme

All three lines correct = 1.5 marks (AO1.1)
Two correct = 1 mark
One correct = 0.5 marks
Guidance: more than one line from a mineral ion = that line is not credited.
Question 28 · Closed selection
1.5 marks
Doctors use information about people's lifestyles to study heart disease.

Tick (✓) three boxes to show the risk factors that increase the chance of developing cardiovascular disease.

☐ Regular aerobic exercise
☐ A diet high in saturated fat
☐ Smoking cigarettes
☐ High blood pressure
☐ Eating five portions of fruit and vegetables a day
☐ Having blood group O
Show answer & marking scheme

Worked solution

Saturated fat raises cholesterol and causes fatty deposits in arteries; smoking damages artery walls; high blood pressure damages vessels. Exercise and fruit and vegetables lower risk; blood group is not a recognised risk factor.

Marking scheme

All three correct and no others = 1.5 marks (AO1.1)
Two correct and no incorrect = 1 mark; or three correct with one incorrect extra tick = 1 mark
One correct = 0.5 marks
Guidance: more than three ticks, award marks for correct ticks minus incorrect ticks.
Question 29 · Closed selection
1.5 marks
Some plants reproduce by sexual reproduction and some by asexual reproduction.

Tick (✓) one box in each row to show whether each statement applies to sexual reproduction, asexual reproduction or both.

Row 1: Offspring are genetically identical to the parent.
Row 2: Gametes are produced by meiosis.
Row 3: Offspring can show variation that helps a species survive a change in the environment.

Columns: Sexual reproduction only | Asexual reproduction only | Both
Show answer & marking scheme

Worked solution

Asexual reproduction uses mitosis and produces clones. Gametes are made by meiosis only in sexual reproduction, and fusion of gametes gives genetic variation.

Marking scheme

All three rows correct = 1.5 marks (AO1.1)
Two rows correct = 1 mark
One row correct = 0.5 marks
Question 30 · Closed selection
1.5 marks
Diseases have different causes.

Draw one line from each disease to the type of pathogen that causes it.

Diseases: Athlete's foot | Malaria | Salmonella food poisoning

Pathogens: A. Bacterium | B. Fungus | C. Protist | D. Virus
Show answer & marking scheme

Worked solution

Athlete's foot is caused by a fungus, malaria by a protist carried by mosquitoes, and Salmonella food poisoning by a bacterium. Virus is a spare answer.

Marking scheme

All three lines correct = 1.5 marks (AO1.1)
Two correct = 1 mark
One correct = 0.5 marks
Question 31 · Closed selection
1.5 marks
Cells contain different structures. Each structure has a function.

Complete the sentences. Use words from the list.

cell membrane chloroplast mitochondria nucleus ribosomes vacuole

Aerobic respiration happens in the ________________ . Proteins are made at the ________________ . In a plant cell, photosynthesis happens in the ________________ .
Show answer & marking scheme

Worked solution

Mitochondria are the site of aerobic respiration, ribosomes make proteins, and chloroplasts contain chlorophyll for photosynthesis.

Marking scheme

mitochondria = 0.5 mark
ribosomes = 0.5 mark
chloroplast = 0.5 mark (AO1.1)
Guidance: ALLOW 'mitochondrion' and 'chloroplasts'.
Question 32 · Closed selection
1.5 marks
A person touches a hot pan and pulls their hand away before they feel pain. This is a reflex action.

The steps in the reflex arc are listed below. Write the letters in the boxes to show the correct order. The first one has been done for you.

A. Relay neurone passes the impulse on
B. Receptor in the skin detects the heat
C. Muscle contracts
D. Sensory neurone carries the impulse to the spinal cord
E. Motor neurone carries the impulse to the muscle

Order: B → ☐ → ☐ → ☐ → ☐
Show answer & marking scheme

Worked solution

The receptor detects the stimulus, the sensory neurone carries the impulse to the spinal cord, the relay neurone connects to the motor neurone, the motor neurone carries the impulse to the effector, and the muscle contracts.

Marking scheme

B D A E C all correct = 1.5 marks (AO1.1)
Two or three of D, A, E, C in the correct position = 1 mark
One in the correct position = 0.5 marks
Guidance: ECF allowed for relative order of correct pairs.
Question 33 · Closed selection
1.5 marks
Farmers add fertiliser to the soil to help crop plants grow well.

Complete the sentences about how plants take in substances. Use words from the list. Each word may be used once, more than once or not at all.

Word list: active transport diffusion nitrate osmosis phosphate stomata xylem

1. Plants take in water from the soil by ......................... . [0.5]
2. Plants need ......................... ions from the soil to make amino acids and proteins. [0.5]
3. Mineral ions are taken into root hair cells against a concentration gradient by ......................... . [0.5]

[Total: 1.5]
Show answer & marking scheme

Worked solution

Water moves into root hair cells from a dilute solution (soil) to a more concentrated one across a partially permeable membrane: osmosis. Nitrate ions provide nitrogen for amino acids and proteins. Mineral ions are usually at a lower concentration in the soil than in the root hair cell, so they are moved against the gradient using energy: active transport.

Marking scheme

1. osmosis (0.5) AO1.1
2. nitrate (0.5) AO1.1
3. active transport (0.5) AO1.1
DO NOT ALLOW phosphate for 2 (it is needed for DNA/ATP, not amino acids). Total 1.5 marks; if more than one word is written on a line for that line, award 0.
Question 34 · Closed selection
1.5 marks
A person touches a hot pan and their hand pulls away before they feel pain. This is a reflex action.

The statements below are about the nervous system and the reflex action. Tick (✓) one box in each row to show whether each statement is true or false.

| Statement | True | False |
|---|---|---|
| A sensory neuron carries impulses from a receptor to the central nervous system. | [ ] | [ ] |
| A reflex action is slower than a voluntary action because the brain must decide the response. | [ ] | [ ] |
| A synapse is a gap between two neurons where a chemical transmitter diffuses across. | [ ] | [ ] |

[Total: 1.5]
Show answer & marking scheme

Worked solution

Sensory neurons carry impulses towards the CNS, so row 1 is true. Reflexes are rapid and automatic and do not involve conscious thought, so they are faster than voluntary actions and row 2 is false. At a synapse a transmitter chemical diffuses across the gap, so row 3 is true.

Marking scheme

Row 1: True (0.5) AO1.1
Row 2: False (0.5) AO1.1
Row 3: True (0.5) AO1.1
More than one tick in a row = 0 for that row. Total 1.5 marks.
Question 35 · Closed selection
1.5 marks
Cells contain structures that each have a different job.

Draw one straight line from each cell structure to its correct function. Draw only one line from each structure.

Cell structure and function:

Mitochondria -> ?
Ribosome -> ?
Chloroplast -> ?

Functions (in a different order):
A. where proteins are made
B. where photosynthesis takes place
C. where aerobic respiration releases energy
D. controls what enters and leaves the cell

[Total: 1.5]
Show answer & marking scheme

Worked solution

Mitochondria are the site of aerobic respiration (C). Ribosomes make proteins during protein synthesis (A). Chloroplasts contain chlorophyll and are where photosynthesis takes place (B). D describes the cell membrane and is not needed.

Marking scheme

Mitochondria to C (0.5) AO1.1
Ribosome to A (0.5) AO1.1
Chloroplast to B (0.5) AO1.1
If more than one line is drawn from a structure, award 0 for that structure. Total 1.5 marks.
Question 36 · Short open response (state, suggest, describe, explain)
1.5 marks
A gardener grows tomato plants in soil that lacks nitrate ions. The leaves of the plants turn pale yellow.

Explain why a lack of nitrate ions affects the growth of the plants. [1.5]
Show answer & marking scheme

Worked solution

Plants absorb nitrate ions from the soil. Nitrates provide nitrogen needed to make amino acids, which are joined to make proteins used for new cells and growth. Nitrogen is also needed for chlorophyll, so a shortage causes yellow leaves.

Marking scheme

0.5 mark each, any three from:
- nitrate ions are a source of nitrogen / needed to make amino acids (AO1.1)
- amino acids are used to make proteins (AO1.1)
- proteins are needed for growth / new cells / enzymes (AO2.1)
- (nitrogen needed to make) chlorophyll, so less photosynthesis (AO2.1)
ALLOW 'protein synthesis'. IGNORE 'nitrates are plant food'.
Question 37 · Short open response (state, suggest, describe, explain)
1.5 marks
A pond food chain is:

algae → water fleas → small fish → heron

The small fish are removed from the pond by a disease.

Suggest what happens to the number of water fleas and to the number of algae, and give a reason for each. [1.5]
Show answer & marking scheme

Worked solution

Small fish eat water fleas, so with no small fish fewer water fleas are eaten and their numbers rise. More water fleas eat more algae, so algae numbers fall.

Marking scheme

- water fleas increase (0.5) (AO2.1)
- because fewer are eaten / no predators (0.5) (AO2.1)
- algae decrease because more are eaten by (more) water fleas (0.5) (AO2.2)
ALLOW 'go up'/'go down'. IGNORE any answer about the heron only.
Question 38 · Short open response (state, suggest, describe, explain)
1.5 marks
Cholera is a communicable disease caused by a bacterium. It spreads where drinking water is contaminated with sewage.

Describe how cholera could be prevented from spreading in a village. [1.5]
Show answer & marking scheme

Worked solution

Break the transmission route: keep sewage away from drinking water, treat water, boil it, and improve hygiene so bacteria are not passed on.

Marking scheme

0.5 mark each, any three from:
- treat / purify / chlorinate drinking water
- boil water before drinking
- separate sewage from drinking water / proper sewage disposal
- wash hands (with soap) before eating / after toilet
- vaccinate people
- isolate / treat infected people
IGNORE 'keep clean' without detail. (AO1.2 / AO2.1)
Question 39 · Short open response (state, suggest, describe, explain)
1.5 marks
A student looks at a plant cell and an animal cell using a light microscope. The student then looks at the same cells using an electron microscope.

State three differences between what the student sees using the electron microscope compared with the light microscope. [1.5]
Show answer & marking scheme

Worked solution

Electron microscopes use beams of electrons, giving much greater magnification and resolving power, so sub-cellular structures like ribosomes and the detailed structure of mitochondria are visible.

Marking scheme

0.5 mark each, any three from:
- greater magnification
- greater resolution / clearer detail
- can see sub-cellular structures / ribosomes / internal structure of mitochondria
- (image is) black and white / not natural colour
- specimen must be dead / in a vacuum
DO NOT ALLOW 'bigger cells'. (AO1.1)
Question 40 · Short open response (state, suggest, describe, explain)
1.5 marks
A person touches a hot pan and pulls their hand away before they feel any pain.

Explain why this response is a reflex and why it is useful. [1.5]
Show answer & marking scheme

Worked solution

A reflex is an automatic, fast response, travelling via a reflex arc (sensory neuron, relay neuron in the spinal cord, motor neuron) without waiting for conscious decision. The speed reduces tissue damage.

Marking scheme

- automatic / involuntary / no conscious thought (0.5) (AO1.1)
- fast / rapid response (0.5) (AO1.1)
- protects from harm / prevents burns / damage (0.5) (AO2.1)
ALLOW 'does not involve the brain'.
Question 41 · Short open response (state, suggest, describe, explain)
1.5 marks
Cells in the root tip of an onion plant are seen dividing by mitosis.

(a) State two ways in which the daughter cells produced by mitosis compare with the parent cell. [1]

(b) Name the type of cell division that produces gametes. [0.5]
Show answer & marking scheme

Worked solution

Mitosis copies the chromosomes and then divides to give two cells with the same genetic information and chromosome number as the parent. Gametes are made by meiosis.

Marking scheme

(a) genetically identical / same DNA / clones (0.5); same number of chromosomes (0.5) (AO1.1)
(b) meiosis (0.5) (AO1.1)
DO NOT ALLOW 'mitosis' for (b).
Question 42 · Short open response (state, suggest, describe, explain)
1.5 marks
A study of 2000 adults found that people who ate more fruit and vegetables each day had lower blood pressure. A newspaper headline said: 'Eating vegetables lowers blood pressure.'

Explain why the study does not prove that eating vegetables lowers blood pressure. [1.5]
Show answer & marking scheme

Worked solution

A correlation does not show cause. People who eat more vegetables may also exercise more or eat less salt. These uncontrolled variables could be the real cause.

Marking scheme

- it shows a correlation / link / association only (0.5) (AO3.2b)
- other factors / variables not controlled (0.5) (AO3.2b)
- named example e.g. exercise / salt / smoking / age / weight (0.5) (AO2.2)
IGNORE 'sample too small'.
Question 43 · Short open response (state, suggest, describe, explain)
1.5 marks
Some bacteria reproduce asexually. Most animals reproduce sexually.

Explain why sexual reproduction produces more variation in offspring than asexual reproduction. [1.5]
Show answer & marking scheme

Worked solution

In sexual reproduction two parents contribute genes through gametes that differ from each other, and random fertilisation produces new combinations. Asexual reproduction copies one parent's DNA, so offspring are identical apart from mutation.

Marking scheme

- two parents / genes from both parents (0.5) (AO1.1)
- gametes genetically different / meiosis mixes genes (0.5) (AO1.1)
- random fertilisation gives new combinations of alleles (0.5) (AO2.1)
ALLOW ORA for asexual (clones / identical to parent). IGNORE mutation alone.
Question 44 · Short open response (state, suggest, describe, explain)
1.5 marks
Root hair cells absorb mineral ions from the soil by active transport.

Explain why active transport, rather than diffusion, is needed, and state what the cell needs to supply for it to happen. [1.5]
Show answer & marking scheme

Worked solution

Diffusion only moves particles down a concentration gradient. Soil mineral ions are at a lower concentration than inside the root hair cell, so they must be moved in against the gradient. This requires energy released by respiration.

Marking scheme

- ions at lower concentration in soil than in the cell (0.5) (AO2.1)
- movement is against the concentration gradient (0.5) (AO1.1)
- requires energy / from respiration / ATP (0.5) (AO1.1)
IGNORE 'carriers' alone.
Question 45 · Short open response
1.5 marks
A scientist measured the number of hours of sleep and the reaction time of 40 students. The scatter diagram showed that students who slept for more hours had shorter reaction times.

State the type of correlation shown and explain why the scientist cannot conclude that less sleep causes slower reactions. [1.5]
Show answer & marking scheme

Worked solution

As sleep increases, reaction time decreases, so the correlation is negative. A correlation only shows a link; other variables were not controlled, so cause is not proven.

Marking scheme

Negative (correlation) (0.5) AO2.1
Correlation does not show / prove cause (0.5) AO1.2
Other variable(s) could affect reaction time / not controlled, e.g. caffeine, age (0.5) AO3.2b
IGNORE 'inverse' alone. DO NOT ALLOW 'positive'.
Question 46 · Short open response
1.5 marks
A food chain in a pond is: algae → water snail → stickleback → heron.

A disease kills most of the sticklebacks. Suggest what happens to the number of water snails and the number of herons in the short term. Give a reason for each answer. [1.5]
Show answer & marking scheme

Worked solution

Fewer sticklebacks means less predation on snails, so snail numbers rise. Herons have less food, so their numbers fall.

Marking scheme

Snails increase / go up (0.5) AO2.1
because fewer predators / less eaten by sticklebacks (0.5) AO2.1
Herons decrease because less food / fewer sticklebacks to eat (0.5) AO2.1
ALLOW ECF if both directions reversed consistently with reasoning. IGNORE 'die' without reason.
Question 47 · Short open response
1.5 marks
Tomato plants grown in soil lacking magnesium have pale yellow leaves.

Explain why a lack of magnesium ions affects the plant's growth. [1.5]
Show answer & marking scheme

Worked solution

Magnesium ions are absorbed by roots and used to make chlorophyll. Without enough, leaves are yellow, absorb less light, photosynthesise less and make less glucose for growth.

Marking scheme

Magnesium needed to make chlorophyll (0.5) AO1.1
Less light absorbed / less photosynthesis (0.5) AO2.1
Less glucose / carbohydrate / biomass made for growth (0.5) AO2.1
IGNORE 'magnesium is a food'.
Question 48 · Short open response
1.5 marks
Regular smoking and a diet high in saturated fat are both risk factors for cardiovascular disease.

Describe how a diet high in saturated fat can lead to a heart attack. [1.5]
Show answer & marking scheme

Worked solution

Fat deposits narrow the coronary arteries, restricting blood flow. A blockage stops oxygen and glucose reaching heart muscle, causing a heart attack.

Marking scheme

Fatty deposits / cholesterol build up in (coronary) arteries (0.5) AO1.1
Arteries narrowed / blocked, (blood clot) (0.5) AO1.1
Less oxygen / glucose reaches heart muscle (so cells cannot respire) (0.5) AO2.1
DO NOT ALLOW veins. IGNORE 'heart blocked'.
Question 49 · Short open response
1.5 marks
Some farmers grow potatoes by planting pieces of old potatoes (asexual reproduction) instead of seeds.

Explain one advantage and one disadvantage of this method for a population of potato plants facing a new disease. [1.5]
Show answer & marking scheme

Worked solution

Asexual reproduction produces clones. This keeps good traits but gives no variation, so a disease can affect all plants.

Marking scheme

Advantage: offspring genetically identical / clones (0.5) so keep desired characteristics (0.5) AO1.1
Disadvantage: no variation so all (equally) susceptible to the disease / none may be resistant (0.5) AO2.1
ALLOW AW. IGNORE 'faster' alone.
Question 50 · Short open response
1.5 marks
Cholera is a communicable disease caused by a bacterium. Cancer is a non-communicable disease.

State what is meant by a communicable disease and give one way cholera could spread between people. [1.5]
Show answer & marking scheme

Worked solution

Communicable diseases are caused by pathogens that can spread between individuals. Cholera spreads in water contaminated with faeces.

Marking scheme

Disease caused by pathogen / microorganism (0.5) AO1.1
Can be passed / spread between people / organisms (0.5) AO1.1
Contaminated water / food (0.5) AO1.2
IGNORE 'catching it' alone. DO NOT ALLOW 'air' or 'touch' only.
Question 51 · Short open response
1.5 marks
Liver cells have many mitochondria, and a very thin plant root hair cell has a large vacuole but few chloroplasts.

Describe the function of mitochondria and suggest why liver cells contain large numbers of them. [1.5]
Show answer & marking scheme

Worked solution

Mitochondria release energy by aerobic respiration. Liver cells carry out many energy-demanding reactions, so need many mitochondria.

Marking scheme

Site of (aerobic) respiration (0.5) AO1.1
releases energy / makes ATP (0.5) AO1.1
Liver cells are very active / need lots of energy (for metabolic reactions) (0.5) AO2.1
DO NOT ALLOW 'makes / produces energy'. IGNORE 'powerhouse'.
Question 52 · Short open response
1.5 marks
A person touches a hot pan and pulls their hand away before feeling pain.

Describe the pathway of the nerve impulse in this reflex action, from the receptor to the effector. [1.5]
Show answer & marking scheme

Worked solution

The receptor detects heat and sends impulses along a sensory neurone to the relay neurone in the spinal cord. Impulses pass via a synapse to a motor neurone, then to the muscle, which contracts.

Marking scheme

Sensory neurone carries impulse from receptor (to CNS / spinal cord) (0.5) AO1.1
Relay neurone in CNS / spinal cord, impulses cross synapse(s) (0.5) AO1.1
Motor neurone to effector / muscle (0.5) AO1.1
ALLOW intermediate neurone. Order must be correct.
Question 53 · Short open response
1.5 marks
A student investigates how temperature affects the rate of photosynthesis in pondweed by counting oxygen bubbles released in one minute.

State the independent variable and the dependent variable, and suggest one variable that should be controlled. [1.5]
Show answer & marking scheme

Worked solution

The student changes temperature (independent) and measures bubbles per minute (dependent). Light intensity, CO2 concentration or pondweed size must be kept the same.

Marking scheme

Independent variable: temperature (0.5) AO2.2
Dependent variable: number of bubbles (in one minute) / rate of oxygen production (0.5) AO2.2
One control: light intensity / distance of lamp / CO2 concentration / same pondweed / time (0.5) AO3.3a
IGNORE 'same amount of water' unqualified.
Question 54 · Short open response
1.5 marks
A student measured the heart rate of five volunteers after running for 2 minutes. The heart rates in beats per minute were: 128, 135, 131, 190, 136.

One result is anomalous. State which result is anomalous and calculate the mean heart rate without it. Give your answer to the nearest whole number.
Show answer & marking scheme

Worked solution

The value 190 is much higher than the others, so it is anomalous. Remaining values: 128 + 135 + 131 + 136 = 530. Mean = 530 / 4 = 132.5, which is 133 to the nearest whole number.

Marking scheme

190 identified as anomalous (0.5)
Adds the four remaining values / divides by 4 (0.5)
133 (bpm) (0.5)
ALLOW 132.5 for the method marks. ECF if a different anomaly is chosen and the mean is correctly calculated. AO2.1 / AO3.1a
Question 55 · Short open response
1.5 marks
A food chain in a pond is: algae → water snail → stickleback → heron.

The number of sticklebacks in the pond falls sharply because of a disease. Suggest what happens to the numbers of water snails and of algae in the short term. Explain your answers.
Show answer & marking scheme

Worked solution

With fewer sticklebacks, fewer snails are eaten so the snail population rises. More snails eat more algae, so the algae population falls.

Marking scheme

Water snail numbers increase (0.5) because fewer are eaten / less predation by sticklebacks (0.5)
Algae numbers decrease because more snails are eating them (0.5)
IGNORE references to herons. AW. AO2.1
Question 56 · Short open response
1.5 marks
Root hair cells absorb mineral ions such as nitrate from the soil, even when the concentration of nitrate in the soil is lower than inside the cell.

Name the process used and explain why the root hair cell needs mitochondria for this process.
Show answer & marking scheme

Worked solution

Moving ions against a concentration gradient is active transport. This needs energy, which mitochondria supply through aerobic respiration.

Marking scheme

Active transport (0.5)
It needs energy / ATP (0.5)
Mitochondria release energy / are the site of (aerobic) respiration (0.5)
DO NOT ALLOW 'produce' or 'make' energy. DO NOT ALLOW diffusion or osmosis. AO1.1 / AO2.1
Question 57 · Short open response
1.5 marks
A newspaper reports that people who drink more than four cups of coffee a day are more likely to have trouble sleeping. A reader says that coffee must be the cause of the sleep problems.

State what type of relationship the data shows and suggest two reasons why the reader's conclusion may not be correct.
Show answer & marking scheme

Worked solution

The data shows a correlation. A correlation does not prove one factor causes the other, because other variables such as stress or work patterns could affect both coffee drinking and sleep.

Marking scheme

Correlation (0.5)
Any two from:
A correlation does not show cause (0.5)
Other factors / a named factor (e.g. stress, work hours) may affect both (0.5)
Sample size small / not representative (0.5)
Max 1.5. AO3.2b
Question 58 · Short open response
1.5 marks
Strawberry plants can reproduce asexually by growing runners, and sexually by producing seeds.

Describe one advantage of sexual reproduction for the strawberry population when a new fungal disease spreads through the area. Use the idea of variation.
Show answer & marking scheme

Worked solution

Seeds come from gametes that combine, giving offspring that differ genetically. Some may be resistant to the fungus, survive, and pass on resistance, whereas asexual offspring are all clones and equally vulnerable.

Marking scheme

Sexual reproduction produces variation / offspring that are genetically different (0.5)
Some plants may be resistant to the disease (0.5)
These survive and reproduce / pass on the allele (0.5)
ORA for asexual clones. AO2.1
Question 59 · Short open response
1.5 marks
Cholera is a communicable disease caused by a bacterium. Asthma is a non-communicable disease.

State what is meant by a communicable disease and give two ways in which the spread of cholera could be reduced.
Show answer & marking scheme

Worked solution

Communicable diseases are caused by pathogens that spread between individuals. Cholera spreads through contaminated water, so clean water and sewage treatment reduce transmission.

Marking scheme

Can be passed on / spread from one person to another (caused by a pathogen) (0.5)
Any two from: clean / treated drinking water; sewage treatment / separating sewage from water; handwashing / good hygiene; vaccination; cooking food thoroughly (0.5 each)
IGNORE 'medicine' alone. AO1.1 / AO2.1
Question 60 · Short open response
1.5 marks
An electron microscope shows more detail than a light microscope.

Explain why electron microscopes allowed scientists to discover structures such as ribosomes, and state one function of ribosomes.
Show answer & marking scheme

Worked solution

Ribosomes are too small to be seen clearly with a light microscope. Electron microscopes have a higher resolving power so can show them. Ribosomes are where amino acids are joined to make proteins.

Marking scheme

Higher resolution / resolving power (0.5)
Ribosomes are too small to be seen with a light microscope / need higher magnification (0.5)
Ribosomes make / synthesise protein (0.5)
DO NOT ALLOW 'clearer' alone. AO1.1 / AO1.2
Question 61 · Short open response
1.5 marks
A person touches a hot pan and pulls their hand away before they feel pain.

Name this type of response and describe the pathway of the nerve impulse from the receptor to the effector.
Show answer & marking scheme

Worked solution

The response is automatic and rapid, so it is a reflex. The impulse travels along the sensory neurone to the relay neurone in the spinal cord, then along the motor neurone to the muscle, which contracts.

Marking scheme

Reflex (action) (0.5)
Sensory neurone to relay neurone / spinal cord / CNS (0.5)
Motor neurone to muscle / effector (0.5)
DO NOT ALLOW 'nerve' for neurone if the order is unclear. AO1.1
Question 62 · Calculation
2 marks
A student views a cheek cell through a light microscope. In the student's drawing the cell is 45 mm long. The magnification of the drawing is ×300.

Use the equation:

\( \text{magnification} = \dfrac{\text{size of image}}{\text{size of real object}} \)

Calculate the real length of the cell. Give your answer in millimetres (mm).

Working may earn marks if your answer is wrong.

real length = ........................ mm [2]
Show answer & marking scheme

Worked solution

Rearrange: real size = image size ÷ magnification.
real length = \( 45 \div 300 = 0.15 \) mm.

Marking scheme

First check the answer on the answer line. If answer = 0.15 (mm) award 2 marks.
1 mark: correct rearrangement/substitution, \( 45 \div 300 \) (AO2.1).
1 mark: 0.15 (AO2.1).
ALLOW 0.150. ALLOW 150 µm (units must be correct if given in µm). ECF for a wrong rearrangement giving 1 mark for method only. DO NOT ALLOW 13500 (45 × 300) for the answer mark.
Question 63 · Calculation
2 marks
A student estimates the number of dandelion plants growing on a school field. The field has an area of 400 m². The student places 1 m² quadrats at random and counts the dandelions in each one.

Table 1.1

| Quadrat | 1 | 2 | 3 | 4 | 5 |
|---|---|---|---|---|---|
| Number of dandelions | 6 | 3 | 5 | 2 | 4 |

Calculate the estimated total number of dandelions on the whole field.

Working may earn marks if your answer is wrong.

estimated number of dandelions = ........................ [2]
Show answer & marking scheme

Worked solution

Mean per quadrat = \( (6+3+5+2+4) \div 5 = 20 \div 5 = 4 \) per m².
Estimated total = \( 4 \times 400 = 1600 \).

Marking scheme

First check the answer on the answer line. If answer = 1600 award 2 marks.
1 mark: calculates mean = 4 (per m²) (AO2.1).
1 mark: \( 4 \times 400 = 1600 \) (AO2.1).
ALLOW ECF from an incorrect mean multiplied by 400 for the second mark. DO NOT ALLOW 4 on its own as the final answer.
Question 64 · Calculation
2 marks
A student investigates osmosis. A cylinder of potato is weighed, left in a concentrated sugar solution for 1 hour, then weighed again.

Table 2.1

| | Mass of potato cylinder in g |
|---|---|
| At the start | 5.0 |
| After 1 hour | 4.2 |

Use the equation:

\( \text{percentage change in mass} = \dfrac{\text{change in mass}}{\text{starting mass}} \times 100 \)

Calculate the percentage change in mass of the potato cylinder.

Working may earn marks if your answer is wrong.

percentage change = ........................ % [2]
Show answer & marking scheme

Worked solution

Change in mass = \( 4.2 - 5.0 = -0.8 \) g.
Percentage change = \( (-0.8 \div 5.0) \times 100 = -16\% \).

Marking scheme

First check the answer on the answer line. If answer = -16 / 16 decrease award 2 marks.
1 mark: change in mass = 0.8 (g) and divided by 5.0, i.e. \( 0.8 \div 5.0 \times 100 \) (AO2.1).
1 mark: 16 (%) with a decrease shown by minus sign or the word decrease/loss (AO2.1).
ALLOW 16 for 2 marks if the answer line or working clearly shows a decrease. If no indication of a decrease, award 1 mark. DO NOT ALLOW 19 (dividing by 4.2) for the answer mark; ALLOW 1 mark for \( 0.8 \div 4.2 \times 100 \) only if method is clear (ECF).
Question 65 · Graph plotting / curve
1 marks
A student investigates how light intensity affects the rate of photosynthesis in pondweed. She counts the number of oxygen bubbles released per minute at different light intensities.

Table 1.1

| Light intensity (arbitrary units) | Bubbles per minute |
|---|---|
| 0 | 0 |
| 20 | 6 |
| 40 | 12 |
| 60 | 17 |
| 80 | 19 |
| 100 | 19 |

The student has drawn a graph grid with 'Light intensity (arbitrary units)' on the x-axis (0 to 100) and 'Bubbles per minute' on the y-axis (0 to 20). The points for 0, 20, 40, 80 and 100 have already been plotted.

Plot the point for a light intensity of 60 arbitrary units on the graph. Use a sharp pencil. [1]
Show answer & marking scheme

Worked solution

Find 60 on the x-axis. Move up to 17 on the y-axis. Mark a small cross or dot at (60, 17).

Marking scheme

Point plotted at (60, 17) correctly = 1 mark (AO2.2). ALLOW a plot within half a small square of the correct position. DO NOT ALLOW a large blob covering more than one small square. IGNORE a line joining points.
Question 66 · Graph plotting / curve
1 marks
A scientist counts the number of rabbits in a nature reserve each year after a new rabbit population is introduced.

Table 2.1

| Year | Number of rabbits |
|---|---|
| 0 | 10 |
| 1 | 25 |
| 2 | 60 |
| 3 | 110 |
| 4 | 140 |
| 5 | 150 |

All six points from Table 2.1 have been plotted on a graph with 'Year' on the x-axis and 'Number of rabbits' on the y-axis.

Draw a smooth curve of best fit through the points. Use a sharp pencil. [1]
Show answer & marking scheme

Worked solution

Draw one continuous, smooth line that follows the trend of the points: it rises slowly, then steeply between years 1 and 3, then levels off towards 150 at years 4 and 5.

Marking scheme

Smooth curve of best fit passing through or close to all plotted points = 1 mark (AO2.2). DO NOT ALLOW straight lines ruled between points (dot-to-dot), a thick or double line, or a curve that does not follow the trend. IGNORE extending the line slightly beyond the first or last point.

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Paper 2: Depth in Biology

Answer all questions. 90 marks in 1 hour 45 minutes. Nine questions with deeper practical, microscopy and data skills and two asterisked 6-mark extended response questions.
53 Question · 97.69999999999997 marks
Question 1 · closed_selection
1.5 marks
A scientist records the number of hours of daily screen time and the resting heart rate of 200 teenagers. A scatter diagram shows a weak positive correlation.

Tick (✓) one box in each row to show whether each statement is a valid conclusion from this data.

| Statement | Valid | Not valid |
|---|---|---|
| Teenagers with more screen time tend to have slightly higher resting heart rates. | ☐ | ☐ |
| Screen time causes a higher resting heart rate. | ☐ | ☐ |
| Every teenager with high screen time has a high resting heart rate. | ☐ | ☐ |

[1.5]
Show answer & marking scheme

Worked solution

A weak positive correlation shows a general tendency only. Correlation does not prove causation, and 'every' is too strong for a weak correlation.

Marking scheme

Row 1 valid = 0.5 (AO3.2b)
Row 2 not valid = 0.5 (AO3.2b)
Row 3 not valid = 0.5 (AO3.2b)
More than one box ticked in a row = 0 for that row.
Question 2 · closed_selection
1.5 marks
This question is about a pond ecosystem.

Complete the sentences about the pond food chain. Use words from the list. Each word can be used once, more than once or not at all.

Word list: producer primary consumer secondary consumer decomposer predator prey

Algae → water snail → perch

The algae are the ......................... because they make their own food by photosynthesis.
The water snail is the ......................... in this food chain.
The perch is a ......................... of the water snail.

[1.5]
Show answer & marking scheme

Worked solution

Algae photosynthesise so are producers. The snail eats the algae so is the primary consumer. The perch eats the snail so is its predator.

Marking scheme

producer = 0.5 (AO1.1)
primary consumer = 0.5 (AO2.1)
predator = 0.5 (AO2.1)
DO NOT ALLOW secondary consumer for the second gap.
Question 3 · closed_selection
1.5 marks
Plants have structures adapted to take in the substances they need.

Draw lines to connect each plant structure with the substance it is mainly adapted to take in or let through.

| Plant structure | | Substance |
|---|---|---|
| Root hair cell | | Carbon dioxide |
| Stoma (opened by guard cells) | | Water and mineral ions |
| Xylem vessel | | Sugars (sucrose) |
| Phloem | | Water transported up the stem |

Three correct lines are needed. Each structure must have one line only.

[1.5]
Show answer & marking scheme

Worked solution

Root hair cells have a large surface area for absorbing water and mineral ions. Stomata allow carbon dioxide to diffuse into the leaf. Xylem carries water up the stem.

Marking scheme

Root hair cell – water and mineral ions = 0.5 (AO1.1)
Stoma – carbon dioxide = 0.5 (AO1.1)
Xylem vessel – water transported up the stem = 0.5 (AO1.1)
IGNORE a line from phloem unless it replaces a correct link. More than one line from a structure = 0 for that structure.
Question 4 · closed_selection
1.5 marks
Several factors can increase the risk of non-communicable diseases.

Tick (✓) one box in each row to show the type of risk factor.

| Risk factor | Inherited | Lifestyle | Environmental |
|---|---|---|---|
| Eating a diet high in saturated fat | ☐ | ☐ | ☐ |
| Living beside a road with heavy traffic fumes | ☐ | ☐ | ☐ |
| Carrying a faulty allele that raises cholesterol | ☐ | ☐ | ☐ |

[1.5]
Show answer & marking scheme

Worked solution

Diet is a choice, so lifestyle. Air pollution comes from surroundings, so environmental. A faulty allele is passed on in genes, so inherited.

Marking scheme

Diet = lifestyle 0.5 (AO1.1)
Traffic fumes = environmental 0.5 (AO1.1)
Faulty allele = inherited 0.5 (AO1.1)
More than one tick in a row = 0 for that row.
Question 5 · closed_selection
1.5 marks
Some farmers grow new potato plants from pieces of old potato (asexual reproduction). Other crops are grown from seeds produced by sexual reproduction.

Tick (✓) one box in each row to show which type of reproduction each statement describes.

| Statement | Asexual only | Sexual only |
|---|---|---|
| Offspring are genetically identical to the parent. | ☐ | ☐ |
| Gametes fuse at fertilisation. | ☐ | ☐ |
| Offspring show genetic variation, so some may survive a new disease. | ☐ | ☐ |

[1.5]
Show answer & marking scheme

Worked solution

Asexual reproduction uses mitosis and produces clones. Sexual reproduction involves fusion of gametes and produces variation, which helps some offspring survive changes such as a new disease.

Marking scheme

Row 1 asexual = 0.5 (AO1.1)
Row 2 sexual = 0.5 (AO1.1)
Row 3 sexual = 0.5 (AO2.1)
More than one tick in a row = 0 for that row.
Question 6 · closed_selection
1.5 marks
This question is about pathogens.

Complete the sentences. Use words from the list. Each word can be used once, more than once or not at all.

Word list: bacteria viruses fungi protists vector antibody

Malaria is caused by ......................... which are spread by mosquitoes.
A mosquito that carries a pathogen from one person to another is called a .........................
Tuberculosis is caused by ......................... which can be treated with antibiotics.

[1.5]
Show answer & marking scheme

Worked solution

Malaria pathogens are protists. A mosquito carrying a pathogen is a vector. Tuberculosis is a bacterial disease, so antibiotics can treat it.

Marking scheme

protists = 0.5 (AO1.1)
vector = 0.5 (AO1.1)
bacteria = 0.5 (AO1.1)
DO NOT ALLOW viruses for the third gap, since antibiotics do not work on viruses.
Question 7 · closed_selection
1.5 marks
Cells contain structures called organelles that can be seen using microscopes.

Draw lines to connect each cell structure with its function.

| Cell structure | | Function |
|---|---|---|
| Mitochondrion | | Controls the activities of the cell |
| Nucleus | | Site of aerobic respiration |
| Ribosome | | Site of protein synthesis |
| Cell membrane | | Controls what enters and leaves the cell |

Three correct lines are needed. Each structure must have one line only.

[1.5]
Show answer & marking scheme

Worked solution

Mitochondria release energy by aerobic respiration, the nucleus contains the genetic material controlling the cell, and ribosomes make proteins.

Marking scheme

Mitochondrion – aerobic respiration = 0.5 (AO1.1)
Nucleus – controls the activities of the cell = 0.5 (AO1.1)
Ribosome – protein synthesis = 0.5 (AO1.1)
IGNORE a line from the cell membrane unless it replaces a correct link.
Question 8 · closed_selection
1.5 marks
A student measures the length of five leaves from one tree. The lengths in mm are: 62, 58, 61, 95, 59.

Tick (✓) one box in each row to show whether the statement is correct.

| Statement | Correct | Not correct |
|---|---|---|
| The result 95 mm is an anomaly. | ☐ | ☐ |
| The mean of all five lengths is 60 mm. | ☐ | ☐ |
| The median length is 61 mm. | ☐ | ☐ |

[1.5]
Show answer & marking scheme

Worked solution

95 mm is far from the other values, so it is an anomaly. Mean of all five = 335 ÷ 5 = 67 mm, not 60 mm (60 is the mean excluding the anomaly: 240 ÷ 4). Ordered values: 58, 59, 61, 62, 95, so the median is 61 mm.

Marking scheme

Row 1 correct = 0.5 (AO3.2b)
Row 2 not correct = 0.5 (AO2.2)
Row 3 correct = 0.5 (AO2.2)
More than one tick in a row = 0 for that row.
Question 9 · Closed selection
1.5 marks
A student measures the heart rate of five volunteers after they drink different amounts of a caffeinated drink. The student finds that heart rate increases as the volume of drink increases.

Which two statements are correct conclusions? Tick (✓) two boxes.

[ ] A There is a positive correlation between volume of drink and heart rate.
[ ] B Drinking more caffeinated drink causes the heart rate to rise in every person.
[ ] C Heart rate decreases as the volume of drink increases.
[ ] D The data show a pattern, but more volunteers would make the conclusion more reliable.
[ ] E Caffeine is the only factor that affects heart rate.
Show answer & marking scheme

Worked solution

The heart rate rises as volume rises, so there is a positive correlation (A). With only five volunteers, a larger sample would make the conclusion more reliable (D). B claims causation for every person, which five results cannot show. C is the opposite of the pattern. E is not supported by the data.

Marking scheme

A ticked
D ticked
AO3.2b
Both correct = 1.5 marks; one correct tick with no incorrect ticks = 0.5 marks. Deduct 0.5 for each extra tick; total not below 0.
Question 10 · Closed selection
1.5 marks
Read the food chain from a pond.

pondweed → water snail → stickleback → heron

Use the food chain to complete the sentences. Choose words from the list. Each word may be used once, more than once or not at all.

Word list: producer primary consumer secondary consumer tertiary consumer decomposer

1. The pondweed is the ........................ .
2. The water snail is the ........................ .
3. The heron is the ........................ .
Show answer & marking scheme

Worked solution

Pondweed makes food by photosynthesis so it is the producer. The snail eats the producer so it is a primary consumer. The stickleback is the secondary consumer, so the heron, at the fourth level, is the tertiary consumer.

Marking scheme

producer (0.5)
primary consumer (0.5)
tertiary consumer (0.5)
AO1.1
DO NOT ALLOW 'secondary consumer' for the heron.
Question 11 · Closed selection
1.5 marks
Farmers add fertiliser containing nitrate ions and magnesium ions to soil.

Draw one line from each substance taken in by roots to the way the plant uses it.

Substance:
1. Nitrate ions
2. Magnesium ions
3. Water

Use:
A. Needed to make chlorophyll
B. Needed to make amino acids for proteins
C. Needed to keep cells turgid and as a reactant in photosynthesis

Write the letter that matches each number.
Show answer & marking scheme

Worked solution

Nitrate supplies nitrogen for amino acids and proteins. Magnesium is a part of the chlorophyll molecule. Water keeps cells turgid and is a reactant in photosynthesis.

Marking scheme

1-B (0.5)
2-A (0.5)
3-C (0.5)
AO1.1
IGNORE extra lines/letters if the intended match is clear; two links to one item from one number = no mark for that row.
Question 12 · Closed selection
1.5 marks
A study of 2000 adults found that people who ate more processed meat had a higher rate of bowel cancer.

Tick (✓) one box in each row to show whether each statement is supported by this study.

Statement 1: Eating processed meat is correlated with bowel cancer.
Statement 2: Eating processed meat definitely causes bowel cancer in everyone.
Statement 3: Other lifestyle factors may also affect the risk of bowel cancer.

Columns: Supported / Not supported
Show answer & marking scheme

Worked solution

The study shows a link (correlation), which is statement 1. A correlation does not prove cause for everyone, so statement 2 is not supported. Other risk factors such as smoking, obesity, genes and exercise could also affect the risk, so statement 3 is reasonable.

Marking scheme

Row 1 Supported (0.5)
Row 2 Not supported (0.5)
Row 3 Supported (0.5)
AO3.2b
All three correct = 1.5; two correct = 1; one correct = 0.5.
Question 13 · Closed selection
1.5 marks
Some plants reproduce by sexual reproduction and some by asexual reproduction.

Tick (✓) one box in each row to show whether each statement describes sexual reproduction or asexual reproduction.

Statement 1: Offspring are genetically identical to the parent.
Statement 2: Two gametes fuse at fertilisation.
Statement 3: Produces more genetic variation in the population.

Columns: Sexual / Asexual
Show answer & marking scheme

Worked solution

Asexual reproduction involves mitosis in one parent, giving clones. Fertilisation is the fusion of gametes in sexual reproduction. Mixing of genes from two parents gives more variation.

Marking scheme

Row 1 Asexual (0.5)
Row 2 Sexual (0.5)
Row 3 Sexual (0.5)
AO1.1
All correct = 1.5; two correct = 1; one correct = 0.5.
Question 14 · Closed selection
1.5 marks
Which three diseases are communicable? Tick (✓) three boxes.

[ ] A Cholera
[ ] B Type 1 diabetes
[ ] C Tuberculosis
[ ] D Lung cancer
[ ] E Athlete's foot
[ ] F Cystic fibrosis
Show answer & marking scheme

Worked solution

Cholera (bacterium), tuberculosis (bacterium) and athlete's foot (fungus) are caused by pathogens and can be passed between people. Type 1 diabetes, lung cancer and cystic fibrosis are non-communicable.

Marking scheme

A (0.5)
C (0.5)
E (0.5)
AO1.1
Deduct 0.5 for each incorrect extra tick; total not below 0.
Question 15 · Closed selection
1.5 marks
The table lists parts of a cell and their functions.

Draw one line from each cell part to its function. Write the correct letter for each number.

Cell part:
1. Mitochondrion
2. Ribosome
3. Chloroplast

Function:
A. Where protein synthesis takes place
B. Where aerobic respiration releases energy
C. Where photosynthesis takes place
D. Controls the passage of substances into and out of the cell
Show answer & marking scheme

Worked solution

Mitochondria are the site of aerobic respiration, ribosomes make proteins and chloroplasts carry out photosynthesis. D describes the cell membrane and is a spare.

Marking scheme

1-B (0.5)
2-A (0.5)
3-C (0.5)
AO1.1
DO NOT ALLOW D for any row.
Question 16 · Closed selection
1.5 marks
Cells in the small intestine absorb glucose from a low concentration in the gut into a higher concentration in the blood.

Which process moves the glucose, and why? Tick (✓) one box.

[ ] A Diffusion, because glucose moves down a concentration gradient.
[ ] B Osmosis, because glucose moves through a partially permeable membrane.
[ ] C Active transport, because glucose moves against a concentration gradient using energy from respiration.
[ ] D Active transport, because glucose moves down a concentration gradient without energy.
Show answer & marking scheme

Worked solution

The glucose moves from low to high concentration, which is against the concentration gradient. This needs energy from respiration, so it is active transport.

Marking scheme

C ticked (1.5)
AO2.1
More than one tick = 0.
Question 17 · Closed selection
1.5 marks
A student measures the number of earthworms in 1 m² quadrats in a field and the soil moisture at each site. The data show that more earthworms are found where the soil is wetter.

Tick (✓) one box in each row to show whether each statement is a correct conclusion from these data.

| Statement | Correct | Not correct |
|---|---|---|
| There is a positive correlation between soil moisture and earthworm number. | ☐ | ☐ |
| Wet soil causes earthworms to be produced. | ☐ | ☐ |
| Earthworm number is higher at wetter sites in this sample. | ☐ | ☐ |

[1.5]
Show answer & marking scheme

Worked solution

The data show that earthworm number rises as soil moisture rises, so a positive correlation and a higher number at wetter sites are supported. The data alone cannot show that wet soil causes earthworms to be produced, because correlation does not prove causation.

Marking scheme

All three rows correct = 1.5 marks. Two rows correct = 1 mark. One row correct = 0.5 marks. Zero correct = 0. AO3.2b. DO NOT ALLOW more than one tick in a row.
Question 18 · Closed selection
1.5 marks
Fig. 2.1 describes a food chain in a pond: pondweed, tadpole, dragonfly larva, perch.

Part (a): Which organism is the producer? Tick (✓) one box.
☐ pondweed ☐ tadpole ☐ dragonfly larva ☐ perch

Part (b): Perch numbers fall sharply. Tick (✓) one box to show the most likely immediate effect on dragonfly larvae.
☐ Their numbers increase. ☐ Their numbers decrease. ☐ Their numbers stay exactly the same. ☐ They become producers.

[0.75 + 0.75 = 1.5]
Show answer & marking scheme

Worked solution

Pondweed photosynthesises, so it is the producer. Fewer perch means fewer dragonfly larvae are eaten, so larva numbers increase at first.

Marking scheme

(a) pondweed = 0.75 mark. (b) Their numbers increase = 0.75 mark. AO1.1 for (a), AO2.1 for (b). DO NOT ALLOW more than one tick per part.
Question 19 · Closed selection
1.5 marks
Draw lines to connect each plant structure with the correct way it helps the plant take in substances.

Structure: A root hair cell | B stoma | C xylem vessel

Help: 1 allows carbon dioxide to diffuse into the leaf | 2 gives a large surface area for absorbing water and mineral ions | 3 carries water up from the roots

[1.5]
Show answer & marking scheme

Worked solution

Root hair cells have a large surface area for water and mineral uptake. Stomata let carbon dioxide diffuse into leaves. Xylem transports water upwards.

Marking scheme

3 correct links = 1.5 marks; 2 correct = 1 mark; 1 correct = 0.5 marks. AO1.1. DO NOT ALLOW more than one line from a structure.
Question 20 · Closed selection
1.5 marks
Cardiovascular disease is a non-communicable disease with several risk factors.

Tick (✓) two boxes to show which are risk factors for cardiovascular disease.
☐ Eating a diet high in saturated fat
☐ Having a low blood pressure at rest
☐ Smoking cigarettes
☐ Drinking enough water
☐ Having a low cholesterol level

[1.5]
Show answer & marking scheme

Worked solution

A high saturated fat diet raises blood cholesterol and smoking damages artery walls; both increase risk of cardiovascular disease.

Marking scheme

Each correct box = 0.75 mark, maximum 1.5. If more than two boxes are ticked, subtract 0.75 per extra tick (minimum 0). AO1.1.
Question 21 · Closed selection
1.5 marks
Complete the sentences. Use words from the list. Each word may be used once, more than once or not at all.

Word list: mitosis | meiosis | identical | different | two | four | clones | gametes

Sexual reproduction involves the fusion of ......... Each is produced by the process of ......... Offspring from sexual reproduction are genetically ......... from their parents, which increases variation in a population.

[1.5]
Show answer & marking scheme

Worked solution

Gametes fuse at fertilisation and are made by meiosis, which shuffles alleles. Offspring therefore differ genetically from their parents, increasing variation.

Marking scheme

Each correct word = 0.5 mark. gametes; meiosis; different. AO1.1. DO NOT ALLOW mitosis.
Question 22 · Closed selection
1.5 marks
Tick (✓) one box in each row to show whether each disease is communicable or non-communicable.

| Disease | Communicable | Non-communicable |
|---|---|---|
| Measles | ☐ | ☐ |
| Type 1 diabetes | ☐ | ☐ |
| Salmonella food poisoning | ☐ | ☐ |

[1.5]
Show answer & marking scheme

Worked solution

Measles (virus) and salmonella (bacteria) are caused by pathogens that can pass between people. Type 1 diabetes is not caused by a pathogen and cannot be passed on.

Marking scheme

All three correct = 1.5; two correct = 1; one correct = 0.5. AO1.1. DO NOT ALLOW two ticks in a row.
Question 23 · Closed selection
1.5 marks
Draw lines to connect each part of an animal cell with its function.

Part: A mitochondrion | B ribosome | C nucleus

Function: 1 contains the genetic material | 2 site of protein synthesis | 3 site of aerobic respiration

[1.5]
Show answer & marking scheme

Worked solution

Mitochondria release energy by aerobic respiration, ribosomes make proteins, and the nucleus holds the chromosomes.

Marking scheme

3 correct links = 1.5 marks; 2 correct = 1 mark; 1 correct = 0.5 marks. AO1.1.
Question 24 · Closed selection
1.5 marks
A person touches a hot plate and pulls their hand away without thinking. The steps of the reflex are listed below.

A Motor neuron carries impulse to the muscle
B Receptor detects the heat
C Relay neuron passes the impulse in the spinal cord
D Muscle contracts
E Sensory neuron carries impulse to the spinal cord

Write the letters in the boxes to show the correct order. The first is done for you.

B → ☐ → ☐ → ☐ → D

[1.5]
Show answer & marking scheme

Worked solution

Stimulus detected by receptor (B), sensory neuron (E), relay neuron (C), motor neuron (A), effector muscle contracts (D).

Marking scheme

E, C, A in the three boxes in that order = 1.5 marks. Two of three boxes correct = 1 mark. One of three correct = 0.5 marks. AO1.2.
Question 25 · Closed selection
1.5 marks
A student views a thin slice of a leaf under a light microscope. She wants to identify the structures she can see.

Draw lines to connect each cell structure with its correct function.

Cell structure Function
Mitochondrion A. Controls which substances enter and leave the cell
Chloroplast B. Releases energy from glucose during aerobic respiration
Cell membrane C. Absorbs light for photosynthesis
D. Contains the genetic material of the cell

[1.5]
Show answer & marking scheme

Worked solution

Mitochondria are the site of aerobic respiration, which releases energy from glucose. Chloroplasts contain chlorophyll, which absorbs light for photosynthesis. The cell membrane controls the movement of substances into and out of the cell. Function D (genetic material) describes the nucleus, so it is a spare.

Marking scheme

Mitochondrion to B (AO1.1) 1 mark
Chloroplast to C (AO1.1) 0.5 mark
Cell membrane to A (AO1.1) 0.5 mark
All three correct = 1.5 marks; two correct = 1 mark; one correct = 0.5 mark.
DO NOT ALLOW more than one line from a structure (that link scores no mark).
Guidance: D is a distractor (nucleus).
Question 26 · Closed selection
1.5 marks
Plants take up mineral ions from the soil through their roots.

Complete the sentences. Use words from the list. Each word may be used once, more than once or not at all.

diffusion osmosis active transport root hair cells xylem phloem stomata

Nitrate ions are usually at a lower concentration in the soil than inside the root. The ions are taken up against the concentration gradient by ......................... . This process needs energy from respiration. The ions enter the plant through the ......................... , which have a large surface area. The ions are then carried up the plant in the ......................... .

[1.5]
Show answer & marking scheme

Worked solution

Movement against a concentration gradient using energy is active transport. Root hair cells have a large surface area for absorbing ions and water. Xylem carries water and mineral ions upwards from the roots.

Marking scheme

active transport (AO1.1) 0.5 mark
root hair cells (AO1.1) 0.5 mark
xylem (AO1.1) 0.5 mark
Mark each gap in position.
DO NOT ALLOW diffusion for the first gap (contradicts 'against the concentration gradient').
DO NOT ALLOW phloem for the third gap.
Question 27 · Closed selection
1.5 marks
A study of 800 adults found that people who ate more processed meat each week had a higher chance of bowel cancer.

Tick (✓) one box in each row to show whether each statement is a correct conclusion from this study alone.

Statement | Correct conclusion | Not a correct conclusion
1. Eating processed meat is correlated with a higher chance of bowel cancer. | [ ] | [ ]
2. Eating processed meat definitely causes bowel cancer in everyone. | [ ] | [ ]
3. The study proves that no other factor affects the risk of bowel cancer. | [ ] | [ ]

[1.5]
Show answer & marking scheme

Worked solution

The study shows a correlation between processed meat intake and bowel cancer risk. A correlation does not prove that one factor causes the other, and it cannot show that it affects everyone or that no other factors matter.

Marking scheme

Row 1 correct conclusion (AO3.2b) 0.5 mark
Row 2 not a correct conclusion (AO3.2b) 0.5 mark
Row 3 not a correct conclusion (AO3.2b) 0.5 mark
All three correct = 1.5 marks; two correct = 1 mark; one correct = 0.5 mark.
DO NOT ALLOW more than one tick in a row.
Question 28 · Short open response
2 marks
A student views a plant cell under a light microscope. The image of the cell is 45 mm wide. The magnification is \(\times 300\).

Calculate the real width of the cell in micrometres (µm). Use the equation: magnification = image size ÷ real size. Show your working. [2]
Show answer & marking scheme

Worked solution

Real size = image size ÷ magnification = 45 mm ÷ 300 = 0.15 mm. Convert: 0.15 mm × 1000 = 150 µm.

Marking scheme

First check the answer on the answer line. If answer = 150 (µm) award 2 marks.
Rearranges/substitutes: 45 ÷ 300 (= 0.15 mm) (1 mark, method)
Converts to µm: 150 (1 mark, accuracy)
ALLOW 1 mark for 0.15 with no conversion. ECF for a correct conversion of an incorrect value. AO2.1
Question 29 · Short open response
2 marks
A pond food chain is: algae → water snail → stickleback → heron.

A farmer adds a chemical to the pond that kills most of the sticklebacks. Suggest two effects on the numbers of other organisms in the pond. [2]
Show answer & marking scheme

Worked solution

Fewer sticklebacks means fewer snails are eaten, so snail numbers rise. Herons lose a food source so their numbers fall. More snails then eat more algae, so algae fall.

Marking scheme

Any two from:
number of water snails increases / less predation on snails (1)
number of herons decreases / less food for herons (1)
number of algae decreases because more snails eat them (1)
IGNORE 'die' without reference to numbers. DO NOT ALLOW snails decrease. AO2.1
Question 30 · Short open response
2 marks
Root hair cells absorb mineral ions such as nitrate from the soil, even when the concentration of nitrate in the soil is lower than inside the cell.

Name this process and explain why the root hair cell needs energy for it. [2]
Show answer & marking scheme

Worked solution

Moving ions from low to high concentration is active transport. It goes against the concentration gradient, so it requires energy released by respiration.

Marking scheme

active transport (1)
moves ions against the concentration gradient / from low to high concentration, which needs energy (from respiration) (1)
DO NOT ALLOW diffusion or osmosis. AO1.1, AO2.1
Question 31 · Short open response
2 marks
A study of 5000 adults found that people who ate more processed meat had a higher rate of bowel cancer. A newspaper headline states: 'Processed meat causes bowel cancer.'

Explain why the study alone does not prove that the headline is correct. [2]
Show answer & marking scheme

Worked solution

A correlation does not show cause. Other variables may differ between the groups and could explain the result.

Marking scheme

shows a correlation / link only, not a cause (1)
other factors / confounding variables (e.g. smoking, exercise, family history) not controlled / may be responsible / no mechanism shown (1)
IGNORE 'sample too small' as 5000 is large. AO3.2b
Question 32 · Short open response
2 marks
Strawberry plants can reproduce asexually by growing runners. Gardeners can also grow strawberry plants from seeds produced by sexual reproduction.

Explain one advantage to a species of sexual reproduction compared with asexual reproduction. [2]
Show answer & marking scheme

Worked solution

Gametes combine from two parents, giving varied offspring. If conditions change, some individuals will be adapted and survive to reproduce.

Marking scheme

produces genetic variation in offspring / offspring not identical (1)
so some may survive environmental change / disease and reproduce, passing on alleles (1)
ALLOW ORA for asexual reproduction. AO1.1, AO2.1
Question 33 · Short open response
2 marks
Tuberculosis (TB) is a communicable disease caused by bacteria. Type 2 diabetes is a non-communicable disease.

State two differences between communicable and non-communicable diseases. [2]
Show answer & marking scheme

Worked solution

Contrast cause (pathogen or not) and transmission (spreads or not).

Marking scheme

Any two from:
communicable are caused by pathogens / non-communicable are not (1)
communicable can be passed from person to person / non-communicable cannot (1)
non-communicable often linked to lifestyle / genes / environment (1)
IGNORE 'one is curable'. AO1.1
Question 34 · Short open response
2 marks
A person touches a hot pan and pulls their hand away before feeling pain.

Describe the pathway of the nerve impulse in this reflex, starting at the receptor. [2]
Show answer & marking scheme

Worked solution

A reflex arc passes through sensory, relay and motor neurons to the effector without conscious thought.

Marking scheme

sensory neuron carries impulse to the spinal cord / CNS and relay neuron (1)
motor neuron carries impulse to effector / muscle (1)
ALLOW 1 mark for correct order of receptor, sensory, relay, motor, effector if neurons are not described. AO1.1
Question 35 · Short open response
2 marks
A student investigates how light intensity affects the rate of photosynthesis in pondweed by counting oxygen bubbles released in one minute at different distances from a lamp.

Name the independent variable and suggest one variable the student should control. [2]
Show answer & marking scheme

Worked solution

The independent variable is the one deliberately changed. Others that affect photosynthesis rate must be kept constant.

Marking scheme

distance of lamp from the pondweed / light intensity (1)
any one control: temperature (e.g. water bath), carbon dioxide concentration, size/same piece of pondweed, time counted (1)
DO NOT ALLOW number of bubbles (dependent variable). AO3.3a
Question 36 · Short open response
2 marks
Cells in a root tip divide by mitosis. A student counts 200 cells in a root tip and finds that 30 are in the process of dividing.

Calculate the percentage of cells that are dividing, and state why the cells produced by mitosis are genetically identical to the parent cell. [2]
Show answer & marking scheme

Worked solution

30 ÷ 200 × 100 = 15%. Mitosis copies the chromosomes and shares them equally, so daughter cells have identical DNA.

Marking scheme

15 (%) (1)
DNA / chromosomes copied exactly (then shared equally) (1)
AO2.1, AO1.1
Question 37 · Short open response
1.8 marks
A student counted the daisies in ten 1 m\(^2\) quadrats on a school field. The counts were: 4, 6, 5, 21, 7, 5, 6, 4, 5, 7.

One result looks anomalous. Identify the anomalous result and suggest one possible reason for it. Then calculate the mean number of daisies per quadrat without the anomalous result.
Show answer & marking scheme

Worked solution

The value 21 is far from the others. Excluding it, total = 4+6+5+7+5+6+4+5+7 = 49. Mean = 49 ÷ 9 = 5.4 (to 1 d.p.).

Marking scheme

Total 1.8 marks (0.6 each). 21 identified as anomaly (AO3.2b) [0.6]. Reasonable reason, e.g. quadrat placed on a dense patch / counting error / not random placement (AO2.1) [0.6]. Mean = 49 ÷ 9 = 5.4 [0.6]. ALLOW 5.44 or 5.4. ECF if wrong anomaly excluded. IGNORE 'human error' with no detail.
Question 38 · Short open response
1.8 marks
A pond food chain is: algae → water fleas → minnows → heron.

A disease kills most of the minnows. Suggest what would happen to the number of water fleas and to the number of algae in the short term. Explain your answers.
Show answer & marking scheme

Worked solution

With fewer minnows, fewer water fleas are eaten so their numbers rise. More water fleas eat more algae, so the algae population falls.

Marking scheme

Total 1.8 marks (0.9 each). Water fleas increase because fewer eaten by / less predation by minnows (AO2.1) [0.9]. Algae decrease because more water fleas feeding on them (AO2.1) [0.9]. Direction and reason both needed for each mark. IGNORE effects on the heron.
Question 39 · Short open response
1.8 marks
Plants growing in soil short of nitrate ions have yellow leaves and grow slowly.

State how nitrate ions enter a root hair cell and explain why the plant needs nitrate ions.
Show answer & marking scheme

Worked solution

Soil nitrate concentration is lower than in the root cell, so uptake is by active transport using energy. Nitrate supplies nitrogen to make amino acids and proteins needed for growth.

Marking scheme

Total 1.8 marks (0.9 each). Active transport / against the concentration gradient (AO1.1) [0.9]. To make amino acids / proteins (AW) for growth (AO1.2) [0.9]. DO NOT ALLOW diffusion or osmosis. DO NOT ALLOW 'to make glucose'.
Question 40 · Short open response
1.8 marks
A study found that people who eat more processed meat have a higher rate of bowel cancer.

A newspaper says 'eating processed meat causes bowel cancer'. Explain why the data alone do not show this, and suggest one way scientists could strengthen the evidence.
Show answer & marking scheme

Worked solution

The study shows a correlation only. Other risk factors may differ between the groups. Matching groups for these factors, using larger samples or identifying how the meat could damage cells would strengthen the evidence.

Marking scheme

Total 1.8 marks. Correlation does not mean causation / only shows a link (AO3.1a) [0.6]. Other factors may differ between groups, e.g. smoking, exercise, fibre (AO3.2b) [0.6]. One valid improvement: control/match other variables, larger sample, repeat studies, investigate mechanism (AO3.3a) [0.6]. IGNORE 'more tests' with no detail.
Question 41 · Short open response
1.8 marks
Strawberry growers often propagate plants using runners, which are genetically identical copies of the parent plant.

Explain one advantage and one disadvantage of this asexual reproduction for the growers in the long term.
Show answer & marking scheme

Worked solution

Clones keep the high-yield, good-tasting features of the parent. But with no variation, no plants are likely to be resistant to a new disease or change in conditions, so the whole crop is at risk.

Marking scheme

Total 1.8 marks (0.9 each). Advantage: offspring have the same desirable characteristics as parent/ uniform crop (AO2.1) [0.9]. Disadvantage: no genetic variation so all equally susceptible to a new disease/change in environment (AO2.1) [0.9]. Reason must be given with each.
Question 42 · Short open response
1.8 marks
Cholera is a communicable disease caused by a bacterium. It spreads where drinking water is contaminated by sewage.

Explain why cholera is called a communicable disease and describe one way its spread could be reduced in a flooded region.
Show answer & marking scheme

Worked solution

Communicable means a pathogen can be passed between individuals, here via water. Treating or boiling drinking water kills the bacteria and breaks the transmission route.

Marking scheme

Total 1.8 marks. Caused by a pathogen / bacterium (AO1.1) [0.6]. Can be passed on / spread between people (AO1.1) [0.6]. One valid control, e.g. boil/chlorinate water, safe sewage disposal, handwashing (AO2.1) [0.6]. IGNORE vaccination unless a cholera vaccine is stated.
Question 43 · Short open response
1.8 marks
A cell is drawn in a microscope image 48 mm wide. The real width of the cell is 0.06 mm.

Calculate the magnification. Use: magnification = image size ÷ real size. Show your working.
Show answer & marking scheme

Worked solution

Magnification = 48 ÷ 0.06 = 800.

Marking scheme

First check the answer on the answer line. If answer = 800 (or ×800) award 1.8 marks. If incorrect: correct substitution 48 ÷ 0.06 [0.9]; ALLOW 48 000 ÷ 60 (unit conversion). ECF for arithmetic slip [0.9 max for method]. DO NOT ALLOW a unit such as mm with the answer. (AO2.2)
Question 44 · Short open response
1.8 marks
A person touches a hot pan and pulls their hand away before feeling pain.

Name the type of response shown and explain why it is useful.
Show answer & marking scheme

Worked solution

This is a reflex action. The impulse passes via a relay neuron in the spinal cord without involving conscious thought, so it is rapid and limits tissue damage.

Marking scheme

Total 1.8 marks. Reflex (action) (AO1.1) [0.6]. Fast / rapid / does not involve the conscious part of the brain (AO1.2) [0.6]. Protects against / reduces damage or injury (AO2.1) [0.6]. DO NOT ALLOW 'voluntary'.
Question 45 · Short open response
1.8 marks
A student investigates the effect of temperature on the rate of an enzyme-controlled reaction. They mix amylase with starch at 20, 30, 40, 50 and 60 °C and time how long the starch takes to disappear.

State the independent variable and the dependent variable, and suggest one variable that should be controlled.
Show answer & marking scheme

Worked solution

The student changes temperature (independent) and measures the time for starch to disappear (dependent). Anything else that could alter the rate, such as enzyme concentration, starch volume or pH, must be kept the same.

Marking scheme

Total 1.8 marks (0.6 each). Independent variable = temperature (AO2.2) [0.6]. Dependent variable = time taken for starch to disappear / rate of reaction (AO2.2) [0.6]. One control variable: volume or concentration of amylase/starch, pH, volume of solution (AO3.3a) [0.6]. DO NOT ALLOW 'amount' alone without stating what.
Question 46 · Short open response (state, suggest, describe, explain)
2 marks
Farmers growing tomatoes in a greenhouse add nitrate fertiliser to the soil. Plants growing in soil with too little nitrate have small, pale yellow leaves.

(a) State what the plant uses nitrate ions for. [1]

(b) Nitrate ions move into root hair cells by active transport. Explain why active transport, and not diffusion, is needed. [1]
Show answer & marking scheme

Worked solution

(a) Nitrate provides nitrogen, which plants need to make amino acids and so proteins (including chlorophyll-related proteins and enzymes). (b) Soil water usually has a lower nitrate concentration than the root hair cell. Diffusion only moves particles down a concentration gradient, so active transport using energy from respiration is needed to move them in.

Marking scheme

(a) 1 mark (AO1.1): amino acids / proteins ✓. ALLOW (making) protein / enzymes / DNA / nitrogen-containing compounds. DO NOT ALLOW 'to make food' or 'glucose' or 'starch'.
(b) 1 mark (AO2.1): moving against the concentration gradient / from low to high concentration ✓ (and requires energy from respiration). ALLOW AW: concentration in soil is lower than in the root hair cell. IGNORE 'faster'.
Question 47 · Short open response (state, suggest, describe, explain)
2 marks
A student investigates how temperature affects the rate at which the enzyme catalase breaks down hydrogen peroxide. The student measures the volume of oxygen gas collected in 60 seconds at 20 °C, 30 °C, 40 °C and 50 °C.

(a) State the dependent variable in this investigation. [1]

(b) Suggest one variable the student should control, and explain why it must be controlled. [1]
Show answer & marking scheme

Worked solution

(a) The dependent variable is the one measured: the volume of oxygen gas produced in 60 seconds. (b) Any other factor affecting enzyme activity must be kept the same, for example the concentration or volume of hydrogen peroxide, the mass of catalase source or the pH, so that any change in rate is caused only by temperature.

Marking scheme

(a) 1 mark (AO2.2): volume of oxygen (gas) (collected/produced) ✓. ALLOW rate of oxygen production. DO NOT ALLOW temperature or time.
(b) 1 mark (AO3.3a): a valid control variable AND a reason, e.g. concentration/volume of hydrogen peroxide / mass or amount of catalase / pH / time ✓ so that only temperature affects the rate / so it is a fair test / valid results. Both the variable and the reason are needed for the mark. DO NOT ALLOW temperature.
Question 48 · Calculation
1.75 marks
A student draws a single cheek cell as seen under a light microscope. The drawing of the cell is 36 mm long. The real length of the cell is 0.012 mm.

magnification = size of image ÷ size of real object

Calculate the magnification of the drawing.

Working may earn marks if your answer is wrong.

magnification = ×............................ [1.75]
Show answer & marking scheme

Worked solution

magnification = image size ÷ real size = \(36 \div 0.012 = 3000\).

Marking scheme

First check the answer on the answer line. If answer = 3000 award 1.75 marks.
Substitution into the equation: 36 ÷ 0.012 (1 mark, method)
Answer 3000 (0.75 mark, accuracy)
ALLOW ×3000 / 3 × 10^3. ALLOW 36000 ÷ 12 as method. DO NOT ALLOW 0.00033 (equation inverted) for the answer mark; ECF the method mark only. AO2.1 / AO3.1a.
Question 49 · Calculation
1.75 marks
A group of students estimates the number of daisy plants in a school field. The field has an area of 600 m². They place five quadrats, each of area 0.25 m², at random in the field and count the daisies in each one.

Table 4.1

| Quadrat | 1 | 2 | 3 | 4 | 5 |
|---|---|---|---|---|---|
| Number of daisies | 4 | 7 | 5 | 8 | 6 |

Calculate the estimated total number of daisy plants in the whole field.

Working may earn marks if your answer is wrong.

estimated number of daisies = ............................ [1.75]
Show answer & marking scheme

Worked solution

Mean per quadrat = \((4+7+5+8+6) \div 5 = 6\). Mean per m² = \(6 \div 0.25 = 24\). Total = \(24 \times 600 = 14\,400\).

Marking scheme

First check the answer on the answer line. If answer = 14 400 award 1.75 marks.
Mean per quadrat = 6 (0.5 mark)
Density per m² = 6 ÷ 0.25 = 24 (0.5 mark)
24 × 600 = 14 400 (0.75 mark)
ALLOW alternative route: 600 ÷ 0.25 = 2400 quadrats × 6 = 14 400. ECF from an incorrect mean. DO NOT ALLOW 3600 (area not accounted for) for the answer mark. AO2.1 / AO2.2.
Question 50 · Calculation
1.75 marks
A student puts a cylinder of potato into a beaker of pure water for 2 hours to investigate osmosis. The cylinder has a mass of 2.40 g at the start and 2.82 g at the end.

percentage change in mass = (change in mass ÷ starting mass) × 100

Calculate the percentage change in mass of the potato cylinder.

Give your answer to 1 decimal place.

percentage change = ............................ % [1.75]
Show answer & marking scheme

Worked solution

Change in mass = \(2.82 - 2.40 = 0.42\) g. \((0.42 \div 2.40) \times 100 = 17.5\%\) increase.

Marking scheme

First check the answer on the answer line. If answer = 17.5 (%) award 1.75 marks.
Change in mass = 0.42 (g) (0.75 mark)
(0.42 ÷ 2.40) × 100 (0.5 mark)
17.5 (0.5 mark)
ALLOW +17.5 / 17.50. DO NOT ALLOW 18 (not 1 decimal place) for the answer mark. DO NOT ALLOW 14.9 (divided by final mass). AO2.1.
Question 51 · Calculation
1.75 marks
A student investigates the rate of photosynthesis of pondweed. The pondweed is placed 20 cm from a lamp. It releases 13.5 cm³ of oxygen in 9 minutes.

Calculate the mean rate of oxygen production in cm³ per minute.

Working may earn marks if your answer is wrong.

rate = ............................ cm³ per minute [1.75]
Show answer & marking scheme

Worked solution

rate = volume ÷ time = \(13.5 \div 9 = 1.5\) cm³ per minute.

Marking scheme

First check the answer on the answer line. If answer = 1.5 award 1.75 marks.
13.5 ÷ 9 (1 mark, method)
1.5 (0.75 mark, accuracy)
ALLOW 1.50. DO NOT ALLOW 0.67 / 0.7 (inverted) for the answer mark; ECF the method mark only. AO2.1.
Question 52 · Extended level-of-response
6 marks
*A farmer grows tomato plants in a greenhouse. Some of the plants have yellow lower leaves and very poor root growth. A soil test shows that the soil is low in nitrate ions and is also waterlogged because of poor drainage.

The farmer wants to improve the yield of the tomato crop.

Explain how tomato plants take in nitrate ions and water through their roots, and why waterlogged soil and a shortage of nitrate ions would reduce the growth of the plants.

In your answer, include:
- how the roots are adapted to take in water and nitrate ions
- how a shortage of nitrate ions and waterlogging would each reduce growth. [6]
Show answer & marking scheme

Worked solution

Root hair cells have long thin extensions, giving a large surface area for absorption. Water moves into them by osmosis from the soil (higher water potential) to the cell (lower water potential). Nitrate ions are usually at a lower concentration in the soil than in the root cell, so they are taken in by active transport, which needs energy released by aerobic respiration. Nitrate ions are used to make amino acids and proteins (and chlorophyll), so a shortage reduces growth and causes yellow leaves. In waterlogged soil the air spaces are filled with water so less oxygen is available. The root cells cannot respire aerobically, release less energy, and so less active transport of nitrate ions takes place. Roots also grow poorly, which reduces the surface area for uptake further.

Marking scheme

Level 3 (5-6 marks): Gives a clear, detailed explanation covering both bullet points, linking at least four correct points from the indicative content, including active transport needing energy from respiration and the effect of both nitrate shortage and waterlogging. Scientific terms used accurately; the answer is well structured and logical. (6 marks = all aspects fully linked and clear; 5 marks = minor omissions or lack of clarity.)

Level 2 (3-4 marks): Gives a partial explanation covering both bullet points with some correct links, or a detailed explanation of one bullet point only. Some scientific terms used correctly. (4 marks = both aspects addressed but with gaps; 3 marks = mostly one aspect or limited linking.)

Level 1 (1-2 marks): Gives simple statements, such as roots take in water and minerals, or nitrates are needed for growth, with little or no explanation. Limited use of scientific terms; the answer may lack structure.

Level 0 (0 marks): No response or no response worthy of credit.

Indicative content (AO1.1, AO1.2, AO2.1):
- root hair cells have a large surface area (AO1.1)
- water enters by osmosis (AO1.1)
- down a water potential gradient / from high to low water potential (AO1.1)
- nitrate ions are taken in by active transport (AO1.1)
- against a concentration gradient (AO1.2)
- active transport requires energy from (aerobic) respiration (AO1.2)
- nitrate ions are used to make amino acids / proteins / chlorophyll (AO1.1)
- a nitrate shortage means less protein synthesis, so less growth / yellow leaves (AO2.1)
- waterlogged soil has little oxygen / air spaces filled with water (AO2.1)
- so less aerobic respiration, less energy, less active transport of ions, poor root growth (AO2.1)

Guidance: ALLOW 'minerals' for nitrate ions if linked to uptake. ALLOW 'diffusion' for water entry only if osmosis is not contradicted (AW). DO NOT ALLOW 'plants respire only in the dark' or 'roots make food by photosynthesis'. IGNORE comments about fertiliser cost. The communication of ideas decides the mark within a level.
Question 53 · Extended level-of-response
6 marks
*A study followed 4000 adults aged 45 to 60 for ten years. The researchers recorded how many minutes of brisk walking each person did per week and whether the person developed cardiovascular disease (CVD).

Table 2.1

| Walking per week (minutes) | Number of people | Number who developed CVD |
|---|---|---|
| Less than 60 | 1000 | 150 |
| 60 to 150 | 1500 | 135 |
| More than 150 | 1500 | 90 |

A newspaper headline states: 'Walking more prevents heart disease.'

Use Table 2.1 and your own knowledge to evaluate the headline.

In your answer, include:
- what the data show about the relationship between walking and CVD, including a calculation of the percentage in at least two groups
- why the data may not show that walking is the cause of the lower rates, and how lifestyle, genes and the environment could affect the risk of CVD. [6]
Show answer & marking scheme

Worked solution

Less than 60 minutes: \( \frac{150}{1000} \times 100 = 15\% \). 60 to 150 minutes: \( \frac{135}{1500} \times 100 = 9\% \). More than 150 minutes: \( \frac{90}{1500} \times 100 = 6\% \). The percentage developing CVD falls as walking time increases, so there is a negative correlation. A correlation does not prove that walking causes the lower risk. Other factors could differ between the groups, such as diet, smoking, alcohol, body mass, inherited (genetic) risk, age, and environmental factors like air pollution or access to safe places to walk. People who are already unwell may walk less, so the cause may be reversed. The headline is therefore too strong; the data are consistent with walking reducing risk, but a controlled study would be needed.

Marking scheme

Level 3 (5-6 marks): Gives a clear evaluation that uses calculated percentages from at least two groups to describe the trend AND explains clearly that correlation does not prove causation, with at least two specific other factors (lifestyle, genetic or environmental). Reaches a justified judgement about the headline. Well structured, accurate scientific terms. (6 marks = fully developed with judgement; 5 marks = minor gaps.)

Level 2 (3-4 marks): Describes the trend using the data (with some calculation) and makes some attempt to question the headline, or gives a detailed discussion of other factors without using the data. Some correct scientific terms.

Level 1 (1-2 marks): Makes simple statements such as 'more walking means fewer people with CVD' or 'other things could cause it' with little use of data or explanation.

Level 0 (0 marks): No response or no response worthy of credit.

Indicative content (AO2.1, AO3.1a, AO3.2b):
- less than 60 min: 150/1000 = 15% (AO2.1)
- 60 to 150 min: 135/1500 = 9% (AO2.1)
- more than 150 min: 90/1500 = 6% (AO2.1)
- as walking increases, percentage with CVD decreases / negative correlation (AO3.1a)
- correlation does not show cause (AO3.2b)
- other risk factors may differ between groups: diet, smoking, body mass, alcohol, stress (AO3.2b)
- genes / family history may affect CVD risk (AO1.1)
- environment, e.g. air pollution or income / access to healthcare (AO1.1)
- healthier people may be able to walk more (reverse causation) (AO3.2b)
- a trial with matched or randomly allocated groups would be needed / walking time self-reported so may be inaccurate (AO3.3a)

Guidance: ALLOW percentages to the nearest whole number. ECF for a wrongly calculated percentage if the trend described is consistent with it. ALLOW 'the headline is partly supported'. DO NOT ALLOW 'walking definitely causes' without evaluation. IGNORE sample size comments unless they are justified (4000 is a large sample). The communication of ideas decides the mark within a level.

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