Cambridge International AS Level · Mathematics - Further (9231)

級數求和:練習題

5 條多項選擇題即時批改,另有 4 條文字題附完整解題步驟,全部圍繞「級數求和」。

9 條題目21 免費,無需登記
第 1 題
1

Given the standard result \(\sum_{r=1}^{n} r^2 = \frac{1}{6}n(n+1)(2n+1)\), find the value of \(\sum_{r=1}^{10} r^2\).

第 2 題
1

By using partial fractions, the general term of a series is given by \(u_r = \frac{1}{(r+1)(r+2)} = \frac{1}{r+1} - \frac{1}{r+2}\). Find the sum of the first \(n\) terms, \(S_n = \sum_{r=1}^{n} u_r\), and determine the sum to infinity \(S_{\infty}\).

第 3 題
1

Use the standard results for \(\sum r, \sum r^2\) and \(\sum r^3\) to find the value of \(\sum_{r=n+1}^{2n} r(r+1)\) in terms of \(n\).

第 4 題
1

Using the standard formula for the sum of the first \(n\) positive integers, evaluate the sum \(\sum_{r=1}^{20} (2r + 1)\).

第 5 題
1

By using the method of differences on the identity \(\frac{1}{r^2} - \frac{1}{(r+1)^2} = \frac{2r+1}{r^2(r+1)^2}\), find the sum to infinity of the series \(\sum_{r=1}^{\infty} \frac{2r+1}{r^2(r+1)^2}\).

第 6 題
2

Using the standard formula for the sum of the first \( n \) natural numbers, find the value of \( \sum_{r=1}^{20} (2r + 1) \).

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第 7 題
4

Find the sum of the series \(\sum_{r=1}^n \frac{1}{(2r-1)(2r+1)}\) by using the method of differences.

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第 8 題
6

Find the sum to infinity of the series \(\sum_{r=1}^{\infty} \frac{1}{r(r+1)(r+2)}\) by using the method of partial fractions and differences.

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第 9 題
4

(a) Show that \(\frac{1}{r(r+1)} = \frac{1}{r} - \frac{1}{r+1}\).

(b) Hence, use the method of differences to show that \(\sum_{r=1}^{n} \frac{1}{r(r+1)} = \frac{n}{n+1}\).

(c) State whether the series \(\sum_{r=1}^{\infty} \frac{1}{r(r+1)}\) is convergent and find its sum to infinity.

先自己寫一次答案,再對照解題步驟。

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