GCE A-Level - Higher 2 (H2) · Further Mathematics (9649)

Complex numbers:練習題

4 條多項選擇題即時批改,另有 5 條文字題附完整解題步驟,全部圍繞「Complex numbers」。

9 條題目24 免費,無需登記
第 1 題
1

Given that \(z = \cos\theta + i\sin\theta\), use the identity \(z^n + z^{-n} = 2\cos(n\theta)\) to express \(\cos^3\theta\) in terms of multiple angles.

第 2 題
1

Use De Moivre's Theorem to find the exact value of the expression \(\left(\cos\frac{\pi}{10} + i\sin\frac{\pi}{10}\right)^5\).

第 3 題
1

The locus of points in the Argand plane satisfying the equation \(|z - 3i| = |z - 4|\) is described as:

第 4 題
1

Given two complex numbers \(z_1 = 4e^{i\frac{\pi}{3}}\) and \(z_2 = 2e^{-i\frac{\pi}{6}}\), find the product \(z_1 z_2\) in the form \(re^{i\theta}\), where \(r > 0\) and \(-\pi < \theta \le \pi\).

第 5 題
2

Sketch the locus of a point represented by the complex number \( z \) such that \( |z - 2i| = 3 \).

先自己寫一次答案,再對照解題步驟。

第 6 題
3

Use de Moivre’s theorem to find the exact value of \( (1 + i)^8 \).

先自己寫一次答案,再對照解題步驟。

第 7 題
6

By considering the roots of the equation \( z^n - 1 = 0 \), prove that \( \sum_{k=0}^{n-1} \cos\left(\frac{2k\pi}{n}\right) = 0 \) for any integer \( n > 1 \).

先自己寫一次答案,再對照解題步驟。

第 8 題
4

Given that the complex number \( z \) is such that \( |z| = 2 \) and \( \arg(z) = \frac{\pi}{3} \), find the exact value of \( z^6 \) using de Moivre’s theorem.

Express your final answer in Cartesian form \( a + bi \).

先自己寫一次答案,再對照解題步驟。

第 9 題
5

Consider the complex number \( z = \cos \theta + i \sin \theta \).

(a) Use de Moivre’s theorem to show that \( z^n + \frac{1}{z^n} = 2 \cos(n\theta) \).
(b) By expanding \( \left( z + \frac{1}{z} \right)^4 \), find an expression for \( \cos^4 \theta \) in terms of \( \cos(4\theta) \) and \( \cos(2\theta) \).
(c) Hence, evaluate \( \int_{0}^{\frac{\pi}{2}} \cos^4 \theta \, d\theta \).

先自己寫一次答案,再對照解題步驟。

* thinka提供的內容由AI生成,可能並非總是準確或最新。請將其用作輔助資源,並與官方材料進行核實。

你已看過標準答案,接下來輪到批改你的答案。

這一頁可以告訴你好答案的樣子,卻無法指出你的答案欠缺什麼。thinka 按真實評分準則批改你的文字答案,約 15 秒完成。

想多做幾條同類題目?立即開始練習呢個課題,即做即批改。

立即練習