GCE O-Level · Computing (7155)

Logic Gates:練習題

5 條多項選擇題即時批改,另有 5 條文字題附完整解題步驟,全部圍繞「Logic Gates」。

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第 1 題
1

Which logic gate provides a HIGH output (1) if and only if its two inputs are different?

第 2 題
1

A logic circuit has two inputs, \(A\) and \(B\). The output is given by the Boolean statement:
Output = \((A \text{ AND } B) \text{ OR } (\text{NOT } A)\)
What is the output when \(A = 1\) and \(B = 0\)?

第 3 題
1

Using De Morgan's Law and Boolean algebra properties, simplify the following Boolean expression:
\(\text{NOT } (A \cdot (B + \text{NOT } C))\)

第 4 題
1

According to De Morgan's theorem, the Boolean expression \(\overline{A \cdot B}\) is equivalent to which of the following?

第 5 題
1

Consider a 3-input logic system where the output \(Q\) is defined as \(Q = (A + B) \cdot \overline{C}\).
Which set of inputs will result in \(Q = 1\)?

第 6 題
2

State the output of a NOT logic gate when its input is 1.

先自己寫一次答案,再對照解題步驟。

第 7 題
3

Using De Morgan's theorem, simplify the Boolean expression \( \text{NOT } (A \text{ AND } B) \) into an expression using OR and NOT operators.

先自己寫一次答案,再對照解題步驟。

第 8 題
2

A logic circuit is represented by the Boolean statement \( P = \text{NOT } (A \text{ OR } B) \). Identify which single logic gate is equivalent to this statement.

先自己寫一次答案,再對照解題步驟。

第 9 題
4

State the output of an AND logic gate when one input is 1 and the other input is 0.

先自己寫一次答案,再對照解題步驟。

第 10 題
4

Consider the Boolean expression \(X = \overline{\overline{A} + \overline{B}} \cdot (\overline{A + B})\).


(a) Apply De Morgan\'s theorem to simplify the sub-expression \(\overline{\overline{A} + \overline{B}}\).
(b) Determine the fully simplified Boolean expression for \(X\).

先自己寫一次答案,再對照解題步驟。

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