Oxford AQA IGCSE · Combined Science (9204)

結構、鍵結與物質的性質:練習題

5 條多項選擇題即時批改,另有 3 條文字題附完整解題步驟,全部圍繞「結構、鍵結與物質的性質」。

8 條題目19 免費,無需登記
第 1 題
1

A student is investigating the properties of a material. They find that the material has a giant ionic lattice structure. Which of the following is a characteristic property of this type of substance?

第 2 題
1

Substances with simple molecular structures, such as methane \( (CH_4) \), are typically gases or liquids at room temperature. What is the reason for their low boiling points?

第 3 題
1

In the structure of graphite, each carbon atom is bonded to three other carbon atoms. Which statement correctly explains why graphite is soft and can be used as a lubricant?

第 4 題
1

Which of the following statements correctly describes the arrangement and bonding in a metal?

第 5 題
1

When sodium reacts with chlorine to form sodium chloride, an ionic bond is created. Which statement best explains the nature of this bond?

第 6 題
2

Ionic compounds, such as sodium chloride, have very high melting points. Using your knowledge of structure and bonding, explain why a large amount of energy is needed to melt these substances.

先自己寫一次答案,再對照解題步驟。

第 7 題
4

Explain why graphite is soft and can be used as a lubricant, whereas diamond is extremely hard, even though both are composed entirely of carbon atoms.

先自己寫一次答案,再對照解題步驟。

第 8 題
8

(a) Magnesium oxide is an ionic compound formed from the reaction between magnesium atoms and oxygen atoms. Describe, in terms of electrons, what happens when a magnesium atom reacts with an oxygen atom to form magnesium oxide. You should include the charges on the ions formed.

(b) Magnesium oxide has a very high melting point of \(2852\,^{\circ}\text{C}\). Explain why magnesium oxide has such a high melting point by referring to its structure and bonding.

(c) Graphite is a form of carbon that is used in electrodes because it can conduct electricity. Explain why graphite can conduct electricity but diamond cannot, even though both consist of only carbon atoms.

先自己寫一次答案,再對照解題步驟。

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