儲存程式概念：练习题

• a.To store the address of the specific memory location that the CPU needs to access.
• b.To perform arithmetic and logical operations on fetched operands.
• c.To decode the opcode of the instruction currently being executed.
• d.To hold the contents of the memory location being read from or written to.

• a.PC \( \rightarrow \) MAR; MAR content \( \rightarrow \) MBR; PC incremented; MBR \( \rightarrow \) CIR.
• b.MBR \( \rightarrow \) MAR; MAR content \( \rightarrow \) PC; CIR decoded; PC incremented.
• c.PC \( \rightarrow \) CIR; CIR content \( \rightarrow \) MBR; MAR incremented; MBR \( \rightarrow \) Accumulator.
• d.MAR \( \rightarrow \) PC; PC content \( \rightarrow \) CIR; MBR incremented; CIR \( \rightarrow \) ALU.

• a.Immediate addressing is generally faster because the processor does not need to perform an additional memory fetch to retrieve the datum.
• b.Direct addressing requires fewer bits in the instruction opcode than immediate addressing to represent the same command.
• c.Direct addressing is more secure because the actual data never enters the Current Instruction Register.
• d.Immediate addressing allows for a larger range of values to be used as data compared to the total memory capacity.

• a.The processor executes multiple instructions simultaneously by fetching them from separate memory modules for data and code.
• b.Data is stored in the registers while the program instructions are permanently hardwired into the control unit.
• c.Machine code instructions are stored in main memory and are fetched and executed serially by a processor.
• d.Instructions are stored on a secondary storage device and loaded one by one into the ALU for immediate execution.

• a.The binary value \( 1011 \) itself.
• b.The memory address of the next instruction located after \( 1011 \).
• c.The result of adding \( 1011 \) to the current Program Counter value.
• d.The data value located at memory address \( 1011 \).

先自己写一遍答案，再对照解题步骤。

先自己写一遍答案，再对照解题步骤。

先自己写一遍答案，再对照解题步骤。

先自己写一遍答案，再对照解题步骤。