An original Thinka practice paper modelled on the structure and difficulty of the Nov 2024 (V1) Cambridge IGCSE Agriculture (0600) paper. Not affiliated with or reproduced from Cambridge.
Section A
Answer all questions in the spaces provided.
28 Question · 54 marks
Question 1 · multiple_choice
1 marks
The descriptions, A to D, describe different forms of water found in the soil.
A: water held in soil capillary pores that is easily absorbed by plant roots B: water that drains through the soil under the influence of gravity C: water held as a very thin film around soil particles that is unavailable to plants D: water that has chemically combined with soil minerals
Identify the description which links best to: hygroscopic water.
Show answer & marking schemeHide answer & marking scheme
Worked solution
Hygroscopic water is held very tightly as a thin film around soil particles by adhesive forces, making it unavailable for plants to absorb. This corresponds to description C.
Marking scheme
Award 1 mark for identifying C as the correct description.
Question 2 · multiple_choice
1 marks
The descriptions, A to D, describe different methods of weed control.
A: using a hand tool to physically uproot weeds from a field B: introducing a specific insect that feeds only on a target weed species C: applying a chemical spray that kills only broad-leaved plants D: growing a dense cover crop to suppress the growth of weeds by blocking light
Identify the description which links best to: biological control.
Show answer & marking schemeHide answer & marking scheme
Worked solution
Biological control involves using a living organism, such as a predatory insect or herbivore, to manage a pest or weed population. This corresponds to description B.
Marking scheme
Award 1 mark for identifying B as the correct description.
Question 3 · multiple_choice
1 marks
The descriptions, A to D, describe functions of different stomach chambers in a ruminant animal.
A: the chamber where microbial fermentation of fiber and cellulose occurs B: the chamber where water and inorganic minerals are absorbed from the partially digested food C: the chamber where regurgitated food is collected and honeycomb-like structures filter particles D: the chamber that secretes gastric juices containing hydrochloric acid and digestive enzymes
Identify the description which links best to: the abomasum.
Show answer & marking schemeHide answer & marking scheme
Worked solution
The abomasum is the 'true' stomach of a ruminant, where chemical digestion occurs via the secretion of hydrochloric acid and enzymes. This corresponds to description D.
Marking scheme
Award 1 mark for identifying D as the correct description.
Question 4 · Short-answer and explanation
2 marks
Describe two ways in which a high percentage of organic matter improves the physical properties of a clay soil.
Show answer & marking schemeHide answer & marking scheme
Worked solution
Organic matter acts as a binding agent that co-aggregates fine clay particles into larger, stable crumbs. This improves the overall structure, increasing macro-pore space, which allows for better aeration and less compaction in clay soils.
Marking scheme
Award 1 mark for each valid description up to a maximum of 2 marks: - Improves aggregation/crumb structure (1) - Increases aeration / creates macro-pores (1) - Reduces compaction / makes cultivation easier (1) - Improves drainage (1)
Question 5 · Short-answer and explanation
2 marks
Explain how crop rotation can be used as an effective cultural method to control soil-borne pests.
Show answer & marking schemeHide answer & marking scheme
Worked solution
Soil-borne pests often depend on a specific host plant to survive and reproduce. By rotating to a non-host plant species in the subsequent season, the pests are deprived of their food source, which breaks their life cycle and significantly reduces their population in the soil.
Marking scheme
Award 1 mark for each of the following points: - Breaks the pest's life cycle / starves the pests (1) - Pests are host-specific, so planting a non-host crop prevents reproduction/survival (1)
Question 6 · Short-answer and explanation
2 marks
State two structural adaptations of wind-pollinated flowers that distinguish them from insect-pollinated flowers.
Show answer & marking schemeHide answer & marking scheme
Worked solution
Wind-pollinated flowers are adapted to disperse and capture pollen through the air. They possess feathery, branch-like stigmas with a large surface area to trap passing pollen grains, and long filaments that allow anthers to hang outside the flower, exposing the lightweight pollen to air currents.
Marking scheme
Award 1 mark for each valid structural adaptation described (max 2 marks): - Feathery / large surface area stigmas (1) - Stigmas or anthers hanging outside the flower (exserted) (1) - Long or flexible filaments (1) - Small, dull, or absent petals (no nectar or scent) (1) - Produces large quantities of light, smooth pollen grains (1)
Question 7 · Short-answer and explanation
2 marks
Explain the function of the rumen in the digestive system of a ruminant animal.
Show answer & marking schemeHide answer & marking scheme
Worked solution
The rumen is the largest compartment of the ruminant stomach. It provides an anaerobic environment containing a massive population of bacteria, fungi, and protozoa that ferment ingested plant matter, digesting cellulose which the host animal's own enzymes cannot break down.
Marking scheme
Award 1 mark for each of the following points: - Contains symbiotic microbes/bacteria/protozoa that perform fermentation (1) - Digests cellulose/hemicellulose/complex plant fibers (1)
Question 8 · Short-answer and explanation
2 marks
Explain why rotational grazing generally results in higher pasture productivity compared to continuous grazing.
Show answer & marking schemeHide answer & marking scheme
Worked solution
Rotational grazing divides the pasture into smaller paddocks. Animals are moved systematically from one paddock to another, which prevents selective overgrazing, minimizes soil compaction, and crucially provides the rested paddocks with enough time to regenerate biomass, resulting in higher overall forage yield.
Marking scheme
Award 1 mark for each of the following points: - Allows pasture/paddocks a rest period to recover/regrow (1) - Prevents selective overgrazing of palatable species / reduces soil compaction (1)
Question 9 · Short-answer and explanation
2 marks
A homozygous dominant polled (hornless) bull (\(PP\)) is crossed with a horned cow (\(pp\)). State the genotype and phenotype of the \(F_1\) offspring.
Show answer & marking schemeHide answer & marking scheme
Worked solution
Since the bull is homozygous dominant (\(PP\)), it can only pass on the dominant allele \(P\). The cow is homozygous recessive (\(pp\)) and can only pass on the recessive allele \(p\). All \(F_1\) offspring will receive one of each allele, resulting in the genotype \(Pp\) (heterozygous). Since polled is dominant, the phenotype is polled (hornless).
Marking scheme
Award 1 mark for correct genotype and 1 mark for correct phenotype: - Genotype: Pp / heterozygous (1) - Phenotype: Polled / hornless (1)
Question 10 · Short-answer and explanation
2 marks
Explain how an increase in the market price of a crop affects its supply and demand, according to economic principles.
Show answer & marking schemeHide answer & marking scheme
Worked solution
According to the laws of supply and demand, when the price of a crop increases, producers are incentivized to supply more of that crop to maximize their revenue (increase in supply). Conversely, consumers are less willing or able to purchase the crop at the higher price, leading to a decrease in demand (quantity demanded).
Marking scheme
Award 1 mark for each of the following points: - Quantity supplied increases because farmers want to maximize profits (1) - Quantity demanded decreases because consumers find it less affordable / seek substitutes (1)
Question 11 · Short-answer and explanation
2 marks
Explain the role of the transpiration stream in the movement of inorganic minerals within a plant.
Show answer & marking schemeHide answer & marking scheme
Worked solution
Inorganic minerals are absorbed from the soil into the root xylem. As water evaporates from the leaves during transpiration, it creates a tension (transpiration pull) that draws water and these dissolved mineral ions upward through the xylem vessels, distributing them to all parts of the plant.
Marking scheme
Award 1 mark for each of the following points: - Minerals are dissolved in water and transported through the xylem (1) - Transport is driven by the transpiration pull / evaporation of water from the leaves (1)
Question 12 · short-answer
2 marks
State and explain the effect of a high clay content on soil temperature during early spring.
Show answer & marking schemeHide answer & marking scheme
Worked solution
Clay soils hold a large amount of water. Water requires more energy to heat up than soil minerals, which causes wet clay soils to warm up slowly in spring.
Marking scheme
1 mark for stating that it keeps soil cold or slows down warming. 1 mark for explaining that clay retains water or water has high specific heat capacity.
Question 13 · short-answer
2 marks
Describe how using predatory mites can control pest populations on a vegetable crop.
Show answer & marking schemeHide answer & marking scheme
Worked solution
Predatory mites act as biological control agents. They actively search for, kill, and consume pest species. This direct predation rapidly decreases the pest population and prevents them from causing significant damage to the crop.
Marking scheme
1 mark for identifying that they feed on or kill the pest. 1 mark for explaining that this reduces the pest population or prevents crop damage.
Question 14 · short-answer
2 marks
Explain why wind-pollinated flowers have large, feathery stigmas that hang outside the flower.
Show answer & marking schemeHide answer & marking scheme
Worked solution
Wind-pollinated plants rely on air currents to transfer pollen. Stigmas that hang outside the flower are exposed to these currents, and their large, feathery structure increases the surface area, making it easier to intercept and catch passing pollen grains.
Marking scheme
1 mark for pointing out they are exposed to air currents or hang outside to catch pollen. 1 mark for stating that the feathery structure increases the surface area to trap pollen.
Question 15 · short-answer
2 marks
State where the majority of microbial fermentation of cellulose occurs in a ruminant compared to a non-ruminant herbivore.
Show answer & marking schemeHide answer & marking scheme
Worked solution
Ruminants are foregut fermenters, meaning cellulose is broken down by microbes in the rumen before reaching the true stomach. Non-ruminant herbivores are hindgut fermenters, meaning microbial fermentation of cellulose occurs in the large caecum located after the small intestine.
Marking scheme
1 mark for identifying the rumen in ruminants. 1 mark for identifying the caecum in non-ruminants.
Question 16 · short-answer
2 marks
Describe how a rotational grazing system helps prevent pasture degradation compared to a continuous grazing system.
Show answer & marking schemeHide answer & marking scheme
Worked solution
In rotational grazing, animals are moved through a series of paddocks. This ensures that recently grazed pasture is given a rest period to recover and regrow. It also prevents selective overgrazing, which would otherwise weaken palatable grass species and lead to weed invasion or soil erosion.
Marking scheme
1 mark for mentioning the rest or recovery period for grass. 1 mark for explaining that it prevents selective overgrazing or pasture damage.
Question 17 · short-answer
2 marks
In a crop species, red fruit (R) is dominant to yellow fruit (r). State and explain the expected phenotypic ratio of the offspring when a heterozygous red-fruited plant is crossed with a yellow-fruited plant.
Show answer & marking schemeHide answer & marking scheme
Worked solution
A heterozygous red plant has the genotype Rr and produces gametes carrying either R or r. A yellow plant is homozygous recessive (rr) and only produces gametes with r. Crossing them (Rr x rr) yields offspring genotypes Rr (red) and rr (yellow) in equal proportions, giving a 1:1 phenotypic ratio.
Marking scheme
1 mark for stating the ratio is 1 red : 1 yellow or 50% red, 50% yellow. 1 mark for explaining that the heterozygous parent has Rr genotype and the yellow parent has rr genotype, producing Rr and rr offspring.
Question 18 · short-answer
2 marks
Explain how a sudden increase in the cost of fuel can affect a farmer's supply of fresh vegetables.
Show answer & marking schemeHide answer & marking scheme
Worked solution
An increase in fuel prices increases the cost of operating machinery and transporting vegetables to the market. This raises the overall cost of production. Since production is more expensive and profit margins are reduced, farmers will produce and supply fewer vegetables at any given price, causing a shift in the supply curve to the left.
Marking scheme
1 mark for stating that supply will decrease. 1 mark for explaining that higher fuel costs increase production or transportation costs, reducing profit margins.
Question 19 · short-answer
2 marks
State and explain how the addition of organic matter improves the nutrient-holding capacity of a sandy soil.
Show answer & marking schemeHide answer & marking scheme
Worked solution
Sandy soils have large particles with minimal surface area and low electrical charge, leading to high leaching of nutrients. Adding organic matter provides small colloidal particles with highly negative surface charges. This increases the soil's Cation Exchange Capacity, allowing it to bind positively charged nutrient ions and prevent them from being washed away by water.
Marking scheme
1 mark for stating that organic matter provides negatively charged surfaces or increases Cation Exchange Capacity. 1 mark for explaining that this binds nutrients and prevents them from leaching.
Question 20 · short-answer
2 marks
Explain why a soil with a high clay content is typically slower to warm up in spring than a sandy soil.
Show answer & marking schemeHide answer & marking scheme
Worked solution
Clay soils have very small pore spaces which hold a large volume of water. Water has a high specific heat capacity, meaning it takes a large amount of heat energy to raise its temperature compared to air or dry soil minerals. Sandy soils drain freely, leaving pore spaces filled with air, which warms up much more rapidly.
Marking scheme
1 mark for identifying that clay soil has high water-holding capacity / retains more water (or sandy soil drains quickly). 1 mark for explaining that water has a higher specific heat capacity than air (or requires more energy to heat up than air/dry soil).
Question 21 · short-answer
2 marks
Describe how crop rotation acts as a cultural method to control specific soil-borne insect pests.
Show answer & marking schemeHide answer & marking scheme
Worked solution
Many soil-borne pests are host-specific, relying on a particular crop to survive and reproduce. When a non-host crop is planted the following season, the pest's food source is removed, which disrupts its life cycle and starves the remaining population, reducing their numbers without chemical intervention.
Marking scheme
1 mark for explaining that changing the crop removes the specific host/food source for the pest. 1 mark for explaining that this disrupts the pest's life cycle / starves the pests, leading to a population decline.
Question 22 · short-answer
2 marks
State one advantage and one disadvantage to a plant species of reproducing via self-pollination rather than cross-pollination.
Show answer & marking schemeHide answer & marking scheme
Worked solution
Self-pollination ensures that seed production can still occur even when pollinators are scarce or plants are geographically isolated. However, because the genetic material comes from a single parent plant, it leads to decreased genetic variation, making the population less adaptable to environmental changes or disease outbreaks.
Marking scheme
1 mark for a valid advantage (e.g., higher chance of successful pollination / does not rely on wind or insects / conserves energy used to attract pollinators). 1 mark for a valid disadvantage (e.g., limits genetic variation / can lead to inbreeding depression / offspring may be less adaptable to disease/environmental change).
Question 23 · short-answer
2 marks
Explain how ruminants are able to gain nutritional benefit from cellulose, which they cannot digest using their own digestive enzymes.
Show answer & marking schemeHide answer & marking scheme
Worked solution
Ruminants have a specialized stomach compartment called the rumen containing billions of anaerobic bacteria, fungi, and protozoa. These microorganisms secrete the enzyme cellulase, which ferments cellulose into volatile fatty acids (VFAs). These VFAs are then absorbed through the rumen wall and used as the animal's primary energy source.
Marking scheme
1 mark for mentioning the presence of symbiotic/mutualistic microorganisms (bacteria, fungi, or protozoa) in the rumen. 1 mark for explaining that these microbes produce the enzyme cellulase / ferment cellulose into absorbable volatile fatty acids.
Question 24 · short-answer
2 marks
With reference to farm business management, explain the difference between a fixed cost and a variable cost, using examples from a crop production enterprise.
Show answer & marking schemeHide answer & marking scheme
Worked solution
Fixed costs do not change with the volume of crops produced in the short term (for example, the annual depreciation of a tractor or farm rent). In contrast, variable costs fluctuate directly in proportion to production levels (for example, the cost of seed, chemical pesticides, or fertilizer purchased for that season).
Marking scheme
1 mark for defining and giving an example of a fixed cost (does not change with output, e.g., rent/machinery depreciation). 1 mark for defining and giving an example of a variable cost (changes directly with output, e.g., seed/fertilizer/pesticide costs).
Question 25 · short-answer
2 marks
Explain how rotational grazing helps to reduce the parasite burden of livestock compared to continuous grazing.
Show answer & marking schemeHide answer & marking scheme
Worked solution
In a rotational grazing system, livestock are moved systematically from one paddock to another. When a paddock is left empty of hosts (rested), the life cycle of many internal parasites (such as stomach worms) is broken. The parasite eggs and larvae present on the pasture die due to exposure to heat, sunlight, and starvation before the livestock return to graze that area again.
Marking scheme
1 mark for explaining that pasture resting periods remove host animals. 1 mark for explaining that this breaks the parasite's life cycle / causes parasite larvae to starve or die from environmental exposure.
Question 26 · structured
3 marks
In a certain breed of sheep, the allele for white wool (W) is dominant over the allele for black wool (w).
Two heterozygous white sheep are mated.
Draw a genetic diagram to show the expected genotypes and phenotypes of the offspring, and state the expected phenotypic ratio.
Show answer & marking schemeHide answer & marking scheme
Worked solution
Parents' Genotypes: White wool (heterozygous) × White wool (heterozygous) $$\text{Ww} \times \text{Ww}$$
Offspring Genotypes: WW, Ww, ww Offspring Phenotypes: 3 White wool, 1 Black wool Expected Phenotypic Ratio: 3 white : 1 black (or 3 : 1)
Marking scheme
Award marks as follows: - 1 mark for showing correct parental genotypes ($$\text{Ww} \times \text{Ww}$$) and/or correct gametes ($$\text{W}$$ and $$\text{w}$$). - 1 mark for correct offspring genotypes ($$\text{WW}$$, $$\text{Ww}$$, and $$\text{ww}$$). - 1 mark for correct expected phenotypic ratio (3 white : 1 black or 3 : 1).
Question 27 · calculation
2 marks
A farmer measures the annual grass yield of three different paddocks on a farm. The details are as follows: Paddock 1 has an area of 4.0 hectares and a grass yield of 8.5 tonnes per hectare per year; Paddock 2 has an area of 6.5 hectares and a grass yield of 6.0 tonnes per hectare per year; Paddock 3 has an area of 5.0 hectares and a grass yield of 7.2 tonnes per hectare per year. Calculate the total annual grass yield produced by the three paddocks combined. Show your working.
Show answer & marking schemeHide answer & marking scheme
Worked solution
1. Calculate the grass yield for each individual paddock: Paddock 1: \(4.0 \text{ ha} \times 8.5 \text{ tonnes/ha} = 34.0 \text{ tonnes}\). Paddock 2: \(6.5 \text{ ha} \times 6.0 \text{ tonnes/ha} = 39.0 \text{ tonnes}\). Paddock 3: \(5.0 \text{ ha} \times 7.2 \text{ tonnes/ha} = 36.0 \text{ tonnes}\). 2. Sum the yields together to find the total: \(34.0 + 39.0 + 36.0 = 109.0 \text{ tonnes}\).
Marking scheme
1 mark for correct calculations of individual paddock yields or showing a combined formula: \((4.0 \times 8.5) + (6.5 \times 6.0) + (5.0 \times 7.2)\). 1 mark for the correct final total: 109 (tonnes).
Question 28 · calculation
2 marks
A farmer cultivates 2 hectares of cabbages. The total revenue from selling the harvested crop is $3200. The variable costs involved are $450 per hectare for seeds and fertilizer, and $150 per hectare for chemical pest control. Calculate the gross margin for this cabbage crop. Show your working.
Show answer & marking schemeHide answer & marking scheme
1 mark for calculating the total variable costs as $1200 or showing a correct subtraction step: \(3200 - (2 \times 600)\). 1 mark for the correct final gross margin: $2000 (accept 2000).
Ready to test yourself?
Turn these notes into exam-style practice. Get unlimited AI questions on this topic with instant marking and explanations.
Answer any two questions on the lined paper provided.
6 Question · 30 marks
Question 1 · essay
4 marks
Outline the physical and physiological processes that occur during the germination of a seed.
Show answer & marking schemeHide answer & marking scheme
Worked solution
During germination, the dry seed first absorbs water through the micropyle in a process called imbibition, which softens the testa and causes it to burst. The uptake of water mobilizes gibberellins (hormones) which stimulate the synthesis of hydrolytic enzymes. These enzymes break down insoluble stored foods in the cotyledons or endosperm into soluble nutrients. Respiration increases to provide energy for metabolic activities. Cells in the embryo divide and expand, resulting in the radicle emerging first to establish water uptake, followed by the plumule which grows towards the light.
Marking scheme
Award 1 mark for each of the following points up to a maximum of 4 marks: 1. Imbibition / absorption of water causing swelling / rupture of the seed coat / testa. 2. Activation of digestive enzymes / breakdown of stored food (e.g., starch to maltose/glucose). 3. Increase in respiration / release of energy (ATP) for growth. 4. Emergence of radicle (roots) and/or plumule (shoot).
Question 2 · essay
4 marks
Outline how physical weathering contributes to the process of soil formation.
Show answer & marking schemeHide answer & marking scheme
Worked solution
Physical weathering is the mechanical breakdown of large parent rock into smaller mineral fragments. Temperature fluctuations lead to thermal stress, causing cracks to develop. Freeze-thaw cycles exert high pressure inside rock crevices when water expands upon freezing, causing the rock to shatter. Moving water, wind-borne sand, and glaciers physically wear down rock surfaces via abrasion. Additionally, biological physical weathering occurs when growing plant roots exert outward pressure within rock fissures, splitting them.
Marking scheme
Award 1 mark for each of the following physical weathering mechanisms outlined, up to a maximum of 4 marks: 1. Temperature fluctuations / thermal expansion and contraction causing rock surface exfoliation or cracking. 2. Freeze-thaw action / frost wedging where water freezes, expands, and splits rock. 3. Abrasion by wind, water, or ice grinding down rock surfaces. 4. Root action / biological physical wedging where plant roots grow into cracks and split the rocks apart.
Question 3 · descriptive
5 marks
Compare the use of a hand hoe with a knapsack sprayer for weed control in a crop field. In your answer, describe two differences in how they are operated, two differences in their resource requirements (labor or cost), and one difference in their environmental impact.
Show answer & marking schemeHide answer & marking scheme
Worked solution
A hand hoe is operated by physically pulling or cutting weeds from the soil, which also loosens and aerates the topsoil. In contrast, a knapsack sprayer is operated by carrying a pressurized tank on the operator's back and releasing a chemical mist (herbicide) through a nozzle onto the weeds, leaving the soil undisturbed. In terms of resources, using a hand hoe is highly labor-intensive and slow, meaning it requires many working hours to clear a small area, but the tool itself has a very low purchase cost. On the other hand, a knapsack sprayer allows one worker to cover a large area very quickly (low labor hours per hectare), but it requires significant capital investment to purchase the sprayer, protective clothing, and the chemical herbicides. Regarding environmental impact, manual hoeing has a minimal environmental footprint with zero chemical runoff, whereas chemical spraying carries a risk of herbicide drift onto non-target plants, soil contamination, or chemical runoff into water sources.
Marking scheme
Award 1 mark for each valid comparative point (up to a maximum of 5 marks): Operation (Max 2 marks): [1] Hand hoe physically cuts/uproots weeds or disturbs/loosens the soil; [1] Knapsack sprayer applies a liquid chemical (herbicide) mist onto weeds or does not disturb the soil structure. Resource Requirements (Max 2 marks): [1] Hand hoe has high labor demand (slow/tiring) or very low financial cost (cheap tool, no inputs); [1] Knapsack sprayer has low labor demand (fast coverage) or high capital/maintenance cost (expensive equipment, recurring chemical costs, safety gear). Environmental Impact (Max 1 mark): [1] Manual weeding is environmentally friendly with no chemical pollution/runoff risk, whereas chemical spraying risks chemical drift, water contamination, or toxicity to beneficial non-target organisms.
Question 4 · descriptive
5 marks
Compare drip irrigation with overhead sprinkler irrigation for watering crops. Describe two differences in water use efficiency, two differences in their setup or maintenance, and one difference in their suitability for different crop types.
Show answer & marking schemeHide answer & marking scheme
Worked solution
Drip irrigation delivers water slowly and directly to the plant root zone via a network of pipes and emitters, resulting in exceptionally high water efficiency with almost no waste from wind drift or evaporation. In contrast, overhead sprinkler irrigation sprays water into the air to mimic natural rainfall, which is much less efficient as a significant volume of water can evaporate before reaching the ground, especially in hot or windy conditions. For setup and maintenance, drip systems require complex installations with extensive piping, filtration units, and emitter maintenance because the small nozzle holes are prone to clogging by dirt or mineral deposits. Sprinkler systems have a simpler field layout with fewer main pipes on the ground and are easier to move, though they require high-pressure water pumps to operate. Regarding crop suitability, drip irrigation is highly suited to row crops, orchards, and vineyards where individual plants are spaced out. Overhead sprinklers are better suited to closely sown cover crops, pastures, or lawns where uniform ground coverage is needed.
Marking scheme
Award 1 mark for each valid comparative point (up to a maximum of 5 marks): Water Efficiency (Max 2 marks): [1] Drip irrigation targets the roots directly / minimizes evaporation; [1] Sprinkler irrigation experiences high evaporation losses / wind drift / wets non-target soil and foliage. Setup/Maintenance (Max 2 marks): [1] Drip irrigation has a high setup complexity / requires extensive piping / emitters easily clog; [1] Sprinkler systems are simpler to lay out / require high-pressure pumps / less prone to clogging but can suffer from nozzle wear. Crop Suitability (Max 1 mark): [1] Drip is suited to spaced row crops / orchards / vine crops, whereas sprinklers are suited to closely spaced crops / pastures / uniform broad-scale coverage.
Question 5 · essay
6 marks
Analyze the economic and ecological consequences a livestock producer must weigh when choosing to transition from a pasture-based extensive grazing system to an intensive zero-grazing feedlot.
Show answer & marking schemeHide answer & marking scheme
Worked solution
Transitioning to an intensive feedlot system presents several trade-offs: Economic Pros: Cattle reach market weight faster due to high-energy rations, and herd health can be monitored more closely. Economic Cons: Significant capital is required to build pens, and ongoing costs increase for buying feed and hiring labor for cut-and-carry. Environmental Pros: Pasture land is protected from overgrazing, soil compaction, and erosion. Environmental Cons: Large volumes of manure accumulate in one place, creating risks of local water pollution from runoff and increased odor issues.
Marking scheme
Award up to 6 marks in total, with a maximum of 3 marks for economic points and a maximum of 3 marks for environmental points. Economic points (max 3 marks): 1 mark for mentioning high initial capital costs (housing/troughs). 1 mark for increased variable costs (purchased concentrate feed or labor for cut-and-carry). 1 mark for increased profit potential from higher stocking density or faster animal growth. 1 mark for reduced risk of veterinary delays through easier monitoring. Environmental points (max 3 marks): 1 mark for reduced pasture degradation, soil erosion, or compaction on open rangeland. 1 mark for risks of water pollution/eutrophication from concentrated manure runoff. 1 mark for increased localized air/odor pollution. 1 mark for high localized water consumption requirements.
Question 6 · essay
6 marks
A cash-crop cultivator wishes to maximize short-term profits. Evaluate the economic and environmental advantages and disadvantages of replacing organic compost with synthetic inorganic fertilizers.
Show answer & marking schemeHide answer & marking scheme
Worked solution
Replacing compost with synthetic fertilizers has distinct trade-offs: Economic Advantages: Nutrient release is rapid and highly predictable, accelerating crop maturity and increasing immediate yields and revenue. Handling and transport are less labor-intensive because the product is concentrated. Economic Disadvantages: Inorganic fertilizers are expensive to purchase, leaving the farm vulnerable to price fluctuations. Environmental Advantages: Precise formulation and application can target specific plant deficiencies without bulk over-application. Environmental Disadvantages: Chemical fertilizers do not improve soil structure or organic matter, which can lead to increased erosion over time. Furthermore, excess nutrients easily leach, causing eutrophication in nearby streams and harming beneficial soil microorganisms.
Marking scheme
Award up to 6 marks in total, with a maximum of 3 marks for economic points and a maximum of 3 marks for environmental points. Economic points (max 3 marks): 1 mark for explaining that rapid nutrient release boosts yields and short-term profits. 1 mark for identifying the high recurrent cash expenditure required to buy synthetic inputs. 1 mark for noting reduced labor and transport costs compared to bulky organic compost. 1 mark for potential loss of long-term soil productivity causing future economic decline. Environmental points (max 3 marks): 1 mark for noting the high risk of nutrient leaching, leading to water pollution and eutrophication. 1 mark for explaining that chemical fertilizers fail to improve soil crumb structure or water-holding capacity. 1 mark for pointing out the risk of soil acidification or damage to beneficial soil microbes. 1 mark for noting that precise application reduces the land footprint required for high yields.
Wondering how well you actually know this?
thinka is an AI practice app for IGCSE & IB students: unlimited questions, instant auto-marking, and detailed step-by-step solutions. 100,000+ students use it to confirm they actually know it, not just think they do.