Which equation defines the first electron affinity of chlorine?
Cambridge International A Level · Chemistry (9701)
Chemical energetics (A Level only):練習問題
その場で採点される選択問題 5 問と、解説つきの記述問題 5 問。すべて「Chemical energetics (A Level only)」からの出題です。
Use the data below to calculate the lattice energy, \(\Delta H_{\text{latt}}^\ominus\), of sodium chloride, \(NaCl(s)\).
\(\Delta H_f^\ominus[NaCl(s)] = -411\text{ kJ mol}^{-1}\)
\(\Delta H_{\text{at}}^\ominus[Na(s)] = +107\text{ kJ mol}^{-1}\)
\(1^{\text{st}}\text{ Ionisation energy of }Na(g) = +496\text{ kJ mol}^{-1}\)
\(\Delta H_{\text{at}}^\ominus[Cl_2(g)] = +122\text{ kJ mol}^{-1}\)
\(1^{\text{st}}\text{ Electron affinity of }Cl(g) = -349\text{ kJ mol}^{-1}\)
The decomposition of calcium carbonate is shown:
\(CaCO_3(s) \rightarrow CaO(s) + CO_2(g)\)
\(\Delta H^\ominus = +178\text{ kJ mol}^{-1}\) and \(\Delta S^\ominus = +160\text{ J K}^{-1}\text{ mol}^{-1}\).
At what minimum temperature, in Kelvin, does this reaction become feasible?
Which statement best defines the standard enthalpy change of formation, \(\Delta H_f^\ominus\)?
The diagram represents the reaction pathway for a reversible reaction.
What is the activation energy, \(E_a\), for the reverse reaction?
Define the term standard enthalpy change of formation, \(\Delta H_f^\ominus\).
まず自分で答えを書いてから、解説と照らし合わせましょう。
Explain why the lattice energy of magnesium oxide, \(MgO\), is significantly more exothermic than the lattice energy of sodium chloride, \(NaCl\).
まず自分で答えを書いてから、解説と照らし合わせましょう。
In the Born-Haber cycle for magnesium oxide, the second electron affinity of oxygen, \(O^-(g) + e^- \rightarrow O^{2-}(g)\), is endothermic. Explain why energy must be supplied for this process.
まず自分で答えを書いてから、解説と照らし合わせましょう。
(a) Define the term bond energy.
(b) Use the average bond energy values provided below to calculate the enthalpy change, $\Delta H$, for the reaction:
$$\text{CH}_4(\text{g}) + \text{Cl}_2(\text{g}) \rightarrow \text{CH}_3\text{Cl}(\text{g}) + \text{HCl}(\text{g})$$
Average bond energies in $\text{kJ mol}^{-1}$:
- $\text{C}-\text{H}$: $413$
- $\text{Cl}-\text{Cl}$: $242$
- $\text{C}-\text{Cl}$: $346$
- $\text{H}-\text{Cl}$: $432$
まず自分で答えを書いてから、解説と照らし合わせましょう。
Magnesium chloride is an ionic compound. The formation of ionic compounds can be understood through Born-Haber cycles.
(a) Define lattice energy (\(\Delta H_{latt}\)) for magnesium chloride.
(b) Construct a Born-Haber cycle for the formation of magnesium chloride (\(MgCl_2\)) from its elements. Clearly label all enthalpy changes involved.
(c) Using the following data, calculate the lattice energy of magnesium chloride:
Standard enthalpy change of formation of \(MgCl_2\) = \(-641 \text{ kJ mol}^{-1}\)
Enthalpy change of atomisation of Mg = \(+148 \text{ kJ mol}^{-1}\)
First ionisation energy of Mg = \(+738 \text{ kJ mol}^{-1}\)
Second ionisation energy of Mg = \(+1451 \text{ kJ mol}^{-1}\)
Enthalpy change of atomisation of Cl = \(+122 \text{ kJ mol}^{-1}\)
First electron affinity of Cl = \(-349 \text{ kJ mol}^{-1}\)
(d) Explain qualitatively how the ionic radius and ionic charge affect the numerical magnitude of lattice energy.
まず自分で答えを書いてから、解説と照らし合わせましょう。
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