GCE O-Level · Computing (7155)

Logic Gates:练习题

5 道选择题即时批改,另有 5 道文字题附完整解题步骤,全部围绕「Logic Gates」。

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第 1 题
1

Which logic gate provides a HIGH output (1) if and only if its two inputs are different?

第 2 题
1

A logic circuit has two inputs, \(A\) and \(B\). The output is given by the Boolean statement:
Output = \((A \text{ AND } B) \text{ OR } (\text{NOT } A)\)
What is the output when \(A = 1\) and \(B = 0\)?

第 3 题
1

Using De Morgan's Law and Boolean algebra properties, simplify the following Boolean expression:
\(\text{NOT } (A \cdot (B + \text{NOT } C))\)

第 4 题
1

According to De Morgan's theorem, the Boolean expression \(\overline{A \cdot B}\) is equivalent to which of the following?

第 5 题
1

Consider a 3-input logic system where the output \(Q\) is defined as \(Q = (A + B) \cdot \overline{C}\).
Which set of inputs will result in \(Q = 1\)?

第 6 题
2

State the output of a NOT logic gate when its input is 1.

先自己写一遍答案,再对照解题步骤。

第 7 题
3

Using De Morgan's theorem, simplify the Boolean expression \( \text{NOT } (A \text{ AND } B) \) into an expression using OR and NOT operators.

先自己写一遍答案,再对照解题步骤。

第 8 题
2

A logic circuit is represented by the Boolean statement \( P = \text{NOT } (A \text{ OR } B) \). Identify which single logic gate is equivalent to this statement.

先自己写一遍答案,再对照解题步骤。

第 9 题
4

State the output of an AND logic gate when one input is 1 and the other input is 0.

先自己写一遍答案,再对照解题步骤。

第 10 题
4

Consider the Boolean expression \(X = \overline{\overline{A} + \overline{B}} \cdot (\overline{A + B})\).


(a) Apply De Morgan\'s theorem to simplify the sub-expression \(\overline{\overline{A} + \overline{B}}\).
(b) Determine the fully simplified Boolean expression for \(X\).

先自己写一遍答案,再对照解题步骤。

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