What is the amount, in moles, of \(\text{CaCO}_3\) in a \(10.0\text{ g}\) sample?
(Relative atomic masses: \(\text{Ca} = 40.0, \text{C} = 12.0, \text{O} = 16.0\))
IB Diploma Programme (DP) - SL & HL · Chemistry
結構1.4—以質量計數粒子:莫耳:练习题
4 道选择题即时批改,另有 2 道文字题附完整解题步骤,全部围绕「結構1.4—以質量計數粒子:莫耳」。
A sample of an unknown gas occupies a volume of \(4.48 \text{ L}\) at Standard Temperature and Pressure (STP). If the mass of this sample is \(8.0 \text{ g}\), what is the molar mass of the gas?
(Assume the molar volume of an ideal gas at STP is \(22.4 \text{ L mol}^{-1}\))
A sample of an unknown hydrocarbon contains 85.6% carbon and 14.4% hydrogen by mass. If the molar mass of the hydrocarbon is approximately 56.1 g/mol, what is its molecular formula?
(Molar masses: C = 12.01 g/mol, H = 1.01 g/mol)
How many oxygen atoms are present in 147 g of sulfuric acid ($$\text{H}_2\text{SO}_4$$)?
(Molar masses: H = 1.01 g/mol, S = 32.07 g/mol, O = 16.00 g/mol; Avogadro's constant = $$6.022 \times 10^{23} \text{ mol}^{-1}$$)
a) Calculate the number of moles in $$80.1 \text{ g}$$ of calcium carbonate ($$CaCO_3$$).
b) How many oxygen atoms are present in this sample?
(Relative atomic masses: C = 12.01, O = 16.00, Ca = 40.08; Avogadro's constant = $$6.022 \times 10^{23} \text{ mol}^{-1}$$)
先自己写一遍答案,再对照解题步骤。
A compound is found to contain 40.0% carbon, 6.7% hydrogen, and 53.3% oxygen by mass. The molar mass of the compound is approximately $$180.0 \text{ g mol}^{-1}$$.
a) Determine the empirical formula of the compound.
b) Determine the molecular formula of the compound.
(Relative atomic masses: C = 12.01, H = 1.01, O = 16.00)
先自己写一遍答案,再对照解题步骤。
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