SAT (Scholastic Assessment Test) · Math

Equivalent expressions:练习题

5 道选择题即时批改,另有 3 道文字题附完整解题步骤,全部围绕「Equivalent expressions」。

8 道题目16 免费,无需注册
第 1 题
1

Which of the following is equivalent to the expression \( (4x^2 + 7x - 5) - (2x^2 - 3x + 8) \)?

第 2 题
1

Which of the following is equivalent to the expression \( \frac{x^2 - 9}{x + 3} \) for all \( x \neq -3 \)?

第 3 题
1

The expression \( \frac{2x + 5}{x - 3} \) can be rewritten in the equivalent form \( a + \frac{b}{x - 3} \), where \( a \) and \( b \) are constants. What is the value of \( a + b \)?

第 4 题
1

Which of the following is equivalent to the expression \( 3(x^2 - 2x) - 2(x^2 - 5) \)?

第 5 题
1

Which of the following is equivalent to \( \frac{2}{x+3} + \frac{3}{x-1} \) for all \( x \neq -3 \) and \( x \neq 1 \)?

第 6 题
2

The expression \( (3x + 4)^2 - (3x - 4)^2 \) is equivalent to \( ax \) for all values of \( x \). What is the value of the constant \( a \)?

先自己写一遍答案,再对照解题步骤。

第 7 题
5

The expression \( (ax^2 + 10)(3x - 4) - 5x^2 \) is equivalent to \( 12x^3 - 21x^2 + 30x - 40 \), where \( a \) is a constant. What is the value of \( a \)?

先自己写一遍答案,再对照解题步骤。

第 8 题
4

Consider the algebraic expression \( P = \frac{x^2 - 16}{x - 4} + 2(x + 3) - (x - 1) \), where \( x \neq 4 \).
a) Simplify the rational term \( \frac{x^2 - 16}{x - 4} \) by factoring the numerator.
b) Expand and distribute the terms in \( 2(x + 3) \) and \( -(x - 1) \).
c) Combine all terms to write the expression in the simplified form \( mx + b \).
d) What is the value of the expression when \( x = 5 \)?

先自己写一遍答案,再对照解题步骤。

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