Cambridge IGCSE · thinka 原創模擬試題

2024 Cambridge IGCSE Chemistry (0620) 模擬試題連答案詳解

Thinka Nov 2024 (V1) Cambridge IGCSE-Style Mock — Chemistry (0620)

160 180 分鐘2024
An original Thinka practice paper modelled on the structure and difficulty of the Nov 2024 (V1) Cambridge IGCSE Chemistry (0620) paper. Not affiliated with or reproduced from Cambridge.

卷二 (選擇題 Extended)

Answer all 40 multiple-choice questions on the answer sheet. Each question has four options.
40 題目 · 40
題目 1 · 選擇題
1
A substance has a melting point of \(-183^\circ\text{C}\) and a boiling point of \(-161^\circ\text{C}\). What is its physical state at \(-170^\circ\text{C}\) and at \(25^\circ\text{C}\)?
  1. A.liquid at \(-170^\circ\text{C}\), gas at \(25^\circ\text{C}\)
  2. B.solid at \(-170^\circ\text{C}\), liquid at \(25^\circ\text{C}\)
  3. C.liquid at \(-170^\circ\text{C}\), liquid at \(25^\circ\text{C}\)
  4. D.solid at \(-170^\circ\text{C}\), gas at \(25^\circ\text{C}\)
查看答案詳解

解題

The temperature of \(-170^\circ\text{C}\) lies between the melting point (\(-183^\circ\text{C}\)) and the boiling point (\(-161^\circ\text{C}\)), meaning the substance is a liquid. At \(25^\circ\text{C}\), the temperature is well above the boiling point, so the substance is a gas.

評分準則

Award 1 mark for selecting option A. There are no partial marks.
題目 2 · 選擇題
1
An atom of phosphorus is represented as \(^{31}_{15}\text{P}\). How many nucleons and how many neutrons does this atom contain?
  1. A.15 nucleons and 16 neutrons
  2. B.31 nucleons and 16 neutrons
  3. C.31 nucleons and 15 neutrons
  4. D.15 nucleons and 31 neutrons
查看答案詳解

解題

The nucleon number (mass number) is the superscript, which is 31. The atomic number (protons) is the subscript, which is 15. The number of neutrons is the nucleon number minus the atomic number: \(31 - 15 = 16\).

評分準則

Award 1 mark for selecting option B. There are no partial marks.
題目 3 · 選擇題
1
A student wants to obtain pure liquid water from an aqueous solution of copper(II) sulfate. Which separation method should be used?
  1. A.crystallization
  2. B.simple distillation
  3. C.filtration
  4. D.paper chromatography
查看答案詳解

解題

Simple distillation is used to separate a volatile solvent (water) from a non-volatile solute (copper(II) sulfate). The water evaporates and condenses to be collected as pure distillate, while the salt remains in the distillation flask.

評分準則

Award 1 mark for selecting option B. There are no partial marks.
題目 4 · 選擇題
1
Which chemical process is endothermic?
  1. A.the combustion of methane
  2. B.the reaction of sodium with water
  3. C.the thermal decomposition of calcium carbonate
  4. D.the neutralization of hydrochloric acid with sodium hydroxide
查看答案詳解

解題

Thermal decomposition requires a continuous supply of thermal energy to break chemical bonds, making it an endothermic reaction. Combustion, neutralization, and the reaction of reactive metals with water are all exothermic.

評分準則

Award 1 mark for selecting option C. There are no partial marks.
題目 5 · 選擇題
1
Dilute hydrochloric acid is added to solid sodium carbonate. Which products are formed in this reaction?
  1. A.sodium chloride and hydrogen gas only
  2. B.sodium chloride, carbon dioxide and water
  3. C.sodium hydroxide, carbon dioxide and water
  4. D.sodium chloride and water only
查看答案詳解

解題

The reaction between an acid and a metal carbonate produces a salt, carbon dioxide gas, and water. Here, \(2\text{HCl} + \text{Na}_2\text{CO}_3 \rightarrow 2\text{NaCl} + \text{CO}_2 + \text{H}_2\text{O}\).

評分準則

Award 1 mark for selecting option B. There are no partial marks.
題目 6 · 選擇題
1
Which row correctly describes the trends in colour and physical state of the Group VII elements as the group is descended from chlorine to iodine?
  1. A.becomes lighter in colour, changes from gas to solid
  2. B.becomes darker in colour, changes from solid to gas
  3. C.becomes lighter in colour, changes from solid to gas
  4. D.becomes darker in colour, changes from gas to solid
查看答案詳解

解題

As you descend Group VII: chlorine is a pale green gas, bromine is a red-brown liquid, and iodine is a grey-black solid. Thus, the colours become darker, and the physical state transitions from gas to solid.

評分準則

Award 1 mark for selecting option D. There are no partial marks.
題目 7 · 選擇題
1
Which atmospheric pollutant is primarily responsible for the formation of acid rain?
  1. A.carbon monoxide
  2. B.sulfur dioxide
  3. C.methane
  4. D.argon
查看答案詳解

解題

Sulfur dioxide is released by burning fossil fuels that contain sulfur impurities. It dissolves in rainwater to form sulfurous/sulfuric acid, which is the primary component of acid rain.

評分準則

Award 1 mark for selecting option B. There are no partial marks.
題目 8 · 選擇題
1
Which statement correctly describes a homologous series?
  1. A.a group of compounds with different general formulae and different functional groups
  2. B.a group of compounds with the same general formula and similar chemical properties
  3. C.a series of elements located in the same period of the Periodic Table
  4. D.a mixture of hydrocarbons with different boiling points separated from crude oil
查看答案詳解

解題

A homologous series is a family of organic compounds that share the same general formula, have similar chemical properties, show a gradual trend in physical properties, and differ by a \(-\text{CH}_2-\right) unit.

評分準則

Award 1 mark for selecting option B. There are no partial marks.
題目 9 · 選擇題
1
The table shows the melting and boiling points of four substances.

Which substance is a liquid at \(50^\circ\text{C}\)?

| substance | melting point / \(^\circ\text{C}\) | boiling point / \(^\circ\text{C}\) |
| :---: | :---: | :---: |
| A | -110 | -15 |
| B | -10 | 80 |
| C | 60 | 250 |
| D | 120 | 330 |
  1. A.Substance A
  2. B.Substance B
  3. C.Substance C
  4. D.Substance D
查看答案詳解

解題

A substance is a liquid at a temperature that is above its melting point but below its boiling point.
- For substance A: \(50^\circ\text{C}\) is above its boiling point (\(-15^\circ\text{C}\)), so it is a gas.
- For substance B: \(50^\circ\text{C}\) lies between its melting point (\(-10^\circ\text{C}\)) and boiling point (\(80^\circ\text{C}\)), so it is a liquid.
- For substance C: \(50^\circ\text{C}\) is below its melting point (\(60^\circ\text{C}\)), so it is a solid.
- For substance D: \(50^\circ\text{C}\) is below its melting point (\(120^\circ\text{C}\)), so it is a solid.

評分準則

1 mark for correct identification of the state of matter at \(50^\circ\text{C}\) using the melting and boiling points.
題目 10 · 選擇題
1
An atom contains 17 protons, 18 neutrons and 17 electrons.

What is the nucleon number of this atom?
  1. A.17
  2. B.18
  3. C.34
  4. D.35
查看答案詳解

解題

The nucleon number (or mass number) is the total number of protons and neutrons in the nucleus of an atom.

$$\text{Nucleon number} = \text{number of protons} + \text{number of neutrons} = 17 + 18 = 35$$

評分準則

1 mark for calculating the nucleon number as the sum of protons and neutrons.
題目 11 · 選擇題
1
Magnesium reacts with oxygen to form magnesium oxide, which is an ionic compound.

What happens to the magnesium atoms during this reaction?
  1. A.They gain two electrons to form anions.
  2. B.They lose two electrons to form anions.
  3. C.They gain two electrons to form cations.
  4. D.They lose two electrons to form cations.
查看答案詳解

解題

Magnesium is a metal in Group II of the Periodic Table. In chemical reactions, magnesium atoms lose their two outer-shell electrons to form positively charged ions (cations) with a \(2+\) charge: \(Mg \rightarrow Mg^{2+} + 2e^-\).

評分準則

1 mark for stating that magnesium atoms lose electrons to form cations.
題目 12 · 選擇題
1
Molten lead(II) bromide is electrolysed using carbon electrodes.

Which row identifies the products formed at each electrode?

| | product at the negative electrode (cathode) | product at the positive electrode (anode) |
| :---: | :---: | :---: |
| A | bromine | lead |
| B | lead | bromine |
| C | hydrogen | oxygen |
| D | lead | oxygen |
  1. A.Row A
  2. B.Row B
  3. C.Row C
  4. D.Row D
查看答案詳解

解題

During the electrolysis of molten lead(II) bromide, \(PbBr_2(l)\):
- The negative electrode (cathode) attracts positive lead ions (\(Pb^{2+}\)), which gain electrons to form lead metal (\(Pb\)).
- The positive electrode (anode) attracts negative bromide ions (\(Br^-\)), which lose electrons to form bromine gas (\(Br_2\)).

評分準則

1 mark for correctly identifying the cathode product as lead and the anode product as bromine.
題目 13 · 選擇題
1
Which process is an exothermic reaction?
  1. A.the thermal decomposition of calcium carbonate
  2. B.the combustion of methane
  3. C.the reaction of photosynthesis
  4. D.the thermal decomposition of copper(II) carbonate
查看答案詳解

解題

An exothermic reaction is one that releases thermal energy to its surroundings. Combustion reactions (such as the combustion of methane or natural gas) are always exothermic. In contrast, thermal decomposition and photosynthesis are endothermic processes.

評分準則

1 mark for selecting the correct exothermic process.
題目 14 · 選擇題
1
An aqueous solution of substance Y has a pH of 3.

What are the colours of methyl orange and thymolphthalein indicators when added separately to this solution?

| | colour of methyl orange | colour of thymolphthalein |
| :---: | :---: | :---: |
| A | red | colourless |
| B | red | blue |
| C | yellow | colourless |
| D | yellow | blue |
  1. A.Row A
  2. B.Row B
  3. C.Row C
  4. D.Row D
查看答案詳解

解題

A solution with a pH of 3 is acidic.
- Methyl orange turns red in acidic solutions (and yellow in alkaline solutions).
- Thymolphthalein is colourless in acidic solutions (and turns blue in alkaline solutions, above pH 9.3).

評分準則

1 mark for correctly matching indicator colours in an acidic environment (pH 3).
題目 15 · 選擇題
1
Potassium is a Group I element in the Periodic Table.

Which statements about potassium are correct?

1 It is a soft metal with a low density.
2 It reacts violently with cold water.
3 It forms an alkaline solution when it reacts with water.
4 It is stored under oil to prevent reaction with air.
  1. A.1, 2 and 3 only
  2. B.1 and 4 only
  3. C.1, 2, 3 and 4
  4. D.2 and 3 only
查看答案詳解

解題

Group I alkali metals, including potassium, are soft and have low densities (statement 1 is correct). They react vigorously/violently with cold water to form alkaline metal hydroxide solutions and hydrogen gas (statements 2 and 3 are correct). Because they are highly reactive with oxygen and moisture in the air, they must be stored under oil (statement 4 is correct).

評分準則

1 mark for identifying that statements 1, 2, 3 and 4 are correct.
題目 16 · 選擇題
1
Fermentation is used to manufacture ethanol from glucose.

Which row shows the correct conditions required for fermentation?

| | temperature | catalyst | oxygen |
| :---: | :---: | :---: | :---: |
| A | \(35^\circ\text{C}\) | yeast | absent |
| B | \(35^\circ\text{C}\) | yeast | present |
| C | \(70^\circ\text{C}\) | nickel | absent |
| D | \(70^\circ\text{C}\) | nickel | present |
  1. A.Row A
  2. B.Row B
  3. C.Row C
  4. D.Row D
查看答案詳解

解題

The correct conditions for the fermentation of glucose to produce ethanol are:
- A temperature of around \(30-40^\circ\text{C}\) (e.g. \(35^\circ\text{C}\)) to allow enzymes to work optimally without denaturing.
- Yeast, which contains the biological enzymes needed to catalyse the reaction.
- The absence of oxygen (anaerobic conditions) to ensure the yeast ferments glucose into ethanol rather than respiring aerobically, and to prevent the ethanol from being oxidised to ethanoic acid.

評分準則

1 mark for identifying the correct temperature, catalyst, and oxygen conditions for yeast fermentation.
題目 17 · 選擇題
1
The table shows the melting and boiling points of four substances, W, X, Y and Z.

Substance | Melting point / °C | Boiling point / °C
--- | --- | ---
W | -114 | 78
X | -182 | -161
Y | 0 | 100
Z | 801 | 1413

Which substance is a liquid at -10 °C?
  1. A.W
  2. B.X
  3. C.Y
  4. D.Z
查看答案詳解

解題

A substance is a liquid at a temperature that lies between its melting point and boiling point. For -10 °C:
- W: -114 °C < -10 °C < 78 °C (liquid)
- X: -10 °C > -161 °C (gas)
- Y: -10 °C < 0 °C (solid)
- Z: -10 °C < 801 °C (solid)

評分準則

A is the correct answer. 1 mark is awarded for the correct option.
題目 18 · 選擇題
1
Which statement about isotopes of the same element is correct?
  1. A.They have different numbers of electrons.
  2. B.They have different numbers of protons.
  3. C.They have the same number of protons but different numbers of neutrons.
  4. D.They have the same number of neutrons but different numbers of protons.
查看答案詳解

解題

Isotopes are defined as atoms of the same element (which means they have the identical number of protons and electrons) with different numbers of neutrons.

評分準則

C is the correct answer. 1 mark is awarded for the correct option.
題目 19 · 選擇題
1
An atom of element X is in Group VI of the Periodic Table. What happens when X forms an ion?
  1. A.It gains two electrons to form an anion with a 2– charge.
  2. B.It loses two electrons to form a cation with a 2+ charge.
  3. C.It gains six electrons to form an anion with a 6– charge.
  4. D.It loses six electrons to form a cation with a 6+ charge.
查看答案詳解

解題

Group VI elements contain 6 electrons in their outer shell. To achieve a stable octet (8 outer electrons), they gain 2 electrons, which results in the formation of a negatively charged ion (anion) with a 2– charge.

評分準則

A is the correct answer. 1 mark is awarded for the correct option.
題目 20 · 選擇題
1
During the electrolysis of molten lead(II) bromide using inert electrodes, what is produced at each electrode?
  1. A.bromine at the positive electrode and lead at the negative electrode
  2. B.lead at the positive electrode and bromine at the negative electrode
  3. C.bromine at the positive electrode and hydrogen at the negative electrode
  4. D.oxygen at the positive electrode and lead at the negative electrode
查看答案詳解

解題

During the electrolysis of molten lead(II) bromide (PbBr2):
- Negative bromide ions (Br-) migrate to the positive anode, where they lose electrons to form bromine gas (Br2).
- Positive lead(II) ions (Pb2+) migrate to the negative cathode, where they gain electrons to form lead metal (Pb).

評分準則

A is the correct answer. 1 mark is awarded for the correct option.
題目 21 · 選擇題
1
A student adds magnesium ribbon to dilute hydrochloric acid. The temperature of the mixture increases during the reaction.

Which row describes the type of reaction and the energy transfer?
  1. A.Type of reaction: endothermic; Energy transfer: energy is absorbed from the surroundings
  2. B.Type of reaction: endothermic; Energy transfer: energy is released to the surroundings
  3. C.Type of reaction: exothermic; Energy transfer: energy is absorbed from the surroundings
  4. D.Type of reaction: exothermic; Energy transfer: energy is released to the surroundings
查看答案詳解

解題

An increase in the temperature of the reaction mixture shows that thermal energy is released from the chemical system to the surroundings. This describes an exothermic reaction.

評分準則

D is the correct answer. 1 mark is awarded for the correct option.
題目 22 · 選擇題
1
A student investigates the rate of reaction between calcium carbonate and dilute hydrochloric acid.

Which change decreases the rate of this reaction?
  1. A.adding a catalyst to the mixture
  2. B.decreasing the concentration of the acid
  3. C.increasing the temperature of the acid
  4. D.using powdered calcium carbonate instead of large lumps
查看答案詳解

解題

Decreasing the concentration of dilute hydrochloric acid decreases the concentration of reactant particles per unit volume, which reduces the frequency of successful collisions between particles and thus decreases the rate of the reaction.

評分準則

B is the correct answer. 1 mark is awarded for the correct option.
題目 23 · 選擇題
1
Three unlabelled bottles contain solutions with the following pH values:
- Solution 1: pH 2
- Solution 2: pH 7
- Solution 3: pH 11

What are the colours of these solutions when a few drops of universal indicator are added?
  1. A.Solution 1: red; Solution 2: green; Solution 3: purple
  2. B.Solution 1: red; Solution 2: purple; Solution 3: green
  3. C.Solution 1: blue; Solution 2: green; Solution 3: red
  4. D.Solution 1: purple; Solution 2: green; Solution 3: red
查看答案詳解

解題

Universal indicator turns:
- Red in strongly acidic solutions (pH 2)
- Green in neutral solutions (pH 7)
- Purple/violet in strongly alkaline solutions (pH 11)

評分準則

A is the correct answer. 1 mark is awarded for the correct option.
題目 24 · 選擇題
1
Which statement about ethanol is correct?
  1. A.It is manufactured by the reaction of ethene with hydrogen gas.
  2. B.It can be manufactured by the fermentation of glucose using yeast at 37 °C.
  3. C.It belongs to the homologous series of alkanes.
  4. D.It is a hydrocarbon containing only carbon and hydrogen atoms.
查看答案詳解

解題

Ethanol is commonly manufactured by the anaerobic fermentation of glucose (using enzymes in yeast) at a moderate temperature (around 37 °C).

評分準則

B is the correct answer. 1 mark is awarded for the correct option.
題目 25 · 選擇題
1
The table shows the melting and boiling points of four elements, W, X, Y and Z.

| Element | Melting point / °C | Boiling point / °C |
|---|---|---|
| W | -189 | -186 |
| X | -39 | 357 |
| Y | 30 | 2403 |
| Z | 660 | 2519 |

Which element is a liquid at 25 °C?
  1. A.W
  2. B.X
  3. C.Y
  4. D.Z
查看答案詳解

解題

At 25 °C, an element is a liquid if 25 °C is between its melting point and boiling point.
- For W: 25 °C is above its boiling point (-186 °C), so it is a gas.
- For X: 25 °C is between its melting point (-39 °C) and boiling point (357 °C), so it is a liquid.
- For Y: 25 °C is below its melting point (30 °C), so it is a solid.
- For Z: 25 °C is below its melting point (660 °C), so it is a solid.

評分準則

Award 1 mark for the correct answer B.
題目 26 · 選擇題
1
An atom of an isotope of potassium has a nucleon number of 39. Referring to the Periodic Table, how many protons, neutrons and electrons are in this neutral atom?
  1. A.19 protons, 19 neutrons, 20 electrons
  2. B.19 protons, 20 neutrons, 19 electrons
  3. C.20 protons, 19 neutrons, 20 electrons
  4. D.20 protons, 20 neutrons, 19 electrons
查看答案詳解

解題

From the Periodic Table, the atomic number of potassium (K) is 19.
- Number of protons = atomic number = 19.
- Since it is a neutral atom, number of electrons = number of protons = 19.
- Number of neutrons = nucleon number - proton number = 39 - 19 = 20.

評分準則

Award 1 mark for the correct option B.
題目 27 · 選擇題
1
Magnesium reacts with fluorine to form the ionic compound magnesium fluoride, \(MgF_2\).

What happens to the magnesium atoms in this reaction?
  1. A.Each magnesium atom loses two electrons to form a positive ion.
  2. B.Each magnesium atom gains two electrons to form a negative ion.
  3. C.Each magnesium atom shares two electrons with fluorine atoms.
  4. D.Each magnesium atom loses one electron to form a positive ion.
查看答案詳解

解題

Magnesium is in Group II and is a metal. During the formation of ionic bonds, metal atoms lose outer-shell electrons to form positive ions (cations). Each magnesium atom loses two outer electrons to form a stable \(Mg^{2+}\) ion.

評分準則

Award 1 mark for the correct option A.
題目 28 · 選擇題
1
Molten lead(II) bromide is electrolysed using inert carbon electrodes.

Which row correctly identifies the product formed at each electrode?
  1. A.cathode: bromine; anode: lead
  2. B.cathode: lead; anode: bromine
  3. C.cathode: hydrogen; anode: oxygen
  4. D.cathode: lead; anode: oxygen
查看答案詳解

解題

In the electrolysis of molten lead(II) bromide:
- Positively charged lead ions (\(Pb^{2+}\)) travel to the negative electrode (cathode) and gain electrons to form lead metal.
- Negatively charged bromide ions (\(Br^-\)) travel to the positive electrode (anode) and lose electrons to form bromine gas.

評分準則

Award 1 mark for the correct option B.
題目 29 · 選擇題
1
Which statement about an exothermic reaction is correct?
  1. A.The temperature of the surroundings decreases.
  2. B.The chemical energy of the products is higher than the chemical energy of the reactants.
  3. C.Thermal energy is absorbed from the surroundings.
  4. D.The chemical energy of the reactants is higher than the chemical energy of the products.
查看答案詳解

解題

In an exothermic reaction, heat energy is given out to the surroundings, meaning the temperature of the surroundings increases. Because energy is released, the chemical energy of the reactants is higher than that of the products.

評分準則

Award 1 mark for the correct option D.
題目 30 · 選擇題
1
Identical masses of calcium carbonate are reacted separately with excess dilute hydrochloric acid under different conditions.

Which reaction has the highest initial rate of reaction?
  1. A.powdered calcium carbonate at 20 °C using 0.5 mol/dm³ acid
  2. B.powdered calcium carbonate at 40 °C using 1.0 mol/dm³ acid
  3. C.large lumps of calcium carbonate at 20 °C using 1.0 mol/dm³ acid
  4. D.large lumps of calcium carbonate at 40 °C using 0.5 mol/dm³ acid
查看答案詳解

解題

The rate of reaction increases when:
- Surface area of the solid reactant increases (powder has a larger surface area than large lumps).
- Temperature increases (40 °C is higher than 20 °C).
- Concentration of the acid increases (1.0 mol/dm³ is higher than 0.5 mol/dm³).

Option B combines all these factors for the fastest rate.

評分準則

Award 1 mark for the correct option B.
題目 31 · 選擇題
1
A solution has a pH of 12. Which statement describes this solution?
  1. A.It is strongly acidic and turns methyl orange red.
  2. B.It is weakly acidic and turns blue litmus paper red.
  3. C.It is strongly alkaline and turns universal indicator purple.
  4. D.It is weakly alkaline and turns thymolphthalein colourless.
查看答案詳解

解題

A pH of 12 indicates a strongly alkaline solution. Strong alkalis turn universal indicator purple (or dark blue).

評分準則

Award 1 mark for the correct option C.
題目 32 · 選擇題
1
Ethanol is manufactured by the fermentation of glucose.

Which set of conditions is correct for this process?
  1. A.yeast catalyst, 37 °C, absence of oxygen
  2. B.yeast catalyst, 100 °C, presence of oxygen
  3. C.no catalyst, 37 °C, presence of oxygen
  4. D.phosphoric acid catalyst, 300 °C, absence of oxygen
查看答案詳解

解題

Fermentation of glucose requires:
- An enzyme catalyst provided by yeast.
- An optimum temperature around 25–40 °C (37 °C is ideal as enzymes do not denature).
- Anaerobic conditions (absence of oxygen) to prevent the ethanol from oxidizing to ethanoic acid.

評分準則

Award 1 mark for the correct option A.
題目 33 · 選擇題
1
An atom of phosphorus has a nucleon number of 31 and a proton number of 15. How many neutrons and electrons does this neutral atom contain?
  1. A.15 neutrons, 16 electrons
  2. B.16 neutrons, 15 electrons
  3. C.16 neutrons, 16 electrons
  4. D.31 neutrons, 15 electrons
查看答案詳解

解題

In a neutral atom, the number of electrons equals the proton number, which is 15. The number of neutrons is calculated by subtracting the proton number from the nucleon number: \(31 - 15 = 16\).

評分準則

Award 1 mark for the correct option (B).
Reject all other options.
題目 34 · 選擇題
1
When liquid water turns into steam, what happens to the arrangement and movement of the particles?
  1. A.The particles become regularly arranged and vibrate about fixed positions.
  2. B.The particles become randomly arranged and can only slide over each other.
  3. C.The particles become randomly arranged and move freely in all directions.
  4. D.The particles become regularly arranged and move freely in all directions.
查看答案詳解

解題

When a liquid turns into a gas, the particles become randomly arranged, with large spaces between them, and they are able to move freely and rapidly in all directions.

評分準則

Award 1 mark for the correct option (C).
Reject all other options.
題目 35 · 選擇題
1
Which row correctly describes an exothermic chemical reaction?
  1. A.Heat energy is taken in from the surroundings, and the temperature of the surroundings decreases.
  2. B.Heat energy is taken in from the surroundings, and the temperature of the surroundings increases.
  3. C.Heat energy is released to the surroundings, and the temperature of the surroundings decreases.
  4. D.Heat energy is released to the surroundings, and the temperature of the surroundings increases.
查看答案詳解

解題

An exothermic reaction releases thermal (heat) energy to the surroundings, which causes the temperature of the surroundings to increase.

評分準則

Award 1 mark for the correct option (D).
Reject all other options.
題目 36 · 選擇題
1
A mixture contains insoluble barium sulfate, soluble sodium chloride, and water. Which sequence of steps is used to obtain a dry sample of barium sulfate and a separate solution of sodium chloride?
  1. A.crystallisation, then filtration
  2. B.evaporation, then distillation
  3. C.filtration, then washing and drying the residue
  4. D.fractional distillation, then filtration
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解題

First, the mixture is filtered. The insoluble barium sulfate is left as the residue on the filter paper, which is then washed and dried. The soluble sodium chloride passes through the filter paper as the filtrate.

評分準則

Award 1 mark for the correct option (C).
Reject all other options.
題目 37 · 選擇題
1
Metals P, Q, and R are reacted with dilute hydrochloric acid.
- Metal P reacts with dilute hydrochloric acid to produce bubbles of hydrogen.
- Metal Q does not react with dilute hydrochloric acid.
- Metal R reacts more vigorously with dilute hydrochloric acid than metal P.
What is the order of reactivity of the metals, from most reactive to least reactive?
  1. A.P, R, Q
  2. B.Q, P, R
  3. C.R, P, Q
  4. D.R, Q, P
查看答案詳解

解題

Metal R is the most reactive because it reacts more vigorously with the acid than metal P. Metal Q is the least reactive because it does not react at all with dilute hydrochloric acid. Thus, the order is R, P, Q.

評分準則

Award 1 mark for the correct option (C).
Reject all other options.
題目 38 · 選擇題
1
Which statement describes the trends in the physical state and colour of the halogens as Group VII is descended?
  1. A.The physical state changes from gas to solid, and the colour becomes darker.
  2. B.The physical state changes from gas to solid, and the colour becomes lighter.
  3. C.The physical state changes from solid to gas, and the colour becomes darker.
  4. D.The physical state changes from solid to gas, and the colour becomes lighter.
查看答案詳解

解題

As Group VII is descended, the physical state changes from gas (chlorine) to liquid (bromine) to solid (iodine), and the colours of the elements become progressively darker (green-yellow to red-brown to grey-black).

評分準則

Award 1 mark for the correct option (A).
Reject all other options.
題目 39 · 選擇題
1
Which pollutant gas is formed by the incomplete combustion of carbon-containing fuels?
  1. A.carbon dioxide
  2. B.carbon monoxide
  3. C.methane
  4. D.sulfur dioxide
查看答案詳解

解題

Carbon monoxide is produced by the incomplete combustion of carbon-containing fuels due to a limited supply of oxygen. Complete combustion produces carbon dioxide.

評分準則

Award 1 mark for the correct option (B).
Reject all other options.
題目 40 · 選擇題
1
What is the general formula of alkanes, and what are the products when an alkane undergoes complete combustion?
  1. A.\(C_nH_{2n}\) and the products are carbon monoxide and water
  2. B.\(C_nH_{2n}\) and the products are carbon dioxide and water
  3. C.\(C_nH_{2n+2}\) and the products are carbon monoxide and water
  4. D.\(C_nH_{2n+2}\) and the products are carbon dioxide and water
查看答案詳解

解題

Alkanes are a homologous series of hydrocarbons with the general formula \(C_nH_{2n+2}\). Complete combustion of hydrocarbons produces carbon dioxide and water.

評分準則

Award 1 mark for the correct option (D).
Reject all other options.

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Paper 4 (Theory Extended)

Answer all six structured extended theory questions in the spaces provided. Show all calculation working.
33 題目 · 33
題目 1 · 選擇題
1
Which gas has the highest rate of diffusion at room temperature and pressure?
  1. A.argon
  2. B.carbon monoxide
  3. C.fluorine
  4. D.methane
查看答案詳解

解題

The rate of diffusion of a gas is inversely proportional to the square root of its relative molecular mass (\(M_r\)). Therefore, the gas with the lowest \(M_r\) will diffuse the fastest. Computing the \(M_r\) values: argon (\(\text{Ar}\)) = 40; carbon monoxide (\(\text{CO}\)) = 12 + 16 = 28; fluorine (\(\text{F}_2\)) = 19 \times 2 = 38; methane (\(\text{CH}_4\)) = 12 + 4 = 16. Methane has the lowest \(M_r\) and thus the highest rate of diffusion.

評分準則

1 mark for the correct option D.
題目 2 · 選擇題
1
Which statement about the giant covalent structures of diamond and graphite is correct?
  1. A.In diamond, each carbon atom is covalently bonded to three other carbon atoms.
  2. B.Graphite conducts electricity because it has mobile ions between its layers.
  3. C.Both diamond and graphite have high melting points because of strong covalent bonds throughout their structures.
  4. D.Graphite is used as a lubricant because its covalent bonds are easily broken when a force is applied.
查看答案詳解

解題

Both diamond and graphite are giant covalent macromolecules with extremely high melting points due to the large amount of energy required to break the strong covalent bonds throughout their structures. Statement A is incorrect because carbon atoms in diamond form four covalent bonds. Statement B is incorrect because graphite's electrical conductivity is due to delocalised, mobile electrons, not ions. Statement D is incorrect because graphite acts as a lubricant because of weak intermolecular forces between the layers, allowing them to slide over each other without breaking the covalent bonds within the layers.

評分準則

1 mark for the correct option C.
題目 3 · 選擇題
1
Concentrated aqueous sodium chloride is electrolysed using inert electrodes. Which row correctly identifies the product at each electrode and the effect on the pH of the electrolyte?
  1. A.Anode product: chlorine; Cathode product: hydrogen; pH: decreases
  2. B.Anode product: chlorine; Cathode product: hydrogen; pH: increases
  3. C.Anode product: oxygen; Cathode product: sodium; pH: increases
  4. D.Anode product: oxygen; Cathode product: hydrogen; pH: decreases
查看答案詳解

解題

During the electrolysis of concentrated aqueous sodium chloride using inert electrodes: Chloride ions (\(\text{Cl}^-\)) are selectively discharged at the anode to produce chlorine gas. Hydrogen ions (\(\text{H}^+\)) from water are discharged at the cathode to produce hydrogen gas. As \(\text{H}^+\) and \(\text{Cl}^-\) ions are removed, the remaining \(\text{Na}^+\) and \(\text{OH}^-\) ions form a basic sodium hydroxide solution, which increases the pH.

評分準則

1 mark for the correct option B.
題目 4 · 選擇題
1
An iron pipeline is buried underground. To protect the iron from rusting, it is connected by a wire to a block of metal M. Which row correctly identifies a suitable metal M and the reason for its choice?
  1. A.Metal M: copper; Reason: copper is more reactive than iron and oxidises instead of iron
  2. B.Metal M: copper; Reason: iron is more reactive than copper and oxidises instead of copper
  3. C.Metal M: magnesium; Reason: iron is more reactive than magnesium and magnesium oxidises instead of iron
  4. D.Metal M: magnesium; Reason: magnesium is more reactive than iron and magnesium oxidises instead of iron
查看答案詳解

解題

This is a method of sacrificial protection. The sacrificial metal must be more reactive than iron so that it readily loses electrons (oxidises) in place of the iron. Magnesium is more reactive than iron, so it will oxidise preferentially to protect the iron pipeline.

評分準則

1 mark for the correct option D.
題目 5 · 選擇題
1
An organic compound X reacts with a carboxylic acid Y to form an ester with the formula \(\text{CH}_3\text{COOCH}_2\text{CH}_2\text{CH}_3\). What are the names of compound X and carboxylic acid Y?
  1. A.Compound X: ethanol; Carboxylic acid Y: propanoic acid
  2. B.Compound X: propan-1-ol; Carboxylic acid Y: ethanoic acid
  3. C.Compound X: propan-1-ol; Carboxylic acid Y: propanoic acid
  4. D.Compound X: ethanol; Carboxylic acid Y: ethanoic acid
查看答案詳解

解題

The ester propyl ethanoate (\(\text{CH}_3\text{COOCH}_2\text{CH}_2\text{CH}_3\)) is formed by the condensation reaction between propan-1-ol (alcohol, compound X) and ethanoic acid (carboxylic acid, Y).

評分準則

1 mark for the correct option B.
題目 6 · 選擇題
1
What is the minimum volume of oxygen gas, measured at r.t.p., required for the complete combustion of \(0.2\text{ mol}\) of propane gas, \(\text{C}_3\text{H}_8\)? (The volume of one mole of any gas is \(24\text{ dm}^3\) at r.t.p.)
  1. A.\(4.8\text{ dm}^3\)
  2. B.\(12.0\text{ dm}^3\)
  3. C.\(24.0\text{ dm}^3\)
  4. D.\(120.0\text{ dm}^3\)
查看答案詳解

解題

The balanced equation for the complete combustion of propane is: \(\text{C}_3\text{H}_8\text{(g)} + 5\text{O}_2\text{(g)} \rightarrow 3\text{CO}_2\text{(g)} + 4\text{H}_2\text{O}\text{(l)}\). From the stoichiometry, \(1\text{ mol}\) of \(\text{C}_3\text{H}_8\) reacts with \(5\text{ mol}\) of \(\text{O}_2\). Therefore, \(0.2\text{ mol}\) of \(\text{C}_3\text{H}_8\) requires: \(0.2 \times 5 = 1.0\text{ mol}\) of \(\text{O}_2\). At r.t.p., the volume of \(1.0\text{ mol}\) of gas is \(24.0\text{ dm}^3\).

評分準則

1 mark for the correct option C.
題目 7 · 選擇題
1
The structural formula of an addition polymer is shown: \(\text{---[CH}_2\text{---CH(CH}_3\text{)]}_n\text{---}\). Which monomer is used to make this polymer?
  1. A.ethane
  2. B.ethene
  3. C.propane
  4. D.propene
查看答案詳解

解題

The repeating unit \(\text{---CH}_2\text{---CH(CH}_3\text{)---}\) is derived from propene (\(\text{CH}_2\text{=CHCH}_3\)) through addition polymerisation where the double bond opens up to form single bonds linking the monomers.

評分準則

1 mark for the correct option D.
題目 8 · 選擇題
1
In which reaction is the underlined element oxidized?
  1. A.\(\text{Mg} + \underline{\text{Cl}_2} \rightarrow \text{MgCl}_2\)
  2. B.\(\underline{\text{Cu}^{2+}} + \text{Mg} \rightarrow \text{Cu} + \text{Mg}^{2+}\)
  3. C.\(2\underline{\text{I}^-} + \text{Cl}_2 \rightarrow \text{I}_2 + 2\text{Cl}^-\)
  4. D.\(\underline{\text{Fe}^{3+}} + \text{e}^- \rightarrow \text{Fe}^{2+}\)
查看答案詳解

解題

Oxidation is defined as an increase in oxidation number or loss of electrons. In option C, iodide ions (\(\text{I}^-\)) have an oxidation number of -1, which increases to 0 in elemental iodine (\(\text{I}_2\)), meaning iodine is oxidized. In the other options, the underlined species undergo reduction (decrease in oxidation number).

評分準則

1 mark for the correct option C.
題目 9 · multiple_choice
1
An ion of element Y has a charge of 2+ and the formula \(^{56}_{26}\text{Y}^{2+}\). How many neutrons and electrons does this ion contain?
  1. A.30 neutrons and 24 electrons
  2. B.30 neutrons and 26 electrons
  3. C.26 neutrons and 24 electrons
  4. D.26 neutrons and 28 electrons
查看答案詳解

解題

The atomic number is 26, which represents the number of protons. The mass number is 56, so the number of neutrons is mass number minus atomic number: \(56 - 26 = 30\). Since it has a 2+ charge, it has lost 2 electrons, so the number of electrons is \(26 - 2 = 24\).

評分準則

1 mark for the correct answer A.
題目 10 · multiple_choice
1
Which gas has the highest rate of diffusion at room temperature and pressure?
  1. A.carbon monoxide
  2. B.nitrogen
  3. C.neon
  4. D.fluorine
查看答案詳解

解題

The rate of diffusion of a gas is inversely proportional to the square root of its relative molecular mass (Mr). The gas with the lowest Mr will diffuse the fastest. The relative molecular masses are: CO = 28, N2 = 28, Ne = 20, F2 = 38. Neon has the lowest molecular mass and thus the highest rate of diffusion.

評分準則

1 mark for the correct answer C.
題目 11 · multiple_choice
1
Concentrated aqueous sodium chloride is electrolysed using platinum electrodes. Which row correctly identifies the product at each electrode and the change in the electrolyte?
  1. A.Anode product: chlorine; Cathode product: hydrogen; Electrolyte: becomes alkaline
  2. B.Anode product: oxygen; Cathode product: sodium; Electrolyte: becomes acidic
  3. C.Anode product: chlorine; Cathode product: sodium; Electrolyte: remains neutral
  4. D.Anode product: oxygen; Cathode product: hydrogen; Electrolyte: becomes alkaline
查看答案詳解

解題

During the electrolysis of concentrated aqueous sodium chloride, chloride ions (Cl-) are discharged at the anode to produce chlorine gas. Hydrogen ions (H+) from water are discharged at the cathode to produce hydrogen gas. This leaves sodium ions (Na+) and hydroxide ions (OH-) in the solution, making it alkaline.

評分準則

1 mark for the correct answer A.
題目 12 · multiple_choice
1
A series of experiments is set up to find the order of reactivity of four metals: cobalt, copper, magnesium, and tin. Cobalt displaces copper and tin from solutions of their salts, but does not displace magnesium. Tin displaces copper from solutions of copper salts. What is the correct order of reactivity of these metals, starting with the most reactive?
  1. A.magnesium > cobalt > tin > copper
  2. B.magnesium > cobalt > copper > tin
  3. C.cobalt > magnesium > tin > copper
  4. D.tin > copper > cobalt > magnesium
查看答案詳解

解題

Since cobalt cannot displace magnesium, magnesium is more reactive than cobalt (Mg > Co). Cobalt displaces copper and tin, so cobalt is more reactive than both of them (Co > Sn, Cu). Tin displaces copper, so tin is more reactive than copper (Sn > Cu). Combining these gives: Mg > Co > Sn > Cu.

評分準則

1 mark for the correct answer A.
題目 13 · multiple_choice
1
Ethene reacts with bromine water in an addition reaction. What is the structural formula of the product formed?
  1. A.\( \text{CH}_2\text{BrCH}_2\text{Br} \)
  2. B.\( \text{CH}_3\text{CHBr}_2 \)
  3. C.\( \text{CH}_2\text{BrCH}_3 \)
  4. D.\( \text{CHBrCHBr} \)
查看答案詳解

解題

Ethene (\( \text{CH}_2=\text{CH}_2 \)) undergoes an addition reaction with bromine (\( \text{Br}_2 \)) where the double bond opens up and one bromine atom attaches to each carbon atom, forming 1,2-dibromoethane (\( \text{CH}_2\text{BrCH}_2\text{Br} \)).

評分準則

1 mark for the correct answer A.
題目 14 · multiple_choice
1
The reaction between hydrogen and fluorine to form hydrogen fluoride is shown: \( \text{H}_2\text{(g)} + \text{F}_2\text{(g)} \rightarrow 2\text{HF(g)} \). The bond energies are: H-H = 436 kJ/mol, F-F = 158 kJ/mol, H-F = 562 kJ/mol. What is the energy change for this reaction?
  1. A.-530 kJ/mol
  2. B.+530 kJ/mol
  3. C.-1124 kJ/mol
  4. D.+1124 kJ/mol
查看答案詳解

解題

Energy required to break bonds: 1 mol of H-H bonds + 1 mol of F-F bonds = \(436 + 158 = 594\) kJ. Energy released when forming bonds: 2 mol of H-F bonds = \(2 \times 562 = 1124\) kJ. Enthalpy change = Energy in - Energy out = \(594 - 1124 = -530\) kJ/mol.

評分準則

1 mark for the correct answer A.
題目 15 · multiple_choice
1
What is the maximum volume of carbon dioxide gas, measured at r.t.p., produced when 10.0 g of calcium carbonate (\( \text{CaCO}_3 \)) is completely reacted with excess hydrochloric acid? [Relative atomic masses: Ca=40, C=12, O=16. One mole of any gas occupies 24.0 dm3 at r.t.p.]
  1. A.2.4 dm3
  2. B.4.8 dm3
  3. C.24.0 dm3
  4. D.240.0 dm3
查看答案詳解

解題

The equation is \( \text{CaCO}_3 + 2\text{HCl} \rightarrow \text{CaCl}_2 + \text{H}_2\text{O} + \text{CO}_2 \). Mr of CaCO3 = \(40 + 12 + 3(16) = 100\). Moles of CaCO3 = \(10.0 / 100 = 0.1\) mol. Since the mole ratio is 1:1, 0.1 mol of CO2 gas is produced. Volume of CO2 = \(0.1 \times 24.0 = 2.4\) dm3.

評分準則

1 mark for the correct answer A.
題目 16 · multiple_choice
1
An aqueous solution of salt X is tested. It produces a blue-green flame in a flame test. Addition of aqueous sodium hydroxide produces a light blue precipitate that is insoluble in excess. Addition of acidified barium nitrate produces a white precipitate. What is the identity of salt X?
  1. A.copper(II) sulfate
  2. B.copper(II) chloride
  3. C.iron(II) sulfate
  4. D.iron(III) chloride
查看答案詳解

解題

The blue-green flame color and light blue precipitate with NaOH confirm the presence of copper(II) ions (Cu2+). The white precipitate formed with acidified barium nitrate indicates the presence of sulfate ions (SO4 2-). Thus, salt X is copper(II) sulfate.

評分準則

1 mark for the correct answer A.
題目 17 · 選擇題
1
Equal volumes of four different gases are allowed to diffuse under identical conditions of temperature and pressure. Which gas has the highest rate of diffusion?
  1. A.carbon dioxide, \(\text{CO}_2\)
  2. B.sulfur dioxide, \(\text{SO}_2\)
  3. C.methane, \(\text{CH}_4\)
  4. D.neon, \(\text{Ne}\)
查看答案詳解

解題

The rate of diffusion of a gas is inversely proportional to the square root of its relative molecular mass (\(M_r\)). Therefore, the gas with the lowest \(M_r\) diffuses the fastest. Let us calculate the \(M_r\) values: \(M_r(\text{CO}_2) = 12 + (16 \times 2) = 44\); \(M_r(\text{SO}_2) = 32 + (16 \times 2) = 64\); \(M_r(\text{CH}_4) = 12 + (1 \times 4) = 16\); \(M_r(\text{Ne}) = 20\). Since methane has the lowest relative molecular mass, it has the highest rate of diffusion.

評分準則

1 mark for identifying methane (C) as the correct option.
題目 18 · 選擇題
1
The table shows the melting and boiling points of four substances, P, Q, R and S.

$$\begin{array}{|c|c|c|} \hline \text{Substance} & \text{Melting point } / ^\circ\text{C} & \text{Boiling point } / ^\circ\text{C} \\ \hline \text{P} & -95 & 110 \\ \hline \text{Q} & -210 & -196 \\ \hline \text{R} & 44 & 280 \\ \hline \text{S} & 114 & 184 \\ \hline \end{array}$$

Which statement is correct?
  1. A.P is a liquid at $-100\,^\circ\text{C}$.
  2. B.Q is a liquid at $-200\,^\circ\text{C}$.
  3. C.R is a solid at $50\,^\circ\text{C}$.
  4. D.S is a gas at $150\,^\circ\text{C}$.
查看答案詳解

解題

At $-200\,^\circ\text{C}$, Q is above its melting point ($-210\,^\circ\text{C}$) but below its boiling point ($-196\,^\circ\text{C}$), meaning it is in the liquid state.
- P melts at $-95\,^\circ\text{C}$, so at $-100\,^\circ\text{C}$ it is solid.
- R melts at $44\,^\circ\text{C}$, so at $50\,^\circ\text{C}$ it is liquid.
- S melts at $114\,^\circ\text{C}$ and boils at $184\,^\circ\text{C}$, so at $150\,^\circ\text{C}$ it is liquid.

評分準則

Award 1 mark for selecting the correct option B.
題目 19 · 選擇題
1
What is the total number of hydrogen atoms in $0.25\text{ mol}$ of ethanol, $\text{C}_2\text{H}_5\text{OH}$?

[Avogadro constant, $L = 6.02 \times 10^{23}\text{ /mol}$]
  1. A.$1.51 \times 10^{23}$
  2. B.$9.03 \times 10^{23}$
  3. C.$1.05 \times 10^{24}$
  4. D.$3.61 \times 10^{24}$
查看答案詳解

解題

One molecule of ethanol, $\text{C}_2\text{H}_5\text{OH}$, contains 6 hydrogen atoms.
Therefore, the number of moles of hydrogen atoms in $0.25\text{ mol}$ of ethanol is:
$$0.25\text{ mol} \times 6 = 1.5\text{ mol}$$

The total number of hydrogen atoms is:
$$1.5\text{ mol} \times 6.02 \times 10^{23}\text{ atoms/mol} = 9.03 \times 10^{23}\text{ atoms}$$

評分準則

Award 1 mark for selecting the correct option B.
題目 20 · 選擇題
1
Aqueous copper(II) sulfate is electrolysed using carbon (graphite) electrodes.

Which row correctly describes the product at each electrode and the change in the electrolyte solution?

$$\begin{array}{|c|c|c|c|} \hline & \text{Product at anode (+)} & \text{Product at cathode (-)} & \text{Change in electrolyte solution} \\ \hline \text{A} & \text{oxygen} & \text{copper} & \text{remains blue} \\ \hline \text{B} & \text{oxygen} & \text{copper} & \text{turns colourless} \\ \hline \text{C} & \text{copper} & \text{hydrogen} & \text{remains blue} \\ \hline \text{D} & \text{copper} & \text{hydrogen} & \text{turns colourless} \\ \hline \end{array}$$
  1. A.A
  2. B.B
  3. C.C
  4. D.D
查看答案詳解

解題

During the electrolysis of aqueous copper(II) sulfate with inert graphite electrodes:
- At the anode (+), hydroxide ions ($OH^-$) from water are discharged to form oxygen gas.
- At the cathode (-), copper ions ($Cu^{2+}$) are discharged in preference to hydrogen ions ($H^+$) because copper is less reactive, forming copper metal.
- Since $Cu^{2+}$ ions are removed from the solution, the blue colour of the solution gradually fades until it becomes colourless (leaving dilute sulfuric acid).

評分準則

Award 1 mark for selecting the correct option B.
題目 21 · 選擇題
1
Which method is most suitable for preparing a pure, dry sample of the insoluble salt, barium sulfate?
  1. A.Add dilute sulfuric acid to aqueous barium chloride, filter, wash the residue with distilled water, and dry.
  2. B.Add dilute sulfuric acid to solid barium carbonate, and evaporate the mixture to dryness.
  3. C.Add dilute sulfuric acid to solid barium oxide, filter the mixture, and crystallise the filtrate.
  4. D.Add dilute hydrochloric acid to aqueous barium hydroxide, then add aqueous sodium sulfate, and evaporate.
查看答案詳解

解題

Barium sulfate is an insoluble salt. Insoluble salts are prepared by precipitation from two soluble reactants (aqueous barium chloride and dilute sulfuric acid).
- Mixing them forms a precipitate of barium sulfate.
- Filtering collects the precipitate as residue.
- Washing with distilled water removes any remaining soluble impurities.
- Drying yields the pure, dry insoluble salt.

Options B and C are incorrect because the insoluble product forms a layer over the solid reactant, stopping the reaction. Option D is unnecessarily complex and does not yield a pure precipitate directly.

評分準則

Award 1 mark for selecting the correct option A.
題目 22 · 選擇題
1
Which row correctly identifies the monomers and the small molecule released during the formation of the polyester, Terylene?

$$\begin{array}{|c|c|c|} \hline & \text{Monomers} & \text{Small molecule released} \\ \hline \text{A} & \text{dicarboxylic acid + diol} & \text{water} \\ \hline \text{B} & \text{dicarboxylic acid + diamine} & \text{water} \\ \hline \text{C} & \text{dicarboxylic acid + diol} & \text{hydrogen chloride} \\ \hline \text{D} & \text{dicarboxylic acid + diamine} & \text{ammonia} \\ \hline \end{array}$$
  1. A.A
  2. B.B
  3. C.C
  4. D.D
查看答案詳解

解題

Terylene is a polyester, which is a condensation polymer formed from dicarboxylic acid and diol monomers. In the condensation reaction, ester linkages are formed with the elimination of water ($H_2O$) molecules. Therefore, row A is correct.

評分準則

Award 1 mark for selecting the correct option A.
題目 23 · 選擇題
1
A student performs chromatography on a mixture of food colorings. The solvent front travels $8.0\text{ cm}$ from the baseline, and a yellow spot travels $5.2\text{ cm}$ from the baseline.

What is the $R_f$ value of the yellow spot?
  1. A.0.65
  2. B.1.54
  3. C.0.35
  4. D.0.52
查看答案詳解

解題

The retention factor ($R_f$) is calculated using the formula:
$$R_f = \frac{\text{distance travelled by substance}}{\text{distance travelled by solvent front}}$$

Substituting the given values:
$$R_f = \frac{5.2\text{ cm}}{8.0\text{ cm}} = 0.65$$

評分準則

Award 1 mark for selecting the correct option A.
題目 24 · 選擇題
1
The table shows some properties of the Group VII elements (halogens).

$$\begin{array}{|c|c|c|} \hline \text{Element} & \text{State at r.t.p.} & \text{Colour} \\ \hline \text{chlorine} & \text{gas} & \text{pale green} \\ \hline \text{bromine} & \text{liquid} & \text{red-brown} \\ \hline \text{iodine} & \text{solid} & \text{grey-black} \\ \hline \text{astatine} & X & Y \\ \hline \end{array}$$

Which row correctly identifies $X$ and $Y$?
  1. A.$X$: liquid, $Y$: purple
  2. B.$X$: solid, $Y$: black
  3. C.$X$: solid, $Y$: red-brown
  4. D.$X$: gas, $Y$: yellow
查看答案詳解

解題

Down Group VII, the melting and boiling points increase, so the state at r.t.p. changes from gas to liquid to solid. Since iodine is a solid, astatine (below iodine) must also be a solid ($X = \text{solid}$). Additionally, the colours of the halogens become progressively darker down the group (green $\rightarrow$ red-brown $\rightarrow$ grey-black $\rightarrow$ black), so astatine is black ($Y = \text{black}$).

評分準則

Award 1 mark for selecting the correct option B.
題目 25 · 選擇題
1
Which reagent and observation can be used to distinguish between propane and propene?
  1. A.aqueous bromine; propane decolourises it, but propene does not
  2. B.aqueous bromine; propene decolourises it, but propane does not
  3. C.acidified potassium manganate(VII); propane turns it from purple to colourless, but propene does not
  4. D.acidified potassium manganate(VII); propene remains purple, but propane turns it colourless
查看答案詳解

解題

Propane is an alkane (saturated) and does not react with aqueous bromine at room temperature, so the orange-brown colour remains. Propene is an alkene (unsaturated) and undergoes an addition reaction with aqueous bromine, decolourising it from orange-brown to colourless. Therefore, option B is correct.

評分準則

Award 1 mark for selecting the correct option B.
題目 26 · 選擇題
1
An ion \(X^{2+}\) has 24 neutrons and 18 electrons. What is the nucleon number of element \(X\)?
  1. A.38
  2. B.42
  3. C.44
  4. D.46
查看答案詳解

解題

The ion has a 2+ charge and 18 electrons, which means the neutral atom has 20 protons (18 + 2 = 20). The nucleon number (mass number) is the sum of protons and neutrons: 20 + 24 = 44.

評分準則

Award 1 mark for the correct option C.
題目 27 · 選擇題
1
Four gas jars containing different gases are placed upside down over gas jars containing air. Which gas will diffuse into the air the slowest?
  1. A.Carbon monoxide, \(\text{CO}\)
  2. B.Nitrogen, \(\text{N}_2\)
  3. C.Sulfur dioxide, \(\text{SO}_2\)
  4. D.Methane, \(\text{CH}_4\)
查看答案詳解

解題

The rate of diffusion of a gas is inversely proportional to the square root of its relative molecular mass (M_r). The gas with the highest molecular mass will diffuse the slowest. Relative molecular masses: \(\text{CO} = 28\), \(\text{N}_2 = 28\), \(\text{SO}_2 = 64\), \(\text{CH}_4 = 16\). Therefore, sulfur dioxide diffuses the slowest.

評分準則

Award 1 mark for selecting the correct option C.
題目 28 · 選擇題
1
Concentrated aqueous sodium bromide is electrolysed using inert carbon electrodes. Which row correctly describes the observations at each electrode?
  1. A.Cathode: brown liquid formed; Anode: colorless gas which pops with a lighted splint
  2. B.Cathode: colorless gas which pops with a lighted splint; Anode: red-brown solution/orange gas formed
  3. C.Cathode: silver-grey metal formed; Anode: pale green gas formed
  4. D.Cathode: colorless gas which relights a glowing splint; Anode: red-brown solution formed
查看答案詳解

解題

During the electrolysis of concentrated aqueous sodium bromide, hydrogen ions (\(\text{H}^+\)) are discharged at the cathode because hydrogen is less reactive than sodium, producing hydrogen gas (colorless gas, pops with a lighted splint). Bromide ions (\(\text{Br}^-\)) are discharged at the anode because they are in high concentration, producing bromine (red-brown solution or orange gas).

評分準則

Award 1 mark for selecting the correct option B.
題目 29 · 選擇題
1
The properties of four metals, W, X, Y and Z, are listed. Metal W reacts with steam but not with cold water. Metal X reacts violently with cold water. Metal Y does not react with dilute acid. Metal Z is obtained by heating its oxide with carbon. What is the correct order of reactivity of these metals, starting with the most reactive?
  1. A.X > W > Z > Y
  2. B.X > Z > W > Y
  3. C.W > X > Z > Y
  4. D.Y > Z > W > X
查看答案詳解

解題

Metal X is the most reactive as it reacts violently with cold water. Metal W is next since it reacts with steam. Metal Z is less reactive than W but more reactive than Y because its oxide can be reduced by carbon, whereas Y is very unreactive (does not even react with dilute acid).

評分準則

Award 1 mark for selecting the correct option A.
題目 30 · 選擇題
1
What volume of oxygen gas (measured at r.t.p.) is required for the complete combustion of 6.0 g of magnesium? [Relative atomic mass: \(\text{Mg} = 24\)]
  1. A.1.5 \(\text{dm}^3\)
  2. B.3.0 \(\text{dm}^3\)
  3. C.6.0 \(\text{dm}^3\)
  4. D.12.0 \(\text{dm}^3\)
查看答案詳解

解題

The equation for the reaction is \(2\text{Mg} + \text{O}_2 \rightarrow 2\text{MgO}\). Moles of Mg = \(6.0\text{ g} / 24\text{ g/mol} = 0.25\text{ mol}\). According to the stoichiometry, the moles of \(\text{O}_2\) required = \(0.25 / 2 = 0.125\text{ mol}\). Volume of \(\text{O}_2\) at r.t.p. = \(0.125\text{ mol} \times 24\text{ dm}^3\text{/mol} = 3.0\text{ dm}^3\).

評分準則

Award 1 mark for selecting the correct option B.
題目 31 · 選擇題
1
A synthetic polymer has the repeating structure: \(-[- \text{O}-\text{CH}_2-\text{CH}_2-\text{O}-\text{CO}-\text{C}_6\text{H}_4-\text{CO} -]-\). Which pair of monomers is used to form this polymer?
  1. A.\(\text{HO}-\text{CH}_2-\text{CH}_2-\text{OH}\) and \(\text{HOOC}-\text{C}_6\text{H}_4-\text{COOH}\)
  2. B.\(\text{HO}-\text{CH}_2-\text{CH}_2-\text{COOH}\) and \(\text{HO}-\text{C}_6\text{H}_4-\text{COOH}\)
  3. C.\(\text{HOOC}-\text{CH}_2-\text{CH}_2-\text{COOH}\) and \(\text{HO}-\text{C}_6\text{H}_4-\text{OH}\)
  4. D.\(\text{CH}_2=\text{CH}_2\) and \(\text{HOOC}-\text{C}_6\text{H}_4-\text{COOH}\)
查看答案詳解

解題

The polymer is a polyester (Terylene). It contains ester linkages formed by the condensation reaction of a diol (ethane-1,2-diol, \(\text{HO}-\text{CH}_2-\text{CH}_2-\text{OH}\)) and a dicarboxylic acid (benzene-1,4-dicarboxylic acid, \(\text{HOOC}-\text{C}_6\text{H}_4-\text{COOH}\)).

評分準則

Award 1 mark for selecting the correct option A.
題目 32 · 選擇題
1
Which method is most suitable for preparing a pure, dry sample of the insoluble salt, barium sulfate?
  1. A.Reacting barium metal with dilute sulfuric acid, filtering, and evaporating the filtrate
  2. B.Reacting barium hydroxide solution with dilute sulfuric acid, then crystallising the mixture
  3. C.Mixing aqueous barium chloride with aqueous sodium sulfate, filtering, washing the residue with distilled water, and drying the residue
  4. D.Adding barium carbonate to excess dilute sulfuric acid, filtering, and evaporating the filtrate to dryness
查看答案詳解

解題

Barium sulfate is an insoluble salt. Insoluble salts are prepared by precipitation. This involves mixing two soluble salt solutions (aqueous barium chloride and aqueous sodium sulfate), filtering the precipitate, washing it with distilled water to remove soluble impurities, and then drying it.

評分準則

Award 1 mark for selecting the correct option C.
題目 33 · 選擇題
1
Why does an increase in temperature increase the rate of a chemical reaction? 1. The particles collide more frequently. 2. The activation energy of the reaction is lowered. 3. A greater proportion of the colliding particles have energy equal to or greater than the activation energy.
  1. A.1 and 2 only
  2. B.1 and 3 only
  3. C.2 and 3 only
  4. D.1, 2 and 3
查看答案詳解

解題

Increasing the temperature increases the kinetic energy of the particles, causing them to move faster and collide more frequently (statement 1). It also significantly increases the fraction of collisions that have energy equal to or greater than the activation energy (statement 3). Statement 2 is incorrect because the activation energy is a constant for a given reaction and is only lowered by adding a catalyst.

評分準則

Award 1 mark for selecting the correct option B.

Paper 6 (Alternative to Practical)

Answer all four practical investigation questions. Qualitative analysis tables and graph paper are provided.
8 題目 · 80
題目 1 · Structured
10
Carbon-14 is a radioactive isotope of carbon. It can be represented by the nuclide notation \(^{14}_{6}\text{C}\).\
\
(a) Complete the list to show the number of protons, neutrons, and electrons in one atom of carbon-14. [3]\
- Protons: \\dots\\dots\
- Neutrons: \\dots\\dots\
- Electrons: \\dots\\dots\
\
(b) Define the term isotopes. [2]\
\
(c) State the electronic configuration of a neutral carbon-14 atom. [1]\
\
(d) With reference to its electronic configuration, state the Group number of carbon in the Periodic Table and explain why it is placed in this Group. [2]\
\
(e) Nitrogen-14 is in the same period as carbon. State the percentage of nitrogen gas present in clean, dry air. [2]
查看答案詳解

解題

(a) Protons = 6, Neutrons = 14 - 6 = 8, Electrons = 6.\
(b) Isotopes are atoms of the same element with the same proton number but different nucleon numbers (or same number of protons, different number of neutrons).\
(c) 2,4\
(d) Group IV (or Group 14) because there are 4 valence electrons in the outer shell.\
(e) 78% (accept 79%).

評分準則

(a) 1 mark for Protons = 6; 1 mark for Neutrons = 8; 1 mark for Electrons = 6. [3]\
(b) Atoms of the same element / same number of protons (1 mark) with different number of neutrons / different mass number (1 mark). [2]\
(c) 2,4 (1 mark). [1]\
(d) Group IV / Group 4 / Group 14 (1 mark) and because it has 4 electrons in its outer shell (1 mark). [2]\
(e) 78% (1 mark), accept 79%; nitrogen gas / \(\text{N}_2\) (1 mark). [2]
題目 2 · Structured
10
Water is an essential resource that undergoes treatment before domestic use.\
\
(a) Explain the purpose of the following steps in domestic water treatment:\
(i) filtration [1]\
(ii) chlorination [1]\
\
(b) Describe a chemical test to show the presence of water, including the expected colour change. [2]\
\
(c) State how a physical test can show if a sample of water is pure. [2]\
\
(d) A student is given a solid mixture of insoluble barium sulfate and soluble sodium chloride. Describe how the student can obtain a pure, dry sample of solid barium sulfate from this mixture. [4]
查看答案詳解

解題

(a)(i) Filtration: removes insoluble solids/suspended particles.\
(ii) Chlorination: kills harmful microbes/bacteria.\
(b) Test: Add anhydrous copper(II) sulfate (or anhydrous cobalt(II) chloride).\
Colour change: White to blue (or blue to pink for cobalt chloride).\
(c) Determine the boiling point (or melting point). Pure water boils at exactly 100 °C (or melts at 0 °C).\
(d) 1. Add distilled water to the mixture and stir to dissolve the sodium chloride.\
2. Filter the mixture to obtain barium sulfate as the residue on the filter paper.\
3. Wash the residue with distilled water to remove remaining sodium chloride solution.\
4. Dry the barium sulfate residue in a warm place / between filter papers.

評分準則

(a)(i) Removes insoluble solids/dirt (1 mark). (ii) Kills bacteria/microorganisms/pathogens (1 mark). [2]\
(b) Chemical test: Anhydrous copper(II) sulfate / anhydrous cobalt(II) chloride (1 mark). Colour change: turns white to blue / turns blue to pink (1 mark). [2]\
(c) Measure boiling point / melting point (1 mark). Pure water boils at exactly 100 °C / melts at 0 °C (1 mark). [2]\
(d) Add distilled water and stir (1 mark); Filter (1 mark); Wash residue with distilled water (1 mark); Dry residue in a warm oven or with filter paper (1 mark). [4]
題目 3 · Structured
10
A student carries out an acid-base titration to determine the concentration of a sodium hydroxide solution using dilute hydrochloric acid.\
\
(a) Name the piece of apparatus used to:\
(i) measure exactly 25.0 cm³ of the sodium hydroxide solution into a conical flask. [1]\
(ii) add the hydrochloric acid gradually until the end-point is reached. [1]\
\
(b) Methyl orange indicator is added to the sodium hydroxide in the conical flask.\
State the colour change of the indicator at the end-point. [2]\
from \\dots\\dots to \\dots\\dots\
\
(c) Write the word equation for this neutralisation reaction. [2]\
\
(d) During the reaction, the temperature of the mixture increases. State the type of energy change and explain your choice with reference to thermal energy. [2]\
\
(e) In a separate experiment, 20.0 cm³ of hydrochloric acid of concentration 0.10 mol/dm³ is neutralised. Calculate the number of moles of hydrochloric acid used. [2]
查看答案詳解

解題

(a)(i) Pipette / volumetric pipette.\
(ii) Burette.\
(b) Yellow to orange / pink / red.\
(c) hydrochloric acid + sodium hydroxide -> sodium chloride + water\
(d) Exothermic (1 mark), because thermal energy is released / given out to the surroundings (causing temperature to rise) (1 mark).\
(e) \(\text{moles} = \text{concentration} \times \text{volume in dm}^3 = 0.10 \times (20.0 / 1000) = 0.002\text{ mol}\).

評分準則

(a)(i) (Volumetric) pipette (1 mark). (ii) Burette (1 mark). [2]\
(b) From yellow (1 mark) to orange / red / pink (1 mark). [2]\
(c) Hydrochloric acid + sodium hydroxide (1 mark) -> sodium chloride + water (1 mark). [2]\
(d) Exothermic (1 mark); heat/thermal energy is released/given out (1 mark). [2]\
(e) Correct formula used: \(\text{moles} = \text{concentration} \times \text{volume}\) (1 mark); \(0.002\text{ mol}\) (1 mark). [2]
題目 4 · Structured
10
Hydrated copper(II) sulfate crystals can be prepared by reacting insoluble copper(II) oxide with dilute sulfuric acid.\
\
(a) Explain why excess copper(II) oxide is added to the acid. [1]\
\
(b) Describe how the unreacted copper(II) oxide is removed from the reaction mixture. [1]\
\
(c) Describe how to obtain large, pure crystals of hydrated copper(II) sulfate from the resulting solution. [3]\
\
(d) Copper(II) oxide is a basic oxide.\
(i) State what is meant by the term basic oxide with reference to its reaction with acids. [1]\
(ii) Give the chemical formula of an acidic oxide. [1]\
\
(e) Complete the chemical equation for the reaction, including state symbols for all products.\
\
\\text{CuO(s)} + \\text{H}_2\\text{SO}_4\\text{(aq)} \\rightarrow \\dots\\dots(\\dots\\dots) + \\dots\\dots(\\dots\\dots) [3]
查看答案詳解

解題

(a) To ensure all the sulfuric acid is used up / neutralised.\
(b) By filtration.\
(c) 1. Heat the filtrate until saturated / crystallisation point is reached.\
2. Leave the solution to cool and allow crystals to form.\
3. Filter off the crystals and dry them with filter paper.\
(d)(i) A metal oxide that reacts with an acid to form a salt and water.\
(ii) \(\text{CO}_2\) (or \(\text{SO}_2\) / \(\text{NO}_2\)).\
(e) \(\text{CuSO}_4\text{(aq)} + \text{H}_2\text{O(l)}\).

評分準則

(a) To ensure all acid is neutralised / reacts (1 mark). [1]\
(b) Filtration / filter (1 mark). [1]\
(c) Heat to saturation point / crystallisation point (1 mark); cool to allow crystallisation (1 mark); filter off crystals and dry with filter paper (1 mark). [3]\
(d)(i) Reacts with acids to form salt and water (only) / neutralises acids (1 mark). (ii) \(\text{CO}_2\) / \(\text{SO}_2\) / \(\text{P}_2\text{O}_5\) etc. (1 mark). [2]\
(e) \(\text{CuSO}_4\) and \(\text{H}_2\text{O}\) (2 marks, 1 for each correct formula); State symbols: (aq) for \(\text{CuSO}_4\) and (l) for \(\text{H}_2\text{O}\) (1 mark). [3]
題目 5 · Structured
10
Poly(ethene) is a common addition polymer used to make plastic bags.\
\
(a) Poly(ethene) is made from ethene monomers.\
(i) State the name of the feature in the ethene molecule that allows it to polymerise. [1]\
(ii) Complete the diagram to show the structure of poly(ethene) showing two repeating units. [2]\
\
(b) Ethene is an unsaturated hydrocarbon.\
(i) Define the term hydrocarbon. [2]\
(ii) Describe a test to show that ethene is unsaturated, including the expected observations. [2]\
test: \\dots\\dots\
observation: \\dots\\dots\
\
(c) State one environmental problem associated with the disposal of poly(ethene) in landfills and one alternative way to dispose of it. [3]
查看答案詳解

解題

(a)(i) Carbon-carbon double bond (or C=C).\
(ii) Structure showing four carbon atoms in a chain, single bonds between them, with hydrogen atoms attached to each carbon, and open bonds at the ends: \(-\text{CH}_2-\text{CH}_2-\text{CH}_2-\text{CH}_2-\).\
(b)(i) A compound containing carbon and hydrogen only (both terms required for 2 marks).\
(ii) Test: Bromine water / aqueous bromine.\
Observation: Orange/brown to colourless / decolourises.\
(c) Problem: Non-biodegradable / fills up landfill sites / harms wildlife.\
Alternative: Recycling / incineration to produce energy.

評分準則

(a)(i) Carbon-carbon double bond / C=C bond (1 mark). (ii) Correct skeletal/displayed chain of 4 carbons with single bonds (1 mark); correct hydrogens on each carbon and continuation bonds at both ends (1 mark). [3]\
(b)(i) Compound of carbon and hydrogen (1 mark) ONLY (1 mark). (ii) Add bromine water (1 mark); turns from orange/brown to colourless / decolourises (1 mark). [4]\
(c) Environmental problem: Non-biodegradable / visual pollution / harms animals / takes up land space (1 mark); Alternative: Recycling (1 mark); burning/incineration (for energy) (1 mark). [3]
題目 6 · Structured
10
Molten lead(II) bromide is electrolysed using carbon (graphite) electrodes.\
\
(a) Explain why solid lead(II) bromide does not conduct electricity, but molten lead(II) bromide does. [2]\
\
(b) State the observations at each electrode during the electrolysis of molten lead(II) bromide:\
(i) positive electrode (anode) [1]\
(ii) negative electrode (cathode) [1]\
\
(c) Give two reasons why graphite is used for the electrodes. [2]\
\
(d) When concentrated aqueous sodium chloride is electrolysed using inert electrodes:\
(i) Name the gas produced at the negative electrode (cathode). [1]\
(ii) Describe a test for this gas and the positive result. [2]\
test: \\dots\\dots\
result: \\dots\\dots\
(iii) State the name of the alkaline solution left behind in the cell. [1]
查看答案詳解

解題

(a) In solid lead(II) bromide, ions are in fixed positions in a giant lattice and cannot move. When molten, the lattice breaks down and ions are free to move to carry the current.\
(b)(i) Positive electrode (anode): Red-brown / brown gas / vapour of bromine.\
(ii) Negative electrode (cathode): Grey liquid / shiny bead of lead.\
(c) 1. It conducts electricity.\
2. It is inert / does not react with the products.\
(d)(i) Hydrogen gas.\
(ii) Test: Apply a lighted splint.\
Result: Squeaky pop / burns with a squeaky pop.\
(iii) Sodium hydroxide.

評分準則

(a) Solid: ions are in fixed positions / cannot move (1 mark); Molten: ions are free to move (and carry charge) (1 mark). [2]\
(b)(i) Red-brown / brown fumes/gas (1 mark). (ii) Grey liquid / grey metal / shiny bead (1 mark). [2]\
(c) Conducts electricity (1 mark); inert / unreactive / high melting point (1 mark). [2]\
(d)(i) Hydrogen / \(\text{H}_2\) (1 mark). (ii) Lighted splint (1 mark); squeaky pop (1 mark). (iii) Sodium hydroxide / \(\text{NaOH}\) (1 mark). [4]
題目 7 · Structured
10
Chromatography and qualitative analysis tests are important chemical techniques.\
\
(a) A student uses paper chromatography to separate the dyes in a green food coloring.\
(i) Explain why the starting line is drawn in pencil and not ink. [1]\
(ii) Define the term \(R_f\) value and write the formula used to calculate it. [2]\
\
(b) An unknown white solid, X, is analysed.\
(i) A flame test is carried out on solid X. The flame is lilac.\
Identify the metal cation present in X. [1]\
(ii) Solid X is dissolved in water to make solution X. Dilute nitric acid and aqueous silver nitrate are added to solution X.\
A cream precipitate is formed.\
Identify the anion present in X. [2]\
(iii) State the chemical name and chemical formula of solid X. [2]\
\
(c) Describe the test for chlorine gas and state the observation for a positive result. [2]\
test: \\dots\\dots\
result: \\dots\\dots
查看答案詳解

解題

(a)(i) Ink contains dyes that are soluble in the solvent and would separate/run with the sample (1 mark).\
(ii) \(R_f\) value is the ratio of the distance travelled by the substance to the distance travelled by the solvent front. Formula: \(R_f = \frac{\text{distance travelled by substance}}{\text{distance travelled by solvent front}}\).\
(b)(i) Cation: Potassium ion / \(\text{K}^+\).\
(ii) Anion: Bromide ion / \(\text{Br}^-\).\
(iii) Name: Potassium bromide. Formula: \(\text{KBr}\).\
(c) Test: Use damp litmus paper (or universal indicator paper).\
Result: Bleached / turns white.

評分準則

(a)(i) Pencil is insoluble in the solvent / ink would dissolve and separate (1 mark). (ii) Ratio of distance of substance to solvent front (1 mark); formula: \(R_f = \frac{\text{distance travelled by dye}}{\text{distance travelled by solvent}}\) (1 mark). [3]\
(b)(i) Potassium / \(\text{K}^+\) (1 mark). (ii) Bromide / \(\text{Br}^-\)/ cream precipitate (2 marks). (iii) Potassium bromide (1 mark); \(\text{KBr}\) (1 mark). [5]\
(c) Damp blue/red litmus paper (1 mark); bleached / turns white (1 mark). [2]
題目 8 · Structured
10
The reaction between magnesium and dilute hydrochloric acid is investigated.\
\
\\text{Mg(s)} + 2\\text{HCl(aq)} \\rightarrow \\text{MgCl}_2\\text{(aq)} + \\text{H}_2\\text{(g)}\
\
(a) Explain why the rate of reaction decreases as the reaction proceeds. [2]\
\
(b) State two ways to increase the rate of this reaction without changing the concentration of the hydrochloric acid or using a catalyst. [2]\
\
(c) This reaction can be classified as a redox reaction.\
(i) Define the term oxidation in terms of electron transfer. [1]\
(ii) Write the ionic equation for this reaction. [2]\
\
(d) With reference to your ionic equation in (c)(ii):\
(i) Identify the species that is oxidised and explain your choice in terms of electron transfer. [2]\
(ii) Identify the oxidising agent. [1]
查看答案詳解

解題

(a) As the reaction proceeds, reactants (hydrochloric acid/magnesium) are used up. This decreases the concentration of hydrochloric acid, meaning there are fewer particles per unit volume, leading to a lower frequency of successful collisions.\
(b) 1. Increase the temperature of the acid.\
2. Increase the surface area of the magnesium / use powdered magnesium.\
(c)(i) Oxidation is the loss of electrons.\
(ii) \(\text{Mg(s)} + 2\text{H}^+\text{(aq)} \rightarrow \text{Mg}^{2+}\text{(aq)} + \text{H}_2\text{(g)}\).\
(d)(i) Magnesium / \(\text{Mg}\), because it loses two electrons to form \(\text{Mg}^{2+}\).\
(ii) Hydrogen ion / \(\text{H}^+\).

評分準則

(a) Reactants / acid is used up / concentration of acid decreases (1 mark); fewer collisions per unit time / lower frequency of collisions (1 mark). [2]\
(b) Increase temperature (1 mark); use powdered magnesium / increase surface area (1 mark). [2]\
(c)(i) Loss of electrons (1 mark). (ii) \(\text{Mg} + 2\text{H}^+ \rightarrow \text{Mg}^{2+} + \text{H}_2\) (2 marks, 1 mark for correct reactants and products, 1 mark for balanced charges and moles). [3]\
(d)(i) Magnesium / Mg (1 mark); loses electrons (1 mark). (ii) \(\text{H}^+\)/ hydrogen ion / hydrochloric acid (1 mark). [3]

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