Edexcel IAL · Thinka 原創模擬試題

2024 Edexcel IAL Psychology (YPS01) 模擬試題連答案詳解

Thinka Jan 2024 Cambridge International A Level-Style Mock — Psychology (YPS01)

320 420 分鐘2024
An original Thinka practice paper modelled on the structure and difficulty of the Jan 2024 Cambridge International A Level Psychology (YPS01) paper. Not affiliated with or reproduced from Cambridge.

WPS01/01 甲部: Social Psychology

Answer all questions. Show your working in calculations.
5 題目 · 24
題目 1 · Short Answer
4
Describe one strength and one weakness of Milgram's Agency Theory of obedience.
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解題

Strength: One strength of Agency Theory is that it is supported by empirical evidence from Milgram (1963). In his baseline study, 65% of participants administered the maximum 450V shock when instructed by the experimenter, showing they entered an agentic state where they perceived the experimenter as responsible. Weakness: One weakness of the theory is that it does not account for individual differences in obedience. For instance, 35% of Milgram's participants resisted authority and remained autonomous, suggesting personality traits or other factors not accounted for by the theory also play a role.

評分準則

Award 1 mark for identifying a strength and 1 mark for explaining it in relation to obedience (max 2 marks). Award 1 mark for identifying a weakness and 1 mark for explaining it in relation to obedience (max 2 marks). Strength: e.g., Supported by research evidence such as Milgram's (1963) baseline experiment (1 mark). In this study, 65% of participants went up to 450V when instructed, indicating they had shifted responsibility to the authority figure and entered an agentic state (1 mark). Weakness: e.g., The theory has limited explanatory power regarding individual differences (1 mark). It cannot fully explain why 35% of Milgram's participants chose to disobey and remain in an autonomous state despite facing the exact same situational pressures (1 mark).
題目 2 · Short Answer
4
Explain how Social Impact Theory (Latané, 1981) accounts for obedience, using the formula \(I = f(SIN)\).
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解題

Social Impact Theory explains obedience using the formula \(I = f(SIN)\), where social impact (I) is a function of Strength (S), Immediacy (I), and Number (N). Strength refers to the perceived status, authority, or power of the source giving the order. Immediacy refers to the physical or psychological proximity of the source to the target (e.g., being in the same room). Number refers to how many sources are giving the command compared to how many targets are receiving it. The theory states that as strength, immediacy, and number of sources increase, the likelihood of obedience increases multiplicatively.

評分準則

Award 1 mark for explaining each factor (Strength, Immediacy, Number) up to 3 marks, and 1 mark for explaining the multiplicative/overall effect of the formula. e.g., Strength (S) refers to the authority or social status of the person giving the order, where high status leads to more obedience (1 mark). Immediacy (I) refers to the physical distance between the authority and the target; closer proximity increases obedience (1 mark). Number (N) refers to the quantity of authority figures directing the target, which increases pressure to obey (1 mark). The overall impact is a multiplicative function of these three factors, meaning if any of them increase, the total social pressure to obey increases significantly (1 mark).
題目 3 · Short Answer
4
Explain how Social Identity Theory can explain prejudice between two rival school sports teams.
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解題

According to Social Identity Theory, prejudice occurs in three stages. First, social categorisation: students categorise themselves into the 'in-group' (their own sports team) and the 'out-group' (the rival school sports team). Second, social identification: students adopt the identity of their team, wearing the team colors and boosting their self-esteem through team successes. Third, social comparison: students compare their own team favorably against the rival team. To maintain their self-esteem, they engage in in-group favoritism and out-group denigration, leading to negative stereotypes and prejudice towards the rival team.

評分準則

Award 1 mark for each stage of Social Identity Theory correctly described and applied to the scenario (up to 3 marks). Award 1 mark for explaining how this leads to prejudice/in-group favoritism/out-group denigration. e.g., Social categorisation occurs when students divide themselves into the in-group (own sports team) and out-group (rival school team) (1 mark). Social identification occurs when students adopt the identity of their sports team, boosting their personal self-esteem through team affiliation (1 mark). Social comparison occurs when students compare the two teams, finding ways to make their own team seem superior (1 mark). This comparison leads to in-group favoritism and out-group denigration, causing prejudice and hostile attitudes toward the rival team's members (1 mark).
題目 4 · Short Answer
4
Describe the procedure of your social psychology practical investigation.
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解題

In my social psychology practical investigation, I conducted a questionnaire to investigate whether age affects self-reported obedience levels. First, I developed a 10-item questionnaire consisting of 5 Likert-scale questions and 5 open-ended questions. Next, I used opportunity sampling to recruit 20 participants (10 aged 18-25 and 10 aged 45-60) from a local community center. Before they began, I obtained informed consent by explaining their right to withdraw. Finally, participants completed the questionnaire in a quiet room, and I debriefed them afterwards, explaining the purpose of the study and ensuring their data remained confidential.

評分準則

Award 1 mark for describing each distinct step/aspect of the procedure of the student's own social psychology practical investigation (up to 4 marks). Must be relevant to social psychology (e.g., measuring prejudice, obedience, obedience attitudes). e.g., Formulated a hypothesis/aim regarding a social topic (e.g., investigating gender differences in obedience attitudes) (1 mark). Gathered a sample of participants using a specified sampling method (e.g., opportunity sampling of 20 peers) (1 mark). Developed the research materials, such as a questionnaire with closed Likert-scale questions (1 mark). Followed ethical guidelines, including obtaining informed consent and providing a debrief after data collection (1 mark).
題目 5 · Essay
8
Evaluate Social Identity Theory (Tajfel and Turner, 1979) as an explanation of prejudice.
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解題

### AO1 (Knowledge and Understanding) Points:
- Social Identity Theory (SIT) proposes that prejudice arises from the mere existence of two groups, without the need for conflict or competition over resources.
- The theory outlines three stages of identity formation: social categorization (classifying people into 'in-groups' and 'out-groups'), social identification (adopting the norms, values, and identity of the in-group), and social comparison (comparing the in-group with the out-group to elevate self-esteem).
- To maintain positive distinctiveness and collective self-esteem, individuals engage in in-group favoritism (viewing members of their own group positively) and out-group hostility or denigration (viewing the out-group negatively).

### AO3 (Evaluation) Points:
- **Supporting Evidence:** Tajfel's (1970) minimal group experiment supports the theory, showing that teenage boys allocated more points to members of their own group (in-group) rather than the out-group, even when the groups were established on trivial criteria (such as preference for Klee or Kandinsky paintings).
- **Alternative Explanations:** Realistic Conflict Theory (Sherif, 1966) argues that categorization alone is not enough to cause prejudice. It suggests that actual competition for scarce, valued resources is required to trigger intergroup hostility, as demonstrated in the Robbers Cave experiment.
- **Methodological Limitations of Support:** Many supporting studies (like Tajfel's) took place in artificial laboratory settings using trivial tasks, meaning they lack ecological validity and may not represent the deep-seated historical and cultural prejudices found in the real world.
- **Practical Application:** SIT has useful real-world applications. By understanding that prejudice stems from group division, psychologists can develop interventions like 'decategorization' or forming a 'common in-group identity' (e.g., uniting rival groups under a larger, shared identity) to reduce discrimination in communities and workplaces.

評分準則

### Marking Descriptors (8 Marks Total)
- **AO1: 4 marks** (Knowledge and understanding of Social Identity Theory)
- **AO3: 4 marks** (Evaluation of Social Identity Theory as an explanation of prejudice)

#### Level Descriptors:
- **Level 4 (7–8 marks):**
- Demonstrates precise, detailed, and wide-ranging psychological knowledge (AO1).
- Offers a sophisticated, balanced, and logical evaluation with well-developed points (AO3).
- The response is well-structured and presents a coherent, logical conclusion.
- **Level 3 (5–6 marks):**
- Demonstrates mostly accurate psychological knowledge (AO1).
- Offers a detailed evaluation, though some points may lack depth or balance (AO3).
- Structure is clear and logical for the most part.
- **Level 2 (3–4 marks):**
- Demonstrates some relevant psychological knowledge, but with minor inaccuracies or omissions (AO1).
- Evaluation points are present but tend to be simplistic, generic, or lacking critical depth (AO3).
- The argument lacks full development or clear direction.
- **Level 1 (1–2 marks):**
- Demonstrates isolated, basic, or superficial knowledge of the theory (AO1).
- Evaluation is very brief, weak, or absent (AO3).
- Little or no structure to the response.

WPS01/01 乙部: Cognitive Psychology

Answer all questions. Show your working in calculations.
4 題目 · 21.5
題目 1 · Scenario Analysis
4.5
Maya is revising for her history exam. She is reading her textbook while listening to an educational podcast about the same historical period. She finds it very difficult to remember the information. However, when she looks at a timeline diagram of the events while listening to the podcast, she finds it much easier to recall. Describe how the Working Memory Model (WMM) can explain Maya's experience.
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解題

The Working Memory Model (WMM) proposed by Baddeley and Hitch explains Maya's cognitive experience through the concept of limited capacity and specialized slave systems. 1. Reading the textbook and listening to the podcast both rely on the phonological loop (specifically the phonological store and articulatory control process) to process verbal and acoustic information. Because the phonological loop has a very limited capacity, attempting to perform both verbal tasks simultaneously causes acoustic interference and overload, leading to poor recall. 2. When Maya switches to looking at a timeline diagram while listening to the podcast, she is engaging two different slave systems. The diagram is processed by the Visuospatial Sketchpad (VSSP), which handles visual and spatial information, whereas the podcast is processed by the Phonological Loop. 3. Since these slave systems operate independently and have separate attentional capacities, they can process the information concurrently without interference. The Central Executive coordinates this dual-task processing, allowing Maya to integrate the visual timeline and verbal narrative into a coherent episodic buffer representation, greatly improving her memory recall.

評分準則

Apply up to 4.5 marks for applying the Working Memory Model to Maya's scenario: - Up to 1.5 marks for explaining the verbal interference: Award 1 mark for identifying that both reading and listening rely on the Phonological Loop (PL), and 0.5 marks for explaining that this overloads its limited capacity. - Up to 1.5 marks for explaining the dual-task success: Award 1 mark for identifying that the diagram uses the Visuospatial Sketchpad (VSSP) while the podcast uses the PL, and 0.5 marks for explaining that because these are separate slave systems, they can operate simultaneously without interference. - Up to 1.5 marks for explaining cognitive coordination: Award 1 mark for explaining how the Central Executive directs attention between the modalities, and 0.5 marks for noting the integration of information in the episodic buffer.
題目 2 · Scenario Analysis
4.5
Arthur witnessed a minor car accident at a junction. Initially, he remembered seeing a blue car slide on wet leaves. A few days later, after speaking to a police officer who asked, 'Did you see the broken glass from the red sports car?', Arthur recalled seeing broken glass and remembered the blue car speeding, even though there was no glass and the car was travelling slowly. Explain Arthur's memory of the accident using Bartlett's Reconstructive Memory theory.
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解題

According to Bartlett's Reconstructive Memory theory, memory is not an exact recording of events but an active reconstruction influenced by cognitive schemas (mental frameworks of expectations). 1. Arthur's initial memory was of a blue car sliding. However, when the police officer introduced post-event information mentioning 'broken glass' and a 'red sports car', this activated Arthur's cognitive schema regarding high-speed sports car accidents. 2. To make sense of the event (an 'effort after meaning'), Arthur's brain integrated this new, misleading information into his original memory trace during reconstruction. 3. As a result, his schema-driven expectations caused him to remember 'broken glass' and 'speeding' because these details are highly compatible with his mental script of a sports car crash, demonstrating how memory is malleable and prone to distortion.

評分準則

Apply up to 4.5 marks for explaining Arthur's memory using Reconstructive Memory theory: - Up to 1.5 marks for explaining schemas: Award 1 mark for defining schemas as mental frameworks and 0.5 marks for linking them to Arthur's expectations about sports cars speeding. - Up to 1.5 marks for explaining post-event integration: Award 1 mark for describing how the police officer's leading question introduced new details, and 0.5 marks for explaining how these details became integrated into the reconstructed memory trace. - Up to 1.5 marks for explaining 'effort after meaning': Award 1 mark for explaining that memory reconstruction involves making sense of the event, and 0.5 marks for showing how Arthur rationalized the crash by falsely recalling glass and speed.
題目 3 · Scenario Analysis
4.5
Chloe is trying to remember a 12-digit code to access a secure building: 194520012012. Initially, she struggles to keep it in her short-term memory. Her colleague suggests she group the digits into years: '1945', '2001', and '2012'. Chloe can now easily remember the code. Explain Chloe's improved memory recall using the Multi-Store Model of memory (MSM), referencing concepts such as capacity and chunking.
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解題

The Multi-Store Model of memory (MSM) describes the short-term memory (STM) as having a very limited capacity, famously characterized by Miller (1956) as \(7 \pm 2\) items. 1. Initially, Chloe is presented with 12 individual digits (1, 9, 4, 5, 2, 0, 0, 1, 2, 0, 1, 2), which significantly exceeds the maximum capacity of STM, leading to decay or displacement of the numbers. 2. When her colleague suggests grouping them into years, Chloe performs 'chunking' - the process of combining individual pieces of information into larger, meaningful units. 3. This reduces the number of items she needs to hold in STM from 12 separate digits to only 3 chunks ('1945', '2001', '2012'). Since 3 items is well below the capacity limit of \(7 \pm 2\), her STM can easily retain the code, especially as these chunks can leverage semantic links in her Long-Term Memory (LTM).

評分準則

Apply up to 4.5 marks for explaining Chloe's memory improvement using the Multi-Store Model: - Up to 1.5 marks for explaining STM capacity: Award 1 mark for stating that STM capacity is limited to \(7 \pm 2\) items (or 5-9 items) and 0.5 marks for explaining that 12 individual digits exceed this threshold. - Up to 1.5 marks for defining and applying chunking: Award 1 mark for explaining chunking as grouping individual items into larger, meaningful units, and 0.5 marks for showing how this reduced Chloe's cognitive load to 3 items. - Up to 1.5 marks for explaining cognitive mechanism/LTM link: Award 1 mark for explaining how these chunks are easier to hold in STM or link to existing knowledge in LTM, and 0.5 marks for mentioning maintenance rehearsal or prevention of displacement.
題目 4 · Essay
8
Evaluate the Working Memory Model (Baddeley and Hitch, 1974) as an explanation of short-term memory.
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解題

The Working Memory Model (WMM) was proposed by Baddeley and Hitch (1974) to address the limitations of the Multi-Store Model, conceptualising short-term memory (STM) as an active, multi-component processor rather than a single unitary store. The model consists of four key components. The Central Executive acts as the master attentional controller, directing attention and allocating tasks to three subsystem 'slave' units. The Phonological Loop processes auditory information and is divided into the phonological store ('inner ear') and the articulatory rehearsal process ('inner voice'). The Visuospatial Sketchpad (VSS) handles visual and spatial information, split into the visual cache (storing shape and colour) and the inner scribe (dealing with spatial arrangements). In 2000, Baddeley added the Episodic Buffer, which acts as a general temporary store that integrates information from the other subsystems and long-term memory into coherent, chronological representations. In terms of evaluation, a significant strength of the WMM is the support it receives from dual-task performance studies. Baddeley et al. demonstrated that participants had difficulty performing two visual tasks simultaneously, whereas performing a visual and a verbal task together was easily accomplished. This supports the existence of separate, capacity-limited visual and verbal processors. Furthermore, clinical evidence from brain-damaged patients, such as KF, supports the model. KF suffered an impairment where his auditory short-term memory was severely limited, but his visual short-term memory remained intact, demonstrating that the phonological loop and visuospatial sketchpad are indeed distinct cognitive systems. However, a major weakness of the WMM is the lack of clarity regarding the Central Executive. Critics argue that the concept of the Central Executive is too vague and poorly defined, acting as a 'homunculus' or a convenient 'holding space' without its exact mechanisms being empirically operationalised. Additionally, the model has been criticized by Lieberman (1980), who noted that blind people possess excellent spatial awareness despite lacking visual imagery. This suggests that the visuospatial sketchpad should be treated as two completely distinct systems rather than closely linked sub-components. In conclusion, while the WMM offers a highly advanced and dynamic explanation of STM compared to earlier linear models, its core component—the Central Executive—requires further empirical clarification to fully explain cognitive processing.

評分準則

AO1 (4 marks): Candidates should demonstrate accurate and detailed knowledge of the WMM components. Award 1 mark per distinct description point: Identification of the Central Executive as an attentional controller; Description of the Phonological Loop including the phonological store and articulatory loop; Description of the Visuospatial Sketchpad including the visual cache and inner scribe; Explanation of the Episodic Buffer as an integrative temporary store. AO3 (4 marks): Candidates should analyze and evaluate the WMM as an explanation of short-term memory. Award 1 mark per distinct evaluative point: Dual-task research support (e.g., Baddeley et al.); Clinical evidence support from case studies (e.g., KF); Conceptual weakness of the Central Executive (the 'homunculus' criticism); Criticism from Lieberman regarding visual vs. spatial separation. Marking Grid: Level 1 (1-2 marks): Demonstrates isolated elements of knowledge and evaluation. Little structure and logical thread. Level 2 (3-4 marks): Demonstrates limited/unbalanced knowledge and evaluation. Some structure, but lacks depth and consistency. Level 3 (5-6 marks): Demonstrates mostly accurate knowledge and logical/balanced evaluation of the model. Sound structure. Level 4 (7-8 marks): Demonstrates comprehensive, highly accurate knowledge and a balanced, nuanced evaluation of the model. Well-structured and convincing conclusion.

WPS01/01 部分 C: Cognitive Psychology Contemporary Study

Evaluate your chosen contemporary study in detail.
1 題目 · 12
題目 1 · essay
12
Evaluate the contemporary study from cognitive psychology, Sebastian and Hernández-Gil (2012).
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解題

AO1 (Knowledge and Understanding) points:
- Aim: To investigate the development of the phonological loop in Spanish children aged 5-17 using digit span, and compare this with English children and clinical groups.
- Sample: 570 healthy Spanish children from Madrid schools, with no known hearing, reading, or writing difficulties.
- Procedure: Participants were tested individually. Sequences of digits were read aloud to them at a rate of one digit per second, and they had to recall them in order. Digit span was the maximum length at which they successfully recalled at least 2 out of 3 sequences.
- Results: Digit span increased gradually with age, from 3.74 at age 5 to 5.83 at ages 15-17, showing that working memory capacity develops until adolescence.
- Spanish children showed a lower digit span overall compared to English children, which is explained by the word-length effect (Spanish numbers have more syllables than English numbers).

AO3 (Evaluation) points:
- Reliability: Highly standardised procedure (uniform reading rate of one digit per second, controlled testing environment) makes the study highly replicable and objective.
- Generalisability: The large sample of 570 participants provides strong population validity for Spanish-speaking children. However, the sample was restricted to schools in Madrid, meaning results may not represent rural Spanish children or other Spanish dialects.
- Task Validity: The digit span task is an artificial laboratory test of memory (low ecological validity), meaning it may not accurately reflect how children use working memory in everyday, real-life learning situations.
- Internal Validity: Researchers controlled for potential confounding variables by excluding children with learning difficulties or cognitive impairments.
- Application: The findings have useful educational and clinical applications, such as establishing normal digit span developmental benchmarks for Spanish children to help diagnose early learning difficulties or cognitive deficits (e.g., dyscalculia).

評分準則

For 12 marks, the response is graded using a level-based marking grid (AO1 = 6 marks, AO3 = 6 marks):

- Level 1 (1-3 marks): Demonstrates isolated elements of knowledge and understanding. Evaluation is sparse and lacks critical depth.
- Level 2 (4-6 marks): Demonstrates some accurate knowledge and understanding. Evaluation is present but may lack focus or rely heavily on generic points.
- Level 3 (7-9 marks): Demonstrates mostly accurate and detailed knowledge and understanding. Evaluation is logical, balanced, and contains study-specific criticisms (e.g., word-length effect, Madrid sample context).
- Level 4 (10-12 marks): Demonstrates precise, detailed, and comprehensive knowledge and understanding of Sebastian and Hernández-Gil (2012). Evaluation is sophisticated, highly structured, and offers a fully balanced judgment of the study's scientific contribution.

WPS02/01 甲部: Biological Psychology

Answer all questions.
5 題目 · 34
題目 1 · Short Answer & Calculation
6.5
A clinical psychologist measures the salivary cortisol levels (in nmol/L) of a group of participants before and after a high-stress competitive task. The baseline mean cortisol level was 5.40 nmol/L, and the post-stressor mean cortisol level was 13.23 nmol/L.

(a) Calculate the percentage increase in the mean cortisol levels from baseline to post-stressor. Show your working and round your answer to two decimal places. (2.5 marks)

(b) Describe how the hypothalamic-pituitary-adrenal (HPA) axis regulates the release of cortisol in response to stress. (4 marks)
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解題

Part (a):
1. Find the increase: \(13.23 - 5.40 = 7.83\)
2. Divide by the original baseline value: \(7.83 / 5.40 = 1.45\)
3. Convert to a percentage: \(1.45 \times 100 = 145\%\) (or 145.00\%).

Part (b):
- The hypothalamus detects stress and releases Corticotropin-Releasing Hormone (CRH).
- CRH stimulates the anterior pituitary gland to secrete Adrenocorticotropic Hormone (ACTH) into the bloodstream.
- ACTH travels to the adrenal glands and stimulates the adrenal cortex to release cortisol.
- Cortisol increases blood glucose levels and suppresses non-essential bodily functions to help cope with stress.

評分準則

Part (a): [Total 2.5 marks]
- 1 mark for correct calculation of the difference (\(7.83\)).
- 1 mark for dividing by the baseline value and multiplying by 100 (\((7.83 / 5.40) \times 100\)).
- 0.5 marks for the correct final answer rounded to two decimal places (\(145.00\%\)).

Part (b): [Total 4 marks]
- 1 mark for explaining that the hypothalamus releases CRH in response to stress.
- 1 mark for explaining that CRH triggers the pituitary gland to secrete ACTH.
- 1 mark for explaining that ACTH stimulates the adrenal cortex to release cortisol.
- 1 mark for describing a physiological role or negative feedback effect of cortisol (e.g., boosting glucose/energy).
題目 2 · Short Answer & Calculation
6.5
A researcher investigates the genetic basis of physical aggression by calculating concordance rates in twins. In a sample of 75 Monozygotic (MZ) twin pairs, 45 pairs both showed high levels of physical aggression. In a sample of 120 Dizygotic (DZ) twin pairs, 36 pairs both showed high levels of physical aggression.

(a) Calculate the concordance rate (as a percentage) for both the MZ and DZ twin groups, and determine the difference between these two concordance rates. Show your working. (2.5 marks)

(b) Explain how the difference in concordance rates between MZ and DZ twins can be used by biological psychologists to support the role of genetics in aggression. (4 marks)
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解題

Part (a):
1. MZ concordance rate: \((45 / 75) \times 100 = 60.0\%\)
2. DZ concordance rate: \((36 / 120) \times 100 = 30.0\%\)
3. Difference: \(60.0\% - 30.0\% = 30.0\%\)

Part (b):
- MZ twins share 100% of their genetic material, whereas DZ twins share approximately 50%.
- Since both twin types typically share similar environments, a higher concordance rate in MZ twins points toward a genetic explanation for the behaviour.
- In this study, the MZ concordance is double the DZ concordance (60% vs 30%), suggesting a strong genetic influence.
- However, because the MZ concordance rate is not 100%, environmental factors must also contribute to physical aggression.

評分準則

Part (a): [Total 2.5 marks]
- 1 mark for calculating correct MZ concordance rate (\(60\%\)).
- 1 mark for calculating correct DZ concordance rate (\(30\%\)).
- 0.5 marks for calculating the correct difference (\(30\%\)).

Part (b): [Total 4 marks]
- 1 mark for stating that MZ twins share 100% of their DNA whereas DZ twins share 50%.
- 1 mark for explaining that higher concordance in MZ twins suggests genetic influence because environment is assumed to be constant (equal environments assumption).
- 1 mark for applying this to the data (e.g., showing MZ rate is double the DZ rate, pointing to genetic heritability).
- 1 mark for noting that since concordance is not 100% for MZ twins, environmental factors must also play a role.
題目 3 · Short Answer & Calculation
6.5
A neuroscientist compares the volume of the amygdala (in \(mm^3\)) between a group of violent offenders and a control group of non-offenders. The volumes of the left amygdala for 8 violent offenders are: 1350, 1280, 1410, 1190, 1220, 1310, 1250, and 1150.

(a) Calculate the median volume of the left amygdala for this group of violent offenders, and calculate the range of these volumes. Show your working. (2.5 marks)

(b) Explain the role of the amygdala in aggressive behavior. (4 marks)
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解題

Part (a):
1. Sort the data in ascending order: 1150, 1190, 1220, 1250, 1280, 1310, 1350, 1410.
2. Calculate the median: Since there are 8 values (an even number), average the 4th and 5th values: \((1250 + 1280) / 2 = 1265\ mm^3\).
3. Calculate the range: \(\text{Maximum value} - \text{Minimum value} = 1410 - 1150 = 260\ mm^3\).

Part (b):
- The amygdala is part of the limbic system, which is key in processing emotional stimuli, particularly threat detection and fear responses.
- Reactivity of the amygdala is linked to aggressive outbursts; a hyper-reactive amygdala may interpret neutral environmental stimuli as threatening, triggering a 'fight or flight' response.
- Conversely, a smaller or structurally compromised amygdala is associated with a lack of fear conditioning and empathy, making aggressive behavior more likely (as shown in classic research like Raine et al., 1997).
- The amygdala works in conjunction with the prefrontal cortex; if the PFC fails to regulate the amygdala's emotional signals, aggression is more likely to occur.

評分準則

Part (a): [Total 2.5 marks]
- 1 mark for ordering the data and calculating the correct median (\(1265\)).
- 1 mark for calculating the correct range (\(260\)).
- 0.5 marks for including correct units (\(mm^3\) or cubic millimetres) for both answers.

Part (b): [Total 4 marks]
- 1 mark for identifying the amygdala's role in the limbic system (processing emotions/evaluating threats).
- 1 mark for explaining how hyper-reactivity of the amygdala can lead to heightened emotional reactions and impulsive aggression.
- 1 mark for explaining how structural abnormalities (e.g., lower volume) are associated with deficits in empathy and fear conditioning.
- 1 mark for explaining the interaction between the amygdala and the prefrontal cortex in regulating aggression (top-down regulation).
題目 4 · Short Answer & Calculation
6.5
A researcher collects ratings of physical aggression from teachers for a sample of 12 primary school children on a scale of 0 to 50. The scores are as follows:
12, 18, 5, 22, 15, 30, 8, 25, 14, 19, 21, 16.

(a) Calculate the mean score of physical aggression for this group. Show your working and round your answer to two decimal places. (2.5 marks)

(b) Describe Freud’s psychodynamic theory of aggression, with reference to the concepts of 'Id', 'Ego', 'Superego', and 'catharsis'. (4 marks)
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解題

Part (a):
1. Sum of the scores: \(12 + 18 + 5 + 22 + 15 + 30 + 8 + 25 + 14 + 19 + 21 + 16 = 195\)
2. Divide by the total number of children (\(N = 12\)): \(195 / 12 = 16.25\).

Part (b):
- Freud proposed that aggression is an innate biological drive stemming from the 'Id' (specifically Thanatos, the death instinct, which is directed outward).
- The 'Ego' manages these destructive impulses using defense mechanisms to balance the desires of the Id with the moral demands of the 'Superego'.
- If the Ego cannot successfully mediate this conflict, internal tension builds up and is eventually released as aggression.
- 'Catharsis' is the process of releasing this pent-up psychic energy safely (e.g., through playing sports or other sublimated activities), which reduces the subsequent likelihood of actual aggressive behavior.

評分準則

Part (a): [Total 2.5 marks]
- 1 mark for correctly summing the scores to \(195\).
- 1 mark for dividing the sum by \(12\).
- 0.5 marks for the correct final answer of \(16.25\).

Part (b): [Total 4 marks]
- 1 mark for explaining the role of the 'Id' (as the source of innate drive, Thanatos, or death instinct).
- 1 mark for explaining the roles of the 'Ego' and 'Superego' in managing or suppressing these destructive impulses.
- 1 mark for explaining 'catharsis' as the safe release of pent-up aggressive energy.
- 1 mark for explaining how a failure in these psychodynamic mechanisms or lack of catharsis leads to destructive outbursts.
題目 5 · Essay
8
Evaluate the evolutionary explanation of human aggression.
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解題

AO1 Knowledge and Understanding:
- Evolutionary theory states that aggression is an adaptive behavior designed to increase an individual's survival chances and reproductive success in the Environment of Evolutionary Adaptedness (EEA).
- Male-on-male aggression can be explained by competition for scarce resources and mates, where dominant, aggressive males are more likely to attract females and pass on their genes.
- Paternal uncertainty (the risk of raising another man's child) leads to mate retention strategies, which may involve physical or verbal aggression to prevent cuckoldry.
- Aggression can also serve as a mechanism to protect offspring from predators and rival groups, ensuring the survival of shared genetic material.

AO3 Evaluation/Analysis:
- Supporting evidence comes from studies like Daly and Wilson (1988), who found that a high proportion of homicides are committed by young, unmarried men competing for status and mates, supporting the evolutionary concept of intrasexual competition.
- However, the evolutionary explanation can be considered post-hoc (after the event), meaning it constructs historical narratives to explain modern behavior which cannot be directly tested or falsified.
- The explanation is biologically reductionist as it ignores the powerful role of social and cultural factors in aggression. For example, Bandura's Social Learning Theory demonstrates that children learn aggressive behaviors through observation and imitation, not just innate drives.
- It is also socially sensitive and deterministic, as suggesting aggression is hardwired into human nature could be used to excuse domestic violence or antisocial behavior, ignoring cognitive control and free will.

評分準則

Levels-based marking criteria (8 marks total: 4 marks for AO1, 4 marks for AO3):

Level 1 (1-2 marks): Demonstrates isolated elements of knowledge and understanding. Evaluation is sparse and lacks critical analysis.

Level 2 (3-4 marks): Demonstrates some accurate knowledge and understanding. Evaluation is present but basic, with limited link back to the question.

Level 3 (5-6 marks): Demonstrates mostly accurate and detailed knowledge and understanding. Evaluation is logical and structured, with balanced arguments on both sides.

Level 4 (7-8 marks): Demonstrates highly accurate and precise knowledge and understanding. Evaluation is sophisticated, critical, and leads to a balanced, well-supported conclusion.

WPS02/01 乙部: Learning Theories and Development

Answer all questions.
4 題目 · 33.5
題目 1 · Short Answer & Calculation
8.5
Dr. Aris conducted an observational study to investigate the impact of role models on cooperative play in young children. He observed 15 children before and after they watched an adult role model share toys with others. Dr. Aris recorded the frequency of sharing behaviors for each child.

**Part A (4 marks):** Explain how Dr. Aris could use Social Learning Theory to explain how the children acquired the sharing behavior from the adult role model.

**Part B (4.5 marks):** The frequency of sharing behaviors for a subsample of 6 children before watching the model was: 2, 3, 1, 4, 2, 6. After watching the model, the frequencies for the same 6 children were: 5, 8, 4, 9, 6, 10.

Calculate the percentage increase in the mean number of sharing behaviors from before to after watching the model. Show your workings and round your answer to two decimal places.
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解題

**Part A (4 marks):**
- **Attention:** The children must observe and pay attention to the adult role model's sharing behavior. Dr. Aris would ensure the model is high-status or salient to command attention.
- **Retention:** The children must store the observed sharing behavior in their memory as a cognitive representation to retrieve it later during cooperative play.
- **Reproduction:** The children must possess the physical and cognitive ability to replicate the sharing behavior (e.g., physically handing a toy to another child).
- **Motivation/Reinforcement:** The children must have a reason to replicate the behavior. This could be vicarious reinforcement (seeing the model praised) or direct reinforcement if they are rewarded when they share.

**Part B (4.5 marks):**
1. Calculate the mean before watching the model:
\(\text{Mean Before} = \frac{2 + 3 + 1 + 4 + 2 + 6}{6} = \frac{18}{6} = 3.00\)

2. Calculate the mean after watching the model:
\(\text{Mean After} = \frac{5 + 8 + 4 + 9 + 6 + 10}{6} = \frac{42}{6} = 7.00\)

3. Calculate the difference in means:
\(\text{Difference} = 7.00 - 3.00 = 4.00\)

4. Calculate the percentage increase:
\(\text{Percentage Increase} = \left(\frac{4.00}{3.00}\right) \times 100 = 133.333...\%\)

5. Rounded to two decimal places: **133.33%**

評分準則

**Part A (4 marks):**
- 1 mark for explaining attention in context (e.g., children must focus on the adult model sharing toys).
- 1 mark for explaining retention in context (e.g., children must remember the act of sharing the toys).
- 1 mark for explaining reproduction in context (e.g., children must be capable of physically passing toys to others).
- 1 mark for explaining motivation/reinforcement in context (e.g., children desire to reproduce the act to gain praise or because they saw the model being thanked).

**Part B (4.5 marks):**
- 1 mark for calculating correct mean before (3.00) with working shown.
- 1 mark for calculating correct mean after (7.00) with working shown.
- 1 mark for using the correct percentage increase formula: \(\frac{\text{After} - \text{Before}}{\text{Before}} \times 100\).
- 1 mark for correct calculation of 133.33%.
- 0.5 marks for rounding correctly to two decimal places.
題目 2 · Short Answer & Calculation
8.5
A school psychologist, Elena, implements a token economy system to increase homework completion rates among 8 students. She compares the number of completed homework assignments over a two-week period before the token economy and a two-week period during the system.

**Part A (4 marks):** Describe how Elena could utilize negative reinforcement and primary reinforcers within her token economy program to encourage homework completion.

**Part B (4.5 marks):** Elena wants to perform a Sign Test on the homework completion data of the 8 students to see if there is a significant increase.

Data (Before vs During homework count):
- Student 1: 3 vs 7
- Student 2: 5 vs 5
- Student 3: 2 vs 6
- Student 4: 6 vs 4
- Student 5: 4 vs 8
- Student 6: 1 vs 5
- Student 7: 7 vs 9
- Student 8: 3 vs 6

Calculate the observed value of \(S\) for this Sign Test, state the value of \(N\) used to find the critical value, and determine if the result is significant at \(p \le 0.05\) for a one-tailed test where the critical value of \(S\) for \(N=7\) is 1.
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解題

**Part A (4 marks):**
- **Primary Reinforcers:** Elena can offer basic, inherently satisfying rewards (e.g., free play time, snacks, stickers) that tokens can be exchanged for. The tokens acts as secondary reinforcers, which have no intrinsic value but derive value from being exchangeable for these primary reinforcers.
- **Negative Reinforcement:** Elena can allow students who reach a certain threshold of tokens to avoid an unpleasant task, such as a mandatory weekend study session or a chore. Removing this negative stimulus increases the likelihood of homework completion.

**Part B (4.5 marks):**
1. Determine the direction of difference (During - Before):
- S1: \(7 - 3 = +4\) (+)
- S2: \(5 - 5 = 0\) (No change)
- S3: \(6 - 2 = +4\) (+)
- S4: \(4 - 6 = -2\) (-)
- S5: \(8 - 4 = +4\) (+)
- S6: \(5 - 1 = +4\) (+)
- S7: \(9 - 7 = +2\) (+)
- S8: \(6 - 3 = +3\) (+)

2. Count signs:
- Number of positive signs (+) = 6
- Number of negative signs (-) = 1
- Number of zero differences (excluded) = 1

3. Identify Observed Value \(S\):
- \(S\) is the frequency of the less frequent sign: \(S = 1\).

4. Identify \(N\):
- Total pairs minus zero differences: \(N = 8 - 1 = 7\).

5. Determine Significance:
- Critical value of \(S\) for \(N=7\) at \(p \le 0.05\) (one-tailed) is 1.
- For significance, observed \(S\) must be less than or equal to the critical value.
- Since observed \(S = 1\) and critical value = 1, the result is significant.

評分準則

**Part A (4 marks):**
- 1 mark for explaining what a primary reinforcer is (e.g., an intrinsically rewarding stimulus like extra break time).
- 1 mark for linking primary reinforcers to the scenario (e.g., tokens exchanged for extra break time to encourage homework).
- 1 mark for explaining how negative reinforcement works (e.g., removing an unpleasant stimulus to increase behavior).
- 1 mark for linking negative reinforcement to the scenario (e.g., earning enough tokens removes the requirement to attend a weekend catch-up session).

**Part B (4.5 marks):**
- 1.5 marks for calculating the observed value of \(S = 1\) (0.5 marks for indicating plus/minus signs, 1 mark for identifying the lower frequency sign as 1).
- 1 mark for stating that \(N = 7\) because the tie/zero-difference score of Student 2 is omitted.
- 2 marks for determining significance (1 mark for stating that the observed value of \(S = 1\) is equal to or less than the critical value of 1; 1 mark for concluding that the difference is statistically significant).
題目 3 · Short Answer & Calculation
8.5
An experimenter, Jack, replicates Pavlov's salivary conditioning with dogs. He wants to evaluate the strength and consistency of the conditioned response in his canine subjects.

**Part A (4 marks):** Describe how Jack could use the classical conditioning processes of extinction and spontaneous recovery to demonstrate the strength of the conditioned response in the dogs.

**Part B (4.5 marks):** Jack collects saliva volumes (in ml) from a group of 5 dogs in response to the conditioned stimulus (a metronome) alone. The recorded volumes are: 12, 15, 8, 14, 11.

Calculate the standard deviation for this sample of saliva volumes. Show your workings. Round your answer to two decimal places.

Formula:
\(s = \sqrt{\frac{\sum(x - \bar{x})^2}{n - 1}}\)
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解題

**Part A (4 marks):**
- **Extinction:** Jack can repeatedly present the conditioned stimulus (metronome) without the unconditioned stimulus (food). If the saliva volume decreases and eventually stops, extinction has occurred, demonstrating that the conditioned association depends on continuous reinforcement.
- **Spontaneous Recovery:** After extinction and a rest period, Jack can present the metronome again. If the dogs salivate without any food pairings, this shows spontaneous recovery, proving that the original association was not completely erased but temporarily suppressed.

**Part B (4.5 marks):**
1. Calculate the mean (\(\bar{x}\)) of the saliva volumes:
\(\bar{x} = \frac{12 + 15 + 8 + 14 + 11}{5} = \frac{60}{5} = 12.00\text{ ml}\)

2. Calculate the deviation of each score from the mean \((x - \bar{x})\) and square them:
- \((12 - 12)^2 = 0^2 = 0\)
- \((15 - 12)^2 = 3^2 = 9\)
- \((8 - 12)^2 = (-4)^2 = 16\)
- \((14 - 12)^2 = 2^2 = 4\)
- \((11 - 12)^2 = (-1)^2 = 1\)

3. Sum the squared deviations \(\sum(x - \bar{x})^2\):
\(\sum(x - \bar{x})^2 = 0 + 9 + 16 + 4 + 1 = 30\)

4. Divide by \(n - 1\) (where \(n = 5\), so \(n - 1 = 4\)) to find variance:
\(\text{Variance} = \frac{30}{4} = 7.50\)

5. Calculate the square root of the variance to find the standard deviation:
\(s = \sqrt{7.50} \approx 2.7386\)

6. Round to two decimal places: **2.74**

評分準則

**Part A (4 marks):**
- 1 mark for describing the process of extinction (presenting CS without UCS).
- 1 mark for linking extinction to the scenario (metronome presented without food, causing saliva to stop).
- 1 mark for describing spontaneous recovery (reappearance of the CR after extinction and a rest period).
- 1 mark for linking spontaneous recovery to the scenario (dog salivates again to the metronome after a delay/rest, showing association remains).

**Part B (4.5 marks):**
- 1 mark for calculating the correct mean of 12.00 ml.
- 1 mark for calculating the correct sum of squared deviations (30) with clear workings shown.
- 1 mark for dividing by \(n - 1\) (4) to get the variance of 7.50.
- 1 mark for calculating the square root of 7.50 to yield 2.74.
- 0.5 marks for rounding correctly to two decimal places.
題目 4 · Essay
8
Evaluate systematic desensitisation as a treatment for phobias.
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解題

Systematic desensitisation (SD) is a behaviourist therapy designed to reduce phobic anxiety through classical conditioning, where a new response of relaxation is paired with the phobic stimulus (counterconditioning). First, the therapist teaches the client relaxation techniques, such as deep muscle relaxation and controlled breathing, because of reciprocal inhibition—the idea that one cannot be both anxious and relaxed at the same time. Next, they construct an anxiety hierarchy, which is a list of situations involving the phobic stimulus ranked from least to most fear-inducing. Finally, the client is exposed to these situations gradually, either in imagination (in vitro) or real life (in vivo), while practicing their relaxation techniques, progressing to the next stage only when they are completely relaxed at the current level. In terms of evaluation, SD is supported by research showing its clinical effectiveness. For instance, Capafons et al. (1998) found that aerophobics treated with SD showed significant reductions in fear during a flight simulator compared to a control group, demonstrating its real-world utility. Furthermore, SD is generally preferred by patients over alternative treatments like flooding because it is less traumatic. This is reflected in lower attrition (drop-out) rates and higher patient satisfaction, making it a more ethical and viable treatment option. However, SD is less effective for complex or evolutionary phobias (such as fear of the dark or social phobias) that do not stem from a simple learned association, where cognitive therapies (CBT) may be more appropriate to address maladaptive thought patterns. Additionally, psychodynamic theorists argue that SD only treats the symptoms rather than the root cause of the phobia, which could lead to symptom substitution, where another fear or issue arises in its place because the underlying conflict remains unresolved.

評分準則

AO1 (4 marks): Candidates should demonstrate accurate and detailed psychological knowledge of systematic desensitisation. Up to 4 marks can be awarded for describing: counterconditioning (pairing fear with relaxation), reciprocal inhibition, relaxation techniques (deep breathing), creation of an anxiety hierarchy, and gradual exposure (in vivo/in vitro) up the hierarchy. AO3 (4 marks): Candidates should evaluate the treatment. Up to 4 marks can be awarded for: evidence of effectiveness (e.g., Capafons et al., 1998; McGrath et al., 1990), comparison to flooding (lower attrition, more ethical/less distressing), limitations in treating evolutionary or complex phobias, and the issue of symptom substitution if the root cause is not addressed. Marking Grid: - Level 1 (1-2 marks): Demonstrates isolated or limited knowledge (AO1). Evaluation is generic or very basic (AO3). - Level 2 (3-4 marks): Demonstrates some accurate knowledge but lacks depth (AO1). Evaluation has some relevance but is unbalanced or lacks development (AO3). - Level 3 (5-6 marks): Demonstrates detailed and accurate knowledge (AO1). Evaluation is developed, mostly balanced, and shows logical chains of reasoning (AO3). - Level 4 (7-8 marks): Demonstrates precise and comprehensive knowledge (AO1). Evaluation is fully developed, highly relevant, and presents well-structured, logical chains of reasoning throughout (AO3).

WPS02/01 部分 C: Integrative Evaluation

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2 題目 · 28
題目 1 · essay
12
Evaluate biological psychology and learning theories as explanations of human aggression.
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解題

Biological psychology explains human aggression through physiological mechanisms. The limbic system, particularly the amygdala, is responsible for processing emotions and triggering aggressive responses. The prefrontal cortex regulates these impulses; deficits in this region are associated with poor self-control and increased impulsivity. Hormones like testosterone are also implicated, with higher levels correlating with dominant and competitive behaviors. Conversely, learning theories suggest aggression is acquired through environmental interactions. Operant conditioning posits that aggressive behavior is repeated if it is directly reinforced (e.g., acquiring resources through physical dominance). Social Learning Theory (SLT) highlights observation and imitation of aggressive role models. Through attention, retention, reproduction, and motivation (e.g., vicarious reinforcement), individuals learn specific aggressive behaviors. In evaluating these approaches, biological theories are supported by neuroimaging evidence. Raine et al. (1997) found reduced glucose metabolism in the prefrontal cortex of murderers pleading not guilty by reason of insanity, demonstrating a physical link to violence. However, biological explanations are reductionist as they ignore social contexts and cognitive appraisals. Learning theories are supported by Bandura, Ross, and Ross (1961), who demonstrated that children copy aggressive models. Yet, these lab experiments lack ecological validity, as hitting a Bobo doll does not equate to hurting a human. Additionally, learning theories are environmentally deterministic, neglecting innate predispositions such as the MAOA gene. Ultimately, an interactionist view is superior, suggesting biological factors create a predisposition to aggression, which is then shaped, triggered, or suppressed by environmental learning experiences.

評分準則

AO1 (6 marks): Candidates demonstrate accurate, relevant, and detailed knowledge of both biological and learning explanations of aggression. Up to 3 marks for biological points (e.g., role of testosterone, prefrontal cortex, amygdala) and up to 3 marks for learning points (e.g., positive reinforcement of aggression, SLT stages of attention, retention, reproduction, motivation, vicarious reinforcement). AO3 (6 marks): Candidates evaluate both approaches, presenting a balanced and logical argument with clear conclusions. Points include supporting research (Raine et al. for biology; Bandura et al. for learning), methodological criticisms (low ecological validity of Bobo doll studies, correlational nature of hormone research), and conceptual debates (nature vs nurture, reductionism, and the strength of an interactionist model). Level 1 (1-3 marks): Superficial knowledge with minimal evaluation. Unbalanced. Level 2 (4-6 marks): Basic knowledge with limited evaluation. Lacks clear structure. Level 3 (7-9 marks): Good, detailed knowledge with a logical evaluation of both theories. Mostly structured. Level 4 (10-12 marks): Excellent, comprehensive knowledge and highly balanced, sophisticated evaluation. Leads to a coherent, well-supported conclusion.
題目 2 · essay
16
Evaluate the extent to which research within biological psychology and learning theories is both ethical and reliable.
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解題

This essay requires candidates to demonstrate knowledge and understanding (AO1) and conduct a critical evaluation (AO3) of ethical issues and reliability in both biological psychology and learning theories. AO1 Points: 1. Biological research frequently utilises standardized scanning technologies like fMRI and PET scans, which offer objective and replicable measurements, or genetic studies utilizing twins reared apart. 2. Learning theories historically rely on animal models (such as Skinner boxes) and human laboratory experiments (such as Bandura's Bobo doll studies) that employ highly structured, standardized environments. 3. Ethical guidelines dictate that researchers must protect participants (human or animal) from physical and psychological harm, obtain informed consent, and maintain confidentiality. AO3 Points: 1. In biological psychology, brain scans like those used by Raine et al. (1997) demonstrate high reliability due to the standardized CPT task and PET imaging protocol, yet they raise ethical issues around socially sensitive findings and labelling of vulnerable clinical populations. 2. Biological research using animals provides high reliability through absolute control over confounding variables, but causes significant ethical concerns regarding physical harm and distress. 3. In learning theories, Bandura's experiments had exceptionally high inter-rater reliability due to standardized modeling behaviors and pre-determined rating scales, but they deliberately exposed young children to aggression, raising significant concerns about the psychological harm and lack of protection. 4. Watson and Rayner's (1920) study on Little Albert is notoriously unethical as they conditioned a phobia without deconditioning it, which simultaneously makes the study impossible to ethically replicate, thereby limiting its reliability as a one-off case study. Conclusion: Both biological psychology and learning theories show a clear tension where maximizing reliability through highly artificial, standardized conditions often compromises ethical treatment or ecological validity, needing careful balance.

評分準則

AO1 (6 marks): Demonstrates precise and thorough knowledge of research methods, ethics, and reliability across biological psychology and learning theories. AO3 (10 marks): Offers a balanced, sophisticated evaluation that directly compares ethical standards and reliability issues, showing how scientific rigour and ethical compliance interact. Levels-Based Marking Scheme: Level 4 (13-16 marks): Accurate and thorough knowledge (AO1) of both ethics and reliability across both fields. Evaluation (AO3) is highly developed, balanced, and logical throughout. Level 3 (9-12 marks): Mostly accurate knowledge (AO1). Evaluation (AO3) is logical but may have minor imbalances between topics or debates. Level 2 (5-8 marks): Limited knowledge (AO1) with superficial points. Evaluation (AO3) lacks depth, contains logical gaps, or focuses heavily on one aspect. Level 1 (1-4 marks): Isolated, descriptive points with little to no analytical evaluation. Reject responses that completely omit one of the fields (biological or learning theories) from reaching Levels 3 or 4.

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