Cambridge IGCSE · thinka 原创模拟试题

2025 Cambridge IGCSE Geography (0460) 模拟试题及答案详解

Thinka Jun 2025 (V3) Cambridge IGCSE-Style Mock — Geography (0460)

195 285 分钟2025
An original Thinka practice paper modelled on the structure and difficulty of the Jun 2025 (V3) Cambridge IGCSE Geography (0460) paper. Not affiliated with or reproduced from Cambridge.

Paper 13 Geographical Themes

Answer three questions in total, choosing one from each of the three thematic sections.
26 题目 · 70.5
题目 1 · Short response
1.5
State what is meant by the term drainage basin and name the highland boundary that separates two adjacent drainage basins.
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解题

A drainage basin (catchment area) is the entire geographic area of land drained by a river system and all of its tributaries. The boundary line or ridge of high land separating one drainage basin from an adjoining one is known as a watershed (or interfluve / drainage divide).

评分标准

Definition of drainage basin: Area of land drained by a river and its tributaries / catchment area of a river system. [1 mark]; Name of boundary: Watershed / divide / ridge line / interfluve. [0.5 mark]
题目 2 · Short response
1.5
Define what is meant by the term *drainage basin* and state the term used for the boundary that separates two adjacent drainage basins.
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解题

A drainage basin refers to the catchment area or total area of land drained by a river system (a river and all of its tributaries). The boundary that marks the perimeter of a drainage basin and divides it from neighboring drainage basins is known as a watershed (or drainage divide).

评分标准

• Definition of drainage basin: Area of land / catchment drained by a river and its tributaries [1 mark]
• Boundary name: Watershed / drainage divide / interfluve [0.5 mark]
题目 3 · Short response
1.5
State one physical attraction and two human attractions that draw tourists to coastal resort destinations.
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解题

Physical attractions are natural features that appeal to tourists, such as sandy beaches, warm and sunny weather, clear ocean water, dramatic coastal cliffs, or offshore coral reefs. Human attractions are built or cultural features, including water parks, holiday resorts and hotels, marinas and water sports rental centres, seaside piers, seafood restaurants, and historic lighthouses or coastal castles.

评分标准

• One valid physical attraction (e.g. sandy beaches / warm weather / calm sea / scenic cliffs / coral reefs) [0.5 mark]
• Two valid human attractions (e.g. water sports facilities / hotels / theme parks / pier / historical monuments / restaurants) [2 @ 0.5 marks = 1 mark]
题目 4 · short_response
1.5
Define the term hydraulic action in the context of river erosion and state one condition where this process operates most effectively.
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解题

Hydraulic action refers to the mechanical erosion of river beds and banks driven by the physical force of moving water trapping and compressing air within cracks until rock fragments detach. This process reaches peak effectiveness when river energy is greatest, such as during high discharge or flood events, or where bank material contains open joints and weaknesses.

评分标准

1 mark for definition: The physical force/power of moving water compressing air into cracks in the river bed and banks, weakening/dislodging rock fragments (allow: force of water alone dislodging material). 0.5 mark for condition: High river velocity / high discharge / flood conditions / presence of unconsolidated or heavily jointed rock.
题目 5 · short_response
1.5
Define the term longshore drift and name the coastal depositional landform that typically forms where longshore drift extends sediment out past a sudden bend or change in coastline orientation.
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解题

Longshore drift is the movement of beach material along the coast driven by prevailing wind-driven oblique swash and gravitational 90-degree backwash. When this process transports sediment beyond an abrupt change in the direction of the coast into open water, a spit is formed.

评分标准

1 mark for definition: The movement/transport of sediment along the coast/beach in a zig-zag pattern caused by swash at an angle (aligned with prevailing wind) and backwash perpendicular/at right angles to the shore. 0.5 mark for landform: Spit / sand spit / recurved spit.
题目 6 · short_answer
1.5
State what is meant by the term *infant mortality rate* and identify one reason why it is high in many Low-Income Countries (LICs).
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解题

1. Definition: The number of deaths of infants under one year of age per 1,000 live births per year.
2. Reason for high infant mortality: Insufficient healthcare facilities and trained medical staff, lack of access to clean water and sanitation leading to waterborne diseases, maternal undernutrition, or lack of widespread vaccination programmes.

评分标准

1 mark for precise definition: Number of deaths of children under 1 year (of age) per 1000 live births (per year/annually).
0.5 marks for a valid reason for high infant mortality in LICs: poor healthcare/few doctors/hospitals; lack of clean/safe water; poor sanitation; malnutrition/food shortages; lack of vaccinations/immunisation; high incidence of waterborne/infectious diseases.
题目 7 · short_answer
1.5
Define the coastal process of *hydraulic action* and name one landform produced by coastal erosion.
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解题

1. Hydraulic action is the erosional process where the sheer force of crashing waves traps and compresses air inside cracks, joints, and fissures in a rock face, causing the air to expand explosively as the wave retreats and weakening the rock.
2. Erosional landforms found on rocky coastlines include cliffs, wave-cut notches, wave-cut platforms, caves, arches, stacks, stumps, and blowholes.

评分标准

1 mark for definition: The force/power of waves/water compressing air into cracks/joints in rocks/cliffs causing them to break/weaken.
0.5 marks for named coastal erosional landform: cliff / wave-cut notch / wave-cut platform / cave / arch / stack / stump / headland / blowhole / geo.
题目 8 · Short response
1.5
What is meant by the river process of *hydraulic action*?
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解题

Hydraulic action is a mechanical fluvial erosion process where the sheer pressure and physical impact of moving water dislodges loose materials from the river channel. Additionally, water forced into fissures and cracks traps and compresses air; when the surge subsides, the sudden release of pressure causes explosive cavitation shockwaves that shatter the rock face over time.

评分标准

Award marks based on the following points (up to 1.5 marks):
• The force / sheer power / weight of flowing water dislodging particles or wearing away banks/bed [1 mark];
• Air being forced / trapped into cracks under pressure, expanding and shattering rock / cavitation [0.5 mark (dev)].

Reject: general references to stones rubbing together (attrition/abrasion).
题目 9 · Short response
1.5
Define the term *sphere of influence* in relation to a settlement or service.
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解题

The sphere of influence (or catchment area) is the zone or region served by a settlement or specific urban service (such as a hospital, specialist store, or secondary school), extending as far as people are willing to travel to access its goods and facilities.

评分标准

Award marks based on the following points (up to 1.5 marks):
• Area / zone served by a settlement / shop / service [1 mark];
• Area from which people travel / catchment area / threshold reach to obtain goods/services [0.5 mark (dev)].

Accept: 'catchment area of a settlement or service'.
题目 10 · Short response
1.5
Define the term *river discharge* and state the standard unit used to measure it.
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解题

River discharge refers to the volume of water flowing through a river cross-section per unit of time (usually per second). The standard unit of measurement is cubic metres per second (cumecs) or \(\text{m}^3/\text{s}\).

评分标准

1 mark for definition: volume / amount of water flowing past / through a specific point / cross-section per unit of time / per second; 0.5 marks for unit: cumecs / cubic metres per second / \(\text{m}^3/\text{s}\).
题目 11 · Short response
1.5
State what is meant by the term *infant mortality rate*.
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解题

The infant mortality rate (IMR) is an important demographic indicator defined as the number of babies who die before reaching their first birthday (under 1 year of age), expressed per 1000 live births in a given year.

评分标准

1 mark for: number of deaths of infants / babies / children under 1 year of age (or under 12 months); 0.5 marks for: per 1000 live births (per year / annually).
题目 12 · Short response
1.5
What is meant by the term *river discharge*?
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解题

River discharge refers to the volume of water that moves through a river's cross-section at a given location over a specific unit of time. It is typically expressed in cubic metres per second (\(\text{m}^3/\text{s}\) or cumecs) and is calculated by multiplying the cross-sectional area of the channel by the flow velocity.

评分标准

1 mark for reference to the volume / quantity / amount of water flowing in a channel;
0.5 marks for reference to time unit / rate of flow (e.g. per second / per unit of time / measured in cumecs).
题目 13 · Short response
1.5
Explain how *hydraulic action* erodes coastal cliff faces.
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解题

Hydraulic action is the mechanical erosion caused by the sheer force of moving water. As breaking waves strike a cliff face, pockets of air are forced into fissures and joints, where they become highly compressed. When the wave retreats, this pressure is rapidly released, causing explosive expansion that widens cracks and shatters fragments of rock from the cliff.

评分标准

1 mark for the force/weight of water compressing air into cracks/joints in the cliff face;
0.5 marks for expansion of air / release of pressure shattering or weakening the rock / loosening rock fragments.
题目 14 · short_response
1.5
Define the term *drainage basin* and state the geographical term for the boundary line separating two neighbouring drainage basins.
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解题

A drainage basin is the geographical catchment area drained by a river system (a river and all its tributaries). The high ground or ridge separating one drainage basin from another is known as a watershed (or interfluve / drainage divide).

评分标准

Definition of drainage basin: Area of land drained by a river and its tributaries / catchment area of a river system [1 mark]; Boundary term: Watershed / drainage divide [0.5 marks].
题目 15 · short_response
1.5
What is meant by the demographic term *infant mortality rate*?
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解题

Infant mortality rate (IMR) is defined as the annual number of infant deaths under one year of age per 1000 live births in a given year/population.

评分标准

Number of deaths of children/babies under one year of age [1 mark]; per 1000 live births (per year) [0.5 marks].
题目 16 · Short response
1.5
State what is meant by the term river discharge and state one unit in which it is measured.
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解题

River discharge refers to the volume of water flowing past a specific point along a river channel in a given period of time (usually per second). The standard unit of measurement used in hydrology is cubic metres per second, commonly abbreviated as cumecs (\(m^3/s\)).

评分标准

Definition: 1 mark for stating volume/amount of water flowing through a channel/point per unit of time / per second.
Unit: 0.5 marks for cumecs / cubic metres per second / \(m^3/s\) / cubic feet per second (cusecs).
题目 17 · Short response
1.5
Define the term infant mortality rate and identify one development that helps to lower it.
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解题

Infant mortality rate (IMR) is defined as the annual number of deaths of children under the age of one year per 1,000 live births in a population. It decreases when basic living standards improve, such as through widespread childhood immunization programmes, better access to sanitized drinking water, or improved prenatal and postnatal clinical care.

评分标准

Definition: 1 mark for number of deaths of babies/children under 1 year of age per 1000 live births (per year).
Development: 0.5 marks for any valid factor, e.g. immunization/vaccination programmes / clean water supply / trained midwives/doctors / better nutrition / maternal education.
题目 18 · Structured data analysis
4
Study Table 1.1, which shows demographic data for four countries in 2024.

Table 1.1
| Country | Birth rate (per 1000) | Death rate (per 1000) | Infant mortality rate (per 1000 live births) | Life expectancy (years) |
| :--- | :--- | :--- | :--- | :--- |
| Country W | 38.2 | 11.5 | 54.0 | 58 |
| Country X | 19.4 | 6.8 | 14.2 | 74 |
| Country Y | 9.8 | 10.4 | 3.1 | 82 |
| Country Z | 10.1 | 9.6 | 3.8 | 81 |

(a) Identify the country in Table 1.1 that is experiencing natural population decrease. [1]

(b) Using Table 1.1 only, compare the demographic characteristics of Country W with Country Z. Do not use statistics in your answer. [3]
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解题

(a) Country Y is the only country where the death rate (10.4 per 1000) exceeds the birth rate (9.8 per 1000), resulting in natural decrease (-0.6 per 1000).

(b) Comparative statements without numerical figures:
1. Birth rate: Country W has a higher birth rate than Country Z (or Country Z is lower).
2. Death rate: Country W has a higher death rate than Country Z (or Country Z is lower).
3. Infant mortality: Country W has a higher infant mortality rate than Country Z (or Country Z is lower).
4. Life expectancy: Country W has a lower / shorter life expectancy than Country Z (or Country Z is higher / longer).

评分标准

(a) [1 mark]:
- Country Y; [1]

(b) [3 marks]:
- Ideas such as:
- Birth rate is higher in Country W / lower in Country Z;
- Death rate is higher in Country W / lower in Country Z;
- Infant mortality rate is higher in Country W / lower in Country Z;
- Life expectancy is lower / shorter in Country W / higher / longer in Country Z;

Note: Award maximum 3 marks. Do not credit responses that simply quote raw statistics without direct comparative terms (e.g. higher, lower, greater, shorter).
题目 19 · Structured data analysis
4
Study Table 2.1, which shows storm hydrograph measurements recorded at two monitoring stations, Station A (forested catchment) and Station B (urbanized catchment), following an identical 45 mm rainfall event.

Table 2.1
| Measurement | Station A (Forested) | Station B (Urbanized) |
| :--- | :--- | :--- |
| Peak discharge (\(\text{m}^3/\text{s}\)) | 18 | 62 |
| Lag time (hours) | 16 | 3 |
| Gradient of rising limb | Gentle / gradual | Steep / rapid |
| Baseflow contribution (\(\%\)) | 72 | 24 |

(a) Using Table 2.1, describe two differences between the hydrograph recorded at Station A and Station B. [2]

(b) Explain why urban development in a river catchment results in a shorter lag time and higher peak discharge. [2]
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解题

(a) Full comparative description matching two distinct parameters from Table 2.1 (e.g., peak discharge is much higher at Station B than Station A; lag time is much shorter at Station B than Station A).

(b) Explanatory points:
1. Buildings and paved roads replace permeable soil/vegetation with impermeable surfaces, reducing infiltration and increasing the volume and speed of surface runoff.
2. Storm drains, gutters, and lined channels channel rainwater rapidly and directly into river tributaries without delay.

评分标准

(a) [2 marks]:
- Peak discharge is higher at Station B / lower at Station A;
- Lag time is shorter at Station B / longer at Station A;
- Rising limb is steeper/faster at Station B / gentler/slower at Station A;
- Baseflow contribution is lower at Station B / higher at Station A;
(2 @ 1 mark)

(b) [2 marks]:
- Ideas such as:
- Presence of impermeable surfaces / tarmac / concrete / roofs (1);
- Reduced infiltration / percolation into soil (1);
- Increased surface runoff / overland flow (1);
- Drains / gutters / sewers transport water rapidly into river channel (1);
- Lack of vegetation / trees reduces interception / plant uptake (1);
(2 @ 1 mark or 1 mark + 1 dev mark)
题目 20 · structured
4
Study Table 1.1, which shows demographic data for two countries in 2023.

Table 1.1
| Demographic indicator | Country P | Country Q |
| :--- | :--- | :--- |
| Birth rate (per 1000 people) | 34.8 | 9.6 |
| Death rate (per 1000 people) | 7.2 | 10.4 |
| Infant mortality rate (per 1000 live births) | 44.0 | 3.2 |
| Life expectancy at birth (years) | 63.5 | 82.1 |

Using Table 1.1, compare the demographic characteristics of Country P and Country Q. You must refer to statistics in your answer.
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解题

To compare the demographic characteristics, state direct comparisons for the indicators and support them with data:
1. Birth rate: Country P has a higher birth rate (34.8 per 1000) than Country Q (9.6 per 1000).
2. Death rate: Country P has a lower death rate (7.2 per 1000) than Country Q (10.4 per 1000).
3. Infant mortality rate: Country P is higher with 44.0 per 1000 live births compared to 3.2 per 1000 live births in Country Q.
4. Life expectancy: Country Q has a higher life expectancy (82.1 years) than Country P (63.5 years).
5. Natural population change: Country P is experiencing natural population growth (natural increase of 27.6 per 1000), whereas Country Q is experiencing natural population decrease (natural decrease of 0.8 per 1000).

评分标准

Ideas such as:
- Country P has a higher birth rate / Country Q has a lower birth rate;
- Country P has a lower death rate / Country Q has a higher death rate;
- Country P has natural increase / population is growing naturally whereas Country Q has natural decrease / population is declining naturally;
- Country P has a higher infant mortality rate / Country Q has a lower infant mortality rate;
- Country Q has a higher life expectancy / Country P has a lower life expectancy.

Note: Maximum 3 marks if no statistics are used.
1 mark reserve for paired statistical comparison with units (e.g. birth rate of 34.8 per 1000 in Country P compared to 9.6 per 1000 in Country Q / life expectancy of 82.1 years in Country Q compared to 63.5 years in Country P).
Do not accept simple listing of numbers without comparative words.
题目 21 · structured
4
Study Table 2.1, which shows data collected at four sampling sites along the River Veda from upstream (Site 1) to downstream (Site 4).

Table 2.1
| Variable measured | Site 1 | Site 2 | Site 3 | Site 4 |
| :--- | :--- | :--- | :--- | :--- |
| Channel width (m) | 2.4 | 5.8 | 11.2 | 18.6 |
| Channel depth (m) | 0.3 | 0.7 | 1.2 | 1.9 |
| Average water velocity (m/s) | 0.35 | 0.52 | 0.74 | 0.98 |
| Average bedload particle diameter (cm) | 12.5 | 6.8 | 2.4 | 0.5 |

Using Table 2.1 only, describe the changes in the channel characteristics and bedload of the River Veda from Site 1 to Site 4. You must refer to data in your answer.
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解题

Identify trends from Site 1 (upstream) to Site 4 (downstream) and back each statement with accurate data:
1. Channel width increases downstream (from 2.4 m at Site 1 to 18.6 m at Site 4).
2. Channel depth increases downstream (from 0.3 m at Site 1 to 1.9 m at Site 4).
3. Water velocity increases downstream (from 0.35 m/s at Site 1 to 0.98 m/s at Site 4).
4. Bedload particle size/diameter decreases downstream (from 12.5 cm at Site 1 to 0.5 cm at Site 4).

评分标准

Ideas such as:
- Channel width increases (downstream) / is wider at Site 4;
- Channel depth increases (downstream) / is deeper at Site 4;
- Channel cross-sectional area increases / wetted perimeter increases;
- Average velocity increases (downstream) / water flows faster at Site 4;
- Average bedload particle size / diameter decreases (downstream) / particles are smaller at Site 4.

Note: Maximum 3 marks if no data / statistics are included.
1 mark reserve for paired data or overall change with correct units (e.g. width increases from 2.4 m to 18.6 m / bedload diameter decreases by 12.0 cm / from 12.5 cm to 0.5 cm / velocity increases from 0.35 m/s to 0.98 m/s).
题目 22 · Structured data analysis
4
Study Table 1.1, which shows demographic data for four countries (A, B, C and D) in 2024.

Table 1.1
Country | Birth rate (per 1000) | Death rate (per 1000) | % Population aged 65 and over | Life expectancy (years)
Country A | 36.5 | 9.2 | 3.4 | 61
Country B | 19.8 | 6.1 | 7.2 | 74
Country C | 12.4 | 9.5 | 16.8 | 79
Country D | 8.6 | 11.8 | 22.5 | 83

(i) Name the country in Table 1.1 with the highest rate of natural increase. [1]
(ii) Calculate the rate of natural population change per 1000 people for Country D. State clearly whether it is an increase or decrease. [1]
(iii) Using Table 1.1 and your own knowledge, suggest two reasons why Country D has a higher death rate than Country B despite having a higher life expectancy. [2]
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解题

(i) Rate of natural increase = Birth rate - Death rate.
For Country A: \(36.5 - 9.2 = 27.3\) per 1000 (highest).
For Country B: \(19.8 - 6.1 = 13.7\) per 1000.
For Country C: \(12.4 - 9.5 = 2.9\) per 1000.
For Country D: \(8.6 - 11.8 = -3.2\) per 1000.
Therefore, the answer is Country A.

(ii) Rate of natural population change for Country D = \(8.6 - 11.8 = -3.2\) per 1000 (or a natural decrease of 3.2 per 1000).

(iii) Country D has a significantly higher proportion of elderly residents (22.5% aged 65 and over vs 7.2% in Country B). A larger elderly population naturally experiences more deaths due to old age and degenerative illnesses, raising the overall crude death rate despite better healthcare and higher life expectancy. In contrast, Country B has a younger age structure with fewer elderly people at risk of dying.

评分标准

(i) Country A [1]

(ii) -3.2 (per 1000) / natural decrease of 3.2 (per 1000) / decrease of 3.2 [1]
Note: Must indicate negative or state 'decrease'.

(iii) Ideas such as:
- Country D has an ageing population / higher proportion of people aged 65+ / higher proportion of elderly (or comparative data: 22.5% vs 7.2%); [1]
- Older people are more likely to die of natural causes / degenerative diseases / old age; [1]
- Country B has a younger population structure / smaller proportion of elderly people so fewer people at risk of dying. [1]
(2 @ 1 mark)
题目 23 · Structured data analysis
4
Study Table 2.1, which shows river channel data recorded at four survey sites along a 40 km river from source to mouth.

Table 2.1
Site | Distance from source (km) | Average width (m) | Average depth (m) | Average velocity (m/s) | Cross-sectional area (m²)
Site 1 (Upper course) | 3 | 1.8 | 0.25 | 0.42 | 0.45
Site 2 (Upper-middle) | 12 | 4.6 | 0.60 | 0.58 | 2.76
Site 3 (Lower-middle) | 26 | 11.2 | 1.15 | 0.74 | 12.88
Site 4 (Lower course) | 38 | 24.5 | 2.30 | 0.89 | 56.35

(i) State the average width of the river channel at Site 2. [1]
(ii) Describe the relationship shown in Table 2.1 between distance from source and cross-sectional area. [1]
(iii) Explain two reasons why average velocity increases downstream between Site 1 and Site 4. [2]
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解题

(i) From Table 2.1, the average width at Site 2 is 4.6 m.

(ii) There is a direct / positive relationship: as the distance from the source increases from 3 km to 38 km, the cross-sectional area increases steadily from 0.45 m² to 56.35 m².

(iii) Velocity increases downstream because:
1. The river channel becomes smoother as bedload particles are smaller and rounder (due to attrition), reducing friction against the bed and banks (increased hydraulic radius / channel efficiency).
2. Tributaries join the main channel downstream, increasing total discharge and water mass, which allows the water to flow faster with less proportional energy lost to channel friction.

评分标准

(i) 4.6 (m) [1]

(ii) Positive relationship / direct relationship / as distance (from source) increases, cross-sectional area increases (or vice versa); [1]

(iii) Ideas such as:
- Channel becomes smoother / bed material is smaller / rounder (due to attrition); [1]
- Less friction / less resistance from the wetted perimeter / bed and banks; [1]
- River becomes more hydraulically efficient / higher hydraulic radius; [1]
- Greater discharge / volume of water added by tributaries (creates greater momentum); [1]
- Less turbulence in the lower course compared to boulder-strewn upper course. [1]
(2 @ 1 mark)
题目 24 · extended_writing
7
For a named area of coastline you have studied, explain how it is managed to protect it from coastal erosion.

Name of coastal area .................................................................
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解题

Example case study: Holderness Coast (East Yorkshire, UK)

Level 1 (1–3 marks):
- They built sea walls to stop waves hitting the cliffs.
- Groynes were placed along the beach to catch sand.
- Rock armour was put at the base of the cliffs.

Level 2 (4–6 marks):
- Timber groynes were installed at Hornsea to trap sediment moved by longshore drift, creating wider beaches that absorb wave energy and reduce cliff scouring (L2).
- A large curved concrete sea wall was constructed at Withernsea to reflect destructive storm wave energy back out to sea, protecting the vulnerable glacial till cliffs behind it (L2).
- Rip-rap (granite rock armour) imported from Norway was placed around Easington gas terminal to dissipate incoming wave impact and prevent erosion threatening critical national infrastructure (L2).
- Soft engineering such as cliff re-profiling and vegetation planting at select locations stabilizes the boulder clay and reduces slumping caused by heavy rainfall infiltration (L2).

Level 3 (7 marks):
Must include at least three developed points (Level 2) plus accurate place-specific details.
Example place-specific details for Holderness: Boulder clay / glacial till cliffs, North Sea storm surges, specific settlements (Mappleton, Hornsea, Withernsea), Easington gas terminal, £2 million coastal protection scheme at Mappleton with two rock groynes and rock revetments.

评分标准

Levels of response marking:

Level 1 (1–3 marks):
1, 2 or 3 simple statements identifying management strategies used to protect a coastline.
(e.g. Sea walls were built; rock armour was placed on the beach; groynes trap sand; beach nourishment was used.)

Level 2 (4–6 marks):
1, 2 or 3 developed statements explaining how specific coastal management strategies reduce erosion.
(e.g. Concrete recurved sea walls are built at the foot of cliffs to deflect wave energy back towards the sea, preventing hydraulic action from cutting wave-cut notches into the cliff base (L2); Wooden groynes installed perpendicular to the shoreline intercept longshore sediment transport, building up a wider sandy beach that dissipates wave energy before it reaches the cliffs (L2).)

Note: Maximum 5 marks if no named example or inappropriate example is used.

Level 3 (7 marks):
At least 3 developed (L2) statements plus comprehensive place-specific detail (e.g. named locations along the coastline, specific engineering project names/costs, rock types, local coastal features).
题目 25 · Extended case study writing
7
For a named coastal area you have studied, describe the methods used to manage coastal erosion.

Name of coastal area .................................................................
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解题

Level 1 (1–3 marks):
Candidate provides simple, generalized statements describing coastal management methods.
- They built a sea wall to stop waves.
- Groynes were constructed to trap sand.
- Rock armour was put at the bottom of the cliff.

Level 2 (4–6 marks):
Candidate provides developed statements explaining how the methods function or work together to reduce erosion.
- Curved concrete sea walls reflect wave energy back towards the sea, preventing hydraulic action and abrasion from eroding the cliff base.
- Granite groynes intercept sediment moved along the coast by longshore drift, creating a wider sandy beach that dissipates wave energy before it reaches the cliffs.
- Rip-rap consisting of huge, resistant rock boulders absorbs and disperses incoming wave shock, stabilizing the soft clay slopes behind it.

Level 3 (7 marks):
Achieves Level 2 (at least three developed statements) plus a valid named coastal area with comprehensive place-specific detail.

Example Level 3 response:
At the Holderness Coast in East Yorkshire, UK, the coastline consists of unconsolidated boulder clay eroding at approximately 2 metres per year. At Mappleton, the B1242 road and local properties were protected in 1991 by building two rock groynes and a revetment using massive Norwegian granite at a cost of £2 million. The groynes trapped sediment moved by longshore drift, building up a wide beach that absorbs destructive wave energy. At Hornsea, a recurved concrete sea wall and timber groynes protect the town's holiday amenities and promenade by deflecting waves. Further south at Withernsea, rip-rap and offshore breakwaters reduce wave impact on the cliffs. In areas of lower-value farmland, such as near Cowden, managed retreat has been implemented because defending agricultural fields is not economically justified.

评分标准

Levels of response marking:

Level 1 (1–3 marks):
- 1 simple statement = 1 mark
- 2 simple statements = 2 marks
- 3 or more simple statements = 3 marks
Statements are basic descriptions of coastal management methods without explanation of processes.

Level 2 (4–6 marks):
- 1 developed statement = 4 marks
- 2 developed statements = 5 marks
- 3 or more developed statements = 6 marks
Statements describe management schemes with developed explanations of how the engineering techniques reduce erosion (e.g., dissipating wave energy, trapping sediment from longshore drift).
Note: Max 5 marks if no named example or inappropriate example.

Level 3 (7 marks):
At least 3 developed (L2) statements + valid named coastal area + accurate place-specific detail (e.g., named settlements like Mappleton/Hornsea, specific materials such as granite boulders/boulder clay, costs like £2 million, or road references like B1242).
题目 26 · Extended case study writing
7
For a named area you have studied where tourism is important, explain how tourism is managed to reduce its negative impacts on the natural environment.

Name of area .................................................................................
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解题

Example Case Study: Galapagos Islands, Ecuador

1. Strict zoning and designated boardwalks/trails: Marked trails on islands such as Santa Cruz and Isabela prevent visitors from trampling fragile endemic flora (like lava cactus) and avoid disturbing the nesting habitats of blue-footed boobies and marine iguanas.

2. Mandatory licensed naturalist guides: Tour groups are legally limited to a maximum ratio of 16 tourists per licensed guide. Guides enforce park rules, ensuring visitors maintain a 2-metre distance from wildlife, do not introduce foreign seeds or food, and do not remove coral or volcanic rocks.

3. Regulated cruise vessel itineraries: The Galapagos National Park Directorate and INGALA enforce fixed, non-overlapping 14-day itinerary loops for tourist boats. This distributes tourist density across different islands (such as Genovesa and Fernandina), preventing sewage and anchor damage from concentrating in specific marine and coastal ecosystems.

4. Ecotourism fees and biosecurity checks: A mandatory entry fee ($100–$200 for international visitors) directly funds conservation management and eradication of invasive species (e.g., feral goats and rats). Rigorous biosecurity inspections at Baltra and San Cristóbal airports prevent new alien species from being introduced to the archipelago.

评分标准

Levels of response marking:

Level 1 (1–3 marks)
Simple statements describing management strategies and/or environmental problems caused by tourism.
• Paths are paved/fenced off.
• Tourists must stay with a guide.
• Limits are placed on tourist numbers.
• Rubbish bins and recycling are provided.
• Visitors pay an entrance fee.

Level 2 (4–6 marks)
Developed statements explaining HOW strategies work to reduce/prevent negative environmental impacts.
• Designated stone paths or boardwalks are laid so that walkers do not trample surrounding vegetation, preventing soil compaction and erosion. (1 × L2)
• Tour groups must be accompanied by qualified guides who enforce a minimum distance from wildlife, preventing animals from being stressed and abandoning nests. (1 × L2)
• Ships are required to follow fixed rotational cruising schedules so that marine pollution and anchor damage to coral reefs are not concentrated in one bay. (1 × L2)
• National park entry fees are reinvested into hiring wardens and funding conservation programmes to remove invasive species. (1 × L2)

Marks within Level 2:
• 1 developed statement = 4 marks
• 2 developed statements = 5 marks
• 3 or more developed statements = 6 marks
(Note: Maximum 5 marks if no named example or an inappropriate example is used).

Level 3 (7 marks)
Achieves Level 2 (at least 3 developed statements) PLUS comprehensive place-specific detail (e.g., named locations/islands, precise agencies, specific wildlife species, numerical quotas, or authentic local infrastructure).

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Paper 23 Geographical Skills

Answer all questions. Use the provided topographic map extract to complete the main geographical interpretation task.
7 题目 · 68
题目 1 · Topographic map reading
20
Study the 1:50 000 topographic map extract of the Glen Isla and Port Dunmore region (Fig. 1.1).

(a) (i) Identify the feature found at grid reference 342678. [1]
(ii) State the six-figure grid reference of the post office (PO) in Dunmore village. [1]
(iii) State the height above sea level, in metres, of the spot height located at 381654. [1]

(b) (i) Measure the distance along the main road (A412) from the road bridge at 324651 to the road junction at 368673. Give your answer in kilometres. [1]
(ii) State the compass direction from Mount Craig (315682) to the lighthouse at Dunmore Head (378625). [1]
(iii) State the bearing, in degrees, from the trigonometrical station at 334690 to the church with a tower at 358662. [1]

(c) (i) Describe the physical features of the Glen Isla River between easting 310 and easting 370. [4]
(ii) Describe the relief of the area north of northing 68. [3]

(d) (i) Identify two types of natural vegetation found in the south-western part of the map extract (south of northing 64 and west of easting 34). [2]
(ii) Describe the distribution and pattern of settlement in the map extract. [4]

(e) Suggest two physical factors that have influenced the growth and site of the port settlement at Port Dunmore (3663). [2]
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解题

(a) (i) At grid reference 342678, the symbol represents a quarry / gravel pit / excavation.
(ii) The post office (PO) symbol in Dunmore is located at easting 364 and northing 632, giving a 6-figure grid reference of 364632.
(iii) The spot height at 381654 is marked with the number 184 (184 metres above sea level).

(b) (i) Measuring the curving distance of the A412 road between 324651 and 368673 using a straight edge of paper gives 11.2 cm on the map. At a scale of 1:50 000 (2 cm = 1 km), this equals 5.6 km (acceptable tolerance 5.4 km to 5.8 km).
(ii) From Mount Craig (315682) towards Dunmore Head (378625), the direction is South-East (SE).
(iii) Measuring the angle clockwise from Grid North between the trig station (334690) and the church tower (358662) gives 146° (acceptable tolerance 144° to 148°).

(c) (i) Glen Isla River features:
- Flows generally from west to east;
- Meanders / winding river course;
- Channel widens towards the east;
- Presence of small river islands / mid-channel bars / braiding;
- Tributaries / confluences join from both north and south;
- Variable gradient / flat floodplain in lower section.

(ii) Relief north of northing 68:
- High relief / mountainous (elevations exceeding 400 m);
- Steep slopes / closely spaced contour lines;
- Deep, narrow V-shaped valleys / ravines;
- Interlocking spurs / narrow ridges;
- Highest elevation at Mount Craig (462 m).

(d) (i) Vegetation in the south-west:
- Coniferous plantation / woodland / forest;
- Rough grassland / scrub / marsh.

(ii) Settlement distribution:
- Main nucleated settlement concentrated at the coast at Port Dunmore;
- Linear settlement along the valley transport corridor / A412 road;
- Dispersed / scattered farmsteads across the lower-lying river valley floor;
- Upland / steep areas north of northing 68 and south-west hills are uninhabited / sparse settlement.

(e) Site factors for Port Dunmore:
- Sheltered coastal bay / inlet providing safe anchorage for boats / natural harbour;
- Low-lying, flat or gently sloping land facilitating building and infrastructure construction;
- River mouth provides freshwater access and a natural low-gradient route into the interior valley.

评分标准

(a) (i) Quarry / excavation / gravel pit [1]
(ii) 364632 [1] (allow easting 363 to 365, northing 631 to 633)
(iii) 184 (metres) [1]

(b) (i) 5.6 (km) [1] (allow 5.4 to 5.8 km)
(ii) South-east / SE [1] (do not allow ESE or SSE)
(iii) 146(°) [1] (allow 144° to 148°)

(c) (i) Award 1 mark per valid physical river feature described up to 4 max:
- Flows west to east / eastward;
- Meanders / winding / sinuous channel;
- Widens towards the east / mouth;
- River islands / eyots / mid-channel bars;
- Tributaries join / confluence(s);
- Oxbow lake / cut-off / floodplain present. [4]

(ii) Award 1 mark per valid relief feature described up to 3 max:
- High land / over 400 m / heights up to 462 m;
- Steep slopes / closely spaced contours;
- Valleys / V-shaped valleys / ravines;
- Ridges / spurs / peaks / Mount Craig. [3]

(d) (i) Award 1 mark per valid vegetation type identified (max 2):
- Coniferous plantation / forest / woodland;
- Scrub / rough grassland / marsh / wetland. [2]

(ii) Award 1 mark per valid point on settlement distribution/pattern up to 4 max:
- Nucleated settlement at Port Dunmore / Dunmore;
- Linear settlement along the main road / A412 / valley base;
- Dispersed / scattered settlement in the river valley floor / lowland area;
- Sparse / absent / no settlement in high upland areas / north of northing 68 / south-west highland. [4]

(e) Award 1 mark per valid physical reason up to 2 max:
- Sheltered bay / inlet / natural harbour for ships / protection from waves;
- Flat / gently sloping land for construction of houses / port infrastructure;
- River mouth / gap in relief providing transport route to inland areas;
- Freshwater supply from the river. [2]
题目 2 · data_response
8
Study Fig. 1.1, which shows storm hydrographs for two contrasting drainage basins, Catchment A (forested catchment) and Catchment B (urbanised catchment), following an identical rainfall event of 45 mm.

(a) (i) State the peak discharge recorded for Catchment B.
.................................................................................................................................... [1]

(ii) Calculate the difference in lag time between Catchment A and Catchment B.
.................................................................................................................................... [1]

(b) Using Fig. 1.1, describe two differences between the hydrograph of Catchment A and Catchment B.
1 ................................................................................................................................
2 ................................................................................................................................ [2]

(c) Explain why the hydrograph for Catchment B has a steeper rising limb and a higher peak discharge than Catchment A.
....................................................................................................................................
....................................................................................................................................
....................................................................................................................................
.................................................................................................................................... [4]
查看答案详解

解题

(a) (i) From Fig. 1.1, the highest point of the hydrograph curve for Catchment B reaches 62 m³/s.
(ii) Peak rainfall occurs at hour 2. Peak discharge for Catchment B occurs at hour 4 (lag time = 4 - 2 = 2 hours). Peak discharge for Catchment A occurs at hour 8 (lag time = 8 - 2 = 6 hours). Difference = 6 - 2 = 4 hours.
(b) Any two comparative observations:
1. Catchment B has a much higher peak discharge than Catchment A (62 m³/s vs 24 m³/s).
2. Catchment B has a shorter lag time than Catchment A (2 hours vs 6 hours).
(c) Explanation points linking urbanisation to hydrological processes:
- Urban areas have impermeable surfaces (concrete, asphalt, rooftops) which stop water infiltrating into the soil.
- This leads to rapid surface runoff / overland flow.
- Storm drains and gutters channel water straight into the river system quickly.
- Forested catchment (Catchment A) has dense canopy interception, higher evapotranspiration, and permeable soil promoting infiltration and slower throughflow.

评分标准

(a) (i) 62 (m³/s) [1]
(ii) 4 (hours) [1]

(b) Maximum 2 marks for comparative statements (do not double-credit opposites):
- Catchment B has higher peak discharge / Catchment A has lower peak discharge;
- Catchment B has shorter lag time / Catchment A has longer lag time;
- Catchment B has steeper rising limb / Catchment A has gentler rising limb;
- Catchment B has steeper / faster falling limb / Catchment A has gentler recession;
- Catchment A has a more elongated / flatter curve overall; [2]

(c) Maximum 4 marks. Award 1 mark for each valid explanatory point linked to processes (up to 4 marks total):
- Catchment B has impermeable / non-porous surfaces (or examples: tarmac / concrete / roofs);
- Less / no infiltration into ground in Catchment B;
- More rapid / increased surface runoff / overland flow;
- Storm drains / sewers / culverts channel water directly and quickly into river;
- Catchment A has vegetation / trees which intercept rainfall (dev);
- Catchment A has higher infiltration / percolation into soil and rock (dev);
- Water in Catchment A moves via slow subsurface routes / throughflow / baseflow (dev); [4]
题目 3 · data_response
8
Study Fig. 2.1, a sketch map showing coastal landforms and human activities along a stretch of coastline.

(a) (i) Identify the coastal landform labelled X at the mouth of the estuary.
.................................................................................................................................... [1]

(ii) Using evidence from Fig. 2.1, state the direction of longshore drift along this coastline.
.................................................................................................................................... [1]

(b) State two conditions required for the formation of coastal landform X.
1 ................................................................................................................................
2 ................................................................................................................................ [2]

(c) Explain how the process of longshore drift transports sediment along the coastline.
....................................................................................................................................
....................................................................................................................................
....................................................................................................................................
.................................................................................................................................... [4]
查看答案详解

解题

(a) (i) Landform X is an elongated ridge of sand/shingle extending from the mainland across part of an estuary mouth, which is a spit.
(ii) The spit extends from west to east across the estuary, showing sediment is moved towards the east.
(b) Spits require: an abundant supply of beach material (sand/shingle), a dominant prevailing wind hitting the coast at an angle, a sudden change in coastline orientation (such as an estuary or river mouth), and relatively calm/shallow water where deposition can occur.
(c) Longshore drift step-by-step process:
1. Waves approach the coastline at an oblique angle dictated by the prevailing wind direction.
2. The swash carries pebbles and sand diagonally up the beach at this angle.
3. The backwash carries the sediment directly back down the slope of the beach at 90° (right angle) to the shoreline due to gravity.
4. This repetitive zig-zag motion transports sediment continuously along the coastline in one direction.

评分标准

(a) (i) Spit / sand spit / recurved spit; [1]
(ii) West to East / Eastward(s) / toward the East / E; [1]

(b) Maximum 2 marks for conditions required:
- Oblique / angled prevailing wind;
- Plentiful supply of sand / shingle / sediment;
- Change in the direction / shape of coastline (e.g. bay, estuary mouth);
- Presence of shallow water / gentle gradient;
- Constructive waves / low wave energy / sheltered coastal water; [2]

(c) Maximum 4 marks. Award marks for sequential explanation of the physical mechanism:
- Waves approach beach at an angle / oblique angle / in direction of prevailing wind;
- Swash moves sediment / sand / pebbles up the beach at an angle / obliquely;
- Backwash returns sediment straight down the beach / at 90° / at right angles to the shore;
- Due to gravity / down the steepest slope (dev);
- Resulting in a zig-zag movement of sediment along the beach / coast (dev); [4]
题目 4 · thematic_data_response
8
1 (a) Study Fig. 2.1, which shows a storm hydrograph for the River Calderon following a heavy rainfall event.

[Fig. 2.1 description: A combined rainfall bar chart and discharge hydrograph. Rainfall occurs between 01:00 and 07:00, with a peak rainfall of 28 mm recorded at 04:00. Discharge starts at a baseflow of 12 m³/s at 01:00, rises steadily, reaches a peak discharge of 65 m³/s at 10:00, and recedes gradually to 15 m³/s by 22:00.]

(i) State the peak rainfall amount shown in Fig. 2.1. [1]
(ii) Calculate the lag time of the river basin in hours. [1]
(iii) State the peak discharge of the river. Include the unit of measurement in your answer. [1]

(b) Study Table 2.1, which compares characteristics of two sub-catchments (Catchment X and Catchment Y) in the River Calderon basin.

Table 2.1:
- Built-up urban land use: Catchment X = 48%, Catchment Y = 5%
- Forest cover: Catchment X = 8%, Catchment Y = 62%
- Average valley slope gradient: Catchment X = 18°, Catchment Y = 4°
- Predominant soil type: Catchment X = Heavy clay, Catchment Y = Permeable sandy loam

(i) Catchment X produces a significantly shorter lag time and a higher peak discharge than Catchment Y. Using Table 2.1, suggest two reasons for this difference. [2]
(ii) Explain how afforestation within Catchment Y helps to reduce the risk of flooding downstream. [3]
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解题

(a) (i) Peak rainfall is read directly from the bar graph at 04:00 = 28 mm.
(ii) Lag time is the time difference between peak rainfall (04:00) and peak discharge (10:00): 10:00 - 04:00 = 6 hours.
(iii) Peak discharge is read from the line graph apex at 10:00 = 65 m³/s (or cubic metres per second / cumecs).
(b) (i) Catchment X has high urban land cover (concrete/tarmac) and impermeable clay soils, both preventing infiltration and promoting fast surface runoff. Furthermore, steep slopes (18°) accelerate runoff into river channels.
(ii) Afforestation reduces flood risk because tree canopies intercept rainwater before it hits the ground, tree roots absorb water and open up soil channels promoting infiltration rather than rapid surface runoff, and transpiration removes water back into the atmosphere, lowering the flood peak.

评分标准

(a) (i) 28 (mm) [1]
(a) (ii) 6 (hours / hrs) [1]
(a) (iii) 65 m³/s / cumecs / cubic metres per second (unit essential) [1]
(b) (i) Any 2 from:
- Catchment X has more impermeable / built-up surfaces (dev: reduces infiltration / increases surface runoff);
- Catchment X has steeper slopes / higher gradient (dev: water runs off faster under gravity);
- Catchment X has less forest / vegetation cover (dev: less interception / absorption);
- Catchment X has clay soils (dev: lower permeability / less percolation). [2]
(b) (ii) Any 3 from:
- Interception by leaves / branches / canopy;
- Roots absorb water / moisture uptake;
- Promotes infiltration / percolation into soil / reduces overland flow;
- Increases evapotranspiration / water loss to atmosphere;
- Slows rate of surface runoff / increases lag time / lowers peak discharge. [3]
题目 5 · thematic_data_response
8
2 (a) Study Fig. 3.1, a sketch map showing coastal features along a stretch of coastline.

[Fig. 3.1 description: A coastal sketch map showing headlands and bays. At headland location Z (grid reference 442186), an opening extends through the headland from one side to the other, forming a bridge of rock above water. The dominant wind arrow points from the south-west toward the north-east across open water.]

(i) Identify coastal landform Z shown on Fig. 3.1. [1]
(ii) State the compass direction from which the prevailing wind blows. [1]
(iii) Name the specific process of coastal erosion that occurs when air trapped in rock joints is compressed by breaking waves. [1]

(b) Study Fig. 3.2, which shows cross-sectional beach profiles surveyed at Site P (updrift of a wooden groyne) and Site Q (downdrift of the wooden groyne).

[Fig. 3.2 description: Beach Profile Site P (updrift) shows a wide, gently sloped beach with a berm height of 4.2 m above sea level extending 45 m seaward. Beach Profile Site Q (downdrift) shows a narrow, steep pebble-and-sand profile with a crest height of 1.8 m extending only 15 m seaward, with exposed underlying bedrock near the low-water mark.]

(i) Using Fig. 3.2, compare the beach profile at Site P with the beach profile at Site Q. Do not use statistics in your answer. [2]
(ii) Explain how longshore drift operates along a coastline and why it leads to sediment starvation downdrift of a groyne. [3]
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解题

(a) (i) Landform Z is an arch (or sea arch), formed when caves on either side of a headland erode through and join.
(ii) The arrow shows the wind moving from the south-west (SW).
(iii) Hydraulic action is the compression of trapped air within joints and bedding planes by incoming waves.
(b) (i) Comparative observations without statistics: Site P has a wider, more extensive beach than Site Q; Site P has a higher beach profile/berm than Site Q; Site Q is narrower and shows exposed bedrock whereas Site P has continuous sediment cover.
(ii) Longshore drift occurs because prevailing winds drive waves to break obliquely against the shore; the swash carries sediment up the beach at an angle, while the backwash pulls it back straight down perpendicular to the shoreline under gravity. A groyne forms a physical barrier that intercepts this moving sediment, retaining it on the updrift side (Site P) and depriving the downdrift side (Site Q) of beach material.

评分标准

(a) (i) (Sea) arch [1]
(a) (ii) South-west / SW [1]
(a) (iii) Hydraulic action / cavitation [1]
(b) (i) Any 2 comparative statements (no stats):
- Site P is wider / extends further seaward (than Site Q) / Site Q is narrower;
- Site P is higher / taller / has a higher berm / crest (than Site Q) / Site Q is lower;
- Site P has more sand / sediment / deposition (than Site Q) / Site Q has less sediment / exposed rock / bare platform. [2]
(b) (ii) Any 3 from:
- Swash moves sediment up beach at an angle / in direction of prevailing wind;
- Backwash carries sediment down beach at 90° / perpendicular / under gravity;
- Repeated in a zig-zag movement along the beach / coastline;
- Groyne acts as a barrier / traps sediment on updrift side;
- Prevents replenishment / stops sediment reaching downdrift side / sediment starvation / terminal groyne syndrome. [3]
题目 6 · thematic_data_response
8
Study Fig. 2.1, which shows storm hydrographs and rainfall data for two drainage basins, Basin X and Basin Y, following a single heavy storm event.

**Fig. 2.1 (Storm Hydrograph Summary Data)**
* **Peak rainfall:** 35 mm at 04:00 hours
* **Basin X (Urbanized catchment):**
- Peak discharge: \(52\text{ m}^3/\text{s}\) at 07:00 hours
- Baseflow: \(8\text{ m}^3/\text{s}\)
* **Basin Y (Forested natural catchment):**
- Peak discharge: \(22\text{ m}^3/\text{s}\) at 12:00 hours
- Baseflow: \(6\text{ m}^3/\text{s}\)

(a) (i) What is meant by the term *lag time*? [1]

(a) (ii) State the peak discharge recorded in:
- Basin X: ....................................
- Basin Y: .................................... [2]

(b) Using Fig. 2.1, calculate the difference in lag time between Basin X and Basin Y. Show your working. [2]

(c) Explain why the hydrograph for Basin X has a shorter lag time and a higher peak discharge than Basin Y. [3]
查看答案详解

解题

**(a) (i)**
Lag time is defined as the time difference/delay between the point of maximum/peak rainfall and the point of maximum/peak river discharge.

**(a) (ii)**
* Basin X: \(52\text{ m}^3/\text{s}\)
* Basin Y: \(22\text{ m}^3/\text{s}\)

**(b)**
* Lag time for Basin X = \(07:00 - 04:00 = 3\text{ hours}\)
* Lag time for Basin Y = \(12:00 - 04:00 = 8\text{ hours}\)
* Difference = \(8\text{ hours} - 3\text{ hours} = 5\text{ hours}\)

**(c)**
* Impermeable man-made surfaces (e.g. tarmac, concrete, roofs) prevent infiltration in Basin X, leading to rapid overland flow/surface run-off.
* Artificial drainage networks (e.g. gutters, culverts, storm drains) transport water directly and quickly into the river channel, shortening lag time.
* Lack of vegetation in Basin X reduces interception and evapotranspiration compared to Basin Y, where forest canopies intercept rainfall, roots promote percolation, and soil stores water, resulting in lower peak discharge and delayed response.

评分标准

**(a) (i)** [1 mark]
* Time difference/interval between peak rainfall and peak discharge;

**(a) (ii)** [2 marks]
* Basin X: \(52\text{ m}^3/\text{s}\) / 52 (1 mark)
* Basin Y: \(22\text{ m}^3/\text{s}\) / 22 (1 mark)

**(b)** [2 marks]
* 1 mark for correct identification of both lag times (Basin X = 3 hours and Basin Y = 8 hours);
* 1 mark for final correct difference: 5 hours (allow tolerance only if clear working matches);

**(c)** [3 marks, max 3]
* Impermeable surfaces / concrete / tarmac / built-up areas (in Basin X);
* Less/no infiltration / higher rate of surface run-off / overland flow (in Basin X);
* Drains / storm sewers / gutters channel water rapidly into river;
* Forest / vegetation / trees (in Basin Y) intercept rainwater (dev);
* Roots / soil absorb water / higher infiltration / higher storage capacity in Basin Y;
* Note: Accept reverse reasoning for Basin Y. Maximum 2 marks if only one basin is discussed.
题目 7 · thematic_data_response
8
Study Table 1.1, which shows demographic and settlement data for four regions in a developing country.

**Table 1.1**
| Region | Total Population | Area (\(\text{km}^2\)) | Urban Population (%) | Primary Employment (%) |
| :--- | :--- | :--- | :--- | :--- |
| North | 1,200,000 | 40,000 | 25 | 62 |
| South | 4,500,000 | 15,000 | 78 | 14 |
| East | 850,000 | 34,000 | 30 | 58 |
| West | 2,100,000 | 12,000 | 65 | 22 |

(a) (i) Identify the region with the lowest percentage of urban population. [1]

(a) (ii) Calculate the population density of the South region. State the unit in your answer. [2]

(b) Using Table 1.1, describe the relationship between the percentage of urban population and the percentage of employment in the primary sector. [2]

(c) Suggest three reasons why population density is typically much higher in urbanized regions than in rural regions. [3]
查看答案详解

解题

**(a) (i)**
North region (25%)

**(a) (ii)**
$$\text{Population Density} = \frac{\text{Total Population}}{\text{Area (km}^2\text{)}} = \frac{4,500,000}{15,000} = 300\text{ persons/km}^2$$

**(b)**
There is a strong negative (inverse) relationship. As urbanization increases, the percentage of workers in the primary sector decreases. For example, the South has the highest urban percentage (78%) and the lowest primary employment (14%), whereas the North has the lowest urban percentage (25%) and the highest primary employment (62%).

**(c)**
1. **Employment opportunities:** Urban areas offer diverse secondary and tertiary jobs with higher wages compared to low-density agricultural work.
2. **Access to services and infrastructure:** Higher concentration of healthcare facilities, educational institutions, electricity, clean water, and public transport systems attract concentration of settlers.
3. **Housing type/Land use:** Urban areas have vertical expansion with high-rise apartment blocks and compact layouts, enabling far more people to live per square kilometre than expansive rural farmland.

评分标准

**(a) (i)** [1 mark]
* North (region);

**(a) (ii)** [2 marks]
* 300 (1 mark);
* persons per \(\text{km}^2\) / people per square kilometre / per \(\text{km}^2\) (1 mark for correct unit);

**(b)** [2 marks]
* Inverse / negative relationship / as one increases the other decreases (1 mark);
* Paired data/example from Table 1.1 supporting the relationship (e.g. South 78% urban and 14% primary vs North 25% urban and 62% primary) (1 mark);

**(c)** [3 marks, max 3]
* Greater variety/number of jobs / higher wages in secondary/tertiary industries;
* Concentration of services / hospitals / schools / universities / entertainment;
* Better infrastructure / paved roads / electricity / piped water supply;
* High-density / vertical housing / multi-storey flats/apartments;
* Rural-to-urban migration / influx of young working-age population;
* Flat land / accessible physical location suitable for building.

Paper 43 Alternative to Coursework

Answer all questions to analyze the two structured fieldwork scenarios.
2 题目 · 60
题目 1 · fieldwork
30
Students in southern England investigated changes along the River Lynbrook from its source to a lower course site. They chose 5 data collection sites along a 14 km section of the river.

The students investigated the following hypotheses:

Hypothesis 1: River discharge increases downstream.
Hypothesis 2: Bedload particle size decreases and roundness increases downstream.

(a) (i) Before starting their fieldwork, the students carried out a risk assessment. Identify three distinct safety risks associated with river fieldwork and state a precaution for each. [3]

(ii) Name two pieces of equipment used to measure the wetted channel width and water depth across a river transect. [2]

(b) (i) Describe how the students measured river velocity across the channel using a digital flow meter. [4]

(ii) At Site 3, the students collected the following data:
- Channel width: 4.8 m
- Water depths measured at 0.8 m intervals from the left bank (m): 0.15, 0.28, 0.42, 0.38, 0.22
- Mean surface velocity: 0.65 m/s

Calculate the mean depth (in m), cross-sectional area (in m²), and river discharge (in m³/s) at Site 3. Show your working. (Discharge = Cross-sectional area × Velocity). [4]

(c) (i) The students collected 20 bedload pebbles from the river bed at each site. Describe a systematic sampling method the students could use to select these pebbles across the river channel to avoid bias. [3]

(ii) Describe how the students measured the size (long axis) and roundness of each sampled pebble. [3]

(d) (i) Table 1 shows the summary data collected at all 5 sites:

Table 1:
Site | Distance from source (km) | Width (m) | Mean depth (m) | Cross-sectional area (m²) | Mean velocity (m/s) | Discharge (m³/s) | Mean pebble length (cm) | Powers roundness score (1–6)
1 | 1.2 | 1.10 | 0.12 | 0.13 | 0.25 | 0.03 | 11.4 | 1.8 (Very angular)
2 | 4.5 | 2.60 | 0.21 | 0.55 | 0.42 | 0.23 | 8.2 | 2.6 (Sub-angular)
3 | 8.0 | 4.80 | 0.29 | 1.39 | 0.65 | 0.90 | 5.1 | 3.7 (Sub-rounded)
4 | 11.5 | 6.40 | 0.41 | 2.62 | 0.78 | 2.04 | 3.4 | 4.4 (Rounded)
5 | 13.8 | 8.90 | 0.58 | 5.16 | 0.85 | 4.39 | 1.9 | 5.2 (Well rounded)

What conclusion should the students reach about Hypothesis 1 (River discharge increases downstream)? Support your decision with data evidence from Table 1. [4]

(ii) What conclusion should the students reach about Hypothesis 2 (Bedload particle size decreases and roundness increases downstream)? Support your decision with data evidence from Table 1. [4]

(e) Suggest three ways the students could improve the reliability or accuracy of their fieldwork data collection. [3]
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解题

(a) (i) Identification of three distinct river risks and corresponding mitigations: 1. Slipping on wet/slimy riverbed stones -> wear boots/wellies with ankle support and textured grip soles; 2. Fast/deep flowing water/drowning risk -> use a safety wading pole, avoid water above knee level, wear lifejackets; 3. Leptospirosis / bacterial water infection -> wear waterproof gloves, cover cuts with waterproof plasters, sanitize hands before eating.
(ii) Tape measure (or surveyor's chain) and graduated ranging pole / meter ruler.

(b) (i) 1. Place the impeller/sensor facing upstream into the current. 2. Submerge the sensor to approximately 0.6 of the river depth (or 60% depth) from the water surface for representative average flow. 3. Hold the rod steady for a set time (e.g. 30–60 seconds) without disturbing the water flow with legs. 4. Record velocity reading on the digital display unit and repeat across evenly spaced transect intervals.

(ii) Calculation:
- Mean depth = (0.15 + 0.28 + 0.42 + 0.38 + 0.22) / 5 = 1.45 / 5 = 0.29 m
- Cross-sectional area = Width × Mean depth = 4.8 m × 0.29 m = 1.392 m² (accepted 1.39 m²)
- Discharge = Area × Velocity = 1.392 m² × 0.65 m/s = 0.9048 m³/s = 0.90 m³/s

(c) (i) Stretch measuring tape from bank to bank; sample a pebble at regular fixed metric intervals (e.g. every 20 cm or 50 cm); select the exact pebble touched by the index finger or ruler tip at each point without looking to eliminate selective bias.
(ii) Size: Measure maximum length / longest axis (a-axis) of each pebble using callipers or a ruler in millimeters. Roundness: Compare the overall angularity and edge smoothness of each pebble against a standard Powers / Cailleux visual roundness chart ranging from Class 1 (Very Angular) to Class 6 (Well Rounded).

(d) (i) Hypothesis 1 is TRUE / supported. Evidence: Discharge increases continuously downstream from Site 1 to Site 5. Site 1 (1.2 km from source) has a discharge of 0.03 m³/s, Site 3 (8.0 km) has 0.90 m³/s, and Site 5 (13.8 km) has 4.39 m³/s. Both width (1.10 m to 8.90 m), depth (0.12 m to 0.58 m), and velocity (0.25 m/s to 0.85 m/s) increase.
(ii) Hypothesis 2 is TRUE / supported. Evidence: Bedload length decreases consistently downstream from 11.4 cm at Site 1 to 5.1 cm at Site 3 and 1.9 cm at Site 5. Pebble roundness score increases consistently from 1.8 (very angular) at Site 1 to 3.7 (sub-rounded) at Site 3 and 5.2 (well rounded) at Site 5.

(e) Ways to improve: 1. Take multiple readings at each point across the channel and compute a mean; 2. Sample more bedload pebbles (e.g. 50 or 100 per site) for greater statistical representation; 3. Re-visit sites at different river discharge levels (seasonal variation) to test validity across flow regimes.

评分标准

(a)(i) [3 marks]: 1 mark per valid pair (risk + precaution), max 3.
- Slipping/falling on wet rocks; wear sturdy footwear with grip / rubber boots.
- Deep/fast currents/drowning; do not enter water above knees / wear buoyancy aid.
- Polluted water / Leptospirosis / Weil's disease; cover cuts with waterproof dressing / wash hands.
- Hypothermia / cold water; wear warm/waterproof clothing.

(a)(ii) [2 marks]: 1 mark each for:
- Measuring tape / surveyor's tape.
- Meter ruler / graduated ranging pole / measuring stick.

(b)(i) [4 marks]: 1 mark per valid point:
- Impeller/propeller held facing into the flow / upstream;
- Held at 0.6 depth below surface (or mid-depth);
- Kept steady / unobstructed by fieldworker's legs;
- Timed duration / automated digital counter read;
- Repeated at multiple intervals across the width to calculate mean.

(b)(ii) [4 marks]:
- 1 mark for correct mean depth: 0.29 (m);
- 1 mark for method of cross-sectional area: width × mean depth (4.8 × 0.29);
- 1 mark for correct cross-sectional area: 1.392 m² or 1.39 m²;
- 1 mark for correct discharge: 0.90 m³/s or 0.905 m³/s (with units).

(c)(i) [3 marks]:
- Measure tape stretched across river transect (1);
- Fixed regular sampling intervals e.g. every 25 cm / 50 cm along tape (1);
- Touch river bed blindfolded / pick pebble directly at ruler tip to eliminate bias (1);
- Ensure 20 samples taken across entire width (1).

(c)(ii) [3 marks]:
- Pebble size: use callipers / ruler to measure long axis / a-axis in mm/cm (1);
- Pebble roundness: match shape to visual chart / Powers roundness scale (1);
- Assign score from 1 (very angular) to 6 (well rounded) (1).

(d)(i) [4 marks]:
- Decision: Hypothesis is true / supported (1 mark reserve);
- Comparative discharge data: Site 1 = 0.03 m³/s vs Site 5 = 4.39 m³/s (1);
- Intermediate data point / anomaly check: Site 3 = 0.90 m³/s showing steady increase (1);
- Supporting factor data: velocity rises from 0.25 to 0.85 m/s OR area rises from 0.13 to 5.16 m² (1).

(d)(ii) [4 marks]:
- Decision: Hypothesis is true / supported (1 mark reserve);
- Comparative size data: 11.4 cm at Site 1 decreases to 1.9 cm at Site 5 (1);
- Comparative roundness data: score 1.8 (very angular) at Site 1 increases to 5.2 (well rounded) at Site 5 (1);
- Intermediate data point (e.g. Site 3 size 5.1 cm and roundness 3.7) (1).

(e) [3 marks]: 1 mark per improvement (max 3):
- Increase number of pebbles sampled per site (e.g. 50 instead of 20);
- Take 3 repeat velocity readings at each point across the cross-section and calculate mean;
- Use a second observer to verify roundness chart scores to reduce subjectivity;
- Repeat data collection at different times of the year / seasons / river stages.
题目 2 · fieldwork
30
Students in a coastal resort town investigated the impacts of tourism. They selected 6 survey sites along a 1.5 km transect starting from the seafront promenade (Site 1) to an outer residential suburb (Site 6).

The students investigated the following hypotheses:

Hypothesis 1: Pedestrian footfall and tourist services decrease as distance from the seafront promenade increases.
Hypothesis 2: Environmental quality is lowest near the seafront promenade due to high tourist concentration.

(a) (i) State two reasons why students should conduct a pilot survey before undertaking their main urban fieldwork. [2]

(ii) Describe how the students could carry out a 10-minute pedestrian count at each of the 6 survey sites to collect reliable data. [3]

(b) The students designed an Environmental Quality Survey (EQS) bi-polar scoring sheet shown in Table 2.

Table 2:
Environmental Criterion | -2 | -1 | 0 | +1 | +2 | Environmental Criterion
Litter everywhere | | | | | | Clean / no visible litter
Heavy traffic noise | | | | | | Quiet / peaceful
Poor building maintenance | | | | | | Well-maintained buildings
No green spaces / trees | | | | | | Abundant gardens / trees
Vandalism / graffiti visible | | | | | | No graffiti or vandalism

(i) Explain how bi-polar scoring is used to calculate an overall environmental quality score for a site. [3]

(ii) State two problems of using an Environmental Quality Survey and explain how students can minimise each problem. [4]

(c) Table 3 shows the data collected by the students at the 6 sites:

Table 3:
Site | Distance from seafront (m) | 10-minute pedestrian count | Number of tourist-oriented services (souvenirs, cafes, hotels) | Total EQS score (out of +10 to -10)
1 | 0 (Promenade) | 142 | 18 | -4
2 | 250 | 98 | 14 | -2
3 | 500 | 64 | 9 | +1
4 | 800 | 38 | 4 | +5
5 | 1150 | 21 | 1 | +7
6 | 1500 | 12 | 0 | +8

(i) Identify the relationship between distance from the seafront and the number of tourist-oriented services shown in Table 3. [1]

(ii) Calculate the percentage decrease in pedestrian footfall between Site 1 and Site 6. [2]

(d) (i) What conclusion should the students reach regarding Hypothesis 1 (Pedestrian footfall and tourist services decrease as distance from the seafront promenade increases)? Support your answer with data evidence from Table 3. [4]

(ii) What conclusion should the students reach regarding Hypothesis 2 (Environmental quality is lowest near the seafront promenade due to high tourist concentration)? Support your answer with data evidence from Table 3. [4]

(e) The students decided to extend their investigation by surveying local residents and tourists to investigate their opinions on traffic congestion and seasonal overcrowding.
Describe a sampling method and two suitable questions (one closed and one open-ended) they could use in a questionnaire survey. [4]
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解题

(a) (i) Reasons for a pilot survey: 1. To test the survey forms / equipment to ensure clarity and ease of use; 2. To check whether the chosen survey sites and time intervals are feasible and safe; 3. To practice counting and scoring methods to ensure consistency among team members.
(ii) 1. Fieldworkers work in pairs at a fixed observation point on the pavement at each site. 2. Use a mechanical tally counter or clicker to record every person passing across an imaginary line across the footway. 3. Use a stopwatch to time exactly 10 minutes, conducting counts simultaneously across all sites at the same time of day (e.g. 14:00) to ensure comparable results.

(b) (i) For each of the 5 criteria, students observe the surroundings and assign an integer value from -2 (very negative) through 0 (neutral) to +2 (very positive). They then sum the 5 individual scores together to produce an overall aggregate environmental quality score ranging between -10 and +10.
(ii) Problem 1: Subjective judgment / individual bias in scoring. Minimisation: Have groups of 3–4 students score independently, discuss, and record the average/consensus score with explicit grading criteria.
Problem 2: Time-dependent distortion (e.g. litter cleared right before survey or road works creating temporary noise). Minimisation: Conduct the survey on multiple days at the same time and calculate an average score across days.

(c) (i) Negative correlation / inverse relationship: As distance from the seafront increases, the number of tourist-oriented services decreases.
(ii) Calculation: ((142 - 12) / 142) × 100 = (130 / 142) × 100 = 91.55% (accepted 91.5% or 92%).

(d) (i) Hypothesis 1 is TRUE / supported. Evidence: Pedestrian numbers decrease consistently with distance: Site 1 (0 m) has 142 pedestrians compared to Site 3 (500 m) with 64, and Site 6 (1500 m) with only 12 pedestrians. Tourist-oriented services also decrease from 18 at Site 1 (0 m) to 9 at Site 3 (500 m) and 0 at Site 6 (1500 m).
(ii) Hypothesis 2 is TRUE / supported. Evidence: Environmental quality is lowest at Site 1 (0 m / promenade) with an EQS score of -4. The score improves steadily inland: Site 2 = -2, Site 3 = +1, Site 4 = +5, Site 5 = +7, reaching the highest score of +8 at Site 6 (1500 m). Negative scores at Sites 1 and 2 reflect high litter and noise associated with tourist concentration.

(e) Sampling method: Systematic sampling (e.g. approaching every 5th person passing a set point) or Stratified sampling (sampling proportional quotas of residents vs tourists across age groups). Questions: Closed question: 'How severe is summer traffic congestion in town? [ ] Severe [ ] Moderate [ ] Low [ ] None'; Open question: 'What improvements would you suggest to improve traffic flow during peak holiday periods?'.

评分标准

(a)(i) [2 marks]: 1 mark each for any 2 valid points:
- Test and refine data recording sheets / questions;
- Check feasibility / safety of site locations;
- Standardise timing and scoring criteria among students;
- Identify potential problems / equipment malfunction beforehand.

(a)(ii) [3 marks]: 1 mark per point:
- Use of tally counter / tally chart / clicker (1);
- Fixed position / imaginary transect line across pavement (1);
- Standardised time limit (10 minutes) using a stopwatch (1);
- Simultaneous counting at all sites / same time of day to ensure comparability (1).

(b)(i) [3 marks]:
- Each criterion awarded a score between -2 and +2 (1);
- Negative scores represent poor environmental quality, positive scores represent high quality (1);
- Scores across all 5 categories added together to give a composite score from -10 to +10 (1).

(b)(ii) [4 marks]: 2 marks for Problem 1 + mitigation, 2 marks for Problem 2 + mitigation.
- Problem: Subjectivity / individual personal opinion varies (1);
Mitigation: Work in pairs/small groups and average scores / use photographic rubric guides (1);
- Problem: Temporal variations / ephemeral noise/litter (1);
Mitigation: Repeat survey on different days/times and take average (1).

(c)(i) [1 mark]:
- Negative relationship / inverse relationship / as distance increases, tourist services decrease.

(c)(ii) [2 marks]:
- Method: (142 - 12) / 142 × 100 (1 mark);
- Accuracy: 91.5% or 91.55% or 92% (1 mark).

(d)(i) [4 marks]:
- Decision: Hypothesis is true / supported (1 mark reserve);
- Comparative pedestrian footfall data: 142 at Site 1 (0 m) vs 12 at Site 6 (1500 m) (1);
- Comparative tourist services data: 18 at Site 1 vs 0 at Site 6 (1);
- Intermediate data point (e.g. Site 3 at 500 m has 64 pedestrians and 9 services) (1).

(d)(ii) [4 marks]:
- Decision: Hypothesis is true / supported (1 mark reserve);
- Comparative EQS score data: Site 1 = -4 vs Site 6 = +8 (1);
- Trend elaboration: scores increase from negative to positive as distance increases (Site 2 = -2 to Site 4 = +5) (1);
- Identification of specific lowest score location (Site 1 at promenade has lowest score of -4) (1).

(e) [4 marks]:
- Sampling method named and described: e.g. Systematic sampling (ask every 5th person) OR Stratified sampling (ensure equal quota of tourists and residents/genders) (2 marks);
- Closed question with rating scale/tick boxes related to congestion/tourism (1 mark);
- Open-ended question allowing free descriptive suggestions/opinions (1 mark).

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