Cambridge IGCSE · thinka 原创模拟试题

2025 Cambridge IGCSE Physics (0625) 模拟试题及答案详解

Thinka Nov 2025 (V2) Cambridge IGCSE-Style Mock — Physics (0625)

80 75 分钟2025
An original Thinka practice paper modelled on the structure and difficulty of the Nov 2025 (V2) Cambridge IGCSE Physics (0625) paper. Not affiliated with or reproduced from Cambridge.

部分 Structured Theory Questions

Answer all questions. Write your answers in the spaces provided. Show all your working and use appropriate units.
37 题目 · 80
题目 1 · Structured Calculation
2
A cyclist accelerates constantly from a speed of \(3.0\text{ m/s}\) to \(11.0\text{ m/s}\) in a time of \(4.0\text{ s}\).

Calculate the acceleration of the cyclist.
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解题

1. Use the acceleration formula: \(a = \frac{v - u}{t}\)
2. Substitute the given values: \(a = \frac{11.0 - 3.0}{4.0}\)
3. Calculate the final value: \(a = \frac{8.0}{4.0} = 2.0\text{ m/s}^2\).

评分标准

C1: For stating or using \(a = \frac{v - u}{t}\) or substituting values correctly
A1: For correct final answer with unit: \(2.0\text{ m/s}^2\) (accept \(\text{m/s}^2\) or \(\text{m } s^{-2}\))
题目 2 · Structured Calculation
3
A piece of glass has a mass of \(75.0\text{ g}\). When it is fully submerged in water inside a measuring cylinder, the water level rises from \(32.0\text{ cm}^3\) to \(62.0\text{ cm}^3\).

Calculate the density of the glass.
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解题

1. Determine the volume of the glass: \(V = 62.0 - 32.0 = 30.0\text{ cm}^3\)
2. Use the density formula: \(\rho = \frac{m}{V}\)
3. Substitute the values: \(\rho = \frac{75.0}{30.0} = 2.5\text{ g/cm}^3\).

评分标准

C1: For calculating volume: \(V = 30.0\text{ cm}^3\)
C1: For recalling/using density formula \(\rho = \frac{m}{V}\)
A1: For correct final answer with unit: \(2.5\text{ g/cm}^3\) (accept \(\text{g/cm}^3\) or \(\text{g cm}^{-3}\))
题目 3 · Structured Calculation
3
A crane lifts a crate of weight \(1500\text{ N}\) vertically upwards through a height of \(8.0\text{ m}\). This task takes a time of \(6.0\text{ s}\).

Calculate the useful power output of the crane.
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解题

1. Calculate the work done by the crane: \(W = F \times d = 1500 \times 8.0 = 12\,000\text{ J}\)
2. Use the power formula: \(P = \frac{W}{t}\)
3. Substitute the values: \(P = \frac{12\,000}{6.0} = 2000\text{ W}\) (or \(2.0\text{ kW}\)).

评分标准

C1: For calculating work done: \(W = F \times d\) or \(12\,000\text{ J}\)
C1: For using power formula: \(P = \frac{W}{t}\) or substituting \(\frac{12\,000}{6.0}\)
A1: For correct final answer with unit: \(2000\text{ W}\) or \(2.0\text{ kW}\)
题目 4 · Structured Calculation
3
A heavy metal block of mass \(15\text{ kg}\) rests on a flat table. The base of the block has a contact area of \(0.050\text{ m}^2\).

The acceleration of free fall \(g = 9.8\text{ m/s}^2\).

Calculate the pressure exerted by the block on the table.
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解题

1. Calculate the weight (force) of the block: \(F = W = m \times g = 15 \times 9.8 = 147\text{ N}\)
2. Use the pressure formula: \(p = \frac{F}{A}\)
3. Substitute the values: \(p = \frac{147}{0.050} = 2940\text{ Pa}\).

评分标准

C1: For calculating weight: \(W = m \times g = 147\text{ N}\)
C1: For recalling/using pressure formula: \(p = \frac{F}{A}\)
A1: For correct final answer with unit: \(2940\text{ Pa}\) (or \(2900\text{ Pa}\) to 2 s.f., accept \(2.94\text{ kPa}\) or \(\text{N/m}^2\))
题目 5 · Structured Calculation
3
An electric heater is switched on for \(5.0\text{ minutes}\). During this time, a charge of \(1200\text{ C}\) passes through the heating element.

Calculate the electric current in the heater.
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解题

1. Convert the time to seconds: \(t = 5.0 \times 60 = 300\text{ s}\)
2. Use the charge formula: \(I = \frac{Q}{t}\)
3. Substitute the values: \(I = \frac{1200}{300} = 4.0\text{ A}\).

评分标准

C1: For converting time to seconds: \(300\text{ s}\)
C1: For recalling/using current formula: \(I = \frac{Q}{t}\) or substituting \(\frac{1200}{300}\)
A1: For correct final answer with unit: \(4.0\text{ A}\)
题目 6 · Structured Calculation
2
A sound wave traveling through water has a frequency of \(1500\text{ Hz}\) and a wavelength of \(1.2\text{ m}\).

Calculate the speed of the sound wave in water.
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解题

1. Use the wave speed equation: \(v = f \times \lambda\)
2. Substitute the given values: \(v = 1500 \times 1.2\)
3. Calculate the speed: \(v = 1800\text{ m/s}\).

评分标准

C1: For recalling/using wave speed equation: \(v = f \times \lambda\)
A1: For correct final answer with unit: \(1800\text{ m/s}\)
题目 7 · Structured Calculation
3
A satellite orbits a planet in a circular path of radius \(8.0 \times 10^6\text{ m}\). The orbital period of the satellite is \(4.0 \times 10^3\text{ s}\).

Calculate the orbital speed of the satellite.
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解题

1. Use the circular orbital speed formula: \(v = \frac{2\pi r}{T}\)
2. Substitute the values: \(v = \frac{2 \times \pi \times 8.0 \times 10^6}{4.0 \times 10^3}\)
3. Calculate the speed: \(v = \frac{1.6 \times 10^7 \pi}{4.0 \times 10^3} = 4000\pi \approx 12\,566\text{ m/s}\).
4. Rounding to 2 significant figures gives \(1.3 \times 10^4\text{ m/s}\) (or \(13\,000\text{ m/s}\)).

评分标准

C1: For stating/using the orbital speed equation: \(v = \frac{2\pi r}{T}\)
C1: For correct substitution: \(v = \frac{2 \times \pi \times 8.0 \times 10^6}{4.0 \times 10^3}\)
A1: For correct final answer: \(1.3 \times 10^4\text{ m/s}\) or \(13\,000\text{ m/s}\) (accept \(12\,500\) to \(12\,600\))
题目 8 · Structured Calculation
3
A radioactive sample contains an isotope with an initial activity of \(2400\text{ counts/s}\). After a time of \(18\text{ hours}\), the activity has decreased to \(300\text{ counts/s}\).

Calculate the half-life of this isotope.
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解题

1. Find the number of half-lives that have elapsed:
- \(2400 \rightarrow 1200\) (1 half-life)
- \(1200 \rightarrow 600\) (2 half-lives)
- \(600 \rightarrow 300\) (3 half-lives)
2. The total time elapsed is \(18\text{ hours}\) for 3 half-lives.
3. Calculate the duration of one half-life: \(t_{1/2} = \frac{18\text{ hours}}{3} = 6.0\text{ hours}\).

评分标准

C1: For determining that 3 half-lives have elapsed
C1: For setting up the relation: \(3 \times t_{1/2} = 18\text{ hours}\)
A1: For correct final answer with unit: \(6.0\text{ hours}\)
题目 9 · Structured Calculation
2
A toy car of mass 0.80 kg is pulled along a smooth horizontal surface by a force of 3.2 N. Calculate the acceleration of the toy car.
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解题

Using the formula F = ma, we can rearrange to find acceleration: a = F / m. Substituting the given values: a = 3.2 N / 0.80 kg = 4.0 m/s^2.

评分标准

C1: for quoting the formula F = ma or rearranged a = F/m. A1: for the correct final answer with appropriate unit: 4.0 m/s^2 (accept 4 m/s^2).
题目 10 · Structured Calculation
2
A trolley of mass 2.0 kg travels at a speed of 3.5 m/s. Calculate the momentum of the trolley.
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解题

Using the formula p = mv, we substitute the mass and speed: p = 2.0 kg * 3.5 m/s = 7.0 kg m/s.

评分标准

C1: for quoting the formula p = mv or showing substitution 2.0 * 3.5. A1: for the correct final answer with appropriate unit: 7.0 kg m/s (accept 7 kg m/s or 7 N s).
题目 11 · Structured Calculation
2
A box of weight 150 N rests on a table. The area of the bottom of the box in contact with the table is 0.25 m^2. Calculate the pressure exerted by the box on the table.
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解题

Using the formula p = F / A, we substitute the force (weight) and area: p = 150 N / 0.25 m^2 = 600 Pa.

评分标准

C1: for quoting the formula p = F/A or showing substitution 150 / 0.25. A1: for the correct final answer with appropriate unit: 600 Pa (accept 600 N/m^2).
题目 12 · Structured Calculation
2
An electric motor does 1200 J of work in 15 seconds. Calculate the power output of the motor.
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解题

Using the formula P = W / t, we substitute the work and time: P = 1200 J / 15 s = 80 W.

评分标准

C1: for quoting the formula P = W/t or showing substitution 1200 / 15. A1: for the correct final answer with appropriate unit: 80 W (accept 80 J/s).
题目 13 · Structured Calculation
2
A potential difference of 12 V is applied across a resistor, producing a current of 0.75 A. Calculate the resistance of the resistor.
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解题

Using Ohm's law, R = V / I. Substituting the potential difference and current: R = 12 V / 0.75 A = 16 ohms.

评分标准

C1: for quoting the formula R = V/I or V = IR. A1: for the correct final answer with appropriate unit: 16 Δ (or 16 ohms).
题目 14 · Structured Calculation
2
A block of metal has a mass of 450 g and a volume of 50 cm^3. Calculate the density of the metal.
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解题

Using the formula rho = m / V, we substitute the mass and volume: rho = 450 g / 50 cm^3 = 9.0 g/cm^3.

评分标准

C1: for quoting the formula rho = m/V or showing substitution 450 / 50. A1: for the correct final answer with appropriate unit: 9.0 g/cm^3 (accept 9 g/cm^3 or 9000 kg/m^3 if conversions are correctly shown).
题目 15 · Structured Calculation
2
A water wave has a wavelength of 0.20 m and a frequency of 5.0 Hz. Calculate the speed of the water wave.
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解题

Using the wave equation v = f * lambda, we substitute frequency and wavelength: v = 5.0 Hz * 0.20 m = 1.0 m/s.

评分标准

C1: for quoting the formula v = f * lambda or showing substitution 5.0 * 0.20. A1: for the correct final answer with appropriate unit: 1.0 m/s (accept 1 m/s).
题目 16 · structured
2
Explain why a double-glazed window with a vacuum between the two glass panes is more effective at reducing thermal energy transfer than one containing a layer of dry air.
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解题

A vacuum contains no particles (is empty space), which completely prevents thermal energy transfer by conduction and convection, as both processes require a material medium. Although dry air is a poor conductor, it still contains molecules that allow some conduction and can support the formation of convection currents within the gap.

评分标准

- [1 mark] State that a vacuum contains no particles (empty space), so conduction and convection cannot occur.
- [1 mark] State that dry air contains particles, which still allows some conduction and/or the formation of convection currents.
题目 17 · structured
2
A ray of light in water approaches the boundary with air. State and explain what happens to this ray of light when the angle of incidence in the water is greater than the critical angle.
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解题

When light travels from a more optically dense medium (water) to a less optically dense medium (air), and the angle of incidence exceeds the critical angle, the light cannot refract. Instead, it undergoes total internal reflection and is entirely reflected back into the water.

评分标准

- [1 mark] State that total internal reflection occurs (the light is reflected back into the water).
- [1 mark] Explain that this is because the light is travelling in a more dense medium towards a less dense medium and the angle of incidence is greater than the critical angle.
题目 18 · structured
2
Explain, in terms of momentum and forces, how an inflatable airbag in a car reduces the risk of serious injury to a passenger during a collision.
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解题

The airbag increases the time interval \( t \) over which the passenger's momentum changes to zero. Since force is equal to the rate of change of momentum, \( F = \frac{\Delta p}{t} \), a larger value of \( t \) results in a much smaller average force acting on the passenger, reducing the risk of injury.

评分标准

- [1 mark] State that the airbag increases the time duration of the collision / impact.
- [1 mark] Explain that this reduces the rate of change of momentum, resulting in a smaller force acting on the passenger (or mention the relationship \( F = \frac{\Delta p}{t} \)).
题目 19 · structured
2
Explain why a person wearing wide snowshoes can walk on deep, soft snow without sinking, whereas the same person wearing ordinary boots sinks into the snow.
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解题

Snowshoes have a much larger surface area in contact with the snow compared to ordinary boots. According to the formula for pressure, \( P = \frac{F}{A} \), spreading the person's weight (force \( F \)) over a larger area \( A \) results in a much lower pressure \( P \) on the snow, preventing them from sinking.

评分标准

- [1 mark] State that the snowshoes have a larger surface area than ordinary boots.
- [1 mark] Explain that the larger area reduces the pressure exerted on the snow because the force (weight) is distributed over a larger area (or mention \( P = \frac{F}{A} \)).
题目 20 · structured
2
Explain why permanent bar magnets are stored in pairs with opposite poles adjacent and with soft iron keepers across their ends.
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解题

The soft iron keepers become magnetised by induction from the permanent magnets. This creates a continuous, closed magnetic loop for the magnetic field lines. By keeping the magnetic loops closed, the magnetic domains within the permanent bar magnets remain aligned over time, preventing demagnetisation.

评分标准

- [1 mark] State that the iron keepers become magnetised by induction, forming closed loops of magnetic field lines.
- [1 mark] Explain that this keeps the magnetic domains aligned and prevents demagnetisation of the permanent magnets.
题目 21 · structured
2
Explain why alpha (\( \alpha \)) particles have a very short range in air (only a few centimetres) compared to gamma (\( \gamma \)) rays, which can travel many metres.
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解题

Alpha particles have a relatively large mass and a positive charge of \( +2e \), which makes them highly ionising. They interact strongly and frequently with air molecules, losing their kinetic energy rapidly over a short distance. In contrast, gamma rays are electromagnetic waves with no charge and no mass, making them weakly ionising so they interact rarely and travel much further before losing their energy.

评分标准

- [1 mark] State that alpha particles are highly ionising (or have a double positive charge / large mass), so they collide frequently with air molecules and lose energy quickly.
- [1 mark] State that gamma rays are weakly ionising (or have no charge / no mass), so they interact rarely and have a much greater range.
题目 22 · structured
2
State and explain how the orbital speed of a planet changes as it moves further away from the Sun in its elliptical orbit.
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解题

As the distance between the planet and the Sun increases, the gravitational force of attraction holding the planet in its orbit decreases. This weaker force results in a smaller centripetal acceleration, meaning the planet's orbital speed decreases. Alternatively, as the planet moves further away, its kinetic energy is converted into gravitational potential energy, resulting in a slower speed.

评分标准

- [1 mark] State that the orbital speed decreases.
- [1 mark] Explain that the gravitational force of attraction from the Sun becomes weaker at greater distances (or explain in terms of kinetic energy converting to gravitational potential energy).
题目 23 · structured
2
Light from distant galaxies is observed to be redshifted. State what redshift is and explain what this observation indicates about the Universe.
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解题

Redshift is the increase in the observed wavelength (or decrease in frequency) of light emitted by distant galaxies as they move away from the observer. This observation indicates that distant galaxies are moving away from us, and the fact that almost all distant galaxies show redshift indicates that the Universe is expanding.

评分标准

- [1 mark] Define redshift as an increase in the observed wavelength of light (or shift of light towards the red end of the spectrum).
- [1 mark] Explain that this indicates galaxies are moving away from us, which shows that the Universe is expanding.
题目 24 · Structured Explanation
2
A small heater is placed at the bottom of a beaker filled with cold water. Explain, in terms of the density of water, how the water throughout the beaker becomes hot.
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解题

When the water at the bottom of the beaker is heated, it expands and its volume increases. This expansion causes its density to decrease. The less dense warm water rises towards the top. At the same time, the cooler, denser water at the top sinks to the bottom to take its place. This continuous cycle forms a convection current that heats all the water in the beaker.

评分标准

1. [1] Heating causes the water to expand and decrease in density.
2. [1] The less dense warm water rises and the cooler, denser water sinks, forming a convection current.
题目 25 · Structured Explanation
2
A ray of light travels inside a semicircular glass block and strikes the straight edge at an angle of incidence greater than the critical angle. Describe and explain the path of the light ray after it meets the straight edge.
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解题

Since the light ray is travelling in a more dense medium (glass) towards a less dense medium (air) and the angle of incidence is greater than the critical angle, total internal reflection occurs. No light is refracted out of the glass block. Instead, all of the light is reflected back into the glass block, obeying the law of reflection where the angle of reflection equals the angle of incidence.

评分标准

1. [1] Total internal reflection occurs / no light refracts out of the block.
2. [1] All the light reflects back into the glass with the angle of reflection equal to the angle of incidence.
题目 26 · Structured Explanation
2
An astronaut on a spacewalk outside the International Space Station cannot hear the sound of a nearby thruster firing, but can see the flash of light from it. Explain this observation by comparing the propagation of light and sound.
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解题

Sound waves are longitudinal mechanical waves that propagate through the vibration of particles. Because space is a vacuum, there are no particles, so sound cannot travel to the astronaut's ears. On the other hand, light is an electromagnetic wave that consists of oscillating electric and magnetic fields, which does not require any material medium to travel and can easily propagate through a vacuum.

评分标准

1. [1] Sound is a mechanical wave / requires a material medium to travel (which is absent in the vacuum of space).
2. [1] Light is an electromagnetic wave / does not require a medium to travel (and can propagate through a vacuum).
题目 27 · Structured Explanation
2
A beam containing both alpha (\(\alpha\)) particles and beta (\(\beta\)) particles is directed into the region between two oppositely charged horizontal plates. State and explain the difference in the deflection of these two types of radiation.
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解题

Alpha particles are positively charged helium nuclei and are attracted towards the negatively charged plate. Beta particles are negatively charged electrons and are attracted towards the positively charged plate, so they deflect in opposite directions. Additionally, beta particles are deflected much more than alpha particles because their mass is extremely small compared to the mass of alpha particles, resulting in a much larger acceleration for a given force.

评分标准

1. [1] Deflection is in opposite directions because alpha is positively charged (deflected towards negative plate) and beta is negatively charged (deflected towards positive plate).
2. [1] Beta particles deflect much more because they have a much smaller mass than alpha particles.
题目 28 · Structured Recall & Diagram
2
State what is meant by the electromotive force (e.m.f.) of an electrical source.
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解题

The electromotive force (e.m.f.) is defined as the work done by the source (or energy transferred from other forms to electrical energy) per unit charge in driving charge around a complete circuit.

评分标准

1 mark for: work done per unit charge (or energy transferred per unit charge). 1 mark for: around a complete circuit.
题目 29 · Structured Recall & Diagram
2
A bar magnet is placed on a sheet of paper. State two rules that must be followed when drawing magnetic field lines to represent the magnetic field of the magnet.
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解题

When drawing magnetic field lines, the lines must never cross each other, and they must show the direction of the magnetic field from the North pole to the South pole.

评分标准

1 mark for: field lines do not cross/intersect. 1 mark for: direction is from North to South (indicated by arrows).
题目 30 · Structured Recall & Diagram
2
Explain, in terms of density changes, why hot air rises above a heater in a cold room.
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解题

When air is heated, it expands and its volume increases, causing its density to decrease. The surrounding cooler, denser air sinks and pushes the less dense warm air upwards, causing it to rise.

评分标准

1 mark for: heated air expands and its density decreases. 1 mark for: less dense warm air is pushed up by the cooler denser air.
题目 31 · Structured Recall & Diagram
2
A student stands at a distance of 85 m from a large flat wall. She claps her hands once and hears an echo. The speed of sound in air is 340 m/s. Calculate the time interval between the clap and hearing the echo.
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解题

The sound travels to the wall and back, so the total distance is 2 * 85 m = 170 m. Using the formula time = distance / speed, we get time = 170 / 340 = 0.50 s.

评分标准

1 mark for: using total distance 170 m or formula t = 2d/v. 1 mark for: 0.50 s (with unit).
题目 32 · Structured Recall & Diagram
2
Describe how the acceleration of an object can be determined from its speed–time graph, and state how the distance travelled can be found from the same graph.
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解题

On a speed-time graph, the acceleration is given by the gradient (or slope) of the line. The distance travelled by the object is represented by the area under the line.

评分标准

1 mark for: acceleration is the gradient/slope. 1 mark for: distance is the area under the graph.
题目 33 · Structured Recall & Diagram
2
An atom of radium-226 ({}^{226}_{88}Ra) decays by emitting an alpha particle to form an isotope of radon (Rn). State the proton number and the nucleon number of this isotope of radon.
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解题

An alpha particle has a proton number of 2 and a nucleon number of 4. Emitting an alpha particle decreases the proton number of the nucleus by 2 (88 - 2 = 86) and the nucleon number by 4 (226 - 4 = 222).

评分标准

1 mark for: proton number is 86. 1 mark for: nucleon number is 222.
题目 34 · Structured Recall & Diagram
2
A ray of light strikes a plane mirror with an angle of incidence of 40 degrees. State the angle of reflection, and state what happens to the speed of the light as it reflects from the mirror.
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解题

According to the law of reflection, the angle of reflection is equal to the angle of incidence, so it is 40 degrees. Reflection is a boundary phenomenon where light stays in the same medium, so the speed of light remains unchanged.

评分标准

1 mark for: 40 degrees. 1 mark for: speed remains unchanged/constant.
题目 35 · Structured Recall & Diagram
2
State the two main physical effects that cause the Earth to experience a cycle of day and night, and a cycle of seasons throughout the year.
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解题

The daily cycle of day and night is caused by the Earth rotating on its own axis once every 24 hours. The yearly cycle of seasons is caused by the tilt of the Earth's axis of rotation relative to its orbital plane as it travels around the Sun.

评分标准

1 mark for: rotation of the Earth (on its axis) causing day and night. 1 mark for: tilt of the Earth's axis / orbit around the Sun causing seasons.
题目 36 · Structured
2
Fig. 1.1 shows a ray of light inside a semi-circular glass block striking the flat boundary with air at an angle of incidence of \(48^\circ\). The critical angle for this glass-air boundary is \(42^\circ\). State what happens to the ray of light at the boundary and name this phenomenon.
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解题

Since the angle of incidence (\(48^\circ\)) is greater than the critical angle (\(42^\circ\)) and the light is travelling from a more optically dense medium (glass) to a less optically dense medium (air), the ray of light cannot refract out into the air. Instead, it undergoes total internal reflection, reflecting back into the glass block with an angle of reflection equal to the angle of incidence (\(48^\circ\)).

评分标准

[1] State that the ray is reflected back into the glass / undergoes reflection (at an angle of \(48^\circ\)). [1] Identify the phenomenon as total internal reflection.
题目 37 · Structured
2
Fig. 2.1 shows a standard bar magnet with its North (N) and South (S) poles. State the direction of the magnetic field lines outside the magnet and explain how the spacing of these lines represents the strength of the magnetic field.
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解题

The magnetic field lines always point from the North pole to the South pole outside a magnet. The density or spacing of the magnetic field lines represents the strength of the field: where the lines are closer together (such as near the poles), the magnetic field is strongest.

评分标准

[1] Direction of field lines: from North (N) to South (S). [1] Spacing: closer/denser lines represent a stronger magnetic field (or vice versa).

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